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2 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
Contents
# Title Page
1 Energy Balance and Body Weight Control 3
2 Colorimetric Determination of Sugars in Dates: Phenol-Sulfuric Acid Colorimetric
Method 11
3 Qualitative Estimation of Fructose in Biological Material 16
4 Extraction of Total Lipids by Bligh and Dyer Method 20
5 Determination of Fat in Potato Chips 25
6 Determination of protein in milk using formaldehyde method 31
7 Determination of chloride content in cheese 35
8
Determination of Vitamin C in Foods by Iodometric Assay 40
Total acidity of fruit juices 46
9 Determination of nicotinic acid in food 50
10 Determination of Tannins in Tea 55
11 Estimation of water content in cow‟s milk 59
3 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
Energy Balance and Body Weight Control
Nutritional Assessment
Nutrition assessment evaluates a person’s health from a nutrition perspective by:
- History taking.
- Physical examination
- Biochemical analysis.
- Anthropometric measurements.
There are different methods that can help you evaluate the health of your current body weight.
1) Body Mass Index
Body Mass Index (BMI) is a number calculated from a person‟s weight and height. BMI is used
as a screening tool to identify possible weight problems for adults. However, BMI is not a diagnostic
tool. For example, a person may have a high BMI. However, to determine if excess weight is a health
risk, a healthcare provider would need to perform further assessments. BMI is calculated as:
Methods
Body Mass Index
(BMI) Body Composition Fat Distribution Pattern
BMI =𝐵𝑜𝑑𝑦 𝑤𝑒𝑖𝑔ℎ𝑡 (𝑘𝑔)
𝐻𝑒𝑖𝑔ℎ𝑡𝟐(𝑚)
4 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
BMI for adults are interpreted as follows:
BMI Weight Status Comment < 18.5 Under weight Associated with increased risk of
health problems and death
18.5 to 24.9 Normal Healthy weight-for-height
25 to 29.9 Over weight
30 to 39.9 Obese Increased health risk
≥40 Morbid obesity Major health risk
Note: Adult BMIs should not be applied to children, still growing
adolescents, older people, pregnant and lactating women and high muscular
.
Exercise (1):
Calculate your BMI? What your value
shows?
5 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
2) Body Composition
Body composition is the proportion of fat and fat-free mass (muscle, bone, organs,
and water) that make up a person‟s total body weight. Direct measures of body
composition are impossible in living human beings. Instead, researchers assess body
composition indirectly based on the following assumption
Body weight = Fat + Lean tissue (including water)
Healthy body composition involves a high proportion of fat-free mass
and an acceptably low level of body fat, adjusted for age and gender.
Figure 1: Body Composition
6 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
How is Body Composition Measured?
There are several different methods used to determine how much
fat your body is carrying
Skinfold measurement
Girth measurements
Body Weight
Hydrostatic Weighing (also known
as underwater weighing)
How many factors influence body composition
Gender, age, diet, activity level, and genes
*Some aspects of your body composition are genetic (where you store fat), but
most fat increase is related to lifestyle
How to lose fat?
Through a lifestyle that includes a sensible diet and exercise.
How to add muscle mass?
Through resistance training/strength training.
7 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
3) Fat distribution patterns:
The prevalence of abdominal obesity exceeds that of general obesity. Obesity is
associated with an increased risk of multiple cardio-metabolic risk factors. To evaluate
the health of your body weight, it is also helpful to consider the way fat is distributed
throughout your body. This is because your fat distribution is known to affect your risk
for various diseases. Some people store fat in upper- body areas whereas others stores fat
lower on the body.
Types of fat patterning
Figure 2: Types of fat patterning.
Pear
shaped
Doesn'tseemto
significantlyincreasea
person'sriskforchronic
disease
8 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
To determine the type of fat patterning, flow these steps:
1-Measure your circumference of natural waist in inches
(i.e. the narrowest part of your torso from the front).
2- Measure your hip circumference (in inches).
3- Divide the waist value by the hip value. This
measurement is called “waist-to- hip ratio”.
A ratio higher than 0.90 (in men) and higher than 0.80 (in women) is an
apple shaped fat distribution pattern.
