3/11/2013 Standards : 6 (Solutions) O bjectives :

3/11/2013 Standards: 6 (Solutions) Objectives: ● Students will be able to calculate problems involving Molarity (M)

and molality (m)DO NOW: 1. Calculate M (molarity) of a solution with 4.7 L of solution in which

there are 2.2 mol of NaClO4HOMEWORK: 1. Ch 15.2 PP's p. 466 17-20 and Ch 15 Assess. p. 485 76 (a, b, & c)

5 pts (Std 6) 2. Two PRINTS (see website) 3. HANDOUTS TODAY - Tutorial Ch 15.1 - What Are Solutions,

Ch 15.2 - Molarity - Molality - Colligative Properties Std 6===========================================================STAMPS: ● Journal 3/8 1. App A, p. 880 1-2 (1 pt) Std 6 2. Ch 15.2 p. 464-465 PP's 11-16 (4 pts) Std 6

Units of measure in Henry's Law

S (solubility)g/L g/mL mol/L mol/mL (or any unit of volume besides L or mL)

P (pressure)atm, mmHg, Torr, kPa, Pa, psi

(any unit of pressure is OK)

http://group.chem.iastate.edu/Greenbowe/sections/projectfolder/flashfiles/thermochem/solutionSalt.html

SOLVATION ANIMATION

1. agitation

2. increase surface area

3. temperature

Demo - see videomade in classyesterday

http://group.chem.iastate.edu/Greenbowe/sections/projectfolder/flashfiles/thermochem/solutionSalt.html

Units of measure in Henry's Law

S (solubility)g/L g/mL mol/L mol/mL (or any unit of volume besides L or mL)

P (pressure)atm, mmHg, Torr, kPa, Pa, psi

(any unit of pressure is OK)

M

Molarity

Molarity

Molarity

Molarity

Molarity

Molarity

Molarity

Molarity

Molarity

Molarity

Molarity

Molarity

Molarity

Molarity

Molarity

Molarity

Molarity

MolarityMolarity

Molarity

Molarity

Molarity

Molarity

Molarity

Molarity

Molarity

Molarity

Molarity

Molarity

Molarity

Molarity

Mola

rity

Mola

rity

M =

mol L

molarity

molarity

solute

solution

Calculate the molarity of a solution having 15.0 g NaCl in 2.80 L of water (volume of solution is still 2.80 L).

Molar mass Cl = 35.5Molar mass Na = 23.0

In your answer, use 3 sig. figs and do not use any units of measure. NUMBER ONLY

1

m = (milli-) = 1

1000

How to derive equality with prefixes

What is 1 mL equal to in terms of L ?

1

1000mL = L x 10001000 x

1

1000mL = L x 10001000 x

1000 mL = 1 L

1

1000mL = L

k = (kilo-) = 1000

1 kg = 1000 g

How to derive equality with prefixes

What is 1 kg equal to in terms of g ?

Summary

Is it 1000 kg = 1 g or 1000 g = 1 kg ?

prefix letter x its mass unit (or volume)

1 kg = 1000 g

1

10001 mL = L

1 mg = g1

1000

1 kL = 1000 L

prefix value x its mass unit

Make --

=

PREFIXES

1 kg = 1000 g 1 mL = L1

1000

Everything in blue will be a fraction.

Everything in green will be a fraction.

http://mrwiggersci.com/chem/Tutorials/conv-units-all-prefixes.htm

Big Bigger

http://mrwiggersci.com/chem/Tutorials/conv-units-all-prefixes.htm

M

Molarity

2 What is the value of S if 25.0 g of gas is dissolved in 1.00 L of water?

Number only3 sig figs onlyno units of

measure

3 What is the solubility of a gas if 25.0 g of the gas will dissolve in 1.00 L of water.

Number only3 sig figs onlyno units of

measure

p. 463

possible solutes: a. salt (NaCl)b. sugar (sucrose)c. MgCl2 d. C (smaller portion of steel)e. paint pigments

possible solvents:f. waterg. iron (Fe major portion of steel)h. laquer thinner

`

3/13/2013 Standards: 6 (Solutions) (same as yesterday) Objectives: ● Practice Calculations of molarity and mass percentDO NOW: 1. Ch 15 Assess - p. 484 69-71 and 77 (all) & 78 (all) will be stamped as

a 5 pt HW stamp for Th. (5 pts) Std 6HOMEWORK:

None===========================================================STAMPS: ● Journal 3/11 1. Ch 15.2 PP's p. 466 17-20 and Ch 15 Assess. p. 485 76 (a, b, & c)

5 pts (Std 6)

AT YOUR DESK: 1. Two PRINTS (see website) (Bigger - Units of Measure, and

Mass% & Molarity Lab Sheet) (1 pts) Std 6

For Quiz 3.3 number correct x 2.4 = points earned

60 = total possible

Summary

Is it 1000 kg = 1 g or 1000 g = 1 kg ?

prefix letter x its mass unit (or volume)

1 kg = 1000 g1

10001 mL = L

1 mg = g1

10001 kL = 1000 L

prefix value x its mass unit =

Make --

PREFIXES

answers:

