B dy hc sinh gii s 1Cu 1:C 3 cht: Al, Mg, Al2O3. Ch c dng mt ha cht lm thuc th hy phn bit 3 cht trn?Cu 2: Mui X va tc dng vi dung dch HCl va tc dng vi dung dich NaOH. Hi mui X thuc loi mui trung ha hayaxit? Cho v d minh ha?Cu 3: nh ngha phn ng trao i? iu kin phn ng trao i xy ra? Cho v d minh ha? Phn ng trung ha c phi l phn ng trao i khng?Cu 4: Kh CO2 c iu ch bng cch phn ng gia HCl v CaCO3 c ln hi nc v HCl. Lm th no thu c CO2 tinh khit?Cu 5: Mt oxit kim loi c cng thc l MxOy, trong M chim 72,41% khi lng. Kh hon ton oxit ny bng kh CO thu c 16,8 gam kim loi M. Ha tan lng M bng HNO3 c nngthu c mui M ha tr III v 0,9 mol kh NO2 . Vit cc phng trnh phn ng v x nh oxit kim loi6. Nung m gam hn hp 2 mui cacbonat trung tnh ca 2 kim loi A v B u c ha tr II. Sau mt thi gian thu c 3,36 lt kh CO2 (ktc) v cn li hn hp rn Y. Cho Y tc dng hon ton vi dung dch HCl d ri cho kh thot ra hp th hon ton bi dung dch Ca(OH)2 d, thu c 15 gam kt ta. Phn dung dch c cn c 32,5 gam hn hp mui khan. Vit cc phng trnh phn ng v tnh m ? 12. Cho 5,22 gam mt mui cacbonat kim loi (hp cht X) tc dng vi dung dch HNO3 . Phn ng gii phng ra gm 0,336 lit NO v x lit kh CO2. Cc th tch kh c o iu kin tiu chun. Hy xc nh mui cacbonat kim loi v tnh th tch kh CO2 (x) ? 13. Cho mt lng Cu2S tc dng vi dung dch HNO3 un nng. Phn ng to ra dung dch A1 v gii phng kh A2 khng mu, b ha nu trong khng kh. Chia A1 thnh 2 phn. Thm BaCl2 vo phn 1, thy kt ta trng A3 khng tan trong axit d. Thm mt lng d NH3 vo phn 2, ng thi khuy u hn hp, thu c dung dch A4 c mu xanh lam m.a) Hy ch ra A1, A2, A3, A4 l g?b) Vit cc phng trnhha hc m t qu trnh nu trn?14. t cacbon trong khnh kh nhit cao, c hn hp kh A. Cho A tc dng vi Fe2O3 nung nng c kh B v hn hp rn C. Cho B tc dng vi dung dch Ca(OH)2 thu c kt ta K v dung dch D, un si D li c kt ta K. Cho C tan trong dung dch HCl thu c kh v dung dcg E. Cho E tc dng vi dung dch NaOH d c hn hp kt ta hirxit F. Nung F trong khng kh c xit duy nht. Vit cc phng trnh phn ng?15. Fe + O2 AA + HCl B + C + H2OB + NaOH D + GC + NaOH E + GDng phn ng ha hc no chuyn D thnh E? Bit rng B + Cl2 C.16.Cho mt lung hir d ln lt i qua cc ng mc ni tip sau y: CaO CuO Al2O3 Fe2O3 Na2O. Sau ly cc cht cn li trong ng cho tc dng ln lt vi CO2 , vi dung dch HCl v AgNO3. Vit tt c cc phng trnh xy ra? Trang 1 B dy hc sinh gii17. C 5 mu kim loi : Ba, Mg, Fe, Ag, Al. Nu ch c dung dich H2SO4 long c th nhn bit c nhng kim loi no?18. Cho 4 kim loi A, B, C, D c mu gn ging nhau ln lt tc dng vi HNO3 c, dung dch HCl, dung dch NaOH ta thu c kt qu nh sau:A B C DHNO3HClNaOH-++-+-+--++-Hi chng l cc kim loi gh trong cc kim loi sau y :Mg, Fe, Ag, Al, Cu? Vit cc phng trnh phn ng, bit rng kim loi tc dng vi HNO3 c ch c kh mu nu bay ra.19. Kh 2,4 g hn h CuO v mt st oxit bng hir thy cn li 1,76 g cht rn. Nu ly cht rn ha tan bng dung dch HCl th thot ra 0,448 lt kh (ktc) . Xc nh cng thc ca st oxit. Bit rng s mol ca 2 oxit trong hn hp bng nhau. 20. Xc nh cng thc phn t ca mt loi mui clorua kp xKCl.yMgCl2.zH2O(mui A) ngi ta tin hnh 2 th nghim sau:- Nung 11,1 g mui thu c 6,78 g mui khan.- Cho 22,2 g mui tc dng vi xt d ri ly kt ta em nung thu c 3,2 g cht rn. Bit khi lng phn t mui kp l 277,5. Tm cc gi tr x, y, z?21. Khi nung 6,06 g mt mui Nitrat ca mt kim loi kim ta thu c 5,1 g cht rn (nitrit). Hi phn hy mui nitrat ca kim loi gh?22. xc nh thnh phn ca mui kp A c cng thc p(NH4)2SO4.qFex(SO4)y.tH2O ngi ta tin hnh th nghim sau:Ly 9,64 g mui A ha tan vo nc, sau cho tc dng vi Ba(OH)2 d, khi un nng ta thu c kt ta B v kh C. Ly kt ta B nung nhit cao ( c mt khng kh) ta thu c 10,92 g cht rn. Cho ton b kh C hp th vo 200 ml dung dch H2SO4 0,1 M. trung ha lng axit d cn dng 200 ml dung dch NaOH 0,1 M1) Vit tt c cc phng trnh phn ng xy ra?2) Xc nh cc gi tr x, y, p, q, t?23. Cn ly bao nhiu gam tinh th CuSO4.5H2Ov bao nhiu gam dung dch CuSO4 8% iu ch280 g dung dch CuSO4 16%?24. Trn V1 lit dung dch A cha 9,125d HCl vi V2 lit dung dch B cha 5,47 g HCl, ta thu c 2 lit dung dch C. Tnh nng d mol ca dung dch A, B, C bit V1 + V2 = 2l, v hiu s gia nng mol dung dich A v B l 0,4 mol/l.25. ng nitrat b phn hy khi nung nng theo phn ng:Cu(NO3)2 CuO + 2NO2 + O2.Nu khi nung 15,04g ng nitrat thy cn li 8,56g cht rn, th c bao nhiu phn trm ng nitrat b phn hy v xc nh thnh phn cht rn cn li. 26. Ha tan 1,42g hp kim Mg - Al - Cu bng dung dch HCl dta thu c dung dch A, kh B v cht rn C. Cho dung dch A tc dng vi xt d ri ly kt ta nung nhit cao th thu c 0,4g cht rn. Mt khc t nng cht rn C trong khng kh th thu c 0,8g mt oxit mu en.1) Tnh khi lng mi kim loi trong hn hp ban u? 2) Cho kh B tc dng vi 0,672 lit kh clo (ktc) ri ly sn phm ha tan vo 19,72 lit nc, ta c dung dch D. Ly 5 g dung dch D tc dng vi AgNO3 thy to thnh 0,7175g kt ta. Tnh hiu sut phn ng gia kh B v clo? Trang 2 B dy hc sinh gii27. Chia 1,5g hn hp bt Fe - Al - Cu thnh 2 phn bng nhau:1) Ly mt phn ha tan bngdung dich HCl thy cn li 0,2g cht rn khng tan v 448 cm3 kh bay ra. Tnh khi lng mi kim loi trong hn hp?2) Ly phn th 2 cho vo 400 ml dung dch hn hp AgNO3 0,08 M v Cu(NO3)2 0,5 M. Sau khi kt thc cc phn ng ta thu c cht rn A v dung dch B. Tnh khi lng cht rn A v nng mol ca cc cht trong dung dch B?28. Mt loi cha CaCO3, MgCO3, Al2O3, khi lng nhm oxit bng 1/8 khi lng cc mui cacbonat. em nung nhit cao ta thu c cht rn c khi lng bng 6/10 khi lng trc khi nung. Tnh thnh phn trm ca MgCO3 trong ?29. Ha tan 4,59g nhm bng dung dch HNO3 c dung dch nhm nitrat v hn hp kh NO v N2O c t khi so vi hir l 16,75.1) Tnh khi lng nhm nitrat?2) Tnh th tch cc kh NO v N2O ?30.* A l mt mu hp kim Cu - Zn. Chia mu hp kim thnh 2 phn bng nhau. Phn th nht ha tan bng dung dch d thy cn li 1 gam khng tan, phn th 2 luyn thm vo 4 gam Al th thu c mu hp kim trong B c hm lng phn trm ca Zn nh hn 33,3% so vi hm lng Zn trong mu hp kim A.Tnh % ca Cu trong mu hp kim A, bit rng khi ngm mu hp kim B trong dung dch NaOH th sau mt thi gian lng kh bay ra vt qu 6 lit.31. Hn hp kh O2 v SO2 c t khi so vi hir bng 24, sau khi ung nng hn hp vi cht xc tc ta thu c hn hp kh mi c t khi hi so vi hir bng 30.a) Xc nh thnh phn hn hp trc v sau phn ng?b) Tnh thnh phn trm mi kh tham gia phn ng?Ch : Trong bi tp ny cc cht u phn ng khng hon ton.32. Hon thnh ccphn ng theo s sau:Fe + ... A + BA + NaOH C + NaClC + O2 + H2O DD E;E + BFe33. Hy ly 3 cht v c ( A, B, C) tha mn cc iu kin sau:- Khi trn 2 dung dch A v B th to thnh kt ta.- Khi cho A hoc B tc dng vi C th to thnh mt cht kh khng chy.34. A, B, C l cc hp cht ca kim loi, khi t nng nhit cao c ngn la mu vng, D l mt hp cht ca cacbon. A tc dng vi D to thnh B hoc C, A tc dng vi B to thnh C. Nung D nhit cao c mt sn phm l D, D tc dng vi dung dch C to thnh B.A, B, C l nhng cht gh? Vit cc phng trnh phn ng?35. C mt hn hp 3 kim loi ha tr II ng trc H. T l khi lng nguyn t ca chng l 3 : 5 : 7. T l s mol ca cc kim loi l4 : 2 : 1. Khi ha tan 14,6 gam hn hp bng dung dch HCl thy thot ra 7,84 l hir. Xc nh khi lng nguyn t v gi tn ca chng? 36.* A l dung dch NaOH, B l dung dch H2SO4. Trn 0,2 lit A v 0,3 lit B thu c 0,5 lit dung dch C. Ly 20 ml dng dch C, thm mt t qu tm vo ta thy mu xanh. Sau thm t t dung dch HCl 0,05M cho ti khi qu tm chuyn thnh mu tm thy tn ht 40 ml axit. Trng 0,3 l A v 0,3l B c dung dch D. Ly 20 ml dung dch D, thm vo 1 t qu tm thy c Trang 30t0t B dy hc sinh giimu , sau thm t t dung dch NaOH 0,1 M cho ti khi qu tm i thnh mu tm thy tn ht 80 ml dung dch NaOH. Tnh nng mol ca cc dung dch A v B?37. Cho cht A tc dng vi cht B c kh I c mi trng thi. t chy kh I khi c mt oxi d c kh II c mi hc. Cho kh I tc dng vi kh II c cht C mu vng. Nung cht C vi st c cht D, cho D tc dng vi dung dch HCl c kh I.Vit cc phng trnh phn ng xy ra?38.* Hn hp A gm BaO, FeO, Al2O3. Ha tan A trong lng d nc, c dung dch D v phn khng tan B. Sc kh CO2 d vo dung dch D, phn ng to kt ta. Cho kh CO d i qua B nung nng thu c cht rn E. Cho E tc dng vi dung dch NaOH d, thy tan mt phn cn li cht rn G. Ha tan ht G trong mt lng d dung dch H2SO4 long ri cho dung dch thu c tc dng vi dung dch KMnO4. Vit cc phng trnh phn ng xy ra?39. Cho 18,5 g hn hp Z gm Fe, Fe3O4 tc dng vi 200 ml dung dch HNO3 long un nng v khuy u. Sau khi phn ng xy ra hon ton thu c 2,24 lit kh NO duy nht (ktc), dung dch Z1 v cn li 1,46 gam kim loi.1/ Vit cc phng trnh phn ngxy ra?2/ Tnh nng mol/l ca dung dch HNO3?3/ Tnh khi lng mui trong dung dch Z1?40. Vit 4 phng trnh thch hp cho s sau: Ba(NO3)2 + ? NaNO3 + ?41. Vit phng trnh phn ng xy ra (nu c):a) Cho bt nhm vo dung dch NaClb) Cho mt mu Natri vo dung dch FeCl3.c) Cho bt Fe vo dung dch AgNO3 d.d) Sc kh SO2 t t vo dung dch nc vi trong cho n d kh SO2.42. Trong t nhin cc nguyn t Ca, Mg c trong qung lmit: CaCO3.MgCO3. t qung ny, hy trnh by phng php iu ch CaCO3, MgCO3 dng ring bit tinh khit?43. C hai dung dch NaOH nng C%(dung dch 1) v C2% (dung dch 2). Cn trn chng theo t l khi lng nh th no thu c dung dch NaOH C% (dung dcg 3). ( Khng s dng quy tc ng cho)p dng bng s: C1 = 3%, C2 = 10%, C1 = 5%.44.Cho 10 lt N2 v CO2 (ktc) i qua2 lt dung dch Ca(OH)2 0,02M, thu c 1 g kt ta. Xc nh thnh phn % (theo th tch) ca CO2 trong hn hp.45. Cho 1 dung dch c ha tan 16,8g NaOH tc dng vi dung dch c ha tan 8g Fe2(SO4)3, sau li thm vo dung dch trn 13,68g Al2(SO4)3. T nhng phn ng ny ngi ta thu c dung dchA v kt ta. Lc kt ta c cht rn B. Dung dch A c pha long 500 ml. Cc phn ng xy ra hon ton.a) Xc inh thnh phn nh tnh v nh lng ca cht rn B?b) Xc nh nng M ca mi cht trong dung dch A sau khi pha long?46. T Canxicacbua v cc cht v c cn thit khc, vit PTP iu ch nha PE, etylaxtat, cao su Buna?47. t chy hon ton 18g cht hu c A cn lng va 16,8lit O2 (ktc), thu c CO2 v hi nc vi t l th tch V( CO2) : V (H2O) = 3 : 2. Bit t khi hi ca A so vi H2 l 36.a) Hy xc nh cng thc phn t ca A?b) Hy ngh CTCT ca A. Bit rng A c th axit hoc este. Trang 4 B dy hc sinh gii48. Nhit phn hon ton hn hp gm: BaCO3, MgCO3, Al2O3 c cht rn A, kh D. Ha tan A trong NaOH d c dung dch B v kt ta C. Sc B vo D thy c kt ta. Ha tan C trong dung dch NaOH d thy kt ta tan mt phn. Vit cc PTP? s 1Bi 1: Ho tan hon ton 3,34 gam hn hp hai mui cabonat kim loi ho tri II v ho tr III bng dung dch HCl d ta c dung dch A v 0,896 lt kh ktc. Tnh khi lng mui c trong dung dch A.Bi 2: Kh m gam hn hp X gm cc oxit CuO, FeO, Fe2O3 v Fe3O4 bng kh CO nhit cao, ngi ta thu c 40 gamcht rn Y v 13,2 gam kh CO2. Tnh gi tr ca m.Bi 3: Ngm mt vt bng ng c khi lng 15 gam dung dch c cha 0,12 mol AgNO3 . sau mt thi gian ly vt ra thy khi lng AgNO3 trong dung dch gim 25%. Tnh khi lng ca vt sau phn ng.Bi 4: Cho 3,78 gam bt Nhm phn ng va vi dung dch mui XCl3 to thnh dung dch Y gim 4,06 gam so vi dung dch XCl3. Tm cng thc ca mui XCl3.Bi 5: Nung 100 gam hn hp gm Na2CO3 v NaHCO3 cho n khi khi lng hn hp khng i c 69 gam cht rn. Tnh thnh phn phn % khi lng ca cc cht trong hn hp.Bi 6: Ly 3,33 gam mui Clorua ca mt kim loi ch c ho tr II v mt lng mui Nitrat ca kim loi c cng s mol nh mui Clorua ni trn, thy khc nhau 1,59 gam. Hy tm kim loi trong hai mui ni trn.Bi 7: Cho 14,5 gam hn hp gm Mg, Fe v Zn vo dung dich H2SO4 long d to ra 6,72 lt H2 ktc. Tnh khi lng mui Sunfat thu c.Bi 8: Ho tan m gam hn hp A gm St v kim loi M ( c ho tr khng i) trong dung dch HCl d th thu c 1,008 lt kh ktc v dung dch cha 4,575 gam mui khan. Tnh gi tr ca m.Bi 9: Cho 0,25 mol hn hp KHCO3v CaCO3tc dng ht vi dung dch HCl. Kh thot ra c dn vo dung dch nc vi trong d, thu c a gam kt ta. Hy tnh gi tr ca a.Bi 10: Cho 9,4 gam MgCO3 tc dng vi mt lng va dung dch HCl, Dn kh sinh ra vo dung dch nc vi trong. Hy tnh khi lng kt ta thu c. Bi 11: Cho 1,78 gam hn hp hai kim loi ho tri II tan hon ton trong dung dch H2SO4 long, gii phng c 0,896 lt kh Hir ktc. Tnh khi lng hn hp mui Sunfat khan thu c.Bi 12: Ho tan 4 gam hn hp gm Fe v mt kim loi ho tr II vo dung dch HCl thu c 2,24 lt kh H2 ktc. Nu ch dng 2,4 gamkim loi ho tr II th dng khng ht 0,5 mol HCl. Tm kim loi ho tri II. Bi 13: Cho 11,2 gam Fe v 2,4 gam Mg tc dng ht vi dung dch H2SO4 long d sau phn ng thu c dung dch A v V lt kh H2 ktc. Cho dung dch NaOH d vo dung dch A thu c kt ta B. Lc B nung trong khng kh n khi lng khi lng khng i c m gam. Tnh gi tr m. s 2Bi 1. 20oC, ha tan 60g mui kali nitrat vo 190g nc th c dung dch bo ha. Hy tnh tan ca mui kali nitrat nhit .a: 31,6gBi 2. 20oC tan ca kali sunfat l 11,1g. Hi phi ha tan bao nhiu gam mui ny vo 80g nc c dung dch bo ha Trang 5 B dy hc sinh gii nhit cho.a: 8,88gBi 3. Xc nh khi lng mui kali clorua kt tinh c sau khi lm ngui 604g dung dch bo ha 80oC xung 20oC . tan ca KCl 80oC bng 51g 20 oC l 34ga: 68gBi 4. tan ca NaNO3 100 oC l 180g, 20 oC l 88g. Hi c bao nhiu gam NaNO3 kt tinh li khi h nhit ca 84g dung dch NaNO3 bo ha t 100 oC xung 20 oCa: 27,6gBi 5. khi ha tan 48g amoni nitrat vo 80ml nc, lm cho nhit ca nchxungti -12,2oC.Numunhnhitca250ml nct15oC xung 0oC th cn phi ha tan bao nhiu gam amoni nitrat vo lng nc ny.a: 82,72gBi 6. Tnh phn trm v khi lng ca nc kt tinh trong:a. Xoa: Na2CO3 . 10 H2Ob. Thch cao: CaSO4 . 2H2Oa: a. 62,93% b. 20,93%Bi 7: C cn 160 gam dung dch CuSO4 10% n khi tng s nguyn t trong dung dch ch cn mt na so vi ban u th dng li. Tm khi lng nc bay ra.( a: 73,8 gam)Bi 8: Tnh nng phn trm ca dung dch H2SO4 6,95M (D = 1,39 g/ml) MC .M6,95.98C% 49%10D 10.1,39 Bi 9:a. Cn ly bao nhiu gam CuSO4 ha tan vo 400ml dd CuSO4 10% (D = 1,1 g/ml) to thnh dd C c nng l 20,8%b. Khi h nhit dd C xung 12oC th thy c 60g mui CuSO4.5H2O kt tinh, tch ra khi dd . Tnh tan ca CuSO4 12oC. (c php sai s nh hn 0,1%) (a = 60g / b.17,52)Bi 10: Cho 100g dd Na2CO3 16,96%, tc dng vi 200g dd BaCl2 10,4%. Sau phn ng , lc b kt ta c dd A . Tnh nng % cc cht tan trong dd A. (NaCl 4,17%, Na2CO3 2,27%) Bi 11: Ha tan mt lng mui cacbonat ca mt kim loi ha tr II bng dd H2SO4 14,7 %. Sau khi phn ng kt thc kh khng cn thot ra na, th cn li dd 17% mui sunfat tan. Xc nh khi lng nguyn t ca kim loi. s 3Bi 1: Ho tan hon ton 3,34 gam hn hp hai mui cabonat kim loi ho tri II v ho tr III bng dung dch HCl d ta c dung dch A v 0,896 lt kh ktc. Tnh khi lng mui c trong dung dch A.Bi 2: Kh m gam hn hp X gm cc oxit CuO, FeO, Fe2O3 v Fe3O4 bng kh CO nhit cao, ngi ta thu c 40 gam cht rn Y v 13,2 gam kh CO2. Tnh gi tr ca m. Trang 6 B dy hc sinh giiBi 3: Ngm mt vt bng ng c khi lng 15 gam dung dch c cha 0,12 mol AgNO3 . sau mt thi gian ly vt ra thy khi lng AgNO3 trong dung dch gim 25%. Tnh khi lng ca vt sau phn ng.Bi 4: Cho 3,78 gam bt Nhm phn ng va vi dung dch mui XCl3 to thnh dung dch Y gim 4,06 gam so vi dung dch XCl3. Tm cng thc ca mui XCl3.Bi 5: Nung 100 gam hn hp gm Na2CO3 v NaHCO3 cho n khi khi lng hn hp khng i c 69 gam cht rn. Tnh thnh phn phn % khi lng ca cc cht trong hn hp.Bi 6: Ly 3,33 gam mui Clorua ca mt kim loi ch c ho tr II v mt lng mui Nitrat ca kim loi c cng s mol nh mui Clorua ni trn, thy khc nhau 1,59 gam. Hy tm kim loi trong hai mui ni trn.Bi 7: Cho 14,5 gam hn hp gm Mg, Fe v Zn vo dung dich H2SO4 long d to ra 6,72 lt H2 ktc. Tnh khi lng mui Sunfat thu c.Bi 8: Ho tan m gam hn hp A gm St v kim loi M ( c ho tr khng i) trong dung dch HCl d th thu c 1,008 lt kh ktc v dung dch cha 4,575 gam mui khan. Tnh gi tr ca m.Bi 9: Cho 0,25 mol hn hp KHCO3v CaCO3tc dng ht vi dung dch HCl. Kh thot ra c dn vo dung dch nc vi trong d, thu c a gam kt ta. Hy tnh gi tr ca a.Bi 10: Cho 9,4 gam MgCO3 tc dng vi mt lng va dung dch HCl, Dn kh sinh ra vo dung dch nc vi trong. Hy tnh khi lng kt ta thu c. Bi 11: Cho 1,78 gam hn hp hai kim loi ho tri II tan hon ton trong dung dch H2SO4 long, gii phng c 0,896 lt kh Hir ktc. Tnh khi lng hn hp mui Sunfat khan thu c.Bi 12: Ho tan 4 gam hn hp gm Fe v mt kim loi ho tr II vo dung dch HCl thu c 2,24 lt kh H2 ktc. Nu ch dng 2,4 gamkim loi ho tr II th dng khng ht 0,5 mol HCl. Tm kim loi ho tri II. Bi 13: Cho 11,2 gam Fe v 2,4 gam Mg tc dng ht vi dung dch H2SO4 long d sau phn ng thu c dung dch A v V lt kh H2 ktc. Cho dung dch NaOH d vo dung dch A thu c kt ta B. Lc B nung trong khng kh n khi lng khi lng khng i c m gam. Tnh gi tr m. s 41-C 4 l ng ring bit: Nc ct, d.d NaOH, HCl, NaCl. Nu cch nhn bit tng cht trong l.2- Vit cc PTHH v dng qu tm chng minh rng: a) CO2, SO2, SO3, N2O5, P2O5 l cc Oxit axit.b) Na2O, K2O, BaO, CaO l cc xit baz.3- C 5 l ng ring bit: Nc ct,Ru etylic, d.d NaOH, HCl, d.dCa(OH)2 . Nu cch nhn bit tng cht trong l.4- Cho 17,2 gam hn hp Ca v CaO tc dng vi lng nc d thu c 3,36 lt kh H2 ktc.a) Vit PTHH ca cc phn ng xy ra v tnh khi lng mi cht c trong hn hp?b) Tnh khi lng ca cht tan trong dung dch sau phn ng?5-Choccchtsau: P2O5, Ag, H2O, KClO3, Cu, CO2, Zn, Na2O, S, Fe2O3, CaCO3, HCl. Hy chn trong s cc cht trn iu ch c cc cht sau, vit PTHH xy ra nu c? Trang 7 B dy hc sinh gii6- Chn cc cht no sau y: H2SO4 long, KMnO4, Cu, C, P,NaCl, Zn, S, H2O, CaCO3, Fe2O3, Ca(OH)2, K2SO4, Al2O3, iu ch cc cht: H2, O2, CuSO4, H3PO4, CaO, Fe. Vit PTHH?7- Bng phng php ho hc hy nhn bit 4 kh l: O2, H2, CO2, CO ng trong 4 bnh ring bit?8- Bng phng php ho hc hy phn bit cc dung dch sau: HCl, NaOH, Ca(OH)2, CuSO4, NaCl. Vit PTHH xy ra?9-Cmt ccngd.dH2SO4long.Lc ungi tachomt lngbt nhm vo dd axit, phn ng xong thu c 6,72 lt kh H2ktc. Sau thm tip vo dd axit mt lng bt km d, phn ng xong thu c thm 4,48 lt kh H2 na ktc.a) Vit cc PTHH xy ra?b) Tnh khi lng bt Al v Zn tham gia phn ng?c) Tnh khi lng H2SO4 c trong dung dch ban u?d) Tnh khi lng cc mui to thnh sau phn ng?10- Tnh lng mui nhm sunfat c to thnh kh cho 49 gam axit H2SO4 tc dng vi 60 gam Al2O3.Sau phn ng cht no cn d, khi lng l bao nhiu?11-Mt baz A c thnh phn khilng ca kim loil 57,5 %. Hy xc nh cng thc baz trn. Bit PTK ca A bng 40 vC.12-Cho cc cht c CTHH sau: K2O, HF, ZnSO4, CaCO3, Fe(OH)3, CO, CO2, H2O, NO, NO2, P2O5, HClO, HClO4, H3PO4, NaH2PO4, Na3PO4, MgCl2. Hy c tn cc cht ?13-Th tch nc trng thi lng thu c l bao nhiu khi t 112 lt H2 ktc vi O2d ?14- Vit PTHH thc hin s sau: a) Na -> Na2O -> NaOH -> NaCl. b) C -> CO2- > CaCO3-> CaO -> Ca(OH)2 .c) S -> SO2 -> SO3 - > H2SO4-> ZnSO4d)P->P2O5->H3PO4-> Na3PO4.15- Nu cho cng s mol mi kim loi : K , Ca , Al , ln lt tc dng vi dung dch axit HCl th kim loi no cho nhiu Hidro hn ? s 5Cu 1:T cc ha cht c sn sau y: Mg ; Al ; Cu ; HCl ; KClO3 ; Ag . Hy lm th no c th thc hin c s bin i sau:Cu--- >CuO--- >CuCu 2:Kh hon ton 11,5 gam mt xit ca Ch bng kh Hiro, th thu c 10,35 gam kim loi Ch. Tm cng thc ha hc ca Ch xit.Cu 3: Cc cht no sau y c th tc dng c vi nhau? Vit phng trnh ha hc. K ; SO2 ; CaO ; H2O , Fe3O4 , H2 ; NaOH ; HCl.Cu 4: Kh hon ton hn hp (nung nng ) gm CuO v Fe2O3 bng kh Hiro, sau phn ng thu c 12 gam hn hp 2 kim loi. Ngm hn hp kim loi ny trong dd HCl, phn ng xong ngi ta li thu c kh Hiro c th tch l 2,24 lt.A) Vit cc phng trnh ha hc xy ra. Trang 8 B dy hc sinh giiB) Tnh thnh phn phn trm theo khi lng ca mi Oxit c trong hn hp ban u.C)Tnh th tch kh Hiro dng ( ktc ) kh kh hn hp cc Oxit trn.Cu 5: Cho 28 ml kh Hiro chy trong 20 ml kh Oxi.A) Tnh : khi lng nc to thnh.B) Tnh th tch ca nc to thnh ni trn.( Cc kh o iu kin tiu chun )Bi 6:1) Cho cc PTHH sau PTHH no ng, PTHH no sai? V sao?a) 2 Al +6 HCl2 AlCl3+3H2 ; b)2 Fe +6 HCl2 FeCl3 +3H2c)Cu+2 HCl CuCl2 +H2 ;d) CH4+ 2 O2 SO2 +2 H2O 2) Chn cu pht biu ng v cho v d:a) Oxit axit thng l oxit ca phi kim v tng ng vi mt axit.b) Oxit axit l oxit ca phi kim v tng ng vi mt axit.c) Oxit baz thng l oxit ca kim loi v tng ng vi mt baz.d) Oxit baz l oxit ca kim loi v tng ng vi mt baz.3)Hon thnh cc PTHH sau:a)C4H9OH+O2 CO2 + H2O;b) CnH2n - 2 + ? CO2 + H2Oc)KMnO4+? KCl + MnCl2+Cl2 + H2Od) Al + H2SO4(c, nng) Al2(SO4)3+SO2 +H2OBi 7: Tnh s mol nguyn t v s mol phn t oxi c trong 16,0 g kh sunfuric.Bi 8: t chy hon ton kh A cn dng ht 8,96 dm3kh oxi thu c 4,48 dm3 kh CO2 v 7,2g hi nc.a) A do nhng nguyn t no to nn? Tnhkhi lng A phn ng.b) Bit t khi ca A so vi hiro l 8. Hy xc nh cng thc phn t ca A v gi tn A.Bi 9:Cho lung kh hiro i qua ng thu tinh cha 20 g bt ng(II) oxit 400 0C. Sau phn ng thu c 16,8 g cht rn.a) Nu hin tng phn ng xy ra.b) Tnh hiu sut phn ng.c) Tnh s lt kh hiro tham gia kh ng(II) oxit trn ktc. s 6Cu 1: a)Tnh khi lng ca hn hp kh gm 6,72 lt H2 , 17,92 lt N2 v3,36 lt CO2 b) Tnh s ht vi m ( phn t) c trong hh kh trn , vi N= 6.1023Cu 2: C 5,42 gam mui thu ngn clorua , c chuyn ho thnh Hg vCl bng cch t nng vi cht thch hp thu c 4gam Hg.a)Tnh khi lng clo kt hp vi 4g Hg ?b)C bao nhiu mol nguyn t clo trong khi lng trn ?c)C bao nhiu mol nguyn t Hg trong 4g Hg? Trang 9 B dy hc sinh giid) T cutrli (b)v(c), hy tmcng thc hohccamuithungncloruatrn? Cu 3 : Phng trnh phn ng: K2SO3 + HClKCl+H2O+SO2 Cho 39,5 gK2SO3 vo dung dch c 14,6g HCl .a)Tnh th tch kh sinh ra ktc ?b) Tnh khi lng cht tham gia phn ngcn tha trong dung dch?C th thu nhng kh di y vo bnh : H2,Cl2,NH3,CO2, SO2, CH4 c) Bng cch : t ng bnh : t ngc bnh : Cu 4 : Hon thnh cc phng trnh ho hc sau :Al + Cl2----- AlCl3Na + H2O -----NaOH + H2Fe2O3+ HCl ----- FeCl3+ H2OFeS2+ O2-----Fe2O3+ SO2Cu5: Tnhnng%vnngMcadungdchkhi hotan14,3gamxa.(Na2CO3.10H2O) vo 35,7 g nc . Bit th tch dd bng th tch nc . Cu 6: Cho 2,8g mt hp cht A tc dng vi Ba ri clorua . Tnh khilng Bari sunfatv Natri clo rua to thnh. Bit : -Khi lng Mol ca hp cht A l 142g%Na =32,39%;%S=22,54%;cn li l oxi ( hp cht A )Cu 7: Mt cht lng d bay hi , thnh phn phn t c 23,8% C , 5,9% H, v70,3% Cl , c phn t khi bng 50,5 . Tm cng thc ho hc ca hp cht trn. Cu 8:Trn ln 50g dung dch NaOH 8% vi 450g dung dch NaOH 20% .a)Tnh nng phn trm dung dch sau khi trn ?b)Tnh th tch dung dch sau khi trn , bit khi lng ring dung dchny l 1,1g/ml ? Cu 9:Cho 22g hn hp 2 kim loi Nhm v st tc dng vi dd HCl d .Trong nhm chim 49,1% khi lng hn hp.a)Tnh khi lng a xit HCl cn dng ?b) Tnh th tch Hir sinh ra ?( ktc)c) Cho ton b H2 trn i qua 72g CuO nung nng. Tnh khi lng chtrn sau phn ng ? Cu 10: C nhngcht kh sau: Nit , Cacbon ioxit ( kh Cacbonic),Neon (Ne l kh tr ) , oxi, metan (CH4) Kh no lm cho than hng chy sng ? Vit PTHHa)Kh no lm c nc vi trong? Vit PTHHb)Kh no lm tt ngn nn ang chy ? Gii thch c)Kh no trong cc kh trn l kh chy ? Vit PTHH Cu 11: t chy 1,3g bt nhm trong kh Clo ngi ta thu c 6,675g .hp cht nhm clorua. Gi s cha bit ho tr ca Al v Cl .a)Tm CTHH ca nhm clorua ?b)Tnh khi lng ca kh clo tc dng vi nhm ?Cu 12:S phn ng :NaOH + CO2----------- Na2CO3 +H2Oa)Lp PTHH ca phn ng trn ? Trang 10 B dy hc sinh giib) Nu dng 22g CO2 tc dng vi 1 lng NaOH va, hy tnh khilngNa2CO3 iu ch c ?c)Bng thc nghim ngi ta iu ch c 25g Na2CO3 . Tnh hiu sut ca qu trnh thc nghim? s 71/ Ho tan 50 g tinh th CuSO4.5H2O th nhn c mt dung dch c khi lng ringbng 1,1 g/ml. Hy tnh nng % v nng mol ca dung dch thu c.2/Tnh lng tinh th CuSO4.5H2O cn thit ho tan 400g CuSO42% thu c dd CuSO4 c nng 1M(D= 1,1 g/ml).3/ C 3 dung dch H2SO4 . Dung dch A c nng 14,3M (D= 1,43g/ml). Dung dch B c nng 2,18M (D= 1,09g/ml). Dung dch C c nng 6,1M (D= 1,22g/ml).Trn A v B theo t l mA: mB bng bao nhiu c dung dch C.S 3 : mA: mB = 3:54/ Ho tan m1 g Na vo m2g H2O thu c dung dch Bc t khi d. Khi c phn ng: 2Na+2H2O -> 2NaOH + H2a/ Tnh nng % ca dung dch B theo m.b/ Tnh nng molca dung dch B theo m v d.c/ Cho C% = 16% . Hy tnh t s m1/m2.. Cho CM = 3,5 M. Hy tnh d.5/ Ho tan mt lng mui cacbonatca mt kim loi ho tr II bng axit H2SO4 14,7% . Sau khicht kh khng thot ra na , lc b cht rn khng tanth c dung dch cha 17% mui sunpht tan. Hi kim loi ho tr II l nguyn t no.6/Tnh C% ca 1 dung dch H2SO4nu bit rng khi cho mt lng dung dch ny tc dng vi lng d hn hp Na- Mg th lng H2 thot ra bng 4,5% l-ng dung dch axit dng.7/ Trn 50 ml dung dch Fe2(SO4)3vi 100 ml Ba(OH)2 thu c kt ta Av dung dch B . Lc ly A em nung nhit caon hon tonthu -c0,859 g cht rn. Dung dch Bcho tc dng vi 100 ml H2SO4 0,05M th tch ra 0,466 g kt ta. Tnh nng mol ca dung dch ban u S 7 : Tnh c CM dd Fe2(SO4)3= 0,02M v caBa(OH)2 = 0,05M 8/ C 2 dung dch NaOH (B1; B2)v 1 dung dch H2SO4 (A). Trn B1 viB2theo t l th tch 1: 1 th c dung dch X. Trung ho 1 th tch dung dch X cn mt th tch dung dch A. Trn B1 viB2theo t l th tch 2: 1 th c dung dch Y. Trung ho30ml dung dch Y cn 32,5 ml dung dch A. Tnh t l th tch B1 v B2 phi trn sao cho khi trung ho 70 mldung dch Z to ra cn 67,5 ml dung dch A.9/ Dung dch A l dd H2SO4. Dung dch B l dd NaOH. Trn A v B theo t s VA:VB= 3: 2 th c dd X c cha A d. Trung ho 1 lit dd X cn 40 g dd KOH 28%. Trn A v B theo t s VA:VB= 2:3 th c dd Y c cha B d. Trung ho 1 lit dd Y cn 29,2 g dd HCl 25%. Tnh nng mol ca A v B.Hng dn s 7 Trang 11 B dy hc sinh giiHD 1; Lng CuSO4 = 50/250.160 = 32g -> n= 0,2 mol.Lng dung dch 390+ 50= 440g-> C% = 7,27%.Th tch dung dch = 440/1,1=400ml -> CM = 0,2/0,4 =0,5M HD2: Gi lng tinh th bng a gam th lng CuSO4 = 0,64a.Lng CuSO4 trong dung dch to ra = 400.0,02 + 0,64a = 8+ 0,064a.Lng dung dch to ra = 400+ a.Trong khi nng % ca dung dch 1M ( D= 1,1 g/ml) : = 160.1/10.1,1 = 160/11% . Ta c: 8+ 0,64a/400+ a = 160/1100.Gii PT ta c: a= 101,47g.S 3 : mA: mB = 3:5HD4: a/ 2Na+2H2O -> 2NaOH + H2nNa = m1/23 -> nH2 = m1/46 -> lng DDB = m1+ m2 - m1/23 = 22m1 + 23m2/23 Lng NaOH = 40m1 /23 -> C%= 40. m1.100/22m1 + 23m2b/ Th tch B = 22m1 + 23m2/23d ml -> CM = m1 . d .1000/ 22m1 + 23m2 . c/ Hy t giiHD5: Coi lng dung dch H2SO4 14,7%= 100g th n H2SO4 = 0,15 . Gi KL l R; ta c PT:RCO3 + H2SO4-> RSO4 + CO2 + H2O N =0,150,15 0,150,15Lng RCO3 = (R + 60). 0,15 + 100 (44 . 0,15)= (R + 16) .0,15 +100Ta c: (R+ 96).0,15/(R + 16) .0,15 +100 = 0,17-> R = 24 -> KL l Mg.HD6: Coi lng dung dch axit dng = 100 g th lng H2 thot ra = 4,5 g.2Na+ H2SO4 -> Na2SO4+ H2 Mg+ H2SO4-> MgSO4+ H22Na+ H2O->NaOH + H2Theo PTP lng H2 = lng H ca H2SO4 + 1/2 lng Hca H2O.Do : nu coi lng axit = x g ta c: x/98. 2 + 100 x /18 = 4,5 -> x = 30 S 7 : Tnh c CM dung dch Fe2(SO4)3= 0,02M v caBa(OH)2 = 0,05M HD 8 :t b1 v b2l nng 2 dung dch NaOH v a l nng dung dch H2SO4 - Theo gt: Trn 1 lt B1 + 1 lt B2 to -> 2 lt dd X c cha(b1+ b2) mol NaOH Theo PT:H2SO4+ 2NaOH-> Na2SO4+ 2H2O2 lit dd H2SO4c 2a mol ->4a . Nn ta c:b1+ b2= 4a* Trn 2 lt B1 + 1 lt B2 to -> 3 lt dd Y c cha(2b1+ b2) mol NaOH.Trung ho 3 lt dd Ycn 3,25lit dd H2SO4c 3,25a mol. Nn: ta c: 2b1+ b2 =6,5a ** T * v **ta c h PT: b1+ b2= 4a*

