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19. The Fourier Transform in optics What is the Fourier Transform? Anharmonic waves The spectrum of a light wave Fourier transform of an exponential The Dirac delta function The Fourier transform of e jt , cos(t) ( ) ( ) exp F ft j t dt 1 () ( ) exp 2 f t F j td

19. The Fourier Transform in optics - Brown University · Some functions don’t have Fourier transforms. ft dt() A condition for the existence of a given F( ) is: Functions that

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Page 1: 19. The Fourier Transform in optics - Brown University · Some functions don’t have Fourier transforms. ft dt() A condition for the existence of a given F( ) is: Functions that

19. The Fourier Transform in optics

What is the Fourier Transform?

Anharmonic waves

The spectrum of a light wave

Fourier transform of an exponential

The Dirac delta function

The Fourier transform of ejt, cos(t)

( ) ( ) exp

F f t j t dt 1( ) ( ) exp2

f t F j t d

Page 2: 19. The Fourier Transform in optics - Brown University · Some functions don’t have Fourier transforms. ft dt() A condition for the existence of a given F( ) is: Functions that

There’s no such thing as exp(jt)

0Re j tE t E e

All semester long, we’ve described electromagnetic waves like this:

What’s wrong with this description? Well, what is its behavior after a long time?

lim ???E tt

In the real world, signals never last forever. We must always expect that:

lim 0E tt

This means that no wave can be perfectly “monochromatic”. All waves must be a superposition of different frequencies.

Page 3: 19. The Fourier Transform in optics - Brown University · Some functions don’t have Fourier transforms. ft dt() A condition for the existence of a given F( ) is: Functions that

Jean Baptiste Joseph Fourier, our hero

Later, he was concerned with the physics of heat and developed the Fourier series and transform to model heat-flow problems.

“Fourier’s theorem is not only one of the most beautiful results of modern analysis, but it may be said to furnish an indispensable instrument in the treatment of nearly every recondite question in modern physics.”

Lord Kelvin

Joseph Fourier, 1768 - 1830

Fourier went to Egypt with Napoleon’s army in 1798, and was made Governor of Lower Egypt.

He is also generally credited with the first discussion of the greenhouse effect as a source of planetary warming.

Page 4: 19. The Fourier Transform in optics - Brown University · Some functions don’t have Fourier transforms. ft dt() A condition for the existence of a given F( ) is: Functions that

What do we hope to achieve with theFourier Transform?We desire a measure of the frequencies present in a wave. This willlead to a definition of the term, the “spectrum.”

It will be nice if our measure also tells us when each frequency occurs.

This light wave has many frequencies. And the frequency increases in time (from red to blue).

Monochromatic waves have only one frequency, .

Ligh

t ele

ctric

fiel

d

Time

Page 5: 19. The Fourier Transform in optics - Brown University · Some functions don’t have Fourier transforms. ft dt() A condition for the existence of a given F( ) is: Functions that

The Fourier Transform and its Inverse

Inverse Fourier Transform

Fourier Transform ( ) ( ) exp( )

F f t j t dt

1( ) ( ) exp( )2

f t F j t d

Be aware: there are different definitions of these transforms. The factor of 2π can occur in several places, but the idea is generally the same.

Many of you have seen this in other classes:

We often denote the Fourier transform of a function f(t) by F{ f(t) }, and the inverse transform of a function g() by F-1{ g() }.

Page 6: 19. The Fourier Transform in optics - Brown University · Some functions don’t have Fourier transforms. ft dt() A condition for the existence of a given F( ) is: Functions that

Example: the Fourier Transform of arectangle function: rect(t)

/ 2

/ 2/ 2

/ 2

1( ) exp [exp ]

F j t dt j t

j

( sinc 2 F Imaginary Component = 0

F()

The sinc function crops up everywhere...

f(t) 1

1 [exp 2 exp 2

j jj

exp 2 exp 22

sin 2

j jj

Page 7: 19. The Fourier Transform in optics - Brown University · Some functions don’t have Fourier transforms. ft dt() A condition for the existence of a given F( ) is: Functions that

Example: the Fourier Transform of aGaussian is a Gaussian!

2 2

2

exp exp( )exp( )

exp( / 4 )

F at at j t dt

a

t0

2exp( )at

0

2exp( / 4 )a

There are other examples of functions who are their own Fourier transform.

Page 8: 19. The Fourier Transform in optics - Brown University · Some functions don’t have Fourier transforms. ft dt() A condition for the existence of a given F( ) is: Functions that

The Fourier transform of 1/sqrt(t)

0

1 expF H t j t dtt

Consider the function t 1/2, starting at t = 0:0 if 0

( )1 if 0

tH t

t t

4 je

This is another function which is its own Fourier transform!

This result is significant in the analysis of certain types of random processes - “1/f noise”

Page 9: 19. The Fourier Transform in optics - Brown University · Some functions don’t have Fourier transforms. ft dt() A condition for the existence of a given F( ) is: Functions that

Anharmonic waves are sums of sinusoids.Consider the sum of two sine waves (i.e., harmonic waves) of

different frequencies:

The resulting wave is periodic, but not harmonic.

Essentially all waves are anharmonic. But virtually any anharmonic wave can be written as the sum of harmonic waves.

Fourier analysis is useful because it is the primary tool for handling anharmonic waves.