69. 3.9%70. 33.6%71. 25%77. a. 0.02 M (mol/L)

b. 0.27 M (mol/L) c. 0.0847 M (mol/L)78. a. 0.02 M mol

b. 0.00625 molc. 0.648 mol

3/13/2013 Standards: 6 (Solutions) (same as yesterday) Objectives: ● Practice Calculations of molarity and mass percentDO NOW: 1. Ch 15 Assess - p. 484 69-71 and 77 (all) & 78 (all) will be stamped as

a 5 pt HW stamp for Th. (5 pts) Std 6HOMEWORK:

None===========================================================STAMPS: ● Journal 3/11 1. Ch 15.2 PP's p. 466 17-20 and Ch 15 Assess. p. 485 76 (a, b, & c)

5 pts (Std 6)

AT YOUR DESK: 1. Two PRINTS (see website) (Bigger - Units of Measure, and

Mass% & Molarity Lab Sheet) (1 pts) Std 6

3/14/2013 Standards: 6 (Solutions) Objectives: ● Students will be able to calculate boiling point INcreases, and freezing

point DEcreases. ● Demonstrate conducive solutions. Students will be able to recognize

compounds that ionize (make 2 or more particles, salts, acids & bases) as different from those who don't ionize (sugar).

DO NOW: 1. Name 3 kinds of substances ionize in water, and give one example

of each?HOMEWORK: 1. Ch 15 Assess p. 485 79 (a,b,c), Ch 15.4 p. 475 33, 34,

Ch 15 Assess p. 485 87 (a,b,c) (5 pts ) Std 6 (total problems = 8)===========================================================STAMPS: ● Journal 3/13 (for periods 1,3,5) or 3/14 (for periods 2,6) 1. Ch 15 Assess - p. 484 69-71 and 77 (all) & 78 (all) will be stamped as

a 5 pt HW stamp for Th. (5 pts) Std 6

period 2 was in assembly, which I photographed. It was on driving safely.

Answers: 78 a = 0.0320 mol; b = 0.00625 mol ; c = 0.648 mol 79 a = 0.0859 g; b = 34.6 g; c = 5.91 g 87 a = fp = 10.2 deg C, bp = 103.8 deg C

b = fp = -115.8 deg C, bp = 79.1 deg C c = fp = -1.0 deg C, bp = 83.3 deg C

m = molality =

mole solute

kg solvent

M = molarity =

mole solute

L solution

Boiling & freezing points of water can be changed by dissolving:

BP

100°C

FP 0°C

ionic compounds (salts, acids, bases) non-ionic compounds (like sugar that don't form ions)

p. 474p. 472

More in the changes shown in charts

BIGGER

particles

changes

BP

FP

100°C

0°C

Kb °C/m

Kf °C/m

p. 474p. 472


BIGGER

particles

changes

molaltiymol (solute)

kg (kg solvent)=


kg (kg solvent)=


kg (kg solvent)=

p. 474p. 472


BIGGER

particles

changes

3/15/2013 Standards: 6 (Solutions) Objectives:● Polish skills learned in this chapterDO NOW: 1. Due end of period (8 points):

Directions: All problems require calculations. So, show given, find, and calculations. Each problem is worth one point.

p. 484 67 1 x 101 atm p. 487 3 a71 25% 4

cp. 485 78 (b) 0.00625 mol 5 b

89 fp = -6.46 deg C bp = 101.8 deg

HOMEWORK: Enjoy your week off and Think about Easter===========================================================STAMPED: ● Journal 3/14 1. Ch 15 Assess p. 485 79 (a,b,c), Ch 15.4 p. 475 33, 34,

Ch 15 Assess p. 485 87 (a,b,c) (5 pts ) Std 6

3/14/2012 Standards: 6 (Solutions) Objectives:● Complete data gathering and calculations of your mass% & molarity and turn in to basket before end of the periodDO NOW: READ LAB SILENTLY AND try to figure out your procedure.HOMEWORK: Enjoy your week off and Think about Easter===========================================================TURNED IN TO BASKET: ● Journal NONE TODAY

(for this lab, assume vol of solution =

20.00mL)

1.000 g = 1.000 mL (only for water)

mass % =

g soluteg solution x 100

M = (molarity)

mol (solute) L (solution)

When you come to me to get your salt, you will need to show me these masses:

1. filter paper2. graduated cylinder3. 50 mL beaker

All masses must have 3 decimals Examples: 0.l56 g

0.033 g3.427 g

Gp #

g NaCl g H20 g soln Mass % M

1

2

3

4

5

6

7

8

9

Mass % & Molarity LAB - RESULTS BY GROUPPer 1

Gp #

gNaCl g H20 g soln Mass % M

1

2

3

4

5

6

7

8

9


Gp #


1

2

3

4

5

6

7

8

9



Gp #


1

2

3

4

5

6

7

8

9

Gp #


1

2

3

4

5

6

7

8

9


Gp #


1

2

3

4

5

6

7

8

9

Mass % & Molarity LAB - RESULTS BY GROUPPer

Work problems p. 475 33-36

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3/11/2013 Standards : 6 (Solutions) O bjectives :