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16. Cuttings Transport - Slip Velocity

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1

PETE 411

Drilling Engineering

Lesson 16

- Lifting Capacity of Drilling Fluids -- Slip Velocity -

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2

Lifting Capacity of Drilling Fluids

 - Slip Velocity -

 Fluid Velocity in Annulus

 Particle Slip Velocity

 Particle Reynolds Number  Friction Coefficient

 Example

 Iterative Solution Metod

 Alternative Solution Metod

 API RP !"# Metod

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3

Read:  ADE, Ch. 4 - all

HW #8:  Due 10-14-05 

Quiz A 

Thursday, Oct. 11, 6 - 8 p.m. Rm. 101

!"sed ""$ 

1 %&uati"' sheet a!!"(ed, 8 1)*+ 11+ "th sides/

OT%: Quiz A*002 a'd the s"!uti"'

are "' the (e 3 

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4

Lifting Capacity of Drilling Fluids

Historically$ %en an operator felt tat

te ole %as not bein& cleared of cuttin&s

at a satisfactory rate$ e %ould'

Increase te circulation rate 

(ic)en te mud  *increase +P,PV-

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5

Lifting Capacity of Drilling Fluids

  ore recent  analysis so%s tat'

 (urbulent flo% cleans te ole better.

 Pipe rotation aids cuttin&s removal.

 /it %ater as drillin& fluid$ annularvelocities of !001!23 ft,min are

&enerally ade4uate *vertical %ells-

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6

Lifting Capacity of Drilling Fluids

 A relatively 5flat6 velocity

profile is better tan a

i&ly pointed one.

 Mud properties can be

modified to obtain aflatter profile in laminar flo%

  e.&.$ decrease  n

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#rilled cuttin&s typicallyave a density of

about 2! lb,&al.

Since te fluid density is

less tan 2! lb,&al te

cuttin&s %ill tend tosettle$ or 7slip8 relative

to te drillin& mud.slipfluidparticle VVV   −=

Density ! Velocity

slipV

particleVfluid

 9 

V

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Velocity Profile

(e slip velocity can be reduced by

modifyin& te mud properties suc

tat te velocity profile is flattened'

Increase te ratio *+P,PV-

 *yield point,plastic viscosity- or 

#ecrease te value of   n

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Plug Flo"

 Plug Flo" is &ood for ole

cleanin&. Plu& flo% refers

to a 5completely6 flatvelocity profile.

 (e s#ear rate is :ero%ere te velocity profile

is flat.

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Participle Slip Velocity

$e"tonian Fluids%

(e terminal velocity of a small

sperical particle settlin&*slippin&- trou& a Ne%tonian

fluid under ;aminar flo%

conditions is &iven by S(<=E8S

;A/'

µρ−ρ

=2

sf ss

d-*!">v

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Particle Slip Velocity

Sto)es8 ;a% &ives acceptable accuracy for a

particle Reynolds number ? 0.!

For Nre @ 0.! an empirical friction factor

may be used.

µρ

= ssf Re

dvA2>N

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+#at forces act

on a settling

particle,

$on-

sp#ericalparticles

eperience

relati'ely

#ig#er drag

forces

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  Sp#ericities for Various Particle S#apes

  S#ape Sp#ericity

./0 2.r # 

./3 2r # 

./4 r # 

./05 r*4# 

./20 r*10# 

Cylinders

./34 4626 

./33 266 

Pris&

./1 Cu)e

./07cta#edron

1/.. Sp#ere

 

Sp#ericity 8

surface area of

spere of same

volume as particle

surface area of

particle

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Particle 9eynolds $u&)er( fig/ 4/46

-d!0B.B.*E4...........!f 

d>A.!v

sss   

 

  

 −

ρρ

=:n field units(

ased on real cuttin&s

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Slip Velocity Calculation

using oore;s grap# <Fig/ 4/46=

!. Calculate te flo% velocity.

2. #etermine te fluid n and > values.

". Calculate te appropriate viscosity

*apparent viscosity-.

B. ?ssu&e a value for te slip velocity.

3. Calculate te correspondin&

Particle Reynolds number.

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Slip Velocity Calculation

<using oore;s grap#=

D. <btain te correspondin& dra& coeff.$ f$

from te plot of f vs. Nre.

. Calculate te slip velocity and compare%it te value assumed in step B above.

>. If te t%o values are not close enou&$

repeat steps B trou& usin& te

calculated Vs as te assumed slip

velocity in step B.