2b1+ b2 =6,5a ** Gii h PT ta c: b1 = 2,5a ; b2 = 1,5 a. Trang 12 B dy hc sinh giiTheo bi ra: trung ho 7l dung dch Z cn 6,75l dung dch A c 6,75a mol H2SO4. Theo PT trn ta c: s mol ca NaOHtrong 7ldung dch Z = 6,75a.2= 13,5a.Gi th tch 2 dd NaOH phi trn l: x,y (lt) ta c: 2,5ax + 1,5ay = 13,5a vx+ y = 7 -> x/y = 3/4HD 9 : t nng mol ca dd A l a , dd B la b. Khi trn 3 l A (c 3a mol) vi 2 lit B (c 2b mol) c 5 lit dd X c d axit. Trung ho 5 lit dd X cn 0,2.5 = 1molKOH -> s mol H2SO4 d: 0,5 mol.PT: H2SO4+ 2KOH-> K2SO4+ 2H2O b 2b S mol H2SO4 d = 3a b = 0,5*Trn 2l dd A (c 2a mol) vi 3 lt ddB(c 3b mol)to 5 l dd Y c KOH d. Trung ho 5 lit Y cn 0,2 .5 = 1 mol HCl PT: H2SO4+ 2KOH-> K2SO4+ 2H2O 2a4aTheo PTP:KOH d = 3b 4a = 1 ** T * v **ta c h PT: 3a b = 0,5*

