1011251290661340Vijaya Bank Clerk Exam

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    VIJAYA BANK CLERK EXAM, 7-2-2010

    ANSWERS1.(4) 2.(4) 3.(3) 4.(2)

    5.(2) 6.(2) 7.(4) 8.(3)9.(1) 10.(5) 11.(3) 12.(3)13.(3) 14.(5) 15.(2) 16.(3)17.(5) 18.(4) 19.(5) 20.(4)21.(3) 22.(2) 23.(3) 24.(2)25.(2) 26.(4) 27.(4) 28.(1)29.(2) 30.(4) 31.(4) 32.(I)33.(3) 34.(4) 35.(2) 36.(3)37.(5) 38.(4) 39.(4) 40.(1)41.(2) 42.(5) 43.(4) 44.(4)45.(3) 46.(1) 47.(3) 48.(1)49.(2) 50.(5) 51.(2) 52.(1)53. (1) 54.(2) 55.(3) 56.(5)57.(1) 58.(4) 59.(1) 60.(5)61.(4) 62.(3) 63.(4) 64.(2)65.(5) 66.(2) 67.(4) 68.(4)69.(3) 70.(2) 71.(4) 72.(2)73.(2) 74.(1) 75.(3) 76;(3)77.(2) 78.(3) 79.(2) 80.(5)81.(3) 82.(5) 83.(2) 84.(5)85.(3) 86.(5) 87.(3) 88.(4)89.(3) 90.(1) 91.(1) 92.(2)93.(4) 94.(2) 95.(3) 96.(1)97.(2) 98.(1) 99.(2) 100.(5)101.(3) 102.(2) 103.(1) 104.(4)105.(1) 106.(4) 107.(3) 108.(2)109.(3) 110.(4) 111.(2) 112.(1)113.(4) 114.(1) 115.(4) 116.(3)117.(2) 118.(3) 119.(3) 120.(4)121.(2) 122.(3) 123.(4) 124.(1)125.(5) 126.(1) 127.(3) 128.(4)129.(2) 130.(5) 131.(4) 132.(1)133.(2) 134.(3) 135.(1) 136.(3)137.(2) 138.(1) 139.(4) 140.(2)141.(5) 142.(1) 143.(3) 144.(2)145.(4) 146.(1) 147.(4) 148.(5)149.(2) 150.(3) 151.(2) 152.(2)153.(4) 154.(4) 155.(3) 156.(2)

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    157.(3) 158.(4) 159.(5) 160.(5)161.(1) 162.(3) 163.(4) 164.(4)165.(2) 166.(2) 167.(3) 168.(1)169.(3) 170.(3) 171.(3) 172.(2)173.(4) 174.(5) 175.(4) 176.(2)177.

    (1)

    178.(3)

    179.(3)

    180.(4J.

    181.(5) 182.(4) 183.(2) 184.(1)185.(5) 186.(2) 187.(1) 188.(3)189.(5) 190.(4) 191.(3) 192.(2)193.(4) 194.(3) 195.(4) 196.(1)197.(1) 198.(5) 199.(4) 200.(5)

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    EXPLANATIONS

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    (23 - 28) :{i) All coins are glasses Universal Affirmative (A-type)

    (ii) Some glasses are cups Particular Affirmative (I-type)

    (iii) No man is tiger > Universal Negative (E-type)(iv) Some men are not tigers > Particular Negative (O-type)

    23. (3) Some cups are boxes.

    All boxes are pins.

    I+A=>ItypeofConclusion"Somecupsarepins"ThisisConclusionIII.

    24.(2)Somepensarepencils.

    All Pencils are caps.

    I + A.=> I-type of Conclusion "Some pens are caps".

    All pencils are caps.

    Allcapsarebuses.

    A+A=>AtypeofConclusion"Allpencilsarebuses"

    SomePensareCaps.

    All caps are buses.I+A=ItypeofConclusion"Somepensarebuses".ThisisConclusionII.

    25. (2) All shirts are skirts.