Exercise (2):
A 45 years old man, his waist
circumference is 50 inches and his hips
are 40 inches: calculate his hip-to-waist
ratio?
What type of fat patterning does he have?
Is he in risk for chronic disease? Why?
Exercise (3):
- Calculate your waist-to-hip ratio? - What type of fat patterning do you have? - Are you at risk for chronic disease?
9 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
The energy content of
each food is comes from
Carbohydrates
provides 4 Kcal/g
Fat
provides 9 Kcal/g
Alcohol
provides 7 Kcal/g
Protein
provides 4 Kcal/g
Energy Balance
To achieve or maintain a healthy body weight you must pay more attention to the
important concept of Energy Balance, that is the relationship between “energy in”
(food calories taken into the body through food and drink) and “energy out” (calories
being used in the body for our daily energy requirements).
Energy intake
The value of energy intake includes all foods and beverages, expressed as calories
or kilocalories per day (cal/day or Kcal/day).
Energy intake = Energy expenditure
10 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
References
Wardlaw, G. and Smith, A. (2009): Contemporary Nutrition. Seventh edition.
McGrowHill.USA. (chapter 7) How the number of calories in a certain food is
determined with a bomb calorimeter instrument
Thompson, J. and Manore, M. (2009): Nutrition an applied approach. Second edition.
Pearson Benjamin cummings. USA.(chapter 11) various methods for the determination
of body composition.
)األولي الطبعث الغذائية. الوجباخ جخطيظ ( 2004) نحس بي عصام ،ةعويض الحاسع الفصل. ىزأخ قزط (
.ةالكلي ةالطاق تإححياجا إجوالي زيذلحق
Exercise (4):
One cup of oatmeal contains 6 gm of protein, 25 gm
of carbohydrates and 2 gm of fat. Calculate the total
energy content of this oatmeal?
11 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
Colorimetric Determination of Sugars in Dates: Phenol-
Sulfuric Acid Colorimetric Method
Background
Dates are a good source of various vitamins and minerals. It‟s a
good source of energy, sugar and fiber. Essential minerals such as
calcium, iron, phosphorus, sodium, potassium, magnesium and zinc are found in dates. It
also contains vitamins such as thiamin, riboflavin, niacin, folate, vitamin A and vitamin
K.
The phenol-sulfuric acid is simple and rapid colorimetric method to determine total
carbohydrates in a sample. The method detects virtually all classes of carbohydrates,
including mono-di-,oligo- and polysaccharides.
In this method, the concentrated sulfuric acid breaks down any
polysaccharides, oligosaccharides, and disaccharides to monosaccharides. Pentose’s
carbon compounds) are then dehydrated to furfural, and hexoses(6-carbon
compounds) to hydroxyl methyl furfural. These compounds then react with phenol to
produce a yellow-gold color. For products that are very high in xylose(a pentose), such
as wheat bran or corn bran, xylose should be used to construct the standard curve for the
assay, and measure the absorption at 480 nm. For products that high in hexose sugars
glucose is commonly used to create the standard curve and the absorption is measured at
490 nm.
12 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
The color for this reaction is stable for several hours and the accuracy of the
method is within ±2% under proper conditions.
Carbohydrates are the major source of calories in soft drinks, beer and fruit
juices, supplying 4 Cal/g carbohydrate.
Objective
Determine the carbohydrate concentration of dates and soft drinks, then calculate the
calorie content those samples.
Principle
Principle of this method carbohydrates(simple sugars oligosaccharides polysaccharides,
and their derivatives) react in the presence of strong acid and heat to generate furan
derivatives that condense with phenol to form stable yellow-gold compounds that can be
measured spectrophotometrically,
Chemical & Material Hazards
Phenol [C6H6O] 5%: dissolve 50gm of redistilled phenol in water
and dilute to 1-L
Toxic
Sulfuric acid [H2SO4], concentrated, 96% Reagent grade. Corrosive
Sugar solution, fructose, 0.3g/l.
