2-The Laplace Transform

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    The Laplace Transform

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    The s-Domain

    The Laplace Transform of a function, f(t), is defined as;

    0

    [ ( )] ( ) ( )st

    L f t F s f t e dt

    The Inverse Laplace Transform is defined by

    1 1[ ( )] ( ) ( )

    2

    j

    ts

    j

    L F s f t F s e dsj

    )()( sFtf

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    Laplace Transform Pairs

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    Cont

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    Cont

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    Laplace Transform Properties

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    Examples

    Find laplace transform !

    21. 3 cos6 5 sin6

    2. sin

    cos33.

    te t t

    t at

    d tdt

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    2 2 2

    2 2

    6 3 301. 3 5

    36 36 36

    3 2 30 3 24

    4 402 36

    s s

    s s s

    s s

    s ss

    22 2

    2 2

    22.

    d a as

    ds s a s a

    2 2

    93. 19 9

    sss s

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    Background:

    There are three cases to consider in doing the partial fraction expansion of F(s).

    Case 1: F(s) has all non repeated simple roots.

    1 2( ) . . .

    1 2

    kk knF s

    s p s p s p

    n

    Case 2: F(s) has complex poles:

    *( )1 1 1( ) . . .

    ( )( )( ) )1

    P s k k F s

    Q s s j s j s j s j

    Case 3: F(s) has repeated poles.

    ( ) ( )1 11 12 1 1( ) . . . . . .

    2 ( )( )( ) ( ) ( )1 11 1 1 1

    P s k k k P srF s

    r rs p Q sQ s s p s p s p

    Inverse Laplace Transforms

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    Case 1: Illustration:

    Given:

    )10()4()1()10)(4)(1(

    )2(4)( 321

    s

    A

    s

    A

    s

    A

    sss

    ssF

    274)10)(4)(1(

    )2(4)1(|

    11 ssss

    ssA 94

    )10)(4)(1(

    )2(4)4(| 42 ssss

    ssA

    2716)10)(4)(1(

    )2(4)10(|

    103 ssss

    ssA

    )()2716()94()274()(104

    tueeetf

    ttt

    Find A1, A2, A3 from Heavyside

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    Case 2: Complex Roots:

    ...)))()((

    )()(

    *11

    1

    1

    js

    K

    js

    K

    jsjssQ

    sPsF

    F(s) is of the form;

    K1 is given by,

    jeKKK

    jsjssQ

    sPjsK

    js

    ||||

    ))(()(

    )()(

    111

    1

    1

    1|

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    js

    eK

    js

    eK

    js

    K

    js

    K jj11

    *11

    |||

    tje

    te

    je

    tje

    te

    jeK

    js

    eK

    js

    eKL

    jj

    1||

    ||||111

    2

    )()(|

    1|2

    1||

    tjetjeateKtj

    etej

    etj

    etejeK

    Case 2: Complex Roots:

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    )cos(||2|||

    1

    111 teKjs

    eK

    js

    eKL t

    jj

    Case 2: Complex Roots:

    Therefore:

    You should put this in your memory:

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    o

    jj

    j

    jss

    sK

    ss

    sA

    jsK

    jsK

    sAsF

    jsjss

    s

    sss

    ssF

    js

    s

    10832.0)2)(2(

    12

    )2(

    )1(

    5

    1

    )54(

    )1(

    22)(

    )2)(2(

    )1(

    )54(

    )1()(

    |

    |

    2|1

    0|

    11

    2

    2

    *

    Complex Roots: An Example.

    For the given F(s) find f(t)

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    Complex Roots: An Example. (continued)

    We then have;

    jsjsssF

    oo

    2

    10832.0

    2

    10832.02.0

    )(

    Recalling the form of the inverse for complex roots;

    )(108cos(64.02.0)(2 tutetf ot

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    Circuit theory problem:

    You are given the circuit shown below.

    +_

    t = 0 6 k

    3 k100 F

    +

    _v(t)12 V

    Use Laplace transforms to find v(t) for t > 0.

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    Circuit theory problem:

    We see from the circuit,

    +_

    t = 0 6 k

    3 k100 F

    +

    _v(t)12 V

    voltsxv 49

    312)0(

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    Circuit theory problem:

    +

    _vc(t) i(t)

    3 k

    100 F

    6 k

    05)(

    0

    )(

    0)()(

    tv

    dt

    tdv

    RC

    tv

    dt

    tdv

    tvdt

    tdvRC

    c

    c

    cc

    cc

    Take the Laplace transform

    of this equations including

    the initial conditions on vc(t)

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    Circuit theory problem:

    )(4)(

    5

    4

    )(

    0)(54)(

    0)(5)(

    5tuetv

    ssV

    sVssV

    tvdt

    tdv

    t

    c

    c

    cc

    c

    c

    Tentukan transformasi laplacenya !

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    Tentukan transformasi laplacenya !

    Tentukan invers transformasi laplacenya !

    Tentukan besarnya i(t) !

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