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Physics 212Fall 2008
Problem Set #6
Review: 18.2 and lecture notes then do the problems. Due Friday, October 3rd
1) Analyze the circuit below using a V-I-R chart.
2) Analyze the circuit below using a V-I-R chart.
3) Analyze the circuit below using a V-I-R chart.
4) In the circuit below, the current through R4 is 0.5 A. Find the current through (a) R5 and (b) R2.
ANSWERS:1) Req=4.6 5) 2.22 W 9) I1 = 3.5 A2) Req=5.13 6) 0.429 A I2 = 1.0 A3) Req=15 7) 0.12 I3 = 2.5 A4) a) 0.75 A, b) 2.11 A 8) 0.38 A5) Determine the power dissipated in R4 in the circuit below.
6) Find the current through the 12 resistor in the circuit below.
7) A 1.4 resistor is connected across a 9 V battery. The voltage between the terminals of the battery is observed to be 8.3 V. Find the internal resistance of the battery.
8) From the information given in the circuit below, (a) determine the current in the circuit, and (b) state which point, A or B, is at a higher potential.
9) Calculate the unknown currents I1, I2, and I3 for the circuit below.
R1
ValuesR1 = 20 R2 = 3.0 R3 = 4.0 R4 = 9.0 R5 = 8.0 R6 = 6.0
R2 R3
R4 R5
R6
20 V
ValuesR1 = 3.0 R2 = 10.0 R3 = 5.0 R4 = 4.0 R5 = 3.0
R1
R2
R3
R4
R5
40 V
ValuesR1 = 6.0 R2 = 6.0 R3 = 2.4 R4 = 6.0 R5 = 9.0 R6 = 6.0
15 V
R1
R2
R3
R4
R5 R6
ValuesR1 = 18.0 R2 = 9.0 R3 = 16.0 R4 = 8.0 R5 = 20.0 R1
R2
R5
R4
R3
R1
R2 R3
R4 R5
12 V
ValuesR1 = 4.0 R2 = 2.0 R3 = 1.0 R4 = 5.0 R5 = 1.0
R2
R1
R3
R4
R5
R7
R6
18 V
ValuesR1 = 3.0 R2 = 3.0 R3 = 6.0 R4 = 6.0 R5 = 4.0 R6 = 12.0 R7 = 2.0
8
5
12
27
10 V
30 V
A
B
24 V
12 V
2
4
3
5
1
I1
I2
I3