3b 4a = 1 **Gii h PT ta c: a = 0,5 ; b= 1 s 81. Hy thc hin dy chuyn ho sau:a. FeFe3O4 Fe H2

b. KClO3O2CuO H2ONaOHc. H2OH2FeFeSO4d. S SO2 SO3 H2SO4 ZnSO42. Cho cc nguyn t sau, nhng nguyn t no cng mt chu k:A :1S22S22P63S1 D: 1S22S22P63S23P64S1 B :1S22S22P63S2 E : 1S22S22P63S23P64S2C :1S22S22P63S23P5 F : 1S22S22P63S23P63. t chy hon ton 2,3 gam mt hp cht A bng kh oxi , sau P thu c 2,24 lit CO2 ( ktc) v 2,7 gam H2O. Hy xc nh cng thc hp cht A (Bit t khi hi ca kh A so vi kh hidro l 23).4. iu ch H2 ngi ta dng hn hp Al v Zn c s mol bng nhau tc dng va dd HCl thu c 13,44 lt H2 ( ktc).a. Tnh khi lng hn hp Al v Zn?b. Tnh khi lng HCl trong dung dch?5. kh hon ton a gam mt oxit kim loi AxOy phi cn 6,72 lt CO (ktc), sau P thu c 11,2 gam kim loi A. Hy lp PTHH dng tng qut v tm gi tr a ca oxit kim loi trn? s 91. Hy thc hin dy chuyn ho sau:a. H2H2O H2SO4H2 Trang 13 B dy hc sinh giib. CuCuO CuSO4 Cu(OH)2c.FeFe3O4FeH2FeCl3Fe(OH)32. Cho cc nguyn t:A : 8p, 8n ;B: 8p,9n;C: 8e, 10n ; D: 7e,8n. Nhng nguyn t no cng mt nguyn t ho hc? V sao?3. Hy tnh khi lng bng gam ca nguyn t oxi, st, Natri.4. Khi nung vi cha 90% khi lng canxicacbonat thu c 11,2 tn canxi oxit v 8,8 tn kh cacbonic. Hy tnh khi lng vi em phn ng?5. Cho dX/Y = 2,125 v dY/O2= 0,5.Kh X v Y c thnh phn cc nguyn t nh sau:Kh X: 94,12% S; %,885H. Kh Y: 75% C, 25% H.Tm CTHH ca X , Y.6. t chy hon ton 1 Kg thancha 90% C v 10% tp cht khng chy. Tnh khi lng khng kh cn dngvi khi lng CO2 sinh ra trong phn ng chy ny. Bit rng VKK = 5VO27. t chy mt hn hp Fe v Mg trong Mg c khi lng 0,84 gam cn dng ht 672ml O2 ( ktc).a. Tnh khi lng hn hp ban u?b. Tnh thnh phn phn trm v khi lng ca mi kim loi?8. Cho 7,8 gam Zn vo dung dch axit sunfuric long cha 19,6 gam H2SO4.a. Tnh VH2 thu c ( ktc). Bit th tch V H2 b hao ht l 5%.b. Cn d bao nhiu cht no sau phn ng?9. a. Cho mt hp cht oxit c thnh phn phn trm v khi lng: %O l 7,17%. Tm cng thc oxit bit kim c ho tr II.b. Dng CO hoc H2 kh oxit kim loi thnh kim loi. Hi mun iu ch 41,4 gam kim loi cn bao nhiu lit H2 (ktc) hoc bao nhiu lit kh CO? s 101.a. Trong mui ngm nc CuSO4.nH2O khi lng Cu chim 25,6 %. Tm cng thc ca mui ?.b. Ha tan hon ton 3,9 gam kim loi X bng dung dch HCl thu c 1,344 lit kh H2 (ktc). Tm kim loi X ?.2. Cho mt lung H2d i qua 12 gam CuO nung nng. Cht rn sau phn ng em ha tan bng dung dch HCl d thy cn li 6,6 gam mt cht rn khng tan. Tnh hiu sut phn ng kh CuO thnh Cu kim loi ?.3. t chy hon ton 2,3 gam mt hp cht bng kh oxi, sau phn ng thu c 2,24 lit CO2 (ktc) v 2,7 gam nc. Tnh khi lng tng nguyn t c trong hp cht trn?.4. vi c phn hy theo PTHH: CaCO3 CaO+ CO2Sau mt thi gian nung thy lng cht rn ban u gim 22%, bit khi lng vi ban u l 50 gam, tnh khi lng vi b phn hy?.5. Cho 4,64 gam hn hp 3 kim loi Cu, Mg, Fe tc dng vi dung dch HCl d thu c 0,2 gam kh H2 v 0,64 gam cht rn khng tan.a. Tnh t l phn trm v khi lngca 3 kim loi trong hn hp trn?b. Tnh khi lng mi mui c trong dung dch?6. Mt loi vi cha 85% CaCO3 v 15% tp cht khng b phn hy nhit cao. Khi nung mt lng vi thu c mt cht rn c khi lng bng 70% khi lng trc khi nung. Trang 14 B dy hc sinh giia. Tnh hiu sut phn hy CaCO3?b. Tnh thnh phn % khi lng CaO trong cht rn sau khi nung? P N s10 1.aTa c 4 2.uSO C nH OM = 64 100%25025, 6% Ta c 64 32 (16.4) .18 250 5 n n + + + Vy CTHH l CuSO4.5H2O (1 )1.b21, 344: 22, 4 0.06( ) molHm Gi n l ha tr ca kim loi X 2 X+ 2n HCl 2 XCln + n H2S mol 0, 06 2 0,12( ) X moln n Ta c: 0,12. 3, 9 32, 5. X X nn V kim loi thng c ha trn = 1, 2 hoc 3n = 1 X= 32,5 (loi)n = 2 X= 65(Zn)n = 3 X= 97,5 (loi)Vy kim loi X l Zn(1 )2. Ta c PTHH: CuO+H2

0tCu+H2O 80 g 64 g 12 g x g?Lng Cu thu c trn l thuyt: 12 649, 6( )80x g Theo bi, cht rn sau phn ng ha tan bng HCl d thy cn 6,6 gam cht rn khng tan, chng t lng Cu to ra phn ng trn l 6,6 gam. 6, 6100% 68, 75%9, 6H (1,5)3. Khi lng nguyn t C trong hp cht: 2, 24 121, 2( )22, 4Cgm Khi lng nguyn t H trong hp cht: 2, 7 20, 3( )18Hgm Khi lng nguyn t O trong hp cht: 2, 3 (1, 2 0, 3) 0,8( )Ogm + 1,5)4. Lng cht rn ban u gim 22% chnh l khi lng CO2 thot ra.Khi lng CO2 thot ra:222 5011( )100gCOm PTHH:CaCO3

0t CaO+ CO2100g 44g xg? 11g Khi lng vi b phn hy:11 10025( )44x g (1,5)5. V Cu khng tham gia phn ng vi HCl nn 0,64 gam cht rn khng tan chnh l khi lng ca Cu. Khi lng hn hp Fe v Mg l:4,64 0,64 = 4 (g)Gi x l s gam Fe (4 x) l s gam MgPTHH: Fe+2 HCl FeCl2+ H2

Trang 15 B dy hc sinh gii56 g 2 gx g2.56xg Mg+2 HCl MgCl2+ H2

24 g2 g(4-x) g2(4 )24xgT 2 PTHH trn ta c: 2.56x + 2(4 )24x = 0,2 Gii PT ta c x = 2,8 = mFeT l % v khi lngca Fe trong hn hp: %Fe = 2, 8100% 60, 34%4, 64 T l % v khi lngca Cu trong hn hp: %Cu = 0, 64100% 13, 79%4, 64 T l % v khi lngca Mg trong hn hp: %Mg = 100% - (60,34%+13,79%) = 25,87% (2)6.a PTHH:CaCO3

0tCaO+CO2(1)100 g56 g 44 g Gi s lng vi em nung l 100g, trong cha 85% CaCO3 th lng cht rn sau khi nung l 70g.Khi lng gim i chnh l khi lng CO2 v bng: 100 70 = 30 (g)Theo (1): Khi 44g CO2 thot ra l c 100g CaCO3 b phn hy. 30g CO2 thot ra l cx g CaCO3 b phn hyb. Khi lng CaO to thnh l: 56 3038, 2( )44g Trong 70 g cht rn sau khi nung cha 38,2g CaOVy % CaO l: 38, 2100% 54, 6%70 (1,5) s 11Bi 1: Ngi ta dn qua 1 bnh cha 2 lit dung dch Ca(OH)2 0,075M tt c l-ng kh cacbonic iu ch c bng cch cho axit clohidric (d) tc dng vi 25,2 gam hn hp Canxi cacbonat v Magie cacbonat. Sau p c mui no -c to thnh v khi lng l bao nhiu?Bi 2: Khi cho t t lung kh CO2vo dung dch Ca(OH)2, ngi ta nhn thy ban du dung dch tr nn c, sau trong dn v cui cng trong sut. Hy gii thch hin tng trn v vit ptp minh ho.Bi 3: C dung dch NaOH, kh CO2, ng ong chia v cc cc thu tinh cc loi. Hy trnh by phng php iu ch dung dch Na2CO3tinh khit.Bi 4: Thmt t dung dch HCl vo 10 gam mui cacbonat kim loi ho tr II, sau 1 thi gian thy lng kh thot ra vut qu 8,585 gam. Hi l mui kim loi g trong s cc kim loi cho di y? Mg; Ca; Cu; Ba Trang 16 B dy hc sinh giiBi 5: Mt loi cha MgCO3, CaCO3, Al2O3 . Lng Al2O3 bng 1/8 tng khi lng 2 mui cacbonat. Nung nhit cao ti phn hu hon ton thu c cht rn A c khi lng bng 60% khi lng trc khi nung.1. Tnh % khi lng mi cht trong trc khi nung.2. Mun ho tan hon ton 2g cht rn A cn tithiu bao nhiu ml dung dch HCl 0,5M? s 12 Trang 17 B dy hc sinh gii Trang 18 B dy hc sinh giip n s 12Cu 1:(1,00) Tnh 2 4dd1, 6 400 640( )H SOm g , 2 415 64096( )100H SOm g ,2 4960, 98( )98H SOn g ;(0,5)Gi x l s lt nc thm vo dung dch dd mi: x + 0,4 (400ml = 0,4l)Ta c0, 981, 5 1, 5 0, 38 0, 253( )0, 4 +MnC x x lV x

Vy s lt nc cn thm vo l 0,253 lt(0,5)Cu 2:(3,00)23, 384 12% 100% 92, 29%44 1COm C ; (0,25) , 20, 694 1% 2 100% 7, 71%18 1H Om H ;(0,25)%O = 100% (92,29% + 7,71%) = 0 % Khng c oxi (0,5) A ch c C v H CTHH dng CxHy(0,25) 92, 29 7, 71: : 1:112 1x y (0,25) Cng thc n gin (CH)n(0,25 Ta c MA= 29 2,69 ;78 (0,25) (CH)n =78 13n = 78 n = 6(0,5)Vy CTPT ca A l C6H6 (0,5)Cu 3:(2,00)a. Bn knh nguyn t H ln hn bn knh ca ht nhn:941330 106.10 600005 10 ln (0,5)Bn knh ca ht nhn phng i l 63( )2cm Bn knh ca nguyn t tng ng l:3 60000 = 180000 (cm) (0,5)b. Th tch ca nguyn t H: 3 9 34 43,14 (5, 3.10 )3 3V r (0,5)Khilngca nguyntHcoi nhbngkhi lngproton, nnkhi lngringc 2739 31, 6726.102, 68( / )43,14 (5, 3.10 )3m KgD g cmV (0,5)Cu 4:(1,00)Dng qu tm: NaOHH2SO4, HCl NaCl, BaCl2 xanh khng i mu qu( 0,25)(I)(II)Ly 1 mu (I) ln lt + 1 mu (II) sinh ra kt ta trng th l H2SO4 v BaCl2PTHH: H2SO4+BaCl2 BaSO4+ 2 HCl (0,5)(trng)Mu axit cn li l HCl v mu mui cn li l BaCl2(0,25)Cu 5:(3,00)Gi x, y ln lt l s mol ca Zn v AlZn +2 HCl ZnCl2+ H2 x x 2Al+6HCl 2AlCl3+3H2 (0,5) y 1,5y Trang 19 B dy hc sinh giiTa c h: 65x+27y= 17,3(1) x + 1,5y = 15, 6822, 4 (2) (0,5)Gii h ta c:x = 0,1 , y = 0,4 (0,25)mZn=6,5 6, 5% 100% 37, 57%17, 3Zn (0,25) mAl=10,8 10, 8% 100% 62, 43%17, 3Al (0,25)

2136 0,1 13, 6( )ZnClm g (0,25)3133, 5 0, 4 53, 4( )AlClm g (0,25)