Arabinose or fructose Dates Distilled water
13 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
Equipment
Mortar Laboratory balances
Volumetric flask (100ml) Vortex mixer
Conical (Erlenmeyer)flask (100ml) Water Bath
Volumetric Cylinder Spectrophotometer or colorimetric
Filter Paper
Funnel
Pipette 1ml & 5ml
Cuvette
Test Tube
Method
A. Preparation of date’s homogenate
1- Weigh accurately 1gm of dates.
2- Homogenize in 50ml of distilled water in a warring blender.
3- Boil for 10min.
4- Cool, and filter in a 100ml volumetric flask, and complete to volume with water.
Shake well to mix. Decolorize with charcoal if necessary.
5- Dilute 1ml of the above solution to 100ml and use it as unknown.
B. Preparation of date’s homogenate
1- Prepare sugar standard curve from 10-70 μg/ml (0.075-0.15-0.225-0.3 mg/ml).
2- Pipette 0.5ml of aqueous sample solution of sugar into colorimetric tube (cuvette) .
3- Add 0.5ml of 5% phenol and mix.
4- Add 2.5ml of sulfuric acid from a fast-flowing dispenser to each tube in
order to produce good mixing and even heating.
5- Mix the contents of each tube by the same technique and let stand in air for 10 min.
6- Cool to room temperature.
7- Read the absorbance of the yellow-orange color at 490 nm for hexsose and 480 nm for
pentoses.
8- Plot a standard curve of sugar ranging from 10-70 μg/ml of sugar
14 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
Calculation
Determine the concentration of the sugar from the standard curve or by the
equation as follow.
=
References
Nielsen, S. (2003): Food Analysis. Third Edition. Kluwer Academic/Plenum Publishers .
والحوسيع للنشز الفجز دار .األولي الطبعة .األغذية جحليل ( 2002 ) أنور عاطف أبوعزب، دمحم، إبزاهين حسن،
15 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
Result Sheet
* Fill the table with your results
* Draw a standard curve of Conc. vs. Abs.??
* Determine the concentration of the sugar from the standard curve ?
Concentration
(Conc.)
Absorbance
(Abs(
16 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
Qualitative Estimation of Fructose in Biological
Material
Background
Fructose, the sweetest of sugars, is a simple carbohydrate also
known as fruit sugar. It is found mainly is fruits, from which it gets its
name, or in honey. Honey therefore is a form of sugar and cannot be
used as a sugar substitute. The amount of fructose in fruits depends on the degree of
ripeness.
As the fruit ripens, some of the stored starch turns to sugar. High fructose corn
syrups are increasingly being used in processed food products, and contribute a major
source of increases sugar intake. Fructose is the sweetest simple sugars.
Objective
Estimation amount of fructose in different types of food.
Principle
The fructose sugar is dehydrated in the presence of concentrated HCI to form
hydroxymethyl furfural. The formed furfural derivative then condenses with resorcinol
to yield a cherry red colored product that is measured spectrophotometrically at 470nm.
17 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
Method
1-In each tube(standard, unknown and blank*) place the following:
(2 ml sample -2 ml reagent A -6 ml reagent B), then mix
2-Let stand in a water bath for 8 min. at 80oC. Cool to room temperature and read at
530nm.
* Can be use water as blank.
Chemical & Material Hazards
Fructose standard solution: 2mg/ml, 2g/l, or 0.2g/l if it is so concentrated
you can use 1mg/ml).
Fruit juice: Make decolorization by charcoal, filtrates, and then dilutes
1ml juice with 100ml-distilled water.
Honey: 0.4g/100ml.
Reagent (A): freshly prepared: 50mg resorcinol (0.05g) dissolved up to
50ml with 95% ethanol. Store in a dark bottle at 4oC.
Reagent (B): 50ml conc. HCl is added carefully to 10ml water. Corrosive
Equipment
Conical (Erlenmeyer) flask (200ml) Laboratory balances Pipette (5ml) Centrifuge and its tubes
Backer (50ml) Hot Plate
Mortar
Volumetric Cylinder
Dropper
Funnel
Filter Paper
18 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
Abs= Absorbance
Conc.= Concentration
Unk= Unknown
St= Standard
Calculation
Determine the concentration of the fructose
=
Reference
Fasman, G. D. (1989). Practical handbook of biochemistry and molecular biology. CRC
press.
