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8/13/2019 126717676 Tank Heat Calculation
1/7
Job ID: Client :
Title: Tank coil design calculation Item No:1 Tank dia m 74.5
2 Tank height m 20
3
4 Shell Surface area m2 4680.97
5 = Shell Surface area ft2 50385.57
6 Roof surface area m2 4359.16
7 = Roof surface area ft2 46921.57
8
9
10 Minimum ambient temp deg C 18 64.4 F
11 Temperature of Insulation surface 22.89468104 73.210426 F
12 Product temperature deg C 65 149 F
13 Steam inlet temperature deg C 158 316.4 F
14
15 Surface temperature Calculation:
16 Heat transfer coefficient in surrounding h 1.43371 BTU/hr(ft)^2.F
17 Thickness of insulation(mineral wool) x 0.15 ft
18 Thermal conductivity of insulation k 0.025 BTU/hr(ft).F
19 (x/k)*h 8.60226
20 Surface temperature deg C 22.89468104 73.21043 F
21
22 Steam pressure kg/cm2g 4.8
23 Steam pressure kg/cm2A 5.833 82.964661 psia
24 Steam saturation temperature 315.00 Deg F
25 Enthalpy of superheated steam at supply conditions = 1183.80 BTU/lb waspwin software
26 Enthalpy of saturated steam at supply pressure = 1183.80 BTU/lb waspwin software
27 Enthalpy of saturated condensate at supply pressure 284.80 BTU/lb waspwin software
28 Heat available per lb of steam = 899.00 BTU/lb
29 Specific volume of superheated steam = 5.28541 ft3/lb waspwin software
30 Specific volume of condensate = 0.01760 ft3/lb waspwin software
31
32
33 CRUDE specific gravity 0.9
34
35 Heat loss from shell
36 hc = 0.3 Dt 0.25
37 delta t F 8.810425879
38 hc 0.516857092 BTU/hr(ft)^2.F
39 Calculation of radiation coeff - hr
40 hr = 0.173 e [( T1abs/100)^4 - ( T2abs/100)^4]/(T1abs-T2abs)
41 T1abs = 533.2104259 Rankine
42 T2abs = 524.4 Rankine
43 e = 0.8
44 hr = 0.818678533 BTU/hr(ft)^2.F
45 hc + hr = 1.335535625 BTU/hr(ft)^2.F
46 Shell Heat Loss Q = (hc+hr)ADt = 592868.7985 BTU/hr
47
48 Heat loss from roof
49 hc = 0.38 delta t^0.25 0.65468565 BTU/hr(ft)^2.F
50 hr (remains same) = 0.818678533 BTU/hr(ft)^2.F
51 hc+hr = 1.473364183 BTU/hr(ft)^2.F
52 Roof Heat Loss Q = (hc+hr)ADt = 609087.2542 BTU/hr
53
54 Combined heat loss from shell and roof
55 Qc = 1201956.053 BTU/hr
56 Add 20% for combined losses from appurtenences and tank bottom
57 and to take care of wind effects.
58 Total Heat Loss = 1442347.263 BTU/hr
59
Date Date
Description
PROCESS CALCULATION SHEET Document No:
8/13/2019 126717676 Tank Heat Calculation
2/7
Job ID: Client :Title: Tank coil design calculation Item No:
1 Steam flow rate
2 Steam required for maintaning tank temp 1604.390727 lb/hr
3 Steam required for maitening tank temp 727.7402576 kg/hr
4 Steam volume flow rate ( at inlets) 8479.86642 ft3/hr
5 Steam volume flow rate ( at inlets) 357.3771185 m3/hr
6 Number of inlets 2
7 Flow per pipe 178.6885593 m3/hr
8 Pipe ID 0.053 m
9 Pipe c/s area 0.002206183 m2
10 Steam velocity at inlets 22.49845139 m/s
11
12 Thermal calculations
13
14 Crude side convection coefficient
15
16 Neglecting metal tube resistance and neglecting steam superheat
17 Hot surface temperature Th = 315.00 F
18 Cold liquid temperature Tc = 149 F
19 Temperature Difference Dt = 166.00 F
20 Film temperature tf = 232.00 F
21 Pipe OD do = 2.4 inches
22 For a 2" pipe area per ft length 0.62832 ft2/ft
23
24 VGO Properties at film temperature25
26 Thermal Conductivity of VGO k = 0.067 BTU/hr(ft)2(F/ft)
27 VGO Density r = 55.62 lb/ft3
28 acceleration of gravity g = 416687846 ft / hr^2
29 VGO Specific heat c = 0.52 btu/lb/deg F
30 Coeff. of thermal expansion b = approx 0.004310345 1/F
31 Viscosity m =( 12 centistokes x 0.84 ) = 27 Centipoises
32
33 hc= 116 (( k^3 r^2 c b / m) ( Dt/do))^0.25 = 31.361 BTU/hr(ft)2F
34
35 Steam side heat transfer coefficient
36 h(m^2/(k^3 r^2 g))^(1/3) = 1.51 ( 4 G / m)^ ( -1/3) 12.40 pp 265, 269 12.4537
38 No of pipes per tank Nt = 2
39 Assume each pipe length L = 100 ft
40 Total condensate load W = 1604.390727 lb/hr
