14
Bell Ringer 1. What is the solution of 2b + 3b + 6 = 21? 2. Verify that the solution to the equation below is correct. Then justify each step that was used to solve the equation. (Example of step used might be distribution, simplification, addition, multiply, etc.) 8m + 6m − 12 = 72 – Step Used:2a) _________________ 14m − 12 = 72 – Step Used:2b) _________________ 14m = 84 – Step Used:2c) _________________ m = 6 – Step Used:2d) _________________

1. What is the solution of 2b + 3b + 6 = 21? 2. Verify that the solution to the equation below is correct. Then justify each step that was used to solve

Embed Size (px)

DESCRIPTION

WWhen solving an equation, the goal is to get the variable by itself. AAddition and Subtraction are inverse operations. (opposites) MMultiplication and Division are inverse operations. (opposites)

Citation preview

Page 1: 1. What is the solution of 2b + 3b + 6 = 21? 2. Verify that the solution to the equation below is correct. Then justify each step that was used to solve

Bell Ringer

1. What is the solution of 2b + 3b + 6 = 21?2. Verify that the solution to the equation

below is correct. Then justify each step that was used to solve the equation. (Example of step used might be distribution, simplification, addition, multiply, etc.)8m + 6m − 12 = 72 – Step Used:2a) _________________14m − 12 = 72 – Step Used:2b) _________________14m = 84 – Step Used:2c) _________________m = 6 – Step Used:2d) _________________

Page 2: 1. What is the solution of 2b + 3b + 6 = 21? 2. Verify that the solution to the equation below is correct. Then justify each step that was used to solve

Agenda & News

Start Literal Equations Assignment Ticket Out

First holiday, Monday, September 7th Labor day – No School

Page 3: 1. What is the solution of 2b + 3b + 6 = 21? 2. Verify that the solution to the equation below is correct. Then justify each step that was used to solve

Rules to Remember

When solving an equation, the goal is to get the variable by itself.

Addition and Subtraction are inverse operations. (opposites)

Multiplication and Division are inverse operations. (opposites)

Page 4: 1. What is the solution of 2b + 3b + 6 = 21? 2. Verify that the solution to the equation below is correct. Then justify each step that was used to solve

Don’t Forget

The equation is like a balance scale. Whatever you do to one side of the equation must be done to the other side of the equation.

Page 5: 1. What is the solution of 2b + 3b + 6 = 21? 2. Verify that the solution to the equation below is correct. Then justify each step that was used to solve

New Vocabulary

Literal Equation – involves 2 or more variables. The equation is called literal because the coefficients and constants are replaced with letters.

Ex: 3x + 2y = 6

This equation can be solved for either x or y. (We will be told which one to solve for).

Page 6: 1. What is the solution of 2b + 3b + 6 = 21? 2. Verify that the solution to the equation below is correct. Then justify each step that was used to solve

Literal Equations When you rewrite literal equations, you may have to

divide by a coefficient, a variable, or a variable expression.

A formula is a special type of literal equation because it involves two or more variables.

Here are other Literal Equations (or formulas)that you may have seen before:

P = 2L + 2Wd = rtA = bh

You can solve for any of the variables in any of these equations.

Page 7: 1. What is the solution of 2b + 3b + 6 = 21? 2. Verify that the solution to the equation below is correct. Then justify each step that was used to solve

Solve it!1. You are ordering pizzas

and sandwiches. You have a budget of $80. How many sandwiches can you buy if you buy 4 pizzas?

2. What about 5 pizzas? Explain your answer.

1. Px + Sy = 80 10x+5y = 8010(4) + 5y = 80 40+5y=80 40-40+5y=80-40 5y = 40 y= 82. px + sy = 80 10x+5y = 8010(5) + 5y = 80 50+5y=80 50-50+5y=80-30 5y = 30 y= 6

Explain it!

As the number of pizzas

increases, the number of

sandwiches decreases.

Page 8: 1. What is the solution of 2b + 3b + 6 = 21? 2. Verify that the solution to the equation below is correct. Then justify each step that was used to solve

Rewriting a literal equation In the last problem we solved

question 1 and 2 by substituting each x into the equation and then solving for y twice, once for each x-variable.

However, if you rewrite the equation first, you only have to isolate y once. Then substitute for x.

Page 9: 1. What is the solution of 2b + 3b + 6 = 21? 2. Verify that the solution to the equation below is correct. Then justify each step that was used to solve

Redo

1. You are ordering pizzas and sandwiches. You have a budget of $80. How many sandwiches can you buy if you buy 3 pizzas?

2. What about 6 pizzas?

10x + 5y = 8010x + 5y – 10x = 80 – 10x 5y = 80 – 10x y = 16 – 2x

Step 2Step 1 Use the rewritten equation to find

y when x = 3 and when x = 6

y= 16 – 2x y= 16 – 2x y= 16 – 2(3) & y= 16 – 2(6)y= 10 y = 4

Page 10: 1. What is the solution of 2b + 3b + 6 = 21? 2. Verify that the solution to the equation below is correct. Then justify each step that was used to solve

Key Understanding When you work with literal

equations, you can use the methods we have learned to isolate any particular variable.

Page 11: 1. What is the solution of 2b + 3b + 6 = 21? 2. Verify that the solution to the equation below is correct. Then justify each step that was used to solve

Got it? #1 Solve the equation 4 = 2m – 5n for

m. What are the values of m, when n = -2, 0, and 2?

Page 13: 1. What is the solution of 2b + 3b + 6 = 21? 2. Verify that the solution to the equation below is correct. Then justify each step that was used to solve

Got it? #2

What equation do you get when you solve –t = r + px for x?

-t = r + px -t – r = r + px – r -t – r = px = = x

Page 14: 1. What is the solution of 2b + 3b + 6 = 21? 2. Verify that the solution to the equation below is correct. Then justify each step that was used to solve

Rewriting a formula

The formula for the Perimeter of a Rectangle isP = 2L + 2W

Example: Solve for W P = 2L + 2W

– 2L –2L P – 2L = 2W

P – 2L = 2W 2 2 P – 2L = W

2

L

W