19 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
Result Sheet
Calculate the concentration of the fructose in your sample?
20 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
The mixture of organic
solvent used to
prevent any
hydrolysis
or oxidation for lipid
Extraction of Total Lipids by Bligh and Dyer Method
Background
Lipids form a heterogeneous group of hydrocarbon
containing organic compounds which categorized by the fact that
they are soluble in nonpolar solvents (such as alcohol, acetone,
chloroform, benzene, ether and hexane) and are relatively insoluble
in water. Lipid molecules have these properties because they consist largely of long
hydrocarbon tails which are hydrophobic in nature.
Other than this hydrophobicity, no other common features can be attributed to
their structure. This property of specific solubility is made use of in extracting lipids from
tissues; free from any water-soluble matter but the subsequent analytical methods are
largely individualistic.
For general extraction of almost all lipids from biological samples, either a
mixture of ethanol and ethyl ether or a mixture of chloroform and methanol is used. The
lipids are generally bound to proteins in the biological samples and in that situation (as
lipoprotein) cannot be efficiently extracted by non-polar organic solvents alone. The
inclusion of methanol or ethanol helps in breaking the bonds
between the lipids and proteins.
Objective
Extraction of total lipids in different of sample (milk, coffee mate,
chips and chocolate).
21 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
Principle
Lipids are soluble in organic solvents and insoluble in water.
Therefore, water insolubility is the essential analytical property used as the basis for the
separation of lipids from proteins, water, and carbohydrates in foods.
Chemical & Material Hazards
Chloroform carcinogen
Ethanol Flammable liquid and vapor
Samples such as (milk, coffee mate, chips and chocolate)
Distilled water
Equipment
Conical (Erlenmeyer) flask (200ml) Laboratory balances Pipette (5ml) Centrifuge and its tubes
Backer (50ml) Hot Plate
Mortar
Volumetric Cylinder
Dropper
Funnel
Filter Paper
22 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
Method
1- Weigh 1g of sample.
2- Grind it with 5ml of distilled water
3- Transfer in conical flask with 15ml of chloroform and ethanol mixture (2:1 v/v) and
mixed well.
4- For complete extraction, it is advisable to keep this for 30 minutes at room
temperature in dark place.
5- At the end of this period centrifuge for 10 minutes at 2000-3000 rpm.
6- Generally 3 layers are seen, a clear lower layer of chloroform containing the entire
lipid.
7- The methanol layer is discarded and the lower layer is carefully collected free of inter
phase either by sucking out with a fin capillary or by filtration through glass wool.
23 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
8- The organic layer "lower layer" is taken in a pre-weighed beaker (W1) and carefully
evaporated by keep the sample in warm water bath. It is also advisable to keep the sample
covered with a dark paper to protect from light, because some lipids get polymerized or
decomposed on exposure to light and heat.
9- When the solution is free of organic solvents, the weight is determined again (W2).
Calculation
The weight of lipids =W2 – W1= Z gm of lipids
G% =
The kcal provided by the sample
1 gm of lipid 9 kcal
z gm ??
The Kcal provided by the sample= Z × 9= Y Kcal
References
Nielsen, S. (2003): Food Analysis. Third Edition. Kluwer Academic/Plenum Publishers .
24 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
Result Sheet
Calculate the weight of lipid and the kcal provided by the sample
25 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
Determination of Fat in Potato Chips
Background
Recently, there has been a lot discussion of calories and
fats in our foods in the news media. Most food labels list
recommended serving sizes, sometimes with unrealistic
quantities, of the food product and then lists the nutritional
information based on that serving, assuming a 2,000 calorie per day diet.
Nutritional information usually includes calories, total fat, saturated fat, cholesterol,
sodium, total carbohydrate (with separate listing of dietary fiber and sugars), and protein.
The label information may also include vitamins and minerals. Nutritionists recommend
that no more than 30% of our daily 2000 calories come from fat. However, in our snack
food and fast food world, we often eat a diet that contains a larger percentage of fat. So,
the question arises, how much fat is in a snack bag of a food such as potato chips, or a
standard serving of French fries?
Objective
Determining the fat content of several different brands of potato chips using a technique
called extraction.