    All skirts are banks.A+A=AtypeofConclusion"Allshirtsarebanks".

    All shirts are Banks.

    All banks are roads.

    A + A => A-type of Conclusion"All skirts are roads".

    All banks are roads.

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    All roads are brushes.

    A+A => A-type of Conclusion All banks are brushes.

    All Shirts are banks.

    Allbanksareroads.

    A+A => A-type of Conclusion All shirts are roads.

    All shirts are roads.

    All roads are brushes

    A+A => A-type of Conclusion All shirts are Brushes .

    Conclusion III is Converse of it.

    26.

    (4) Some spoons are plants.

    All Plants are crows.

    I+A=> I-type of Conclusion Some spoons are crows.

    Conclusion II is Converse of it.

    Conclusion III is Converse of the third Premise.

    27. (4) Some hens are ducks.

    All ducks are pigeons.

    I+A=>I-type Conclusion"Somehensarepigeons".

    All ducks are pigeons.

    All pigeons are sparrows.

    A+A=> A-type of Conclusion All ducks are sparrows.

    This is Conclusion I

    Some hens are pigeons.

    All pigeons are sparrows.

    A+A =>A-type of Conclusion Some hens are sparrows.

    Some hens are pigeons .

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    All pi eons are sp rrows.

    I+A => I-type of C nclusion Some hens ar Sparrows

    Conclusion III is converse of it.

    28. 1) No tige

    29. (2)L %O

    MTheCon

    ./1.II.III.IV.

    30. (4)B $CD

    TheCon

    I. DII.III.IV.

    31.(4)p @R S %TheCon

    I. RII. S

    III.IV.

    32. ( 1

    H

    I $J @The

    Somecariscat.tsarelions.

    E+1=>01,typeofCon

    L => KLO => L < OM => O = M

    * N = * M Nrefore, K Lclusions:

    O => N $ L => M >* N => K @ N => L =

    * B => A BC => B > CD => C < DE => D Eefore, A B >clusions:$ A = > D > A$ D => B > D% C => E A =

    $ P => F > PR => P = RS => R ST S < Tefore, F > Pclusions:% F => R < F* P => S,P :

    T => P % F => S H I

    J=> I > JK => J = Kefore, G < H

    clusion'Somelionsare n ttigers

    Q = M N

    : True: True

    N : Not trueN : Not true

    C < D E

    : Not true: Not true: Not true

    E : Not true

    R S < T

    : Truerue

    : Not true: True

    < H

    I > J = K

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    Con

    I. Gclusions:

    II.% I => G < I : True

    I I I% J G < J :

    IV.

    . K $ I = > K >ot trueI : Not true

    J : Not true J => H

    33.(3) @ W => V = W

    W

    X *X => W x y

    TheZ => Y > Z

    Con

    efore, V = W X Y > Z

    I. Zclusions:

    II. YX = > Z > X : Not true

    III. V => Y

    IV.% Y => W

    V : Not true

    @ W => Y< Y : True= W : Not true

    34. (4)

    35. (2)

    36. (3)

    37. (5)38. (4)39. (4)40. "(1

    41. (2)

    Except in A E

    B is between

    G and F are si

    A is third to t

    G is to the im

    D is to the im

    ) C is to the i

    The followin

    (l)to(2)

    F, in all other

    and E.

    ting between

    he right of E.

    mediate right

    mediate left o

    mediate left

    changes occ

    (2) to (3)

    the arrangement is anticloc wise.

    and D.

    of A.