2(0,1 0, 6) 2 1, 4( )Hm g + mddsp = (17,3 + 400) 1,4 = 415,9(g) (0,25)213, 6% 100% 3, 27%415, 9ZnCl (0,25) 353, 4% 100% 12,84%415, 9AlCl (0,25)s 13Cu 1: (2 im) Cn bng cc phn ng ho hc sauFe2(SO4)3+NaOH Fe(OH)3+Na2SO4 Fe2O3+COFe+ CO2 FexOy+COFe+ CO2 P2O5 +H2O H3PO4 Cu 2: (2 im)Nung 15 kg vi thnh phn chnh l CaCO3thu c 7,28 kg Canxioxit(CaO) v 5,72kg CO2. Hy xc nh t l phn trm v khi lng ca CaCO3 trong vi.Cu 3: (4 im)Vit cng thc ho hc v xc nh phn t khi ca cc hp cht sau: Ca(II) v O; N(III) v H; Fe(II) v gc SO4(II); Fe(III) v gc SO4(II).Cu 4: (2 im ) Bt nhm chy theo phn ng:Nhm + kh oxiNhm xit(Al2O3)a, Lp phng trnh ho hc.b, Cho bit khi lng nhm phn ng l 54 gam; v khi lng nhm oxit sinh ra l 102 gam. Tnh khi lng kh oxi dng.(Bit: Ca=40; N=14;H=1;S=32;O=16;Fe=56) s 14 Trang 20 B dy hc sinh giiBi 1: a) Khi cho hn hp Al v Fe dng bt tc dng vi dung dch CuSO4, khuy k phn ng xy ra hon ton, thu c dung dch ca 3 mui tan v cht kt ta. Vit cc phng trnh phn ng, cho bit thnh phn dung dch v kt ta gm nhng cht no?b) Khi cho mt kim loi vo dung dch mui c th xy ra nhng phn ng ho hc g ? Gii thch ?Bi 2: C th chn nhng cht no khi cho tc dng vi 1 mol H2SO4 th c:a) 5,6 lt SO2 b) 11,2 lt SO2c) 22,4 lt SO2d) 33,6 lt SO2Cc kh o ktc. Vit cc phng trnh phn ngBi 3: t chy mt t bt ng trong khng kh mt thi gian ngn. Sau khi kt thc phn ng thy khi lng cht rn thu c tng ln 16 khi lng ca bt ng ban u. Hy xc nh thnh phn % theo khi lng ca cht rn thu c sau khi un nngBi 4: a) Cho oxit kim loi M cha 65,22% kim loi v khi lng. Khng cn bit l kim loi no, hy tnh khi lng dung dch H2SO4 19,6% ti thiu cn dng ho tan va ht 15 g oxit b) Cho 2,016g kim loi M c ho tr khng i tc dng ht vi oxi, thu c 2,784g cht rn. hy xc nh kim loi Bi 5: Cho 10,52 g hn hp 3 kim loi dng bt Mg, Al, Cu tc dng hon ton vi oxi, thu c 17,4 g hn hp oxit. Hi ho tan va ht lng hn hp oxit cn dng t nht bao nhiu ml dung dch HCl 1,25MBi 6: C 2 chic cc trong mi chic cc c 50g dung dch mui nitrat ca mt kim loi cha bit. Thm vo cc th nht a (g) bt Zn, thm vo cc th hai cng a (g) bt Mg, khuy k cc hn hp phn ng xy ra hon ton. Sau khi kt thc cc phn ng em lc tch cc kt ta t mi cc, cn khi lng cc kt ta , thy chng khc nhau 0,164 g. em un nng cc kt ta vi lng d HCl, thy trong c 2 trng hp u c gii phng H2 v cui cng cn li 0,864 g kim loi khng tan trong HCl dHy xc nh mui nitrat kim loi v tnh nng % ca dung dch mui ny( Cho: H = 1, C = 12, O = 16, Mg = 24, Zn = 65, Fe = 56, Al = 27, S = 32, Cu = 64) P N s 14 Bi 1: a) Th t hot ng ca cc kim loi Al > Fe > CuBa mui tan l Al2(SO4)3, FeSO4 v CuSO4 cn li2Al+3CuSO4Al2(SO4)3+3CuFe+CuSO4FeSO4+CuDung dch gm: Al2(SO4)3, FeSO4, CuSO4cn d. Kt ta ch l Cu vi s mol bng s mol CuSO4 ban ub) Xt 3 trng hp c th xy ra:- Nu l kim loi kim, Ca, Ba:Trc ht cc kim loi ny tc dng vi nc cadung dch cho baz kim, sau baz kim tc dng vi mui to thnh hiroxit kt taV d: Na+dd CuSO4:Na+H2O NaOH+12H22NaOH+CuSO4Cu(OH)2+Na2SO4 Trang 21 B dy hc sinh gii- Nu l kim loi hot ng hn kim loi trong mui th s y kim loi ca mui ra khi dung dchV d:Zn+FeSO4ZnSO4+Fe- Nu kim loi yu hn kim loi ca mui: phn ng khng xy ra V d Cu+FeSO4

khng phn ngGii thch: Do kim loi mnh d nhng in t hn kim loi yu, cn ion ca kim loi yu li d thu in t hnBi 2: a) nSO2 = 5, 622, 4= 0,25 molnH2SO4 : nSO2 = 1 : 0,25 = 4 : 12FeO+4H2SO4

Fe2(SO4)3+SO2+4H2Ob) nH2SO4 : nSO2 = 2 : 1Cu+2H2SO4 CuSO4+SO2+2H2Oc) nH2SO4 : nSO2 = 1 : 1C+ 2H2SO4 CO2+2SO2+2H2Od) nH2SO4 : nSO2 = 2 : 3S+ 2H2SO4 3SO2+2H2OBi 3:2Cu+O2 2CuO 128g32g160gNh vy khi phn ng oxi ho Cu xy ra hon ton th khi lng cht rn thu c tng ln: 32128=14. Theo u bi, sau phn ng khi lng cht rn thu c tng ln 1/6 khi lng Cu ban u, tc l Cu cha b oxi ho ht, thu c hn hp gm CuO v Cu cn dGi s lm th nghim vi 128g Cu. Theo bi s g oxi phn ng l: 1286= 21,333gTheo PTHH ca phn ng s g Cu phn ng vi oxi v s g CuO c to thnh l:mCu = 128.3221,333 = 85,332g; mCuO = 16032. 21,333 = 106,665gS g Cu cn li l: 128 85,332 = 42,668g%Cu = 42, 668149, 333. 100 = 28,57% ; %CuO = 71,43%Bi 4: a) t kim loi v khi lng mol nguyn t ca n l M, ho tr n. Theo bi ta c: 22 16MM n += 0,6522M = 15n M2On = 2M = 16n = 46n (g)M2On+nH2SO4M2(SO4)n+nH2OTheo phn ng ho tan 1 mol oxit (tc 46n)g cn n mol H2SO4. ho tan 15g oxit cn46nn.15 = 0,3261 mol H2SO4mdd = 10019, 6.0,3261 . 98 = 163,05gb) t k hiu kim loi v khi lng mol nguyn t ca n l M, ho tr n ta c: 4M+nO22M2On4 4 322, 016 2, 784M M n + M = 21n . Xt bng: vi n = 1, 2, 3 Trang 22 B dy hc sinh giin 1 2 3M 21 42 63Vi s liu bi cho khng c kim loi no to nn oxit c ho tr t 1 n 3 tho mn c. Vy M phn ng vi oxit theo 2 ho tr, th d: theo ho tr 2 v 3 (ho tr 8/3). Nh bit: Fe to Fe3O4, Mn to Mn3O4, Pb to Pb3O4. V vy khi n = 8/3 M = 56Kim loi chnh l Fe v oxit l Fe3O4Bi 5: t x, y, z l s mol ca Mg, Al, Cu trong 10,52g hn hp2Mg+O2

2MgO x0,5x x4Al+ 3O2

2Al2O3 y 0,75y 0,5y2Cu+O2

2CuO z 0,5zzMgO+2HClMgCl2+H2Ox 2xAl2O3+ 6HCl2AlCl3+3H2O0,5y3yCuO+2HCl CuCl2+H2Oz2zT cc PTP trn ta thy s mol kh oxi tc dng vi kim loi lun bng s mol axit dng ho tan va ht lng oxit kim loi c to thnh. Theo u bi s mol oxi tc dng vi cc kim loi to thnh hn hp oxit l: 17, 4 10, 5232= 0,125molS mol HCl cn dng ho tan va ht lng hn hp oxit : 0,125 . 4 = 0,86 molTh tch dung dch HCl 1,25M cn dng: 0,861, 25= 0,688 ltBi 6: t kim loi to mui nitrat l M, ho tr n. Cc PTP xy ra trong 2 cc l:nZn+2M(NO3)nnZn(NO3)n+2M (1)nMg+ 2M(NO3)nnMg(NO3)n+2M (2)t s mol mui M(NO3)n trong mi cc l xS mol Zn v Mg: nZn = 65a ; nMg =24anMg > nZnKhi lng kt ta cc nhng thanh Zn l: xM + a - .652nx Khi lng kt ta cc nhng thanh Mg l: xM + a - .242nx(xM + a - .242nx) (xM + a - .652nx) = 32,5nx 12nx = 0,16420,5nx = 0,164 nx = 0,008Khi cho kt ta tc dng ln lt vi dung dch HCl d, thy gii phng hir chng t Mg, Zn d, cui cng cn li 0,864g kim loi khng tan l M vi s mol l xMx = 0,864 ; nx = 0,008 M = 108n. Xt bng:n 1 2 3 Trang 23 B dy hc sinh giiM 108 216 324Ag loi loiVy kim loi M l: Ag ; nAg = 0,008C% = 0, 008.17050. 100 = 2,72% s 15Cu 1: (2 im): Chn p n ng.1. 0,5 mol phn t ca hp cht A c cha: 1 mol nguyn t H ; 0,5 mol nguyn t S v 2 mol nguyn t O. Cng thc ha hc no sau y l ca hp cht A?A. HSO2B. H2SO3C. H2SO4D. H2S3O42. Mt kim loi R to mui Nitrat R(NO3)3. muisunfat ca kim loi R no sau y c vit ng?A. R(SO4)3B. R2(SO4)3C. R(SO4)2D. R3(SO4)2Cu 2( 1, 5 im).Hy ghp cc s 1, 2, 3, 4 ch th nghim v cc ch A, B, C, D, E ch hin tng d on xy ra thnh tng cp cho ph hp.Th nghim Hin tng xy ra trong v sau phn ng.1 Hidro kh ng (II) oxit B. Ngn la mu xanh nht, c git nc nh bm thnh bnh2 Canxi oxit phn ng vi n-c. Sau phn ng cho giyqutmvodung dch thu c.C Cht rn mu to thnh.Thnh ng nghim b m i.3 Natri phnngvi ncc thm vi git phenolphtalein.D Phnngmnhlit. Dungdchto thnh lm giy qu tm ho xanhE Git trnchytrnmt nc, dung dch c mu hng.Cu 3: (2,5 im):Chn cht thch hp han thnh phng trnh phn ng:1. H2O +-------> H2SO42. H2O + ..------> Ca(OH)23. Na +.. -------> Na(OH)2 + H24. CaO + H3PO4 -----> ? + ? Trang 24 B dy hc sinh gii5. ?---------> ? + MnO2 + O2 Cu 4 (6 im)1. Cho cc cht: KMnO4, CO2,CuO, NaNO3, KClO3, FeS, P2O5, CaO. Hi trong s cc cht trn, c nhng cht no:a) Nhit phn thu c O2 ? b) Tc dng c vi H2O, vi dung dch H2SO4 long ,vi dung dch NaOH, lm c nc vi, vi H2 khi nung nng to thnh cht c mu ?Vit cc phng trnh phn ng xy ra.2.Vit mt phng trnh phn ng m trong c mt 4 loi cht v c c bn.Cu 5(8 im)1. Ch t 1,225 gam KClO3 v 3,16 gam KMnO4, hy nu cch tin hnh c th iu ch c nhiu O2 nht. Tnh th tch kh O2 ktc. (Khng c dng thm cc ha cht khc) 2. Ha tan hon ton 11,2 gam CaO vo H2O ta c dung dch A. Cho kh CO2 sc qua dung dch A, sau th nghim thy c 2,5 gam kt ta.Tnh th tch CO2 phn ng ktcp n s 15Cu p n imCu 11.c; 2B 2 imCu 21.c;2d; 3.e 1,5 imCu 3H2O + SO3 H2SO4H2O + CaO Ca(OH)22Na + 2H2O 2NaOH + H23CaO + 2H3PO4 Ca3(PO4)2 + 3H2O2KMnO4 0 t K2MnO4 + MnO2 + O2O,5 O,5O,5O,5O,5Cu 41.a) Nhng cht nhit phn rakh O2 l : KMnO4, NaNO3, KClO3 2KMnO4 otK2MnO4 + MnO2 + O2NaNO3 otNaNO2 + O2KClO3 ot KCl +3/2O2 ( xc tc MnO2)b) Nhng cht tc dng c vi H2O l: P2O5, CaOP2O5 +3 H2O 2H3PO4CaO + H2O Ca(OH)2c)Nhngchttcdngc vidungdch H2SO4longl:CuO,FeS, P2O5, CaOCuO + H2SO4 CuSO4 + H2OFeS + H2SO4 FeSO4 + H2SP2O5 +3 H2O 2H3PO4CaO + H2O Ca(OH)22.HCl + NaOH NaCl + H2O axit baz mui oxit222 Trang 25in phnA xit sunfuaric B dy hc sinh giiCu 5Trn ln KClO3 vi KMnO4 ri em nhit phn, MnO2 c to thnh do KMnO4 nhit phn s lm xc tc cho phn ng nhit phn KClO3112 KMnO4 0t K2MnO4 + MnO2 + O2 316 g22,4 l 3,16 gV1 l V1 = 0,224 (lt)1 KClO3 02,t MnO KCl + 3/2 O2 122,5 g 33,6 l1,225 g V2 l

V2 = 0,336 (lit)1Tng th tch kh O2 l : V = V1 + V2 = 0,224 + 0,336 = 0,56 (lt) Ch : Nu th sinh tnh ng p s nhng khng trn ln 2 cht vinhau th khng cho im, v bi ny khng cho xc tc MnO2. Mt khc, bi yu cu tnh lng O2 ln nht ch khng phi tnh lng O2 do tng cht to ra.12Phng trnh phn ng: CaO + H2O Ca(OH)2 (1)DungdchAldungdchCa(OH)2, smolCa(OH)2=smolCaO= 11,2/56 = 0,2 (mol)Khi cho kh CO2 vo A, c th xy ra cc phn ng sau:Ca(OH)2 + CO2 CaCO3(2)Ca(OH)2 + 2CO2 Ca(HCO3)2(3)1S mol CaCO3 = 2,5/100 = 0,025 (mol) S mol Ca(OH)2 = 0,2 (mol)V s mol CaCO3< s mol Ca(OH)2 nn c th c 2 trng hp1Trng hp 1: Ca(OH)2 d, ch xy ra (2), s mol CO2 tnh theo s mol CaCO3 = 0,025 molTh tch CO2 = 0,025 .22,4 = 0,56 (lt)1Trng hp 2: To c 2 mui CaCO3 v Ca(HCO3)2t x, y ln lt l s mol CO2 tham gia (1) v (2). - S mol CaCO3 l 0,025. Ta c: x = 0,025 (*)- S mol Ca(OH)2 l 0,2. Ta c: x + 0,5y = 0,2 (**)T (*) v (**) y = 0,35Tng s mol CO2= x + y = 0,025 + 0,35 = 0,375Th tch CO2 = 0,375 . 22,4 = 8,4 (lt)1 s 16Cu 1 : (1) Cc dy cht sau, dy no ton l o xt ?a, H2O , CaO , Na2O , SiO2, P2O5, NOb, CaCO3, CO2, SO2, MgO, HClO, NaOHc, SO3, H2SO4, NO2, Al2O3, PbO, Ag2Od, Tt c u sai. Trang 26in phnA xit sunfuaric B dy hc sinh giiCu 2 : (3) Lp phng trnh ho hc cc phn ng sau v m ngoc ghi loi phn ng hc bn cnh phng trnh :a, Km + a xt clohiric km clorua + hiro b, Nhm + oxinhm xit c, Kali CloratKa li Clorua + Oxid, St + ng Sun fat StSun fat+ ng e, Cac bon + nc Cacbon Oxit + hi rog, Kali pemanganat Kali manganat + mangan iox h, Nc hiro +OxiCu 3: C 4 bnh ng ring bit cc cht kh :Khng kh, O2, H2, CO2. Bng th nghim no c th bit c cht kh mi bnh?Cu 4: Cho bit kim loi Na, Mg, A1 ln lt tc dng vi dung dch Hcla, Nu cng mt lng (s mol) kim loi trn tc dng vi a xit Hcl, kim loi no cho nhiu kh H2hn?b, Nu thu c cng lng kh H2 th khi lng kim loi no t hn?Cu 5: Ho tan 10,2(g) hn hp Al v Mg vo dung dch H2SO4 long, ....thu c11,2 LH2 (ktc) .Tnhkhi lngmi kimloi tronghnhpbanuv%khi lngca chng ?Cu 6: Cho 5,4 g kim loi(M) ho tr III tc dng va vi 395,2 g dung dch H2SO4 long. Dung dch mui sau phn ng c nng 8,55% v thu c 0,6(g) H2p n s 16Cu 1: aCu 2: a, Zn + 2Hcl - Zucl2 +H2 (Phn ng th)b, 4AL + 302 2AL2O3 (Phn ng ho hp, phn ng Oxi ho kh), 2Kclo3 2Kcl +302(Phn ng phn hu)d,Fe + CuSO4FeSO4 +Cu (Phn ng th)e, C+H2OCo2 +H2 (Phn ng th, phn ng oxi ho kh)g, 2KMu04K2MnO4+MuO2+O2(Phnngphnhu) h, H2O2H2 +O2 (Phn ng phn hu) Trang 270, xtcao in phnA xit sunfuaric B dy hc sinh giiCu3: -Dnmi khlngbnhra, quemchycntn ming ng dn kh thy :+ Kh no lm tn m bng chy l oxiPhng trnh C+O2 - Co2- Ba kh cn li em t, kh no chy trong khng kh c ngn la xanh nht l H2Phng trnh : 2H2 +O2 . 2H2O- - Hai kh cn li dn vo nc vi trong khi no lm nc vi trong vn c nhanh l Co2 , cn li l khng kh .Cu 4: a, Na, Mg, Al u cng c mt lng tc l cng c s mol bng nhau l a(mol) 2Na+ 2HCl - 2 NaCl +H2 amol...........Mg + 2HCl - MgCl + I+2 amol amlo2Al + 6HCl - 2AlCl3 + 3H2amol amol T (1) nH2 = 2a(mol) ,T (2) NH2 = a (mol), T (3) NH2 = 23a(mol)- So snh ta thy : Cng lng kim loi th Al Sinl ra H2 nhiu nht b, Nu thu c cng lng H2 l b (mol)2Na + 2Hcl - 2Nacl + H2 2b molbmol - nNa = 2b(mol),mNa = 2bx23 = 46b (g)Mg + 2Hcl - Mg Cl2 +H2 b molb mol- nMg = b mol ,mMg = 24 b(g)2Al + 6Hcl - 2AlCl3 + 3H2 32b mol- nAl = 32b mol,mAl = 32b molx 27 = 18 b (g)So snh ta c : 18b ? + Al(OH)33/ FeO + H2---->Fe + ?4/ FexOy + CO---->FeO + ? Cu 2 (4 im): Dn t t 8,96 lt H2 (ktc) qua m gam oxit st FexOy nung nng. Sau phnng c 7,2 gam nc v hn hp A gm 2 cht rn nng 28,4 gam (phn ng xy ra hon ton).1/ Tm gi tr m?2/ Lp cng thc phn t ca oxit st, bit A c cha 59,155% khi lng st n cht.Cu 3(4 im) t chy 16 gam cht X cn dng 44,8 lt xi( ktc) Thu c kh CO2 v hI nc theo t l s mol 1: 2.Tnh khi lng kh CO2 v hi nc to thnh?Cu 4(6 im)Hn hp gm Cu-Mg-Al c khi lng bng 10 g a, Cho hn hp ny tc dng vi dd HCl d , lc phn kt ta ra sch em nung trong khng kh n khi phn ng hon ton thu c sn phm c khi lng 8g. Trang 30 B dy hc sinh giib, Cho thm dd NaOH vo phn nc lc n d . Lc kt ta ra sch nung nhit cao thu c sn phm c khi lng 4g .Tnh thnh phn phn trm v khi lng mi kim loi trong hn hp?p n s 17I/ phn trc nghim: (3 im) (Chn ng mi p n cho 0,5 im)Cu 1 Cu 2 Cu 3 Cu 4 Cu 5 Cu 6C A B B B Dii- phn t lun(17 im)Cu 1(3im)4FeS2 + 11O2