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Ea&ple

se *te modified- Moore8s metod tocalculate te slip velocity and te net particle

velocity under te follo%in& assumptions'

/ell dept' >$000 ft +ield point' B lbf,!00ft2

#rill pipe' B.36$ !D.D G,ft #ensity of Particle' 2! lbm,&al

Mud /ei&t' .! G,&al Particle diameter' 3$000 µm

Plastic viscosity' cp Circulation rate' "B0 &al,min

Hole si:e' 1,>6

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20

Solution - Slip Velociy Pro)le&

1. Calculate the flow velocity

2. Determine the fluid n and K  value

1174300300y   =+=+=⇒−=  p y p   µ τ θ  µ θ τ 

18117300600300600 !   =+=+=⇒−=   θ  µ θ θ θ  µ   p

ft,sec"."23 

-3.B>3.*BB>.2

"B0

-dd*BB>.2

4v 

222

!

2

2

 9 

=

−=

−=

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21

*!>,!!-lo&"."2lo&"2."n"00

D00 =   

  

 θθ

=

7101.0n =

2. Determine the fluid n and K  value " cont#d

Solution - Slip Velociy Pro)le& - cont;d

cp.e4AB.DD=

3!!

!!-3!0*

3!!

-3!0*=

E!0!.0n

"00

=

=

(ADE)

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22

!0!.0

!0!.0!

a

n

n!

 9 

!2a

020>.0

-!0!.0

!2*

"23."

3.B>3.

!BB

AB.DD

*B.!0-E4........... 020>.0

-n

!2*

v

dd

!BB

=

    

 

 

 

  +   

     −=µ

    

 

 

 

  +

  

 

 

 

    −=µ

3. Calculate the a!!ro!riate vicoity

Solution - Slip Velociy Pro)le& - cont;d

=

==

c!e$94.66

7 94.17

 !

 K 

cpcpa

 µ  µ 

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23

ec%663.12

325.3

2

&& 

 ''' 

 ft ===4. (ume a value for the li! velocity

Solution - Slip Velociy Pro)le& - cont;d

5. Calculate the corre!ondin) *article +eynold ,o.

!E.AB

cm2.3B

in

m!0

cm

m3000.DD"-A2>*A.!-*!

dvA2>N

B

a

ssf Re

   

 

 

 

=

=

--

-

[ ] '52/$ 104$ s9e9e   == /1969.0 in @ds =

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24

Fro& grap#( f 8 2/.

Solution - Slip Velociy Pro)le& - cont;d

6. tain the dra) coeff. f  from the !lot of f v. ,re.

 1f 

d1/5'

sss   

 

  

 −=

1/66 ft*s./63's   <<=

=   

   −=

./505 1

5/1

21/.

2/.

./15651/5  Vs

%<4/1.4d=EA/

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25

B *ii- Assume

3 *ii- Particle

D *ii- From &rap$

*ii-

Subse4uent iterations yield 0.3D ft,s and

0.3D ft,s a&ain...

678.0v =

A.D2D>.0J.A2NRe   ==

7.2f  =

.etc.....s,ft3>.0.2

A3A.0vs   ==

Solution - Slip Velocity Pro)le& - cont;d

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26

!. Fully ;aminar'

Slip Velocity - ?lternate et#od

   

  

 −= !

d!.>Av

sss

( )f s

a

2

ss

 9 

Re

Re

d>2.>v 

K

N

B0f 

'"N

-

−=

=

<

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27

2. IntermediateK

 

K

N

22f 

'"00N"

Re

Re

=

<<

!,"

af 

2,"

f sss

 9 

-*

-*d2.A0v

-

  −=

Slip Velocity - ?lternate et#od

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28

". Fully (urbulent'

%..$9e >

Slip Velocity - ?lternate et#od

NOTE:

Check NRef 

f sss

B

=B<Bd'

  −=

1/0f  =

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29

For te above calculations'

 d-4.*B.!0B.........E !f 

d!.>Av

dvA2>N

sss

a

ssf Re

    

   −=

=

-

Slip Velocity - ?lternate et#od

NOTE: Check NRe

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30

Slip Velocity - ?lternate et#od2

If te flo% is fully laminar$ cuttin&s transport isnot li)ely to be a problem.

et#od% 1/ Calculate slip velocity for Intermediate

mode

2. Calculate slip velocity for Fully (urbulentMode.

". Coose te lo"er 'alue/

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31

*i- Intermediate'

ft,sec3B3.0!.AB-J*A.!

