2210 COMPUTER SCIENCE - Max Papersmaxpapers.com/wp-content/uploads/2013/06/2210_s15_ms_complete.pdf · If the broadband data download rate is 40 megabits/ second; how long will it

® IGCSE is the registered trademark of Cambridge International Examinations.

CAMBRIDGE INTERNATIONAL EXAMINATIONS

Cambridge Ordinary Level

MARK SCHEME for the May/June 2015 series

2210 COMPUTER SCIENCE

2210/11 Paper 1, maximum raw mark 75

This mark scheme is published as an aid to teachers and candidates, to indicate the requirements of the examination. It shows the basis on which Examiners were instructed to award marks. It does not indicate the details of the discussions that took place at an Examiners’ meeting before marking began, which would have considered the acceptability of alternative answers. Mark schemes should be read in conjunction with the question paper and the Principal Examiner Report for Teachers. Cambridge will not enter into discussions about these mark schemes. Cambridge is publishing the mark schemes for the May/June 2015 series for most Cambridge IGCSE

®, Cambridge International A and AS Level components and some

Cambridge O Level components.

Page 2 Mark Scheme Syllabus Paper

Cambridge O Level – May/June 2015 2210 11

© Cambridge International Examinations 2015

1 (a) parallel any one from: – 8 bits/1 byte/multiple bits sent at a time – using many/multiple/8 wires/lines (1 mark) serial any one from: – one bit sent at a time – over a single wire (1 mark) [2] (b) parallel – faster rate of data transmission (1 mark) serial any one from: – more accurate/fewer errors over a longer distance – less expensive wiring – less chance of data being skewed/out of synchronisation/order (1 mark) [2] (c) parallel any one from: – sending data from a computer to a printer – internal data transfer (buses) (1 mark) serial – connect computer to a modem (1 mark) [2]




2 (a) – universal serial bus – description of USB [1]

(b) Any two from:

– devices are automatically detected and configured when initially attached – impossible to connect device incorrectly/connector only fits one way – has become the industry standard – supports multiple data transmission speeds – lots of support base for USB software developers – supported by many operating systems – backward compatible – faster transmission compared to wireless [2]

3 (a)

A

B

C

Working

X

0

0

0

1

] 1 mark

0

0

1

0

0

1

0

0

] 1 mark

0

1

1

0

1

0

0

0

] 1 mark

1

0

1

1

1

1

0

1

] 1 mark

1

1

1

1

[4]




(b) 1 mark per dotted section

[3]

(c) X is 1 if:

(A is 1 OR B is 1) (1 mark) AND (1 mark) (B is 1 OR C is NOT 1) (1 mark) accept equivalent ways of writing this: e.g. (A OR B = 1) AND (B OR NOT C = 1) e.g. (A OR B) AND (B OR NOT C) e.g. (A + B) (B + C) [3]

A

B

C

X




4 1 mark per correct word 1 protocol

2 web server name accept these three items in any order

3 file name

HTML tags/text

firewall

proxy server

[6]

5 1 mark per device, 1 mark per category

Description of storage device Name of storage device

Category of storage

Primary Secondary Off-line

optical media which uses one spiral track; red lasers are used to read and write data on the media surface; makes use of dual-layering technology to increase the storage capacity

DVD

�

non-volatile memory chip; contents of the chip cannot be altered; it is often used to store the start-up routines in a computer (e.g. the BIOS)

ROM �

optical media which uses concentric tracks to store the data; this allows read and write operations to be carried out at the same time

DVD-RAM � (�)

non-volatile memory device that uses NAND flash memories (which consist of millions of transistors wired in series on single circuit boards)

Solid State Drive/memory

(SSD)

(SD/XD card) (USB storage

device)

�

(�)

optical media that uses blue laser technology to read and write data on the media surface; it uses a single 1.1 mm polycarbonate disc

Blue-ray

�

[10]




6 (a) virus any two from:

– program/software that replicates/copies itself – can delete or alter files/data stored on a computer – can make the computer “crash”/run slow

pharming any two from:

– malicious code/software installed on a user’s hard drive/actual web server – this code redirects user to a fake website (without their knowledge) – to obtain personal/financial information/data

phishing any two from:

– legitimate-looking emails sent to a user – as soon as recipient opens/clicks on link in the email/attachment … – … the user is directed to a fake website (without their knowledge) – To obtain personal/financial information/data

