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CMAHELP.INcmahelp.weebly.com/uploads/1/5/6/3/15633668/interp... · 10 x 5 = 50 31x5=155 Cost 155+50=205 (100 x 0.6) + (10 x 66 x 5 330 330+205=535 0.3) + Optimal replacement period
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