A.!-*2!J0.!ADAJ2.A0

-*

-*2.A0d

!,"

2,"

s

 9 

!,"af 

2,"f ss

s

 9 

=

=

−= -

*ii- Fully (urbulent'

ft%ec0.7819.1

9.13210.19691.54v

3d1.54v 

 ' 

 ' 

=−

=

−=

Ea&ple

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32

Ea&ple - cont;d

Intermediate' Vs L 0.3B3 ft,sec

Fully (urbulent' Vs L 0.>! ft,sec

(e correct slip velocity is 0.3B3 ft,sec 

a&rees reasonably %ell %it iterative metod on p.23

 

5194.17

1969.0545.01.9928 , Chec  +e   ==

Range OK 

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33

 Slip Velocity - ?P: 9P 1D

Iterative Procedure

Calculate Fluid Properties$ n O =

Calculate Sear Rate

Calculate Apparent Viscosity

Calculate Slip Velocity

Example

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34

Settling

Velocity

of Drilled

Cuttings

in +ater 

FromAPI RP 13D

p.2

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35

Calculation Procedure

!. Calculate ns for te settlin& particle

2. Calculate >s for te particle

". Assume a value for te slip velocity$Vs

B. Calculate te sear rate$ γs

3. Calculate te correspondin& apparent viscosity$ µes

D. Calculate te slip velocity$ Vs

. se tis value of Vs and repeat steps B1D until te

assumed and calculated slip velocities 5a&ree6

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36

Slip Velocity - Ea&ple

ASSUMPTIONS:

3 RPM Reading R3 3 lbf/100 ft

100 RPM Reading R100 20 lbf/100 ft2

 

Particle Density   ρp 22.5 lb/gal

Mud Density   ρ 12.5 lb/gal

Particle Dia. = Dp 0.5 in

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38

Slip Velocity - Ea&ple

". Assume a value for te slip velocity$ Vs

 Assume  Vs 8 1 ft*sec 

B. Calculate te sear rate$  γ!

p

SS

#

V!2=γ  !

S sec0.2B3.0

!J!2   −==γ 

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39

Slip Velocity - Ea&ple

3. Calculate te corresp. apparentviscosity'

D. Calculate te slip velocity$ Vs

!n

ssess=!00

  −γ =µ  

cp3.!B2BJ""D.DJ!00 !3B!".0

es   ==µ   −

 

µ

ρ

 

ρ

ρ

 

ρ

µ

=

ψ 1D

1De35.(52.<1D

e...24./.V

2

es

pp

p

./0

p

es./0

s

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40

Slip Velocity - Ea&ple

D. Calculate te slip velocity$ Vs

f ψ = 0.80 "hen:

Vs 8 ./.3 ft*sec Repea" !"ep! #$

 

µ

ρ

 

ρ

ρ

 

ρ

µ

=

1

D

1D460(161D.144/.V

2

es

pp

p

p

ess

 

 

=

14/143

0/120/.

10/12

0/22

0/.460(1610/120/.

4/143

.144/.V

2

s

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41

Slip Velocity - Ea&ple

%! & '.' *"+!ec

4. hear rate γ! & 1,.3$ !ec#1

5. (!!arent vicoity µe! & 1$2.$- cp

6. li! velocity %! & '.- *"+!ec

econ/ I"era"0on # !0ng

4. hear rate γ! & 1., !ec#1

5. (!!arent vicoity µe! & 1$.- cp

6. li! velocity %! & '.23 *"+!ec

Th0r/ I"era"0on # !0ng %! & '.- *"+!ec

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42

Slip Velocity - Ea&ple

%! & '.23 *"+!ec

4. hear rate γ! & 1.$ !ec#1

5. (!!arent vicoity µe! & 1$-.' cp

6. li! velocity %! & '.1, *"+!ec

For"h I"era"0on # !0ng

0p %eoc0"4 %! & '.1, *"+!ec

5 %! & 1.'4 '.'4 '.24 '.2 *"+!ec 6

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43

Transport 9atio

QEfficiency(ransport 

ft,min!20 velocityFluid ft,minA0 velocityParticle 'Example

!00JvelocityfluidvelocityparticleEfficiency(ransport

velocityfluidvelocityparticle Ratio(ransport

===

=

=

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45

Potential Hole-Cleaning Pro)le&s

!. Hole is enlarged/  (is may result in

reduced fluid velocity %ic is lo%er

tan te slip velocity.

2. Hig# do"n#ole te&peratures may

adversely affect mud properties

do%nole.

T /e measured tese at te surface.U

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46

Potential Hole-Cleaning Pro)le&s

". Lost circulation problems may preclude

usin& tic) mud or i& circulatin&

velocity. T#ic slugs may be te

ans%er.

B. Slo" rate of &ud t#icening 1 after it as

been seared *and tinned-trou& te bit no::les$ %ere te

s#ear  rate is very i&.

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T#e End

Lesson 16

- Lifting Capacity of Drilling Fluids -- Slip Velocity -