17[A Math CD]

1 © Penerbitan Pelangi Sdn. Bhd.

Paper 1

1. x = 90

Answer: C

2.

x°O

P

Q

R55°

x° = 180° − 55° − 90° = 35° x = 35

Answer: B

3.

y°O

E

50°115°

F

G

H

y° = 360° − 115° − 50° − 90° = 105° y = 105

Answer: D

4.

O70°E

H

F

G

∠FOH = 180° – ∠EFO = 180° – 90° = 90°

Answer: B

5. ∠UTQ = ∠PQU x = 75

Answer: A

6.

65°

115°

x °

x°

P

Q

R

ST

U

∠QST = 115° − 65° = 50° x° = ∠QST x = 50

Answer: B

7.

68°x°

E F G

P

O

Q

∠QFP = 90°∠PQF = 180° − 90° − 68° = 22° x° = ∠PQF x = 22

Answer: D

CHAPTER

17 Circles IIICHAPTER

2

Mathematics SPM Chapter 17

© Penerbitan Pelangi Sdn. Bhd.

8.

100°x°O T

QP

RS

x° = 360° − 90° − 90° − 100° = 80° x = 80Answer: B

9.

100° x°

E

Q O

J

F

GH

x° = ∠HQE = 100° x = 100Answer: D

10.

70°

Q

O

L M N

QL and OM are parallel.∠OQL = ∠NOM = 70°Answer: C

Paper 1

1.

35°E

FO

x°

20°G

H

160°70°

∠FOH = 2 × ∠FEH = 2 × 35° = 70°

∠OFG = 180° – 20° = 160° x° = 360° − 90° − 70° − 160° x = 40

Answer: B

2.

46°

J

O

x°GFE

H

22° 44°

∠FOG = 180° – 90° − 46° = 44°

∠OFJ = 442

°

= 22° x° = 90° − 22° x = 68

Answer: C

3.

35°

35° 35°x°

J K L

M

N

∠LKM = ∠KNM = 35° x° = 180° − 35° − 35° x = 110

Answer: C

4. ∠OKG = ∠OFG = 90° x° = 180° − 50° = 130°

∠MNG = ∠MGH = 50°

y° = 180° – 50°2

= 65° x° + y° = 130° + 65° x + y = 195

Answer: D

3



5.

72°

72°72°

x°H

F

J

G

E

∠FEG = 72° x° = 180° − 72° − 72° x = 36

Answer: B

6.

J

E GF H

L

K

240°

55°

65°55°

p°

∠JLG = 55° ∠ELK = 360° − 240° – 55° = 65° 65° + p° = 180° p = 115

Answer: C

7.

55°

35°

110°

70°

y°

O

J

H

E

F

G

∠FOJ = 2 × 55° = 110°

∠FJO = 180° – 110°2

= 35° ∠FJH = ∠HFG = 70° y° = 70° − 35° y = 35

Answer: C

8. E F G

H

O

J

68°44°

50°

68° 68°

x°

∠FHJ = ∠EFJ = 68° ∠JFH = 180° – 68° – 68° = 44° x° + 50° = 68° + 44° x° = 112° – 50° x = 62

Answer: A

Paper 1

1.

32°

64°

O

y°P Q R

T

S

∠QOT = 2 × 32° = 64° y° = 180° − 90° − 64° = 26° y = 26

Answer: C

2.

40°

O

E F G

x°2x°H

J

∠JOF = 2x° 2x° = 180° − 90° − 40°

x° = 50°––––2

x = 25

Answer: B

4



3.

40°40°

Ox°

J

H

G

F

E

∠OGH = 40° x° = 180° − 90° − 40° x = 50

Answer: B

4.

58°116° OP x°

QR

ST

U

∠QOS = 2 × 58° = 116° x° = 360° − 90° − 90° − 116° x = 64

Answer: D

5.

O

40° 50°

50°

x°

G

F

E

∠EGF = 90° − 40° = 50° x° = 180° − 50° − 50° x = 80

Answer: D

6.

O70°

y°

P

Q

R

∠QOR = 360° − 90° − 90° − 70° = 110°

y° = 180° − 110°––––––––––2

y = 35

Answer: A

7.

O 50°

65°x°

G

E

F

∠EFG = 180° − 50°––––––––––2

= 65° x° = 180° − 65° x = 115

Answer: D

8.

35°30°

30°

x°

Q

P

NML

∠PMN = ∠MQP = 30° x° = 180° − 30° − 35° x = 115

Answer: C

5



9.

x°

50°

25°O

P Q R

S

T

∠QTS = 50°––––2

= 25° x° = ∠QTS = 25° x = 25

Answer: B

10.

x°

O

K

J H

E F G

64°32°

∠FHK = 64°––––2

= 32° x° = ∠FHK = 32° x = 32

Answer: B

11.

32°74°

32°

x°S T U

V

W

∠TVW = 32°

∠VTW = 180° − 32°–––––––––2

= 74° x° = 180° − 32° − (74° + 32°) x = 42

Answer: B

12.

80°

80°

40°

y°

PQR

S

T

∠QST = ∠RQT = 80°

∠PQS = 80°––––2

= 40° y° = ∠PQS y = 40

Answer: A

13.

70°

70°70°

x°

O

E

F

G

P

Q

∠FQP = ∠FPQ = 70°∠QFG = ∠FPQ = 70° x° = 90° − 70° x = 20

Answer: C

14.

110°35°

80°y°O P

Q

R

S

T

∠QSO = 180° − 110°––––––––––2

= 35°∠QST = 80° y° = 80° − 35° y = 45

Answer: C

6



15.

35°

35°y° O

PQ

L

MN

∠PQM = ∠LMP = 35°∠PMQ = 90° y° = 35° + 90° y = 125

Answer: B

16.

50°

50°

35°

35°

E

F

GL

M

N

∠LMF = ∠EFL = 50°∠NMF = ∠GFN = 35°∠LMN = 50° + 35° = 85°

Answer: B

17.

25°

25°

x°

O

L M N

P

Q

∠QPM = ∠LMQ = 25°∠QMP = 90° x° = 180° − 25° − (90° + 25°) x = 40

Answer: B

18.

50°50°

x°

E F

OQH

∠FHQ = ∠HFQ = 50°∠FQH = 180° − 50° − 50° = 80° x° = 360° − 90° − 90° − 80° x = 100

Answer: D

19. ∠QOT = 180° – 74° = 106° y° = 180° – 106° = 74°

∠QRT = 106°––––2

= 53°

∠RQS = 90° – 66° = 24

x° = 180° – 53° – 24° = 103°

x° + y° = 103° + 74° x + y = 177

Answer: C

Documents

17[A Math CD]