[6]

(b) (i) Any two from:

– spyware/key logging software can only pick up key presses – using mouse/touchscreen means no key presses to log – the numbers on the key pad are in random/non-standard format, which makes it more difficult to interpret [2]




(ii) 1 mark for name and 1 mark for description any one from: chip and PIN reader – only the user and the bank know which codes can be generated request user name – additional security together with password/PIN anti-virus – removes/warns of a potential virus threat which can’t be passed on to customers firewall – (helps) to protect bank computers from virus threats and hacking encryption – protects customer data by making any hacked information unreadable security protocol – governs the secure transmission of data Biometric – to recognise user through the use of, e.g. facial/retina/finger print Alerts – users IP/MAC address is registered and user is alerted through, e.g. SMS if account is accessed through an unregistered address [2] 7 (a)

2/3 matches – 2 marks 1 match – 1 mark

[2]

address bus

control bus

data bus

this bus carries signals used to coordinate the computer’s activities

this bi-directional bus is used to exchange data between processor, memory and input/output devices

this uni-directional bus carries signals relating to memory addresses between processor and memory




(b)

description of stage sequence number

the instruction is then copied from the memory location contained in the MAR (memory address register) and is placed in the MDR (memory data register)

3

the instruction is finally decoded and is then executed 7

the PC (program counter) contains the address of the next instruction to be fetched

(1)

the entire instruction is then copied from the MDR (memory data register) and placed in the CIR (current instruction register)

4

the address contained in the PC (program counter) is copied to the MAR (memory address register) via the address bus

2

the address part of the instruction is placed in the MAR (memory address register)

6

the value in the PC (program counter) is then incremented so that it points to the next instruction to be fetched

5*

The incrementation of the program counter can appear at any stage after 2. All other stages must be in the correct given order. [6]

8 (a) hours: 18 minutes: 53 [2] (b)

hours (“C”) minutes (“D”)

0 0 0 0 0 1 1 1 : 0 0 0 1 1 1 1 0

[2]




(c) Any three from:

– reads values in registers “C” and “D” – and checks the values against those stored in registers “A” and “B” (NOTE: the first two statements can be interchanged, i.e. “A” and “B” read first) – If values in corresponding registers are the same – the microprocessor sends a signal to sound alarm/ring [3]

(d) Any three from:

– uses a light sensor – sends signal/data back to microprocessor – signal/data converted to digital (using ADC) – value compared by microprocessor with pre-set/stored value – if value < stored value, signal sent by microprocessor … – … to the voltage supply (unit) – … “value” of signal determines voltage supplied/brightness of LED [3]

(e) Any two from:

– no need to warm up – whiter tint/more vivid colours/brighter image – higher resolution – much thinner monitors possible/lighter weight – more reliable technology/longer lasting – uses much less power/more efficient [2]




9

5/6 matches – 5 marks 4 matches – 4 marks 3 matches – 3 marks 2 matches – 2 marks 1 match – 1 mark

[5]

What is the denary (base 10) equivalent to the hexadecimal digit “E”?

If 1 GByte = 2x

then what is the

value of X?

The number of bits in one byte

If the broadband data download rate is 40 megabits/ second; how long will it take to download a 60 MByte file?

What is the denary (base 10) value of the binary number:

0 0 1 0 0 1 0 0?

What hexadecimal value is obtained when the two hexadecimal digits, C and D, are added together?

12

8

14

19

30

36




10 1 mark per correctly placed tick

statement interpreter compiler

takes one statement at a time and executes it �

generates an error report at the end of translation of the whole program

�

stops the translation process as soon as the first error is encountered

�

slow speed of execution of program loops �

translates the entire program in one go �

[5]













1 (a) 1 mark per correctly placed tick

Statement True False

they are a form of spyware �

they are used in advertising only �

they are used to track the browsing of a user �

they act in the same way as a virus �

[4]

(b)