ot2Fe2O3 + 8 SO2 (0,5 )6KOH + Al2(SO4)33K2SO4 + 2Al(OH)3(0,5)FeO + H2

otFe+ H2O(0,5)FexOy + (y-x) CO otxFeO + (y-x)CO2 (0,5)Cc phn ng (1) (3)(4) l phn ng oxi hoa kh(0,5) Cht kh l FeS2, H2, CO, Al v chng l cht chim oxica cht khc. (0,5)Cu 2 (4 im):a/ S mol H2 = 0,4 mol ( 0,25) Smol nc 0,4 mol ( 0,25)=> s mol oxi nguyn t l 0,4 mol( 0,25) => mO = 0,4 x16 = 6,4 gam( 0,25)Vy m = 28,4 + 6,4 = 34,8 gam(0,5) FexOy +y H2

ot xFe+y H2O(0,5)0,4mol 0,4molb/ mFe = 59,155 x 28,4= 16,8 gam(0,5)=>Khi lng oxi l mO= 34,8 16,8 = 18 gam (0,5)Gi cng thc oxit st l FexOy tac x:y =mFe/56 : mO /16 (0,5)=> x= 3, y= 4 tng ng cng thc Fe3O4 (0,5)Cu 3 (4 im)Phngtrnhphnng: X+O2CO2+H2O ( 0,5)Ta c m X +2Om= 2 2CO H Om m += 44,816 .32 8022, 4g + (0,5)V 2212OCOHnn Tc t l khi lng 221.44 112.18 9COH Omm (1)Vy khi lng CO2 = 80.114411 9g +;(1)Khi lng H2O = 80.93611 9g + (1)Cu 4(6 im) Trang 31 B dy hc sinh giiCc phng trnh phn ng:( Vit ng mi phng trnh cho 0,1 im) a,Mg +2HClMgCl2+H2 (1) 2 Al + 6HCl 2AlCl3+H2(2) 2Cu +O2 2 CuO (3) b, MgCl2+2NaOHMg(OH)2 + 2NaCl (4)AlCl3+3NaOHAl(OH)3+ 3NaCl (5)Al(OH)3 + NaOH NaAlO2+2H2O(6) t0Mg(OH)2 MgO+H2O (7)Theo phn ng (3) c nCu = nCuO =80,1( )80mol Do khi lng ca ng l: 0,1 . 64= 6,4( g) Suy ra %Cu = 6, 4.100% 64%10(1)Theo cc phn ng (1), (4),(7) ta c nMg= nMgO = 40,1( )40mol Khilng Mg l : 0,1 .24 = 2,4 (g) Nn %Mg = 2, 4.100% 24%10(1)%Al = 100% - ( 64%+ 24%) = 12% (1) s 181) Hon thnh cc phng trnh phn ng sau ?Cho bit miphn ng thuc loi no ? V sao ?a) KMnO4 to? + ? + ?b) Fe + H3PO4? + ?c) S + O2