41 Condensate Loading G = W/(0.5 L Nt ) = 16.04390727 lb/hr/ft
42
43
44 Condensate properties at condensing temperature
45 Viscosity m = 0.463 lb/ft/hr waspwin software
46 thermal conductivity k = 0.3973 Btu/hr/ft2/(F/ft) waspwin software
47 density r = 57.619 lb/ft3 waspwin software
48 acceleration of gravity g = 416687846 ft / hr^2
49
50 1.51 ( 4 G / m ) (-1/3) = 0.291774432
51 ( m^2/(k^3 r^2 g) )^(1/3) = 0.000135193
52 Condensing film coeff h = 2158.204 Btu/hr/ft2/F
53 Pipe OD 2.4 inches
54 Pipe ID 2.09 inches
55 hio = h ( ID / OD ) 1879.43627 Btu/hr/ft2/F
56
Date Date
Description
Made by / Revised by
PROCESS CALCULATION SHEET Document No:
0
8/13/2019 126717676 Tank Heat Calculation
3/7
Job ID: Client :
Title: Tank coil design calculation Item No:
1 Overall Heat Transfer
2 VGO side ho = 31.361 Btu/hr/ft2/F
3 Steam side hio = 1879.43627 Btu/hr/ft2/F
4 Clean coeff Uc = hio ho /( hio + ho ) = 30.84641207 Btu/hr/ft2/F
5 Fouling factor Rd = 0.004
6 Dirty Coeff UD = ( Uc / Rd ) / ( Uc + 1/Rd ) 27.45843524 Btu/hr/ft2/F
7 Area A = Q/ ( UD Dt ) = 316.4360554 ft2
8 Total pipe length per tank 503.6236239 ft
9 No of pipes per tank Nt = 2
10 Length of each pipe 251.811812 ft
11
12 Length of each pipe 76.75224029 m
13 No of pipes per tank 2
14 Total pipe length per tank 153.5044806 m
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34 RESULTS:35
36 Total Heat Loss = 1442347.263 BTU/hr
37
38 Steam required for maintaining tank temp 727.7402576 kg/hr
39
40 Total pipe length required 153.5044806 m
41
42
43
44
45
46
47
48
49
50
Date Date
Description
Made by / Revised by
Checked by
Approved by
0
PROCESS CALCULATION SHEET Document No:
8/13/2019 126717676 Tank Heat Calculation
4/7
Job ID: Client :Rev.
Title: Tank coil design calculation Item No:1 Tank dia m 74.5
2 Tank height m 20
3
4 Shell Surface area m2 4680.97
5 = Shell Surface area ft2 50385.57
6 Roof surface area m2 4359.16
7 = Roof surface area ft2 46921.57
8
9
10 Minimum ambient temp deg C 18 64.4 F
11 Temperature of Insulation surface 22.89468104 73.210426 F
12 Product temperature deg C 65 149 F
13 Steam inlet temperature deg C 158 316.4 F
14
15 Surface temperature Calculation:
16 Heat transfer coefficient in surrounding h 1.43371 BTU/hr(ft)^2.F
17 Thickness of insulation(mineral wool) x 0.15 ft
18 Thermal conductivity of insulation k 0.025 BTU/hr(ft).F
19 (x/k)*h 8.60226
20 Surface temperature deg C 22.89468104 73.21043 F
21
22 Steam pressure kg/cm2g 4.8
23 Steam pressure kg/cm2A 5.833 82.964661 psia
24 Steam saturation temperature 315.00 Deg F
25 Enthalpy of superheated steam at supply conditions = 1183.80 BTU/lb waspwin software
26 Enthalpy of saturated steam at supply pressure = 1183.80 BTU/lb waspwin software
27 Enthalpy of saturated condensate at supply pressure 284.80 BTU/lb waspwin software
28 Heat available per lb of steam = 899.00 BTU/lb
29 Specific volume of superheated steam = 5.28541 ft3/lb waspwin software
30 Specific volume of condensate = 0.01760 ft3/lb waspwin software
31
32
33 CRUDE specific gravity 0.9
34
35 Heat loss from shell
36 hc = 0.3 Dt 0.25
37 delta t F 8.810425879
38 hc 0.516857092 BTU/hr(ft)^2.F
39 Calculation of radiation coeff - hr
40 hr = 0.173 e [( T1abs/100)^4 - ( T2abs/100) 4]/(T1abs-T2abs)
41 T1abs = 533.2104259 Rankine
42 T2abs = 524.4 Rankine
43 e = 0.8
44 hr = 0.818678533 BTU/hr(ft)^2.F
45 hc + hr = 1.335535625 BTU/hr(ft)^2.F
46 Shell Heat Loss Q = (hc+hr)ADt = 592868.7985 BTU/hr
47
48 Heat loss from roof
49 hc = 0.38 delta t^0.25 0.65468565 BTU/hr(ft)^2.F
50 hr (remains same) = 0.818678533 BTU/hr(ft)^2.F
51 hc+hr = 1.473364183 BTU/hr(ft)^2.F
52 Roof Heat Loss Q = (hc+hr)ADt = 609087.2542 BTU/hr
53
54 Combined heat loss from shell and roof
55 Qc = 1201956.053 BTU/hr
56 Add 20% for combined losses from appurtenences and tank bottom
57 and to take care of wind effects.