4/5 matches – 4 marks 3 matches – 3 marks 2 matches – 2 marks 1 match – 1 mark

[4]

malicious code installed on the hard drive of a user’s computer or on the web server; this code will re-direct user to a fake web site without their consent

software that gathers information by monitoring key presses on a user’s computer and relays the information back to the person who sent the software

program or code that replicates itself and is designed to amend/delete/copy data and files on a user’s computer without their consent

the act of gaining illegal access to a computer system without the owner’s consent

creator of code sends out a legitimate-looking email in the hope of gathering personal and financial data from the recipient; it requires the email or attachment to be opened first

hacking

pharming

phishing

spyware

virus




2 (i) Either of the three options, resistive, capacitive or infra-red must be chosen maximum of two marks from chosen technology:

resistive

− uses multiple layers of material …

− … that transmit electric currents

− when the top layer/screen is pushed/touched into the lower/bottom layer …

− … the electric current changes and location of “touch” is found

capacitive

− current sent/flows out from all 4 corners of the screen

− when finger/stylus touches screen, the current changes

− the location of “touch” is calculated

infra-red

− an “invisible” grid on the screen (pattern of infra-red LED beams)

− sensors detect where the screen has been touched through a break in an infrared beam(s)

− the position where the screen touched is calculated [2] (ii) 1 mark for benefit, 1 mark for drawback

Resistive

benefits:

− inexpensive/cheap to manufacture

− can use stylus/finger/gloved finger/pen drawbacks:

− poor visibility in sunlight

− vulnerable to scratching

− wears through time

− does not allow multi-touch facility

capacitive

benefits:

− good visibility in sunlight

− (very) durable surface

− allows multi-touch facility drawbacks:

− screen (glass) will shatter/break/crack (on impact)

− cannot use when wearing (standard) gloves

infra-red

benefits:

− good durability

− allows multi-touch facility

− can use stylus/finger/gloved finger/pen drawbacks:

− expensive to manufacture

− screen (glass) will shatter/break/crack (on impact)

− sensitive to dust/dirt [2]




3 Input Device to Description Description to Application

3/4 matches – 3 marks 3/4 matches – 3 marks

2 matches – 2 marks 2 matches – 2 marks 1 match – 1 mark 1 match – 1 mark

[6]

copies paper documents and

converts the text and pictures into a

computer-readable form

reads labels containing parallel dark and light lines using laser light; the width of each line represents a binary

code

detects changes in acidity levels; data is

often in analogue form

audio device that allows audio signals to be

converted into electric signals which can be

interpreted by a computer after being converted into digital

barcode reader

microphone

pH sensor

scanner

voice recognition

reading passports

automatic stock control

monitor soil in a greenhouse




4 (a) Any one from:

− secure sockets layer

− encrypts data being transmitted

− use of https

− use public and private keys [1] (b) 1 mark for each number in the correct order, next to the correct stage.

Stage Sequence number

the encrypted data is then shared securely between the web browser and the web server

6

the web browser attempts to connect to a web site which is secured by SSL (1)

the web server sends the web browser a copy of its SSL certificate 3

the web browser requests the web server to identify itself 2

the web server will then send back some form of acknowledgement to allow the SSL encrypted session to begin

5

the web browser checks whether the SSL certificate is trustworthy; if it is then the web browser sends a message back to the web server

4

[5]





Received byte Byte transmitted correctly Byte transmitted incorrectly

1 1 0 0 1 0 0 0 �

0 1 1 1 1 1 0 0 �

0 1 1 0 1 0 0 1 �

[3]

(b) (i) byte number: 7 column number: 6

[2] (ii) Any two from:

− letter “A”(byte 7) transmitted as odd parity (three 1s)

− column 6 has odd parity (seven 1s)

− intersection of byte 7 and column 6 indicates incorrect bit value [2]

(c) 190

[1] (d) Any one from:

− 2 bits interchanged (e.g. 1 → 0 and 0 → 1) that won’t change parity value

− even number of bits/digits are transposed

− If there are multiple errors in the same byte/column, that still produce the same parity bit, the error will not be detected

[1]




6 (a) 1 mark per correct logic gate, correctly connected

[5]

(b)

G C L Workspace X

0 0 0 0

] 1 mark 0 0 1 0

0 1 0 1

] 1 mark 0 1 1 0

1 0 0 1

] 1 mark 1 0 1 1

1 1 0 1

] 1 mark 1 1 1 0

[4]

G

C

L

X




(c) 1 mark for correctly completed truth table

A B C

0 0 0

0 1 1

1 0 1

1 1 0

[1] 7 (a) Maximum 5 marks in total for question part

Description of how street light is controlled: (max 4 marks)