to?d) Fe2O3 + CO t0Fe3O4 + ?2) Mt oxit kim loi c thnh phn % khi lng ca oxi l 30%. Tm cng thc oxit bit kim loi c ho tr III ?3) Trong phng th nghim ngi ta iu ch oxi bng cch nhit phn KMnO4hoc KClO3. Hi khi s dng khi lng KMnO4v KClO3bng nhau th trng hp no thu c th tch kh oxi nhiu hn ? V sao ?4) t12,4(g) phtphotrongkhoxi. Sauphnngthuc21,3(g) iphtphopentaoxit. Tnh.a) Th tch kh O2 (ktc) tham gia phn ng) ?b) Khi lng cht rn thu c sau phn ng ? Trang 32 B dy hc sinh gii5) nhit 1000C tan ca NaNO3 l 180g, 200C l 88g. Hi c bao nhiu gam NaNO3 kt tinh li khi lm ngui 560g dung dch NaNO3 bo ho t 1000C xung 200C ?6) Cho X l hn hp gm Na v Ca. m1(g) X tc dng va vi V (l) dung dch HCl 0,5M thu c 3,36 (lt) H2(ktc). m2(g) X tc dng va vi 10,8 (g) nc. Tnh:a) T l khi lng m1/ m2 ?b) Nu cho m2 (g) X tc dng va vi V dung dch HCl th nng mol/ l ca dung dch HCl dng l bao nhiu ? Cho bitH = 1;N = 14; O = 16;Na = 23;Cl = 35,5; Ca = 40;Mn = 55;Fe = 56;Ba = 107 s 19Cu 1(1,5 im): Lp phng trnh ho hc ca cc s phn ng sau:1/ FeS2 + O2---->Fe2O3 + SO22/ KOH + Al2(SO4)3---->K2SO4 + Al(OH)33/ FeO + H2---->Fe + H2O4/ FexOy + CO---->FeO + CO25/ Al + Fe3O4 ----> Al2O3 + FeV cho bit phn ng no l phn ng oxi ha kh ?Cht no l cht kh? Cht no l cht oxi ha?Ti sao?Cu 2(1,5im): Trnh by phng php nhn bit cc dung dch ng trong 4 l mt nhn sau:Nc, Natri hixit, Axit clohiric, Natriclorua.Vit phng trnh phn ng minh ho nu c.Cu3(1,0 im):Cho cc oxit c cng thc sau: SO3, Fe2O3,K2O, N2O5, CO2.1/ Nhng oxit no thuc loi oxit axit, oxitbaz? v sao?2/ c tn tt c cc oxit. Vit cng thc cu to ca cc oxit axit.Cu 4 (2,0 im): Dn t t 8,96 lt H2 (ktc) qua m gam oxit st FexOy nung nng. Sau phn ng c 7,2 gam nc v hn hp A gm 2 cht rn nng 28,4 gam (phn ng xy ra hon ton).1/ Tm gi tr m?2/ Lp cng thc phn t ca oxit st, bit A c cha 59,155% khi lng st n cht.Cu 5 (2,5 im): 11,2 lt hn hp X gm hiro v mtan CH4 (ktc) c t khi so vi oxil 0,325. t hn hp vi 28,8 gam kh oxi. Phn ng xong, lm lnh hi nc ngng t ht c hn hp kh Y. Trang 33 B dy hc sinh gii1/ Vit phng trnh ho hc xy ra. Xc nh % th tch cc kh trong X?2/ Xc nh % th tch v % khi lng ca cc kh trong Y.Cu6(1,5im): Tnhkhi lngNaCl cnthit phathmvo 200,00gam dung dch NaCl 25% thnh dung dch 30%.Cho: Fe = 56; Al = 27; Mg = 24;Na = 23 ; Zn = 65; C =12; O = 16 ; Cl = 35,5.p n s 19CU 1 1,54FeS2 + 11O22Fe2O3 + 8 SO2 (1)6KOH + Al2(SO4)33K2SO4 + 2Al(OH)3(2)FeO + H2Fe+ H2O(3)FexOy + (y-x)CO xFeO + (y-x)CO2 (4)8Al + 3Fe3O44Al2O3 +9Fe(5) Cc phn ng (1) (3)(4)(5) l phn ng oxi hoa khCht kh l FeS2 , H2, CO, Al v chng l cht chim oxi ca cht khc0,20,20,20,20,20,250,25Cu 2 1,5Rt cc dung dch vo 4 ng nghim tng ng Bc 1 dng qu tm nhn bit ra NaOH lmqu tm chuyn mu xanhv HCl lm qu tm chuyn mu Bc 2 cho dung dch 2 ng nghim cn li khng lm qutm i mu dung cho bay hi nc ng ng nc s bay hi ht ng ng dd NaCl cn li tinh th mui .0,50,50,5Cu 3 1,5OxitSO3, N2O5, CO2,l oxit axit v tng ng vi chng l axit H2SO3, HNO3 H2CO3 ngoi ra chng cn c kh nng tc dng vi baz v oxit baz Oxit Fe2O3,K2O l oxit baz v tng ng vi chng l axit Fe(OH)3KOH ngoi ra chng cn c kh nng tc dng vi dd axitTnlnlt cacc oxit l:khsunfur,st (III)oxit kalioxit ,kh nitpentaoxit,kh cc bonicCng thc cu to ca chng l (v ngoi)0,50,50,25 Trang 34 B dy hc sinh gii0,25Cu 4 2,0S mol H2 = 0,4 mol a/=> s mol oxi nguyn t l 0,4 molSmol nc 0,4 mol => mO = 0,4 x16 = 6,4 gam Vy m = 28,4 + 6,4 = 34,8 gamFexOy +y H2xFe+y H2O 0,4mol 0,4molb/ mFe = 59,155 x 28,4= 16,8gam=>Khi lng oxi l mO = 34,8 16,8 = 18 gamGi cng thc oxit st l FexOy tac x:y =mFe/56 : mO /16=> x= 3, y= 4 tng ng cng thc Fe3O40,50,50,250,50,25Cu 5 2,5MTB= 0,325 x 32=10,4 gamnhhkhi = 11,2 :22,4= 0,5 molp dng phng php ng cho ta c CH4 16 8,43phn10,4H2 2 5,6 2phn=>s mol nCH4= 0,3mol s mol nH2= 0,2mol1,00,250,750,5%CH4= 0,3/0,5 x 100%=60% , %H2 = 100%-60% = 40%S mol kh oxi nO2=28,8:32= 0,9mol2H2+ O2 2H2O 0,2mol 0,1molCH4 +2O2CO2 + 2H2O0,3mol 0,6mol 0,3molHn hp kh cn trong Y gm CO2 v kh O2(d)nO2d = 0,9 (0,6 + 0,1) = 0,2 mol,nCO2 = 0,3 mol%V CO2 = 0,3/ 0,5 x 100% = 60% , %VO2 = 0,2/ 0,5 x 100% = 40%mCO2 = 0,3 x44=13,2 gam ,mO2 = 0,2 x 32 = 6,4gam% mCO2= 13,2/19,6 x 100% =67,34% , % mO2= 6,4/19,6 x 100% = 32,66%Cu 6 1.0 Trang 35 B dy hc sinh giiKhi lngNaClc trong dung dch ban u l ,mNaCl = 25%x200=50 gam gi lng NaCl thm vo l x ta c khi lng NaCl = (50+ x) , mdd = (200+ x) p dng cng thc tnh nng C%x= (200x5):70 = 14,29 gam0,50,5 s 20Bi 1:1) Cho cc PTHH sau PTHH no ng, PTHH no sai? V sao?a) 2 Al +6 HCl2 AlCl3+3H2 ;b)2 Fe +6 HCl 2 FeCl3+3H2c)Cu+2 HCl CuCl2 +H2 ; d) CH4+ 2 O2 SO2 +2 H2O 2) Chn cu pht biu ng v cho v d:a) Oxit axit thng l oxit ca phi kim v tng ng vi mt axit.b) Oxit axit l oxit ca phi kim v tng ng vi mt axit.c) Oxit baz thng l oxit ca kim loi v tng ng vi mt baz.d) Oxit baz l oxit ca kim loi v tng ng vi mt baz.3)Hon thnh cc PTHH sau:a)C4H9OH+O2 CO2 + H2O; b)CnH2n - 2+ ? CO2 + H2Oc)KMnO4 + ?KCl+ MnCl2 + Cl2 + H2O d)Al+H2SO4(c, nng) Al2(SO4)3+SO2 + H2OBi 2: Tnh s mol nguyn t v s mol phn t oxi c trong 16,0 g kh sunfuric. (gi s cc nguyn t oxi trong kh sunfuric tch ra v lin kt vi nhau to thnh cc phn t oxi). Bi 3: t chy hon ton kh A cn dng ht 8,96 dm3kh oxi thu c 4,48 dm3 kh CO2 v 7,2g hi nc.a) A do nhng nguyn t no to nn? Tnhkhi lng A phn ng.b) Bit t khi ca A so vi hiro l 8. Hy xc nh cng thc phn t ca A v gi tn A.Bi 4:Cho lung kh hiro i qua ng thu tinh cha 20 g bt ng(II) oxit 400 0C. Sau phn ng thu c 16,8 g cht rn.a) Nu hin tng phn ng xy ra.b) Tnh hiu sut phn ng.c) Tnh s lt kh hiro tham gia kh ng(II) oxit trn ktc.p n s 20 Trang 36 B dy hc sinh giiBi p n Thang im Trang 37 B dy hc sinh gii1(3)1(1)a) ng, v ng tnh cht 0,125 + 0125b) Sai, v P ny khng to ra FeCl3m l FeCl2 hay l sai 1 sn phm0,125 + 0125c) Sai, v khng c P xy ra 0,125 + 0125d) Sai, v C bin thnh S l khng ng vi L BTKL0,125 + 01252(1)a) . VD: Oxit do PK to nn l SO3tng ng vi axit H2SO4Oxit do KL trng thi ho tr cao to nn l CrO3 tng ng vi axit H2CrO40,25 + 0,25d) . VD: Na2O tng ng vi baz NaOH FeO tng ng vi baz Fe(OH)20,25 + 0,253(1)a) C4H9OH+ 6 O2 4 CO2 +5 H2O0,25b)2 CnH2n - 2+(3n 1) O2 2n CO2 + 2(n-1) H2O0,25c) 2 KMnO4+ 16 HCl 2 KCl+2 MnCl2 + 5 Cl2 + 8 H2O0,25d)2 Al+6 H2SO4(c, nng) Al2(SO4)3 +3 SO2 +6 H2O0,252(1)nSO3 = 16: 80 = 0,2 mol; nO= 0,2 .3 = 0,6 mol. 0,25 + 0,25C 2 O lin kt vi nhau to nn 1 O2=> 2 mol O ----------------------------1 mol O2 Vy: nO2 =(0,6.1): 2 =0,3 mol0,25 + 0,253(3)@-HD: c 6 ln x 0,5 = 3 .* S P chy:A+ O2 CO2 + H2O ; mO trong O2 = g 8 , 12 16 ). 2 .4 , 2296 , 8( ; * mO sau P= mO(trong CO2+ trong H2O) = g 8 , 12 16 ). 1 .182 , 7( 16 ). 2 .4 , 2248 , 4( +a)Sau phn ng thu c CO2v H2O => trc P c cc nguyn t C, H v O to nn cc cht P. Theo tnh ton trn:tng mO sau P = 12,8 g = tng mO trong O2. Vy A khng cha O m ch do 2 nguyn t l C v H 0,50,50,50,50,5 Trang 38 B dy hc sinh giito nn.mA P = mC + mH = g 2 , 3 1 ). 2 .182 , 7( 12 ). 1 .4 , 2248 , 4( +b) Ta c: MA = 8.2 = 16 g;t CTPT cn tm l CxHy vi x, y nguyn dngMA = 12x + y = 16g => phng trnh:12x + y = 16 (*)T l x: y= nC: nH= x 4 y41yxhay 4 : 1 8 , 0 : 2 , 0 ) 2 .182 , 7( : ) 1 .4 , 2248 , 4( > thay vo (*): 12x + 4x = 16 x= 1 => y = 4. Vy CTPT ca A l CH4, tn gi l metan.0,54(3) PTP: CuO +H2 C 4000 Cu+H2O ;a) Hin tng P: Cht rn dng bt CuO c mu en dn dn bin thnh mu (Cu) 0,50,5b) Gis20gCuOP ht thsauP s thuc g 168064 . 20cht rn duy nht (Cu) < 16,8 g cht rn thu c theo u bi => CuO phi cn d. - t x l s mol CuO P, ta c mCRsau P = mCu + mCuO cn d= x.64 + (mCuO ban u mCuO P) = 64x + (20 80x) = 16,8 g. => Phng trnh: 64x + (20-80x) =16,8 16x = 3,2 x= 0,2. => mCuO P = 0,2.80= 16 g Vy H = (16.100%):20= 80%.0,50,50,5c) Theo PTP: nH2=nCuO=x=0,2 mol. Vy: VH2= 0,2.22,4= 4,48 lt0,5 s 21Cu1 (2):1, Nguyn t X c tng cc ht l 52 trong s ht mang in nhiu hn s ht khng mang in l 16 ht.a)Hy xc nh s p, s n v s e trong nguyn t X.b) V s nguyn t X.c) Hy vit tn, k hiu ho hc v nguyn t khi ca nguyn t X.2, Nguyn t M c s n nhiu hn s p l 1 v s ht mang in nhiu hn s ht khng mang in l 10.Hy xc nh M l nguyn t no?Cu 2 (2): Lp phng trnh ho hc ca cc s phn ng sau:1/ FeS2 + O2---->Fe2O3 + SO2 Trang 39 B dy hc sinh gii2/ KOH + Al2(SO4)3---->K2SO4 + Al(OH)33/ FeO + HNO3---->Fe(NO3)3 + NO + H2O4/ FexOy + CO---->FeO + CO2Cu3 (2):Tnh s phn t : a, Ca 0,25 molFe2O3 b, Ca 4,48 lt Cacbnc (ktc). c, Ca 7,1 gam kh Clo.Cu4 (2) :Mt hp cht A c 42,9% C v 57,1% O theo khi lng. a, Lp cng thc ca A , bitdA/H2 = 14.b, Tnh khi lng ca 1,12 lt kh A ( ktc).Cu5 (2): t chy 16g mt chtX cn dng 44,8 lt kh Oxi(ktc ) thu c kh CO2 v hi nc theo t l mol l 2 : 1 .Tnh khi lng kh CO2 v khi lng H2O to thnh. s 22Cu1 (2): 1, Tng s ht p ,e ,n trong nguyn t l 28 ,trong s ht khng mang in chim xp x 35% .Tnh s ht mi loa .V s cu to nguyn t .2, Bit tng s ht p,n,e trong mt nguyn t l 155. s ht mang in nhiu hn s ht khng mang in l 33 ht. Tm p,n,e,NTK ca nguyn t trn ?Cu 2 (2): Lp phng trnh ho hc ca cc s phn ng sau:1/ FeS2 + O2---->Fe2O3 + SO22/ KOH + Al2(SO4)3---->K2SO4 + Al(OH)33/ FeO + HNO3---->Fe(NO3)3 + NO + H2O4/ FexOy + CO---->FeO + CO2Cu3 (2):Tnh s phn t : a, Ca 0,5 molFe2O3 b, Ca 3,36 lt Cacbnc (ktc). c, Ca 14,2 gam kh Clo.Cu4 (2) :Mt hp cht A c 82,76% C v 17,24% H theo khi lng. a, Lp cng thc ca A , bitdA/ KK = 2.b, Tnh khi lng ca 1,12 lt kh A ( ktc).Cu5 (2): t chy 16g mt chtX cn dng 44,8 lt kh Oxi(ktc ) thu c kh CO2 v hi nc theo t l mol l 2 : 1 .Tnh khi lng kh CO2 v khi lng H2O to thnh. s 23I/ Phn trc nghim khch quan (4,0 im)Chn mt p n ng trong 4 phng n mi cu ri ghi vo bi lm:1) NguyntAgonc18protontronght nhn. Slpelectronvs electron lp ngoi cng tng ng l:A- 2 v 6 B- 3 v 7 C- 3 v 8 D- 4 v 72) Tng s ht proton, ntron, electron trong nguyn t R l 28, trong s ht khng mang in chim khong 35,7%.S n v in tch ht nhn bng: Trang 40 B dy hc sinh giiA- 9B- 10 C- 11 D- 123) Lnh vc p dng quan trng nht ca kh oxi l:A- S h hp B- t nhin liu trong tn la C- St nhin liu D- C A v C4) Trong mt nguyn t ca nguyn t X c 8 proton, cn nguyn t ca nguyn t Y c 13 proton. Hp cht ng gia X v Y l:A- YX2B- Y2X C- Y2X3D- Y3X25) Ly mt khi lng cc kim loi km, nhm, magie, st ln lt tc dng vi dung dch axit sunfuric long. Cc kim loi tc dng ht vi axit th kim loi no cho nhiu hiro nht:A- Km B- Nhm C- Magie D- StII/ Phn t lun (16,0 im)Bi 1 (3,0im): Lp phng trnh ho hc ca cc s phn ng sau:1/ FeS2 + O2---->Fe2O3 + SO22/ KOH + Al2(SO4)3---->K2SO4 + Al(OH)33/ FeO + HNO3---->Fe(NO3)3 + NO + H2O4/ FexOy + CO---->FeO + CO25/ CxHyCOOH + O2---->CO2 + H2OBi 2 (3,0 im): Nu cc th d chng minh rng oxi l mt n cht phi kim rt hot ng (c bit nhit cao). Trn c s hy so snh vi tnh cht ho hc c bn ca n cht hiro. Vit phng trnh minh ho.Bi 3(3,0 im): Cho cc oxit c cng thc sau: SO3, Fe2O3, K2O, N2O5, Mn2O7, NO.1/ Nhng oxit no thuc loi oxit axit, oxitbaz? v sao?2/ c tn tt c cc oxit. Vit cng thc cu to ca cc oxit axit.Bi 4(3,0 im): Dn t t 8,96 lt H2 (ktc) qua m gam oxit st FexOy nung nng. Sau phn ng c 7,2 gam nc v hn hp A gm 2 cht rn nng 28,4 gam (phn ng xy ra hon ton).1/ Tm gi tr m?2/ Lp cng thc phn t ca oxit st, bit A c cha 59,155% khi lng st n cht.Bi 5 (4,0 im): 17,92 lt hn hp X gm hiro v axetilen C2H2 (ktc) c t khi so vi nit l 0,5. t hn hp vi 51,2 gam kh oxi. Phn ng xong, lm lnh hi nc ngng t ht c hn hp kh Y.1/ Vit phng trnh ho hc xy ra.2/ Xc nh % th tch v % khi lng ca Y.Cho: Fe = 56; Al = 27; Mg = 24; Zn = 65; C =12; O = 16 s 24Bi 1 (1,5 im) Lp phng trnh ha hc ca cc s phn ng sau: Trang 41 B dy hc sinh gii1) KOH + Al2(SO4)3 K2SO4 + Al(OH)32)FexOy + CO 0tFeO + CO23)CnH2n-2 + ? CO2 + H2O.4)FeS2 + O2 Fe2O3 + SO25) Al + HNO3 Al(NO3)3 + N2O + H2OBi 2: (1,5 im)Bng phng php ha hc hy nhn bit cc l ha cht b mt nhn gm: CaO; P2O5; MgO v Na2O u l cht bt mu trng ?Bi 3:(2,5 im) t chy hon ton 4,48 lt H2 trong 3,36 lt O2 .Ngng t sn phm thu c cht lng A v kh B .Cho ton b kh B phn ng ht vi 5,6 gam Fe thu c hn hp cht rn C. Ho tan ton b cht rn C vo dung dch cha 14,6 gam HCl thu c dung dch D v kh E. Xc nh cc cht c trong A,B,C,D,E. Tnh khi lng mi cht c trong A, C v s mol cc cht c trong dung dch D. Bit : 3Fe+ 2O2 0t Fe3O4 Fe+2HCl FeCl2+ H2 Fe3O4+8 HCl FeCl2 + 2FeCl3 + 4H2O (Cc kh u o iu kin tiu chun )Bi 4: (2,25 im)Mt hn np kh ca Nit gm: NO, NO2; NxO bit thnh phn phn % v th tch cc kh trong hn np l: %VNO = 50% ; 2% 25%NOV . Thnh phn % v khi lng NO c trong hn hp l 40%. Xc nh cng thc ha hc ca kh NxO. Bi 5: (2,25 im)Nung 400gam vi cha 90% CaCO3 phn cn li l tr. Sau mt thi gian thu c cht rn X v kh Y a.Tnh khi lng cht rn X bit hiu sut phn hu CaCO3 l 75%b. Tnh % khi lng CaO trong cht rn X v th tch kh Y thu c ( KTC) s 25Cu 1: (3) Hy khoanh trn vo ch ci u cu m em cho l ng. 1.Dy cng thc sau ton l oxt, axt:A. C02; H20; Fe 203; P205B. C02; S03; Mn07; Cr03C. Cu0; S03 ; CaO ; P205D. Na0; S02; N203; Al203 2. t chy hon ton 1g n cht x cn 0,7 lt kh 02 ( iu kin TC) vy x l: Trang 42 B dy hc sinh giiA. Cc bon B. Lu hunh C. St D. Pht pho3.Khi cho x lin kt vi oxi c cng thc X203, Y lin kt vi hyr c cng thc HY Nu X lin kt vi Y c cng thc no trong cc cng thc sau: A: XYB: X2Y3C: XY3D: X3Y E: X2YCu 2: (5) Cho s phn ng sau:a.FeS2 X Y Z CuS04 A+ M,t0+G B b. A+N, t0 Fe A +Q, t0 +H C Bit: A + HClB + C + H20 Tm cc cht c k hiu bng cc ch ci v hon thnh cc phng trnh ho hc .Cu 3: (2) Mt kim loi A (cha r ho tr ) c t l khi lng oxi l 3/7%A. tm cng thc oxt kim loi .Cu 4 :(4) t chy hon ton 15g hn hp gm CH4 v C0 trong khng kh thu c 16,8 lt C02 (ktc)a. Tnh % khi lng cc kh trong hn hp bn u.b. Tnh th tch khng kh cn dng.Cu 5 : (6) t chy hon ton m1 gam nc ho tan va 16g kali oxt (K20). Bit t l s mol nCO2 : nH2O to thnh l: 1: 2a. Tnh khi lng m1 ca hp cht X dng.b.Tnh th tch kh CO2p n s 25Cu 1: (3) 1:B (1) Trang 43 B dy hc sinh gii2:B (1)3:C (1)Cu 2: (3)a. S phn ngFeS2SO2 SO3 H2SO4CuSO4(1) to 4FeS2 + 11O22FeO3+ 8SO2 (0,5)2SO2 + O2 2SO3(0,5)SO3 + H2O H2SO4 (0,5)CuO + H2SO4CuSO4 + H2O (0,5)b.Fe3O4 + CO, tO+Cl2 FeCl3(1)Fe2O4+Al, toFeFe2O4 + H2, tO +HCl FeCl2 Fe3O4 + 4CO3Fe + 4CO2 (0,25)3Fe3O4 + 8Cl 9Fe + 4AlO3 (0,25)Fe3 + 4H23Fe + 4H2O (0,25)2Fe + 3Cl2FeCl2 + H2 (0,25)Fe + 2HClFeCl2 + H2(0,25)Fe3O4 + 8HCl 2FeCl3 + FeCl2 + 4H2O (0,5) Cu 3: (2)Gi A l nguyn t kim loi, tng s phn oxi v kim loiA l 3/7% + % A = 10/7%Mt khc %0+%A=100%%A=70%(2) %0 = 30%Nu gi n l ho tr ca A ta c cng thc oxt A2On ta c t l v khi l-ng Trang 44 B dy hc sinh gii2A =16n A = 56n(0,5)Kim loi thng c gi tr t 1 n 3n 1 2 3A 18,7 37,3 56Chn n = 3A l Fe (Fe = 56)(0,5)Cu 4: (4)Phng trnh ho hc sy raCH4 + O2CO2 + H2O (1)(0,5)2CO + O22CO2 (2) (0,25)S mol ca CO2 thu c (ktc) nCO2 = 16,8 = 0,75 (mol) (0,25) 22,4 Nu gi x l s mol ca CO2 phng trnh (1) Y l s mol phng trnh (2) ta c: x+ y = 0,75(a)(0,25)Theo phng trnh ho hc (1) nCH4 = nCO2 = x (mol)Theo PTHH (2)nCO = nCO2 = y (mol)Theo bi ra ta c: 16x + 28y = 15 (g) (b) (0,5)T (a) va (b) ta c x = 0,25 (0,5) y = 0,5a. Phn trm v khi lng cc kh hn hp ban u mCH4 = 16 . 0,25 = 4g% CH4 = 4/15 . 100% = 26,66% (0,5) % CO = 100% - 26,66% = 73,34% (0,5) b. T phng trnh ho hc ta c :CH4 + O2 CO2 + H2O 0,25mol0,25 mol2CO + O2 2CO2 Trang 45 B dy hc sinh gii1/2 . 0,5mol0,5 mol Vy th tch oxi cn dng (ktc) V02 = (0,25 + 1/2 .0,5) 22,4 = 11,2 (1) (0,5)V trong khng kh oxi chim 1/5 v th tchNn Vkk = 11,2 x 5 = 56 (1) (0,5)Cu 5: a)S mol ca oxi, K2O cn dng lVO2 =Vkk= 22,4 = 4,48(0,5) 55n02 = 4,48= 0,2 (mol)22,4m02 = 0,2 . 32 = 6,4 (g)nk20 = 16,80,2(mol)(0,5) 84 Theo ra ta cx + O2 CO2 + 2H2O (1) (0,5) Theo lBTKL mx + mO2 + mH2O(0,5) K2O + H2O 2KOH (2) (0,5) 1mol1mol 1molx = 0,2 . 1= 0,2 mol (0,5)1 mH2O = 0,2 . 18 = 3,6 (g)m2 = 3,6 (g) (0,5) T (1) mCO2 = 0,1 . 44 = 4,4 (g) (theo gi thuyt )(3) NCO2 : nH2O = 1: 2) (0,5) T (1) v (2) v (3)mX = (mCO2 + mH2O)Mx = (4,4 + 3,6) - 6,4 = 1,6 (g) (1) Vy m1 = 1,6 (g)b)ThtchkhCO2thucktclVCO2=0,1.22,4=2,24(1) (1) ./. s 26Cu 1: (2 im) Trang 46 B dy hc sinh giia)c tn cc cht sau :K2O :MgCl2:NaNO3:Al(OH)3:b)Vit cng thc ho hc cc cht sau:St(II) oxit :Axit sunfur :Km hirxit :ChCacbonat :Cu 2 : ( 1im)Ni ct A vi ct B cho ph hp :A)B) T khi i vi khng kh :Khi lng mol ca cht kh 278,31,74 322,7 50,51,52 44,158 Cu 3: (3 im)a)Tnh khi lng ca hn hp kh gm 6,72 lt H2 , 17,92 lt N2 v 3,36 lt CO2 ?b) Tnh s ht vi m ( phn t) c trong hn hp kh trn , vi N= 6.1023 ?Cu 4: ( 2im)C 5,42 gam mui thu ngn clorua , c chuyn ho thnh Hg v Cl bng cch t nng vi cht thch hp thu c 4gam Hg .a,Tnh khi lng clo kt hp vi 4g Hg ?b,C bao nhiu mol nguyn t clo trong khi lng trn ?c,C bao nhiu mol nguyn t Hg trong 4g Hg?T cu tr li (b) v (c) , hy tm cng thc ho hc ca mui thu ngn clorua trn ?( Cho bitHg = 200 , Cl = 35,5)Cu 5 : ( 2im) K2SO3+HCl ------ KCl +H2O+SO2Cho 39,5 gK2SO3 vo dung dch c 14,6g HCl .a.Tnh th tch kh sinh ra ktc ?b,Tnh khi lng cht tham gia phn ngcn tha trong dung dch?p n 26Cu3:(3im)a) Khi lngH2 : ( 6,72 : 22,4) x2 = 0,6(g)(0,5)a) Khi lngN2 : (17,92: 22,4) x 28 = 22,4(g) (0,5)a) Khi lngCO2 : ( 3,36 : 22,4) x 44= 0,6(g) (0,5)a) Khi lnghnhp: 0,6 + 22,4 + 6,6= 29,6(g) (0,5)S ht vi m (phn t ) trong hn hp : (6,72 + 17,92 + 3,36) : 22,4x6.10 23 =7,5.1023 (pt) (1) Trang 47 B dy hc sinh giiCu4:(2im)a) mcl= 5,42 4= 1,42(g)(0,5)b) ncl =1,42 : 35,5 = 0,04 (mol)(0,5)c) nHg= 4 : 200=0,02 (mol)(0,5)d) nHg : n Cl = 0,02 : 0,04= 1: 2CTHH:HgCl2(0,5)Cu5:(2im)a)K2SO3 +2HCl 2KCl +H2O +SO2 (0,25) nK2SO3 = (39,5 : 158) = 0,25 (mol)(0,25)nHCl = (14,6: 36,5) = 0,4 (mol)(0,25)0,25 0,4T l s mol>K2SO3 d , th tch SO2 tnh theo HCl1 2(0,25)Th tch SO2 (ktc) :22,4 x0,2= 4,48 (l)(0,5) b) n K2SO3 d : 0,25 0,2= 0,05 (mol) m K2SO4d :0,05 x 158=7,9(g)(0,5) s 27Cu 1: (2 im) Cng thc ho hc no ng ,cng thc ho hc no sai , sa cng thc sai .K2O,Fe3O2,Al(OH)3,MgCl2, Na(NO3)2,H2SCTHH ng CTHH sai Sa CTHH saiCu 2: (1 im) C th thu nhng kh di y vo bnh : H2,Cl2,NH3,CO2, SO2, CH4 Bng cch : t ng bnh :. t ngc bnh :Cu 3 : (2im) Hon thnh cc phng trnh ho hc sau :Al + Cl2----- AlCl3Na + H2O ----- NaOH + H2Fe2O3+ HCl ----- FeCl3+ H2OFeS2+ O2----- Fe2O3+ SO2Cu 4 : ( 2 im) Tnh nng % v nng M ca dung dch khi ho tan 14,3 gam xa (Na2CO3. 10H2O) vo 35,7 g nc . Bit th tch dung dch bng th tch nc . Trang 48 B dy hc sinh giiCu 5: ( 3 im)Cho 2,8g mt hp cht A tc dng vi Ba ri clorua . Tnh khi lng Bari sunfat v Natri clo rua to thnh. Bit :-Khi lng Mol ca hp cht A l 142g- %Na =32,39%;%S=22,54%;cn li l oxi ( hp cht A ) s 28I)PHN TRC NGHIM :(3im)Hy khoanh trn vo ch ci u cu caphng n em cho l ng .Cu 1: (0,5 im) Nguyn t cacbon c khi lng bng 1,9926.10 -23g. Khi lng tnh bng ca nguyn t Nat ri l :A. 3,82 . 10 -23 g B.3,82 . 10 -22 gC. 3,82 . 10 -21 g D.Tt c u sai .Cu2 : ( 0,5im) Hy la chn dy CTHH ng ca cc hp cht :A) N3H , Al2O3 , H2S , NO2 , CO2B) NH3 , Al2O3 , H2S , NO2 , CO3C) NH3 , Al2O3 , H2S , N2O5 , COD) NH3, Al3O2 , H2S , N2O5 , CO2Cu 3: (0,5 im) Cho bit CTHH hp cht ca nguyn t X vi S(II) v hp cht ca nguyn t Y vi H nh sau: X2S3 , YH3 , Hy chn cng thc ho hc ng trong cc hp cht ca Xv Y sau y :A) X2Y ,B) XY2, C)XY , D) X3Y2 Cu 4: (0,5 im)Cho s d phn ng sau : Fe(OH)y+ H2SO4----------- Fex(SO4)y+H2O Hy chn x,y bng cc ch s thch hp no sau y lp c PTHH trn ( bitx = y )A)x =1 , y=2B)x= 2,y= 3C)x =3 ,y=1D) Tt c u sai.Cu 5: ( 0,5im) Cho hn hp gm 2 mui A2SO4 v BSO4 c khi lng 44,2 g tc dng va vi 62,4gBaCl2 trong dung dch th cho 69,9g kt ta Ba SO4 v 2 mui tan . Khi lng 2 mui tan sauphn ng l: A) 36,8g,B)36,7 g, C) 38 g , D)40g Cu 6: (0,5im)Khi t chy 1 mol cht x cn 2,5 molO2 th thu c 2 mol kh CO2 v 1 mol nc.Cht xc cng thc phn t no sau y:A)C2H4 ,B) C2H2 , C) C2H6 ,D) C4H10 I)PHN T LUN :(7im)Cu 1: (1 im) Mt cht lng d bay hi , thnh phn phn t c 23,8% C , 5,9% H, v 70,3% Cl , c phn Trang 49 B dy hc sinh giit khi bng 50,5 . Tm cng thc ho hc ca hp cht trn.Cu 2: (3 im) Trn ln 50g dung dch NaOH 8% vi 450g dung dch NaOH 20% .a, Tnh nng phn trm dung dch sau khi trn ?b,Tnh th tch dung dch sau khi trn , bit khi lng ring dung dchny l 1,1g/ml ?Cu 3: (3 im)Cho 22g hn hp 2 kim loi Nhm v st tc dng vi dung dch HCl d . Trong nhm chim 49,1% khi lng hn hp.a)Tnh khi lng a xit HCl cn dng ?b) Tnh th tch Hir sinh ra ?( ktc)c) Cho ton b H2 trn i qua 72g CuO nung nng. Tnh khi lng cht rn sau phn ng ?p n s 28Cu 1 :ACu 2 :CCu 3 :CCu 4 :BCu 5 :BCu 6 :B s 29I)PHN TRC NGHIM :(4im)Cu 1: (3 im) Hy khoanh trn vo ch ci u cu caphng n em cho l ng .1/ Nu cho cng s mol mi kim loi : K , Ca , Al , ln lt tc dng vi dung dch axit HClth kim loi no cho nhiu Hidro hn ?A)Al,B)Ca , C) K , D) Al v K 2/ Cho bit CTHH hp cht ca nguyn t A viS(II) v hp cht ca nguyn t B vi O nh sau : AS, B2O3 . Hy chn cng thc ho hc ng trong cc hp cht ca A v B sau y :A)AB,B)A2B2 , C) A3B2 , D) A2B33/ S phn ng :Al(OH)y+ H2SO4----------- Alx(SO4)y+H2O Hy chn x,y bng cc ch s thch hp no sau y lp c PTHH trn ( bitx = y )A)x =3, y=1B)x= 1,y= 2C)x =2,y=3 D)x =3, y = 24/ Nguyn t Cacbon c khi lng bng 1,9926.10 23g Khi lng thc ca nguyn t oxi tnh ra gam c th l:A/2,6568 .10 22g B/2,6 .10 23gC/1,328.10 22gD/2,6568 .10 23g5/ Hy la chn dy cng thc ho hc ng ca cc hp cht :A/ Fe(NO3)2 ,CuCl2,NaSO4,Ca3(PO4) 2B/ Fe(NO3)3 ,CuCl3,Na2SO4,Ca3(PO4) 2C/Fe(NO3)2 ,CuCl2,Na2SO4,Ca(PO4) 2D/Fe(NO3)2 ,CuCl2,Na2SO4,Ca3(PO4) 2 Trang 50 B dy hc sinh gii6/Trong mui ngm nc Na2CO3 . xH2O , Na2CO3 chim 37,07% v khi lng, x c gi tr l :A)9,B)8, C)7 , D)10Cu2 : ( 1im) Hy in ch voca cu ng , ch S vo ca cu sai .a) Trong khng kh c nguyn t oxi tn ti dng t do.b) Trong khng kh c nguyn t oxi.c) Kh Sunfur to bi nguyn t lu hunh v nguyn t oxi .d) Kh Sunfur to bi 2 nguyn t lu hunh v oxi .I)PHNT LUN:(6im)Cu 1: (2 im) C nhngcht kh sau: Nit , Cacbon ioxit ( kh Cacbonic), Neon ( Ne l kh tr ) , oximetan (CH4)a,Kh no lm cho than hng chy sng ? Vit PTHHb,Kh no lm c nc vi trong? Vit PTHH c,Kh no lm tt ngn nn ang chy ? Gii thch d,Kh no trong cc kh trn l kh chy ? Vit PTHHCu 2: (2 im) t chy 1,3g bt nhm trong kh Clo ngi ta thu c 6,675g hp cht nhm clorua .Gis cha bit ho tr ca Al v Cl .a,Tm CTHH ca nhm clorua ?b,Tnh khi lng ca kh clo tc dng vi nhm ?Cu 3: ( 2 im) S phn ng : NaOH + CO2 Na2CO3 +H2O+Lp PTHH ca phn ng trn ?+Nu dng 22g CO2 tc dng vi 1 lng NaOH va, hy tnh khilngNa2CO3iu ch c ?+Bng thc nghim ngi ta iu ch c 25g Na2CO3 . Tnh hiu sut ca qu trnh thcnghim? p m s 294:I)PHN TRC NGHIM: (4) Cu 1 : (3) Lm ng mi cu nh 0,5im.1/ A 2/ C 3/ C 4/ D 5/ D 6/ DCu 2 : s a) b)s c) d) II)PHN T LUN (6)Cu1: ng mi cu nh(0,5) Trang 51 B dy hc sinh giia) oxi C+ O2CO2b) Cacbon ioxit CO2+ Ca(OH)2 CaCO3+H2Oc) Nit , cacbon ioxit, neon Cc kh ny khng chy v khng di tr s chy.d) m tan CH4 + 2O2CO2 + 2H2OCu 2:(2) -Xc nh c CTHH ca nhm clorua: AlCl3(1,5)-Tnh khi lng kh Clo (0,5)Cu3: (2) - Vit PTHH (0,25)- nCO2(0,25)-Xc nh s mol Na2CO3 (0,25) -Khi lng Na2CO3 (0,25) Tnh hiu sut ca qu trnh . (1) s 30 bi: Cu 1:Hy nu cc du hiu nhn bit c phn ng ho hc xy ra.Cu 2:Trong thc t ngi ta p nh vi ri xp vo l nung nhit khong 1000oC sau khi nung thu c vi sng v c kh cacbonioxit thot ra t ming l, cho vi sng vo nc ta c vi ti. Em hy ch r hin tng vt l, hin tng ho hc trong cc qu trnh trnCu 3:Mt bn hc sinh ghi CTHH ca cc cht nh sau: Fe2O3, CO3, AlS, S2O3, MgO, N2O3, CaCl, HCl3,NO3, N5O2. EmhyxcnhCTHHno ng ,CTHH no sai, nu sai sa li cho ng Cu 4: Lp PTHH biu din cc phn ng sau: a, Khi ru etylic chy l n tc dng vi oxi trong khng kh to thnh kh cacbonic vhi ncb,Khi t phot pho, cht ny ho hp vi oxi to thnh mt cht rn l anhiritphotphoricCu 5: Xc nh cng thc hohc n gin ca cht kh A bit thnh phn phn trm theo khi lng ca cc nguyn t l 82,35% N v 17,65% H v (d2HA = 8,5)Cu 6: Mt hn hp kh gm c 32 gam O2 v 3 gam H2