Sum

Page 10: 19. The Fourier Transform in optics - Brown University · Some functions don’t have Fourier transforms. ft dt() A condition for the existence of a given F( ) is: Functions that

Fourier decomposing functions

Here, we write asquare wave as a sum of sine waves.

Page 11: 19. The Fourier Transform in optics - Brown University · Some functions don’t have Fourier transforms. ft dt() A condition for the existence of a given F( ) is: Functions that

Some functions don’t have Fourier transforms.

( )f t dt

A condition for the existence of a given F() is:

Functions that do not asymptote to zero in both the + and –directions generally do not have Fourier transforms (with some exceptions).

Of course, such functions don’t describe real waves, so this is usually not a problem.

Page 12: 19. The Fourier Transform in optics - Brown University · Some functions don’t have Fourier transforms. ft dt() A condition for the existence of a given F( ) is: Functions that

The spectrum of a light waveWe define the spectrum of a wave E(t) to be the

magnitude of the square of the Fourier transform:

2{ ( )}S F E t

This is our measure of the frequency content of a light wave.

Note that the Fourier transform of E(t) is usually a complex quantity:

By taking the magnitude, we are throwing away the phase information. So the spectrum does not contain all of the information about the wave. It does not contain the spectral phase, which is sometimes important.

jF E t E E e

Page 13: 19. The Fourier Transform in optics - Brown University · Some functions don’t have Fourier transforms. ft dt() A condition for the existence of a given F( ) is: Functions that

time time

The spectrum of a light wave does not contain all of the information about E(t)

These two E-fields E(t) have the same spectrum. But they are obviously different from each other.

The difference is contained in the spectral phase ().

Page 14: 19. The Fourier Transform in optics - Brown University · Some functions don’t have Fourier transforms. ft dt() A condition for the existence of a given F( ) is: Functions that

Measuring the spectrum of a light waveOne reason that the spectrum is such an important quantity is that it is easy to measure.

“spectrometer” - a device which measures the spectrum of a signal

If we divide a light wave into its components, and measure the irradiance at each frequency (or equivalently, at each wavelength), then we have measured the spectrum of the light wave.

So, how do we divide a light wave into its component parts?

prisms disperse light!

Page 15: 19. The Fourier Transform in optics - Brown University · Some functions don’t have Fourier transforms. ft dt() A condition for the existence of a given F( ) is: Functions that

A prism spectrometer

the light source which we wish to study detector to measure

the irradiance of light at each wavelength.

Robert Bunsen, 1859

Page 16: 19. The Fourier Transform in optics - Brown University · Some functions don’t have Fourier transforms. ft dt() A condition for the existence of a given F( ) is: Functions that

More modern spectrometersCzerny spectrometer

a miniaturized spectrometer designed by NASA

This spectrometer is currently on Mars.

10 cm

Page 17: 19. The Fourier Transform in optics - Brown University · Some functions don’t have Fourier transforms. ft dt() A condition for the existence of a given F( ) is: Functions that

The Dirac delta function - a key tool in Fourier analysis

if 0( )

0 if 0

xx

x

x

(x)

The Dirac delta function is not really a function at all, but it is nevertheless very useful.

Page 18: 19. The Fourier Transform in optics - Brown University · Some functions don’t have Fourier transforms. ft dt() A condition for the existence of a given F( ) is: Functions that

The Dirac delta function

It’s best to think of the delta function as a limit of a series of peaked continuous functions.

if 0( )

0 if 0

xx

x

x

height h

width 1/h

Start with this square function, and imagine taking the limit as h

Note that the area under the function remains constant, equal to 1.

Page 19: 19. The Fourier Transform in optics - Brown University · Some functions don’t have Fourier transforms. ft dt() A condition for the existence of a given F( ) is: Functions that

Dirac function Properties

( ) 1

t a dt

( ) ( ) ( )

t a f t dt f a

The area under a function is one:

Integrating any function f(t) multiplied by a function picks out the value of f(t) at the location of the function:

t

(ta)

a

f(t)

f(a)

t

(t)

a

Page 20: 19. The Fourier Transform in optics - Brown University · Some functions don’t have Fourier transforms. ft dt() A condition for the existence of a given F( ) is: Functions that

Fourier Transforms and (t)

1exp( ) 2 (

j t dt And the Fourier Transform of 1 is (t):

t

(t)

()

t

( ) exp( ) exp( [0]) 1

t j t dt j

The Fourier transform of (t) is one.

Page 21: 19. The Fourier Transform in optics - Brown University · Some functions don’t have Fourier transforms. ft dt() A condition for the existence of a given F( ) is: Functions that

The Fourier transform of exp(j0 t)

0 0exp( ) exp( ) exp( )

F j t j t j t dt

0exp( [ ] )

j t dt 02 ( )

exp(j0t)

t

tRe

Im

F {exp(j0t)}

The function exp(j0t) is the essential component of Fourier analysis. It is a pure frequency - its spectrum consists of only one frequency component.

Page 22: 19. The Fourier Transform in optics - Brown University · Some functions don’t have Fourier transforms. ft dt() A condition for the existence of a given F( ) is: Functions that

The Fourier transform of cos(t)

0 0cos( ) cos( ) exp( )

F t t j t dt

0 01 exp( ) exp( ) exp( )2

j t j t j t dt

0 01 1exp( [ ] ) exp( [ ] )2 2

j t dt j t dt

0 0( ) ( )

cos(0t)t

0F{cos( )}t