− sensor sends signal/data to the microprocessor

− signal/data converted to digital/using ADC

− microprocessor compares value to a stored value

− if input value < stored value …

− … signal sent from microprocessor to actuator

− … and light is switched on/off

− whole process continues in an infinite loop Avoiding frequent on/off switches: (max 2 marks)

− microprocessor continues to keep light on/off for a pre-determined period

− after pre-determined period, sensor output is again sampled

[5]




(b) 1 mark for correct sensor, 1 mark for its matching application (all THREE applications must be different) sensor application infra-red/motion automatic doors burglar alarm systems temperature chemical process central heating/air con system greenhouse environment oven sound/acoustic burglar alarm systems leak detection system disco lighting moisture/humidity clothes drier environmental control (greenhouse, air con) pressure burglar alarm system traffic light control chemical process carbon dioxide/ pollution monitoring in a river oxygen/gas greenhouse environment (growth control) confined area (e.g. space craft) Fish tank/Aquarium magnetic field mobile phone anti-lock braking CD players

[6] 8 1 mark per correct word

Freeware Shareware Free software (Computer) Ethics Plagiarism

[5]





statement interpreter compiler

creates an executable file that runs directly on the computer �

more likely to crash the computer since the machine code produced runs directly on the processor

�

easier to debug since each line of code is analysed and checked before being executed

�

slow speed of execution of program loops �

it is more difficult to modify the code since the executable code is now in machine code format

�

[5]

(b) Any one from:

− code is required to be converted into machine code/binary

− code needs to be produced that can be understood by the computer [1]

(c) Any one from:

− close to English/native/human language

− easier/faster to correct errors/read/write

− works on many different machines/operating systems (portable) [1]

(d) Any one from:

− work directly on registers/CPU

− more control over what happens in computer

− can use machine specific functions [1]

(e) 1 mark per correct letter, maximum 2 marks Assembly code: B High-level language code: C Machine code: A

[2]




10 (a) 1 mark for two correct lines, 2 marks for four correct lines

[2] (b) 1 mark for each correct binary value 1 mark for each correct hexadecimal value

hexidecimal

L: 1 1 0 1 1 0 0 0 D 8

G: 1 1 0 0 1 1 1 0 C E

[4]

0 1 1 0 1 1 0 0

0 1 1 0 1 0 0 1

0 1 1 0 0 1 1 1

0 1 1 0 1 1 1 0

L (108):

I (105):

G (103):

N (110):













Section A 1 (a) (i) Many correct answers, they must be meaningful. These are examples only. – MiddayTemperature[1:30]

or MiddayTemperature[0:29]

or MiddayTemperature[30]

or MiddayTemperature[29]

or MiddayTemperature[] (1 mark)

– MidnightTemperature[1:30]

or MidnightTemperature[0:29]

or MidnightTemperature[30]

or MidnightTemperature[29]

or MidnightTemperature[] (1 mark) [2]

(ii) Answers, must match above and the upper bound should have been changed from 30 to 7 or 29 to 6 or no change if not used. These are examples only. – MiddayTemperature[1:7] MidnightTemperature[1:7]

or MiddayTemperature[7] MidnightTemperature[7] [1]

(iii) Any two variables with matching reasons, 1 mark for the variable and 1 mark for the matching reason. The variables and the matching reasons must relate to the tasks in the pre-release. There are many possible correct answers these are examples only. Variable – Counter: (Integer)

Reason – to use as a loop counter when entering the temperature Variable – HighNoon: (Real)

Reason – to store the highest midday temperature [4]




(b) If loop used – initialisation before loop – loop – running total inside loop – calculation of average outside loop – output of average with message outside loop (Max 4 marks) – completion of at least 3 of initialisation, running total, calculation of average and output of average with message for both midday and midnight (1 mark) [5] sample algorithm:

MiddayTotal ← 0; MidnightTotal ← 0

FOR Count ← 1 TO 7

MiddayTotal ← MiddayTotal + MiddayTemperature[Count]

MidnightTotal ← MidnightTotal + MidnightTemperature[Count]

NEXT Count

MiddayAverage ← MiddayTotal/7

MidnightAverage ← MiddayTotal/7

PRINT 'The average midday temperature is ', MiddayAverage

PRINT 'The average midnight temperature is ', MidnightAverage

If loop not used – total of 7 midday temperatures – calculation of midday average (Note could be combined as one calculation, see example below) – total of 7 midnight temperatures – calculation of midnight average (Note could be combined as one calculation, see example below) – output of both averages with suitable messages [5] sample algorithm:

