1. Twice the cube of a number2. The square of a number decreased by

ten3. The sum of three times a number and

seven4. Seven less than one third a number5. Three times the sum of a number and

seven6. If n represents an odd integer, what Is

the next consecutive odd integer

Algebra II 1

Literal Equations

Algebra II

3Algebra II

4Algebra II

5Algebra II

1. 3x – 2y = 10

-2y = -3x + 10

y = 3/2x – 5

2. ½x + 3y = 5

3y = - ½x + 5

y = - 1/6x + 5/3

3. 10 = 3x – ¾ y

-3x + 10 = - ¾y

4x – 40/3 = y

4. 4x + 8y = 17

8y = -4x + 17

y = -1/2x + 17/8

Algebra II 6

5. 6x – 5y = 13

y = 6/5x – 13/5

6. 2/3x + 3/2y = 10

y = -4/9x + 20/3

7. 4/3x – 2y = 12

y = 2/3 x – 6

8. 3x – 8y = 4

y = 3/8x – ½

Algebra II 7

Ax + By = C

is solved for Cin terms of A, x, B, and y

½bh = A

Is solved for Ain terms of b and h.

Algebra II 8

1. What is P = 2L + 2w solved for? In terms of?

Solved for P in terms of L and W

2. What is C = 2πr solved for? In terms of?

Solved for C in terms of r

3. What are you finding in A = (b)(h)? In terms of?

Finding A in terms of b and h

4. What are you finding in b = A/h ? In terms of?

Finding b in terms A and hAlgebra II 9

1. If A = c, 3tfind t in terms of A and c. A = c 3t A = (3t)(c) A = 3tc A = t 3c

2. If 3L + 2W = 6, find w in terms of L.

3L + 2W = 6

2w = -3L + 6

w = -3/2 L + 3

Algebra II 10

3. If c = 4a2, find a in terms of c.

4. If A = πrL + πr2,

Find L in terms of A and r.

A - πr2 = πrL

A - πr2 = Lπr

A – r = L πr

Algebra II 11

5. If E=mc2, find m in terms of c and E.

6. If V = 1/3πr2h, find r in terms of V and h.

12Algebra II

7. If find p in terms of m, L, and q.

8. If A = 1/2bh, find h in terms of A and b.

A = ½bh

2A = bh

2A = h b

13Algebra II

1. Solve for y: 5x + 2/3 y = 102. Solve for x. 3x - 4y = 123. Solve for r in terms of V and

h: V = 4/3πr2h

14Algebra II

Literal Equations

Algebra II

What is P in terms of right now? L and W

What should you replace? LW = L + 3W – 3 = L

P = 2L + 2WP = 2(w – 3) + 2wP = 4w – 6

16Algebra II

What is A in terms of right now? b and h

What should you replace? Bb = 3h

A = ½bhP = ½ (3h)(h)P = 3/2 h2

17Algebra II

What is V in terms of right now? r and h

What should you replace? hr = 1/2h2r = h

V = 1/3πr2hV = 1/3πr2(2r)V = 2/3πr3

18Algebra II

What is the Area in terms of now? r

What should you replace? RC = 2πrR = C/2π

A = π(r)2

A = π(C/2π)2

A = C/(4π)

19Algebra II

What is the Area in terms of now? b and h

What should you replace? H

A = ½ bhA = ½ b(√3/2)bA = √3b2/4

20Algebra II

h=d V=πr2h What is V in terms of now?

Radius and height What should we replace?

Height h=d h=2rV=πr2hV=πr2(2r)V=2πr3

21Algebra II

h=5 + 3r S=2πrh + 2πr2

What is S in terms of now? Radius and height

What should we replace? Height

h=5+3r S= 2πrh + 2πr2

S= 2πr(5 + 3r) + 2πr2

S= 10πr + 6πr2 +2πr2

S= 10πr + 8πr2

22Algebra II

1. Solve for y: 1/3 x + 2/5 y = 10.

1. Given 4n + 1/2 m = 12, find m in terms of n.

2. If the area of a square can be found by A = s2 and the perimeter of a square can be found by p = 4s, find area of a square (A) in terms of its perimeter (p).

23Algebra II