58 Total Heat Loss = 1442347.263 BTU/hr
59
Date Date
Description Sht
PROCESS CALCULATION SHEET Document No:
8/13/2019 126717676 Tank Heat Calculation
5/7
Job ID: Client :Rev.
Title: Tank coil design calculation Item No: 0
1 Steam flow rate
2 Steam required for maintaning tank temp 1604.390727 lb/hr
3 Steam required for maitening tank temp 727.7402576 kg/hr
4 Steam volume flow rate ( at inlets) 8479.86642 ft3/hr
5 Steam volume flow rate ( at inlets) 357.3771185 m3/hr
6 Number of inlets 2
7 Flow per pipe 178.6885593 m3/hr
8 Pipe ID 0.053 m
9 Pipe c/s area 0.002206183 m2
10 Steam velocity at inlets 22.49845139 m/s
11
12 Thermal calculations
13
14 Crude side convection coefficient
15
16 Neglecting metal tube resistance and neglecting steam superheat
17 Hot surface temperature Th = 315.00 F
18 Cold liquid temperature Tc = 149 F
19 Temperature Difference Dt = 166.00 F
20 Film temperature tf = 232.00 F
21 Pipe OD do = 2.4 inches
22 For a 2" pipe area per ft length 0.62832 ft2/ft
23
24 VGO Properties at film temperature25
26 Thermal Conductivity of VGO k = 0.067 BTU/hr(ft)2(F/ft)
27 VGO Density r = 55.62 lb/ft3
28 acceleration of gravity g = 416687846 ft / hr^2
29 VGO Specific heat c = 0.52 btu/lb/deg F
30 Coeff. of thermal expansion b = approx 0.004310345 1/F
31 Viscosity m =( 12 centistokes x 0.84 ) = 27 Centipoises
32
33 hc= 116 (( k^3 r^2 c b / m) ( Dt/do))^0.25 = 31.361 BTU/hr(ft)2F
34
35 Steam side heat transfer coefficient
36 h(m^2/(k^3 r^2 g))^(1/3) = 1.51 ( 4 G / m)^ ( -1/3) 12.40 pp 265, 269 12.4537
38 No of pipes per tank Nt = 2
39 Assume each pipe length L = 100 ft
40 Total condensate load W = 1604.390727 lb/hr
41 Condensate Loading G = W/(0.5 L Nt ) = 16.04390727 lb/hr/ft
42
43
44 Condensate properties at condensing temperature
45 Viscosity m = 0.463 lb/ft/hr waspwin software
46 thermal conductivity k = 0.3973 Btu/hr/ft2/(F/ft) waspwin software
47 density r = 57.619 lb/ft3 waspwin software
48 acceleration of gravity g = 416687846 ft / hr^2
49
50 1.51 ( 4 G / m ) (-1/3) = 0.291774432
51 ( m^2/(k^3 r^2 g) )^(1/3) = 0.000135193
52 Condensing film coeff h = 2158.204 Btu/hr/ft2/F
53 Pipe OD 2.4 inches
54 Pipe ID 2.09 inches
55 hio = h ( ID / OD ) 1879.43627 Btu/hr/ft2/F
56
Date Date
Description Sht
Made by / Revised by 2
PROCESS CALCULATION SHEET Document No:
0
8/13/2019 126717676 Tank Heat Calculation
6/7
Job ID: Client : Rev.
Title: Tank coil design calculation Item No: 0
1 Overall Heat Transfer
2 VGO side ho = 31.361 Btu/hr/ft2/F
3 Steam side hio = 1879.43627 Btu/hr/ft2/F
4 Clean coeff Uc = hio ho /( hio + ho ) = 30.84641207 Btu/hr/ft2/F
5 Fouling factor Rd = 0.004
6 Dirty Coeff UD = ( Uc / Rd ) / ( Uc + 1/Rd ) 27.45843524 Btu/hr/ft2/F
7 Area A = Q/ ( UD Dt ) = 316.4360554 ft2
8 Total pipe length per tank 503.6236239 ft
9 No of pipes per tank Nt = 2
10 Length of each pipe 251.811812 ft
11
12 Length of each pipe 76.75224029 m
13 No of pipes per tank 2
14 Total pipe length per tank 153.5044806 m
15
16
17
18
19
20
2122
23
24
25
26
27
28
29
30
31
32
33
34 RESULTS:35
36 Total Heat Loss = 1442347.263 BTU/hr
37
38 Steam required for maintaining tank temp 727.7402576 kg/hr
39
40 Total pipe length required 153.5044806 m
41
42
43
44
45
4647
48
49
50
Date Date
Description Sht
Made by / Revised by 3
Checked by of
Approved by 3
0
PROCESS CALCULATION SHEET Document No:
8/13/2019 126717676 Tank Heat Calculation
7/7
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