MiddayAverage ← (MiddayTemperature[1]+ MiddayTemperature[2]+

MiddayTemperature[3]+ MiddayTemperature[4]+

MiddayTemperature[5]+ MiddayTemperature[6]+

MiddayTemperature[7])/7

MidnightAverage ← (MidnightTemperature[1]+

MidnightTemperature[2]+ MidnightTemperature[3]+ Midnight[4]+

Midnight[5]+ Midnight[6]+ MidnightTemperature[7])/7

PRINT 'The average midday temperature is ', MiddayAverage

PRINT 'The average midnight temperature is ', MidnightAverage




(c) 1 mark for the data set and 1 mark for the matching reason. There are many possible correct answers, these are examples only. Data set – 30, 29, 28, 31.5, 32.3, 33, 29.7 Reason – normal data that should be accepted Data set – twenty, 23.99, seventeen, 501, –273, @#@, seventy seven Reason – abnormal data that should be rejected [2] (d) Maximum 6 marks in total for question part Explanation (max 6) – set variable called HighestMidday to a large minus number – loop (30 or 7) times to check each midday temperature in turn – check midday temperature against HighestMidday / midday temperature > HighestMidday – …replace value in HighestMidday by midday temperature – …store array index in MiddayMonthDay/MiddayWeekday – output HighestMidday outside the loop – output MiddayMonthDay/MiddayWeekday outside the loop Sample algorithm (max 4):

HighestMidday ← -999 FOR Count ← 1 TO 7

IF MiddayTemperature [Count] > HighestMidday

THEN HighestMidday ← MiddayTemperature[Count]

MiddayMonthDay/MiddayWeekday ← Count

ENDIF

NEXT Count PRINT 'The highest midday temperature was ',HighestMidday, ' on

day ', Count

If pseudocode or programming only and no explanation, then maximum 4 marks [6]




Section B

2 1 mark for each error identified + suggested correction Line 1 or Small = 0: this should read Small = 999

line 5 or IF…: this should read IF Num < Small THEN Small = Num

line 8 or UNTIL: this should read UNTIL Counter = 10 or

UNTIL Counter > = 10 or UNTIL Counter > 9

line 7 or PRINT…: PRINT Small should come after the end of the repeat loop

or line 8 or UNTIL: this should come before line 7 [4]

3

Total Reject Weight Output

0 0

1.8 1.8

1 26.0

8.8 7.0

20.1 11.3

30.1 10.0

32.6 2.5

2 25.2

37.6 5.0

57.4 19.8

3 29.3

–1 57.4, 3

(2 marks) (–1 for each error)

(then follow though)

(1 mark) 1 mark) (1 mark) (allow follow through)

(from Total and Reject)

[5]




4 1 mark for each correct link, up to maximum of 4 marks

[4] 5 Any two points from – a variable is used to store data that can change during the running of a program – a constant is used to store data that will not be changed during the running of a program [2] 6 – FOR (… TO … NEXT)

– REPEAT (… UNTIL)

– WHILE (… DO … ENDWHILE) [3]

7 (a) – 7 [1] (b) – Brochure No – Uniquely identifies each property [2] (c) Garage – Boolean Number of Bedrooms – Number/Integer/Single Price in $ – Number/Single/Real/Currency [3] (d) 399000 H13 450000 H10 [2]

Integer

Real

Char

String

Boolean

'a'

2

2.0

True

'Twelve'




(e)

Field: Property Type Garage Price in $ Brochure No

Table: PROPERTY PROPERTY PROPERTY PROPERTY

Sort:

Show: � � � �

Criteria: True < 200000

or:

or



Sort:

Show: � � � �

Criteria: Yes < 200000

or:

or



Sort:

Show: � � � �

Criteria: =Yes < 200000

or:

or



Sort:

Show: � � � �

Criteria: =-1 < 200000

or:

(1 mark) (1 mark) (1 mark) (1 mark)

[4]













Section A

1 (a) (i) Many correct answers, they must be meaningful. This is an example only. – PupilName[1:30]

or PupilName[0:29] or PupilName[30] or PupilName[29] or PupilName[] [1]

(ii) Many correct answers, they must be meaningful. This is an example only.