a, Cho bit th tch ca hn hp kh ktc ?b, t hn hp kh, phn ng xong ngui v cho bit: - S phn t kh no cn d , d bao nhiu ? - Th tch ca kh d o ktc l bao nhiu ? - Khi lng ca kh d l bao nhiu?p n s 30Cu Din gii im+Du hiu nhn bit c phn ng ho hc xy ra: Trang 52 B dy hc sinh gii1 (Mt trong s cc du hiu )- C cht kt ta(cht khng tan)- C cht kh thot ra(si bt kh)- C thay i mu sc- C s to nhit hoc pht sng0,250,250,250,252+ Hin tng vt l: p nh vi ri xp vo l nung+ Hin tng ho hc: - vi nung nhit khong 1000oC ta c vi sng vkh ccbonioxit- Cho vi sng vo nc ta c vi ti.0,250,250,253 +CTHH ng: Fe2O3, MgO, N2O3+CTHH Sai: CO3, AlS, S2O3 CaCl, HCl3,NO3,N5O2.+Sa li: CO2, Al2S3, SO2 CaCl2, HCl, NO2, N2O5. 0,250,50,54Lp PTHHa,C2H5OH +3O2->2CO2 +3H2Ob,4P+ 5O2

ot 2P2O5 0,50,55+Gi s CTHH chung hp cht A: NxHy+Bit (d2HA = 8,5) -> MA = 8,5. 2 = 17g+ Tnh s nguyn t ca N v H:ADCT: %N = % 100 y xH NNMM x-> % 100%NH NMM Nxy x->1% 100 1417 % 35 , 82 x Tng t :y = 3% 100 117 % 65 , 17

Vy CTHH ng lNH3 (Kh Amnic)0,250,50, 50, 50, 50,25 Trang 53 B dy hc sinh gii6+Tnh s mol ca O2 v H2ADCT:Mmn mol nH5 , 1232 . 132322mol nO a)-> Vh2 =(nH2 + nO2)x22,4 = ( 1,5 +1) x 22,4 = 56 (lit)b) PTHH:2H2 + O2 ot2H2O2mol 1mol2mol 1,5mol 0,75mol -> O2 d-> nO2 (d)=1- 0,75 = 0,25 (mol)-> S phn t kh O2dl: 0,25 . 6,02 .1023= 1,5.1023 phn t->VO2d= 0,25 . 22,4= 5,6 (lit)-> mO2 d = 0,25. 32= 8 (g)0, 50, 50, 50, 50,50,250,250,250,25 s 31Cu 1: (2 im)Vit phng trnh phn ng vi kh oxi ca cc cht sau:Lu hunh, metan, photpho, st , natri, canxi, nhmCu 2: (3 im)t chy hon ton 7,8 gam hn hp gm Mg v Al trong khng kh.Bit mMg/ mAl = 4/9a,Vit cc phng trnh phn ng xy rab, Tnh th tch o xi phn ng v th tch khng kh cn dng ( ktc)c, Tnh khi lng mi o xt sinh ra sau phn ngd, c c lng o xi nh trn cn phn hu bao nhiu gam KMnO4, bit hiu sut phn ng t 80%.Cu 3: (4 im)t chy 4,48 lt H2 trong 3,36 lt O2. Ngng t sn phm thu c cht lng A v kh B. Cho ton b kh B phn ng vi 5,6 gam Fe thu c rn C. Cho rn C vo dung dch cha 14,6 gam HCl thu c dung dch D v kh E.a, Xc nh cc cht c trong A,B,C,D,Eb, Tnh khi lng mi cht c trong A,C,Dc, Tnh th tch mi kh c trong B,EBit Fe + HCl --> FeCl2 + H2Fe3O4 + HCl --> FeCl2 + FeCl3 + H2OCc kh o c ktc Trang 54 B dy hc sinh giiCu 4: (1 im)35,5 gam oxit ca nguyn t R (ho tr V) c s mol bng s mol ca 5,6 lt O2 (ktc). Xc nh tn ca nguyn t R.Cho: Mg = 24, Al = 27, O = 16, K = 39, Mn = 55, Fe = 56, Cu = 64, Cl = 35,5, P = 31 s 32Cu1:(1,5 im) C 5 bnh, ng 5 cht kh: N2; O2; CO2; H2; CH4. Hy trnh by phng php ho hc nhn bit tng bnh kh?Cu2: (1,0 im) Kh CO2c ln kh CO v kh O2. Hy trnh by ph-ng php thu c kh CO2 tinh khit.Cu3:(2,0im) Cho 2 cc ng 2 dung dch HCl v H2SO4long vo 2 a cn, sao cho cn v tr thng bng. Sau lm th nghim nhsau:- Cho 25,44g Na2CO3 vo cc ng dung dch HCl.- Cho m gam Al vo cc ng dung dch H2SO4.Cn v tr thng bng, tnh m?( bit cc phn ng xy ra hon ton.)Cu4: (2,25 im) Trn 300ml dung dch HCl (ddX) vi 500ml dung dch HCl (ddY) ta c dd Z. Cho dung dch Ztc dng10,53g km phn ng va .a- Tnh CM (Z)b- Dung dchX c pha t dung dch Y, bng cch pha thm nc vo dung dch Y theo t l: YO HVV2=12. Tnh CM ca ddX v dd Y?Cu5:(3,25im) Ho tan hon ton 5,5g hn hp gm Al v Fe bng dung dch HCl 14,6%thu c 4,48 lt hiro (o KTC).a- Tnh thnh % v khi lng ca mi kim loi trong hn hp.b- Tnh nng % cc mui c trong dung dich sau phn ng.( Na = 23; H = 1; O = 16; C = 12; Al = 27; Fe = 56; Cl = 35,5; Zn = 65)p n s 32 Trang 55 B dy hc sinh gii s 33 Trang 56Cu1: ( 1,5 im) Nu c cc c bn sau:- Trch cc mu th, dng que m cn tn than hng cho vo cc mu th+ Kh no lm que m bng chy, kh l O2.+ Nu que m tt l kh N2 v CO2.+ Nu que m tip tc chy l kh H2 v CH4.- phn bit 2 kh N2v CO2, dn ln lt mi kh qua dung dch nc vi trong, kh no lm nc vn c l kh CO2; kh cn li l N2 khng c hin tng g.- t chy 2 kh H2v CH4, sau dn sn phm chy mi kh vo cc nc vi trong, cc no nc vn cth kh chy l CH4. PTHH: 2H2 + O2

0t2H2O CH4 + 2 O2 0tCO2+2H2O CO2 + Ca(OH)2 ->CaCO3 +H2OCu2: (1,0 im)- Dn hn hp kh CO2 c ln kh CO; kh O2 qua dung dch Ca(OH)2 d. Kh CO2 b hp th, cn 2 kh CO v O2 thot ra ngoi. CO2 + Ca(OH)2 d ->CaCO3 + H2OLc ly kt ta, ra sch ri nung nhit cao ( 9000C) n khi lng khng i thu c kh CO2. CaCO3

0tCaO+ CO2Cu3:(2,0im)- n3 2CO Na= 10644 , 25=0,24 mol *nAl = 27mmol- Khi thm dd Na2CO3 vo cc ng dd HCl ( cc A) c phn ng: Na2CO3 +2HCl->2NaCl+CO2 + H2O1mol 1mol0,24mol -> 0,24mol Theo nh lut bo ton khi lng, khi lng cc ng HCl tng thm:25,44- (0,24.44) = 14,88g- Khi thm Al vo cc ng dd H2SO4 c phn ng: 2Al+3 H2SO4->Al2 (SO4)3+ 3H22mol 3mol

27mmol->2 . 27. 3 mmol cn thng bng, khi lng cc ng H2SO4cng phi tng thm 14,88g :m- 2 . 27. 3 m.2 = 14,88g ; gii ra ta c m =16,74 (g)Cu4: (2,25 im)a) VddZ = 300 +500 = 800ml = 0,8 lt nZn = 6553 , 10= 0,162 mol-Phng trnh phn ng:Zn + 2HCl-> ZnCl2+H2 Theo phng trnh : nHCl =2.nZn = 2.0,162 = 0,324 mol CM ddZ = 8 , 0324 , 0 = 0,405 (M)0,250,250,25 0,250,50,250,250,250,250,25 0,50,250,5 0,50,25 B dy hc sinh giiCu1:(1,5 im) C 5 bnh, ng 5 cht kh: N2; O2; CO2; H2; CH4. Hy trnh by phng php ho hc nhn bit tng bnh kh?Cu2: (1,0 im) Kh CO2c ln kh CO v kh O2. Hy trnh by ph-ng php thu c kh CO2 tinh khit.Cu3:(2,0im) Cho 2 cc ng 2 dung dch HCl v H2SO4long vo 2 a cn, sao cho cn v tr thng bng. Sau lm th nghim nhsau:- Cho 25,44g Na2CO3 vo cc ng dung dch HCl.- Cho m gam Al vo cc ng dung dch H2SO4.Cn v tr thng bng, tnh m?( bit cc phn ng xy ra hon ton.)Cu4: (2,25 im) Trn 300ml dung dch HCl (ddX) vi 500ml dung dch HCl (ddY) ta c dd Z. Cho dung dch Ztc dng10,53g km phn ng va .a- Tnh CM (Z)b- Dung dchX c pha t dung dch Y, bng cch pha thm nc vo dung dch Y theo t l: YO HVV2=12. Tnh CM ca ddX v dd Y?Cu5:(3,25im) Ho tan hon ton 5,5g hn hp gm Al v Fe bng dung dch HCl 14,6%thu c 4,48 lt hiro (o KTC).a- Tnh thnh % v khi lng ca mi kim loi trong hn hp.b- Tnh nng % cc mui c trong dung dich sau phn ng.( Na = 23; H = 1; O = 16; C = 12; Al = 27; Fe = 56; Cl = 35,5; Zn = 65)p n s 33 Trang 57 B dy hc sinh gii Trang 58Cu1: ( 1,5 im) Nu c cc c bn sau:- Trch cc mu th, dng que m cn tn than hng cho vo cc mu th+ Kh no lm que m bng chy, kh l O2.+ Nu que m tt l kh N2 v CO2.+ Nu que m tip tc chy l kh H2 v CH4.- phn bit 2 kh N2v CO2, dn ln lt mi kh qua dung dch nc vi trong, kh no lm nc vn c l kh CO2; kh cn li l N2 khng c hin tng g.- t chy 2 kh H2 v CH4, sau dn sn phm chy mi kh vo cc nc vi trong, cc no nc vn cth kh chy l CH4. PTHH: 2H2 + O2

0t2H2O CH4 + 2 O2 0tCO2+2H2O CO2 + Ca(OH)2 ->CaCO3 +H2OCu2: (1,0 im)- Dn hn hp kh CO2c ln kh CO; kh O2 qua dung dch Ca(OH)2 d. Kh CO2 b hp th, cn 2 kh CO v O2 thot ra ngoi. CO2 + Ca(OH)2 d ->CaCO3 + H2OLc ly kt ta, ra sch ri nung nhit cao ( 9000C) n khi lng khng i thu c kh CO2. CaCO3

0tCaO+ CO2Cu3:(2,0im)- n3 2CO Na = 10644 , 25=0,24 mol *nAl = 27mmol- Khi thm dd Na2CO3 vo cc ng dd HCl ( cc A) c phn ng: Na2CO3 +2HCl->2NaCl+CO2 + H2O1mol 1mol0,24mol -> 0,24molTheo nh lut bo ton khi lng, khi lng cc ng HCl tng thm:25,44- (0,24.44) = 14,88g- Khi thm Al vo cc ng dd H2SO4 c phn ng: 2Al+3 H2SO4->Al2 (SO4)3+ 3H22mol 3mol