    B.

    f H.

    r in the subse uent figures :

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    42.(5)hal

    he design 'P'

    diag

    43. (4)Protinu

    44. (4)

    pairdesirowposicont

    45. (3)

    inte46. (1) F

    (3) t47. (3) F

    of eand

    48. (1)andfro

    49. (2)

    (3) t50. (5) F

    clocdesi

    51. (2) 2

    =>=>

    52.(1)

    =

    . step in anticescends step

    onally downw

    From Problelem Figure (2d in the subse

    From Probleof adjacent d

    gn of the midinterchange

    tion while theinued in the s

    rom Problemchange positi

    rom Problemhe entire desi

    rom Problemach column infrom Problem

    rom Problemthe left desigProblem Fig

    rom Problemo (4) and from

    rom Problemkwise directiogns (A) and [

    6 x 451 - ? = 6

    11726-7 = 610= 11726 - 61

    =963-6=9

    957* =478

    = ==5*5=25

    ockwise direcise and ascen

    ard and upwar

    Figure (1) to) to (3) the lequent figures

    Figure (1) toesigns of thele row moveositions. Frotwo pairs ofme order in th

    Figure (1) tons. Similar ch

    Figure (1) to (n rotates thro

    igure (1) to (terchange posFigure (5) to'

    Figure (1) tos move to there (3) to* (4)

    Figure (1) toProblem Fig

    igure (1) to (. From Probl] interchange

    103

    303 = 5623

    7

    5

    5

    tion and rotates in one step

    d respectively

    (2) the two pt most designlternately.

    (2) the rightiddle and loto the left mProblem Fi

    djacent desige subsequent

    (2) the line sanges occur fr

    2) the left andgh 90 anticlo

    ) the two coltions so as thnswer Figure.

    2) the rightmoright side an

    arid from Prob

    (2) the designre (5) to Ans

    ) the centralm Figure (2)

    positions. The

    s through 90fter being rot

    and is replace

    irs of designsof both the r

    ost design oer rows interc

    ost positionure (3) to (4)s of the uppeigures.

    egments movom Problem F

    the right desickwise. These

    mns of desigtwo middle

    st designs moall the three

    lem Figure (5

    are arrangeder Figure.

    esign is replao (3) the lowese two steps ar

    anticlockwiseted through 9

    with a new d

    , situated alonows move to t

    f the upper rohange positiohile the twothe rightmosand middle r

    to the opposigure (3) to (4

    ns are replacetwo steps are

    s interchangeesigns. Simil

    e to the left sdesigns are reto Answer Fi

    in reverse or

    ed with a ner left designe continued al

    after every tw clockwise.

    esign in each

    g the two diahe right most

    moves to ths. From Problairs of adjacedesign of th

    ows interchan

    ite side diagoand from Pro

    d with new dcontinued alte

    positions. Simr changes oc

    ide after beingplaced with ngure.

    er. Similar- c

    design and aloves diagonalernately in th

    figures. Thehe arrow mo

    ubsequent fighird design m

    esoves

    re.

    onals interchposition. Thes

    nge positions.e two steps ar

    Frome con-

    e left most poem Figure (2)nt designs oflower row m

    ge positions.

    sition while tto (3) the righthe upper andoves to the lehese three ste

    e twot mostlower

    ftmostps are

    nally and theblem Figure (

    two middle d) to Answer F

    esignsigure.

    signs. From Prnately in the s

    roblem Figureubsequent fig

    (2) tores.

    ilarly, th^ uppur from Probl

    er and lower dem Figure (3)

    esignsto (4)

    rotated throuw designs. Si

    h 90 anticlomilar changes

    kwiseoccur

    anges occur from Problem Figure

    the four desily to the upper

    subsequent fi

    ns move oneright corner a

    gures.

    tep innd the

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    53. ( 1 ) ? = 11797 - 3695 = 8102

    54.(2) (12.25 x 4.02 - 14.26) x ? = 699.7

    => (49.245 - 14.26) x ? = 699.7 => 34.985 x? = 699.7

    => 34.985*? =699.7

    >? =.

    .

    =20=

    55. (2) (12.25 * 4.02-14.26)*? = 699.7

    (49.245-14.26)* ? = 699.7 34.985 * ?= 699.7

    . ?

    .= = 20

    55. (3) +? 2 = 61.28

    => 25.28 +?

    2

    = 61.28

    =>? 2 = 61.28 -25.28 = 36

    =>? = = 6

    56?

    .(5) = 311.88

    ? = .

    = 69

    .

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