– StartWeight[1:30]

or StartWeight[0:29] or StartWeight[30] or StartWeight[29] or StartWeight[] [1]

(iii) Answers, must match (i) and (ii) above and the upper bound should have been changed from 30 to 600 or 29 to 599 or no change if not used. – StartWeight[1:600] or StartWeight[600]

– PupilName[1:600] or PupilName[600] [1] (b) any four from – prompt for entry of final weight that includes pupil’s name – input final weight – validation check for final weight – calculation of difference in weight – ……using the initial weight stored in the array – store difference in weight (Max 4 marks) – loop for 600 pupils (1 mark) [5] sample algorithm: FOR Count � 1 TO 600

REPEAT

PRINT 'Please enter weight for ', PupilName[Count] INPUT FinalWeight

UNTIL FinalWeight < 120 AND FinalWeight > 20

WeightDifference[Count] � FinalWeight - StartWeight[Count]

NEXT Count




(c) (i) any two from – check that the weights are within a given range – check that the weights are numeric – check that the weights are given to one decimal point – character/type check on name – length check on name

[2] (ii) 1 mark for the data and 1 mark for the matching reason. There are many possible correct answers this is an example only. Weight 1 – 35.2 Reason – normal data that should be accepted Weight 2 – twenty Reason – abnormal data that should be rejected [4] (d) Maximum 6 marks in total for question part Explanation (max 6) – loop 30 or 600 times to check each difference in weight – check for a difference in weight – less than -2.5 (final weight – start weight) or greater than 2.5 (start weight – final weight) – …If so output pupil’s name – …if so output difference in weight – …if so output message that it is a fall in weight Sample algorithm (max 4) FOR Count � 1 TO 30 IF WeightDifference [Count] < -2.5 THEN PRINT PupilName[Count], 'The weight loss was ',

WeightDifference [Count] ENDIF

NEXT Count If pseudocode or programming only and no explanation, then maximum 4 marks [6]




Section B 2 1 mark for each error identified + suggested correction Line 1 or Large =9999: this should read Large = 0 Line 3 or WHILE: this should read WHILE Counter < 30 line 6 or IF: this should read IF Num > Large THEN Large = Num line 7 or Counter =…: this should read Counter = Counter + 1 [4]

3 (a)

Trace table set 1

A B C D E F Total Check Output

5 2 4 3 1 5 38 5 Accept

�-----------------------------------(1 mark)-------------------------��----------(1 mark)------�

Trace table set 2

A B C D E F Total Check Output

3 2 1 0 7 3 45 1 Reject

�-----------------------------------(1 mark)-------------------------��----------(1 mark)------�

[4] (b) – (modulo 11) check digit calculation [1] (c) 1 mark for identifying the problem, 2 marks for the solution Problem – doesn’t deal correctly with remainder 10/a check digit of X Solution – check Z for X as a final digit – have a special case where check = 10 – accept where Check = 10 and F = X [3]




Amount = Amount + 1

4 1 mark for each correct line, two lines from one box not allowed

[4]

5 (a) 1 mark for FOR … TO … NEXT 1 mark for INPUT FOR Count � 1 TO 1000

INPUT A[Count]

NEXT (Count) [2]

(b) 4 marks – initialisation – start of loop – update loop counter – end of loop Example1 Count � 1 (1 mark) REPEAT (1 mark) INPUT A[Count]

Count � Count + 1 (1 mark) UNTIL Count > 1000 (1 mark)

Example2 Count � 0 (1 mark) WHILE Count < 1000 (1 mark) DO

Count � Count + 1 (1 mark) INPUT A[Count]

ENDWHILE (1 mark)

[4]

Counting

Repetition

Selection

Totalling

Sum = Sum + Value[n]

IF Value = 10 THEN PRINT

'X'

FOR Counter = 1 TO 10

Sum = Num1 + Num2




6 (a) – 7 [1] (b) – Class ID – Uniquely identifies each student [2] (c) Diana Abur, Paul Smith – both names – ……. correct order [2] (d)

Field: Student Name Maths English

Table: MARKS MARKS MARKS

Sort:

Show: � � �

Criteria: <40 <40

or:

(1 mark) (1 mark) (1 mark) [3]

Documents

2210 COMPUTER SCIENCE - Max Papersmaxpapers.com/wp-content/uploads/2013/06/2210_s15_ms_complete.pdf · If the broadband data download rate is 40 megabits/ second; how long will it