27mmol->2 . 27. 3 mmol cn thng bng, khi lng cc ng H2SO4 cng phi tng thm 14,88g :m- 2 . 27. 3 m.2 = 14,88g ; 0,250,250,25 0,250,50,250,250,250,250,25 0,50,250,5 0,50,25 B dy hc sinh gii s 341) Hon thnh cc phng trnh phn ng sau ?Cho bit miphn ng thuc loi no ? V sao ?a) KMnO4 to? + ? + ?b) Fe + H3PO4? + ?c) S + O2

to?d) Fe2O3 + CO t0Fe3O4 + ?2) Mt oxit kim loi c thnh phn % khi lng ca oxi l 30%. Tm cng thc oxit bit kim loi c ho tr III ?3) Trong phng th nghim ngi ta iu ch oxi bng cch nhit phn KMnO4hoc KClO3. Hi khi s dng khi lng KMnO4v KClO3bng nhau th trng hp no thu c th tch kh oxi nhiu hn ? V sao ?4) t12,4(g) phtphotrongkhoxi. Sauphnngthuc21,3(g) iphtphopentaoxit. Tnh.a) Th tch kh O2 (ktc) tham gia phn ng) ?b) Khi lng cht rn thu c sau phn ng ?5) nhit 1000C tan ca NaNO3 l 180g, 200C l 88g. Hi c bao nhiu gam NaNO3 kt tinh li khi lm ngui 560g dung dch NaNO3 bo ho t 1000C xung 200C ?6) Cho X l hn hp gm Na v Ca. m1(g) X tc dng va vi V (l) dung dch HCl 0,5M thu c 3,36 (lt) H2(ktc). m2(g) X tc dng va vi 10,8 (g) nc. Tnh:a) T l khi lng m1/ m2 ?b) Nu cho m2 (g) X tc dng va vi V dung dch HCl th nng mol/ l ca dung dch HCl dng l bao nhiu ? Cho bitH = 1;N = 14; O = 16;Na = 23;Cl = 35,5; Ca = 40;Mn = 55;Fe = 56;Ba = 107 s 35Bi 1 (3,0im): Lp phng trnh ho hc ca cc s phn ng sau: Trang 59 B dy hc sinh gii1/ FeS2 + O2---->Fe2O3 + SO22/ KOH + Al2(SO4)3---->K2SO4 + Al(OH)33/ FeO + HNO3---->Fe(NO3)3 + NO + H2O4/ FexOy + CO---->FeO + CO25/ CxHyCOOH + O2---->CO2 + H2OBi 2 (3,0 im): Nu cc th d chng minh rng oxi l mt n cht phi kim rt hot ng (c bit nhit cao). Trn c s hy so snh vi tnh cht ho hc c bn ca n cht hiro. Vit phng trnh minh ho.Bi 3(3,0 im): Cho cc oxit c cng thc sau: SO3, Fe2O3, K2O, N2O5, Mn2O7, NO.1/ Nhng oxit no thuc loi oxit axit, oxitbaz? v sao?2/ c tn tt c cc oxit. Vit cng thc cu to ca cc oxit axit.Bi 4(3,0 im): Dn t t 8,96 lt H2 (ktc) qua m gam oxit st FexOy nung nng. Sau phn ng c 7,2 gam nc v hn hp A gm 2 cht rn nng 28,4 gam (phn ng xy ra hon ton).1/ Tm gi tr m?2/ Lp cng thc phn t ca oxit st, bit A c cha 59,155% khi lng st n cht.Bi 5 (4,0 im): 17,92 lt hn hp X gm hiro v axetilen C2H2 (ktc) c t khi so vi nit l 0,5. t hn hp vi 51,2 gam kh oxi. Phn ng xong, lm lnh hi nc ngng t ht c hn hp kh Y.1/ Vit phng trnh ho hc xy ra.2/ Xc nh % th tch v % khi lng ca Y.Cho: Fe = 56; Al = 27; Mg = 24; Zn = 65; C =12; O = 16 s 36Bi 1:1) Cho cc PTHH sau PTHH no ng, PTHH no sai? V sao?a) 2 Al +6 HCl2 AlCl3+3H2 ;b)2 Fe +6 HCl 2 FeCl3+3H2c)Cu+2 HCl CuCl2 +H2 ; d) CH4+ 2 O2 SO2 +2 H2O 2) Chn cu pht biu ng v cho v d:a) Oxit axit thng l oxit ca phi kim v tng ng vi mt axit.b) Oxit axit l oxit ca phi kim v tng ng vi mt axit.c) Oxit baz thng l oxit ca kim loi v tng ng vi mt baz.d) Oxit baz l oxit ca kim loi v tng ng vi mt baz.3)Hon thnh cc PTHH sau: Trang 60 B dy hc sinh giia)C4H9OH+O2 CO2 + H2O; b)CnH2n - 2+ ? CO2 + H2Oc)KMnO4 + ?KCl+ MnCl2 + Cl2 + H2O d)Al+H2SO4(c, nng) Al2(SO4)3+SO2 + H2OBi 2: Tnh s mol nguyn t v s mol phn t oxi c trong 16,0 g kh sunfuric. (gi s cc nguyn t oxi trong kh sunfuric tch ra v lin kt vi nhau to thnh cc phn t oxi). Bi 3: t chy hon ton kh A cn dng ht 8,96 dm3kh oxi thu c 4,48 dm3 kh CO2 v 7,2g hi nc.a) A do nhng nguyn t no to nn? Tnhkhi lng A phn ng.b) Bit t khi ca A so vi hiro l 8. Hy xc nh cng thc phn t ca A v gi tn A.Bi 4:Cho lung kh hiro i qua ng thu tinh cha 20 g bt ng(II) oxit 400 0C. Sau phn ng thu c 16,8 g cht rn.a) Nu hin tng phn ng xy ra.b) Tnh hiu sut phn ng.c) Tnh s lt kh hiro tham gia kh ng(II) oxit trn ktc.p n s 36Bi p n Thang im1(3)1(1)a) ng, v ng tnh cht 0,125 + 0125b) Sai, v P ny khng to ra FeCl3m l FeCl2 hay l sai 1 sn phm0,125 + 0125c) Sai, v khng c P xy ra 0,125 + 0125d) Sai, v C bin thnh S l khng ng vi L BTKL0,125 + 01252(1)a) . VD: Oxit do PK to nn l SO3tng ng vi axit H2SO4Oxit do KL trng thi ho tr cao to nn l CrO3 tng ng vi axit H2CrO40,25 + 0,25d) . VD: Na2O tng ng vi baz NaOH FeO tng ng vi baz Fe(OH)20,25 + 0,253(1)a) C4H9OH+ 6 O2 4 CO2 +5 H2O0,25b)2 CnH2n - 2+(3n 1) O2 2n CO2 + 0,25 Trang 61 B dy hc sinh gii2(n-1) H2Oc) 2 KMnO4+ 16 HCl 2 KCl+2 MnCl2 + 5 Cl2 + 8 H2O0,25d)2 Al+6 H2SO4(c, nng) Al2(SO4)3 +3 SO2 +6 H2O0,252(1)nSO3 = 16: 80 = 0,2 mol; nO= 0,2 .3 = 0,6 mol. 0,25 + 0,25C 2 O lin kt vi nhau to nn 1 O2=> 2 mol O ----------------------------1 mol O2 Vy: nO2 =(0,6.1): 2 =0,3 mol0,25 + 0,253(3)@-HD: c 6 ln x 0,5 = 3 .* S P chy:A+ O2 CO2 + H2O ; mO trong O2 = g 8 , 12 16 ). 2 .4 , 2296 , 8( ; * mO sau P= mO(trong CO2+ trong H2O) = g 8 , 12 16 ). 1 .182 , 7( 16 ). 2 .4 , 2248 , 4( +a)Sau phn ng thu c CO2v H2O => trc P c cc nguyn t C, H v O to nn cc cht P. Theo tnh ton trn:tng mO sau P = 12,8 g = tng mO trong O2. Vy A khng cha O m ch do 2 nguyn t l C v H to nn.mA P = mC + mH = g 2 , 3 1 ). 2 .182 , 7( 12 ). 1 .4 , 2248 , 4( +b) Ta c: MA = 8.2 = 16 g;t CTPT cn tm l CxHy vi x, y nguyn dngMA = 12x + y = 16g => phng trnh:12x + y = 16 (*)T l x: y= nC: nH= x 4 y41yxhay 4 : 1 8 , 0 : 2 , 0 ) 2 .182 , 7( : ) 1 .4 , 2248 , 4( > thay vo (*): 12x + 4x = 16 x= 1 => y = 4. Vy CTPT ca A l CH4, tn gi l metan.0,50,50,50,50,50,54(3) PTP: CuO +H2 C 4000 Cu+H2O ;a) Hin tng P: Cht rn dng bt CuO c mu en dn dn bin thnh mu (Cu) 0,50,5 Trang 62 B dy hc sinh giib) Gis20gCuOP ht thsauP s thuc g 168064 . 20cht rn duy nht (Cu) < 16,8 g cht rn thu c theo u bi => CuO phi cn d. - t x l s mol CuO P, ta c mCRsau P = mCu + mCuO cn d= x.64 + (mCuO ban u mCuO P) = 64x + (20 80x) = 16,8 g. => Phng trnh: 64x + (20-80x) =16,8 16x = 3,2 x= 0,2. => mCuO P = 0,2.80= 16 g Vy H = (16.100%):20= 80%.0,50,50,5c) Theo PTP: nH2=nCuO=x=0,2 mol. Vy: VH2= 0,2.22,4= 4,48 lt0,5 s 37Cu 1:(2 im)Trnh by phng php ho hc nhn bit cc cht ng ring bit trong cc trng hp sau a) Bn cht bt : Na2CO3, BaCO3, Na2SO4, BaSO4nu ch dng dung dch HClb) Hai cht kh : CH4 v C2H6 .c) Hai cht rn: Fe2O3 v Fe3O4 nu ch dng mt ho chtd) Nm dung dch: NaHSO4, KHCO3, Mg(HCO3)2, Na2SO3, Ba(HCO3)2 ch c dng cch un nngCu2:(2 im)a) Hy nu phng php thc nghim xc nh nng mol ca mi cht trong dung dch hn hp gm Na2CO3 v NaHCO3.b) Ti sao trong bnh cu ho ngi ta dng dung dch NaHCO3m khng dng NaHCO3 rn hoc Na2CO3 ? c) Trnh by s khc nhau v thnh phn khi lng v tnh cht gia hp cht ho hc v hn hp. Ly v d minh ho.d) Cho hn hp A gm Al; Fe2O3; Cu c s mol bng nhau vo dung dch HCl d.Vit cc phng trnh phn ng xy ra.Cu3: :(2 im)a) Tin hnh hai th nghim sau:- Th nghim1: Cho a gam bt st (d) vo V1 lt dung dch Cu(NO3)2 1M.- Th nghim2: Cho a gam bt st (d) vo V2 lt dung dch AgNO3 0,1 M.Sau khi cc phn ng xy ra hon ton, khi lng cht rn thu c hai th nghim u bng nhau. Thit lp mi quan h gia V1 vV2b) Cho mt lng bt km vo dung dch X gm FeCl2 v CuCl2. Khi lng cht rn sau khi cc phn ng xy ra hon ton nh hn khi lng bt km ban u l 0,5 gam. C cn phn dung dch sau phn ng thu c 13,6 gam mui khan. Tnh tng khi lng cc mui trong X. Trang 63 B dy hc sinh giic) t chy hon ton 1 th tch hn hp kh gm C2H2 v hyrocacbon X sinh ra 2 th tch kh CO2 v 2 th tch hi nc (cc th tch kh v hi o cng iu kin). Xc nh cng thc phn t ca X.Cu4: (2 im)Mt hn hp X gm mt kim loi M (c hai ho tr 2 v 3) v MxOy.Khi lng ca X l 80,8 gam. Ho tan ht X bi dung dch HCl thu c 4,48 lt H2 (ktc), cn nu ho tan ht X bi dung dch HNO3thu c 6,72 lt NO (ktc). Bit rng trong X c mt cht c s mol gp 1,5 ln s mol cht kia. Xc nh M v MxOyCu5: :(2 im)Ho tan hon ton a mol kim loi M bng dung dch H2SO4 c nng, thy tiu tn ht a mol H2SO4 thu c 1,56 gam mui A v kh A1. Lng kh A1 -c hp th hon ton bi 45 ml dung dch NaOH 0,2M to thnh 0,608 gam mui. Lng mui A thu c trn cho ho tan hon ton vo nc, sau cho thm 0,387 gam hn hp B gm Zn v Cu, sau khi phn ng xong tch c 1,144 gam cht rn C.a) Tnh khi lng kim loi M ban u.b) Tnh khi lng ca cc kim loi trong hn hp B v trong cht rn Cp n s 37Cu 1: 2 im (mi y ng 0,5 im)Cu 2: 2 im(mi y ng 0,5 im)Cu 3:2 im a, V1 = V2 (0,75 im) b, m = 13,1gam(0,5 im) c, Cng thc C2H6(0,75 im)Cu 4: 2 imTrng hp 1: nMxOy = 1,5 nM(1 im)M: Fe, MxOy: Fe3O4Trng hp 2: nM = 1,5 nMxOy: Loi(1 im)Cu 5:2ima, (M l Ag) mM = 1,08 gam(0,5im)Trng hp 1: Zn phn ng ht b, Trong B: Khi lng Zn: 0,195 gam Khi lng Cu: 0,192 gam(0,5 im)Trong C: Khi lng Ag: 1,08 gam Khi lng Cu: 0,064 gam(0,5 im)Trng hp 2: Zn phn ng cha ht: Loi(0,5 im) s 38Cu1 : Nhng hin tng no sau y tng ng vi hin tng vt l ( V) v hin tng ho hc ( H)1. S bin i trng thi ca mt cht 6. Stothnhkt tadung dch 2. S bc mi 7. S bin di mu sc Trang 64 B dy hc sinh gii3. S bin i hnh dng 8. S thot kh4. S bin i phn tn9. S to nhit5. Sthnghoa(Trngthi rn sag trng thi hi) 10. S bin i th tchCu 2: Dy hp cht no trong cc hp cht di y c sp xp theo th t tng dn ca khi lng mola) NaOH; CaO ; MgCl2 ; Cu(OH)2b) NaOH; MgCl2 ; CaO; Cu(OH)2c) CaO; MgCl2;NaOH; Cu(OH)2d) Cu(OH)2; MgCl2; CaO;NaOHCu3:Hotanht3.25gkmbngdungdchHCl thucquabnh ng CuO ( d) , un nng . Phn ng xy ra theo phng trnh :H2 + CuO Cu + H2OTnh s gam Cu to thnhCu 4:t chy ht m gam cht A cn 62.7 (l) kh Oxi ( ktc) thu c 8.8 g CO2v 5.4 g H2O . Tm CTPT ca A bit t khi hi ca A i viHiro bng 23 s 39Cu 1: a: S chy v s oxi ho chm c g ging v khc nhau dn ra 1 v d v s oxi ho v s chy .b:Nhngmchbngxngducthdngncdpttschykhngvsao?Cu 2: Lp cng thc ho hc ca cc hp cht gm K, Ca, H via; Oxi b; Cl c; Nhm OH, nhm SO4Vit tnmi cht v chobit cht thuc loi hpcht oxit, axit, baz, mui.Cu 3; Vit PTPth hin dy bin ho sau v cho bit thuc loi phn ng noKClO3 O2 Fe3O4 Fe FeCl2Cu 4 : Cho 8,3 g hn hp gm Fe , Al tc dng vi dung dch HCl d sau khi phn ng kt thc thu c 5,6 lt kh H2 (ktc)a; Vit PTP sy rab: Tnh % v khi lng ca mi kim loi trong hn hpc: Bnh ng dung dch HCl tng hay gim bao nhiuCu 5; Xc nh cng thc ho hc ca hp cht A bit thnh phn % ca cc nguyn t l ; 32,39% Na, 22,53% S, 45,08% O( Bit Fe = 56, Al = 27, Na = 23, S = 32 , O = 16 ) s 40 Trang 65 B dy hc sinh giiCu I :( 1,5 im )Lp cng thc ho hc ca A , B , C bit :A to bi 2 nguyn t C v H , trong H chim 25% v khi lng . 0o C 760 mmHg , 1lt kh A c khi lng l 0,7142g .B l oxit mt kim loi ho tr III . Dng C0 kh hon ton 16g B thu c 11,2g kim loi .t chy hon ton 6,8g Dthu c 12,8g kh sunfur ( S02) v 3,6g hi nc .Cu II : ( 4 im )1 . Vit phng trnh phn ng gia kh oxi vi cc cht sau : Na , Zn , C , N Ca ? cho bit trong sn phm cc nguyn t c ho tr ln lt l : Na (I) ,Zn (II) , C (IV) , N (V) , Ca (II) .2. Tnh thnh phn , phn trm theo khi lng ca Fe trong cc oxit sau : Fe0 , Fe203 , Fe304 ? Cu III :( 2,5 im )Ngi ta t lu hunh trong mt bnh cha 10g oxi , sau phn ng ngi ta thu c 12,8g kh sunfur S02.a . Tnh khi lng lu hunh chy .b . Tnh khi lng oxi cn tha sau phn ng .Cu IV :( 2 im )Hn hp X gm Fe v Fe304 c chia lm 2 phn bng nhau :phn 1 : Oxi ho nhit cao thu c 58gam Fe304 .phn 2 : Cho kh C0 i qua khi nung nng n khi phn ng va thu c 8,96 lt C02 thot ra KTC . tnh khi lng hn hp X v thnh phn % v khi lng ca hn hp X .( cho nguyn t khi ca cc cht ln lt l : Fe = 56 ; 0 =16 ; S = 32 ; H = 1 ; C = 12 )p n s 40Cu 1(1,5 )- A c CTHH l : CH4- B c CTHH l : Fe203- C c CTHH l :H2SLu : hc sinh c th gii theo nhiu cch khc nhau , nu gii ng vn cho im ti a .cu ng c 0,5Cu 2( 4 )1 . Cc phng trnh phn ng xy ra l :4Na + 02--> 2Na202Zn + 02 ---> 2Zn0C + 02 ---> C024N + 5 02 ---> 2N2052Ca + 02 ----> 2Ca02 . Fe0 : %Fe = 78 %Fe203 : % Fe = 70%Fe304 : %Fe = 72,4%Cu 3( 2,5 )-Theo bi ra ta c s mol ca kh S02l :nS02 = 12,8 : 64 = 0,2 ( mol )-Ta c phng trnh phn ng :S + 02-> S021mol 1mol 1mol Trang 66 B dy hc sinh gii0,2mol 0,2mol 0,2mol-a) vy ta c khi lng ca S l :ms = ns . Ms = 0,2 . 32 = 6,4 ( gam )-b ) theo phng trnh phn ng ta c :+ s mol 02 phn ng l : n02 = nS02= 0