26 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
Principle
Extract the fat from food. Extraction is the process of dissolving one substance
from a mixture of chemicals and separating it from the rest of the mixture. Fat is soluble
in organic solvents but not water. Adding an organic solvent to a mixture will separate
the fat from the rest of the chemicals. You can then evaporate the solvent (these are
almost always low boiling liquids) to leave the fat behind.
Method
1. Take amount of potato chips. Place them in a small plastic bag and crush them.
2. Weigh 2g of potato chips
3. Transfer them in round bottom flask and weigh (W1)
4. Add 4 mL of hexane to the flask.
5. Mix the hexane with the crushed chips by gently swirling the flask for about 1
minute.
Chemical & Material Hazards
Hexane [C6H14] Flammable
Chips
Equipment
Conical (Erlenmeyer)flask (250ml) Laboratory balances
Pipette (5ml) Water Bath
Beaker (30ml) Hot plate
Small plastic bag
27 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
6. Carefully, pour off the hexane into a waste container, without pouring any pieces
of the crushed chips. A small amount of hexane will remain in the flask.
7. Add 2 mL of hexane to the flask.
8. Mix the hexane with the crushed chips by gently swirling the flask for about 1
minute.
9. Carefully, pour off the hexane into a waste container, without pouring any pieces
of the crushed chips. A small amount of hexane will remain in the flask.
10. Repeat steps 7,8 and 9
11. Heat the flask, with the crushed chips, in the hot water bath for about 5 minutes to
evaporate any residual hexane.
12. Remove the flask from the water bath, allow it to cool and wipe any drops of
water from its outer surface.
13. Determine the mass of the flask and the rinsed crushed chips(W2).
14. Calculate the amount of fat in your sample of chips. Share your results with your
class.
28 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
Calculation
Mass of fat in the chip sample: W1-W2= X g
The percent of fat in a sample:
% Fat = ( )
( )
× 100= Z g%
Total fat at bag: X 2 g of chips
Y Weigh of chips in bag
Kilocalories: 1g of fat 9 kcal
X ? kcal
References
David A. Katz. (2013). Determination of Fat in Potato Chips and French Fried Potatoes
https://www.pdffiller.com/en/project/50436156.htm?form_id=25636407
Determining How Much Fat is in Food -Austin Peay State University Department of
Chemistry - CHEM 1021
https://www.apsu.edu/sites/apsu.edu/files/chemistry/SP11_1021_DETERMINING_HO
W_MUCH_FAT_IS_IN_FOOD.pdf
29 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
Result Sheet
Calculations
Brand of chips used __________________
Mass of chips _________________ g
Mass of flask and crushed chips _______________g
Mass of flask and the rinsed crushed chips _________________ g
Mass of fat in the chip sample _________________ g
Percent of fat in the chip sample _________________ %
Share your results with your class of another brand of chips
Brand of chips Mass of fat in 5 g of chips Percent of fat in the chip sample
30 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
Result Sheet
Answer the following
1. How much fat is in one recommended serving of the chips you tested.
2. How do your results compare with the fat content as listed on the label of the
chips?
3. What sources of error may have occurred in this experiment. (Do not include
calculation error.)
4. Why is hexane used to extract the fat from the chips? Why was water not
used?
5. Why was the hexane added in three separate portions and not in one portion?
31 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
Determination of protein in milk using formaldehyde
method
Background
On addition of formaldehyde to milk. Aldehyde group and free
amino group present in protein combines together these group exist for
this reaction. Due to that the basic character of the amino group and due
to enters the reaction with formaldehyde → media for the reaction
becomes acidic rather than neutral (due to a produce of carboxylic
acidic group)
When neutralizing the acidity results for formaldehyde addition → we can
estimate the amount of the amine group and there for the protein content of the milk is
determined.
Objective
Determination of protein in milk
Protein (neutral) (Acidic)
Formaldehyde
32 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
Chemical & Material Hazards
NaOH 0.1- 0.5 N Corrosive/ irritant
Phenolphthalein (indicator) Harmful/ irritant
Formalin 40% highly flammable
Milk
Method
1- Pipette 5ml of milk in conical flask then add 2 drops of ph.ph.
2- Titer with NaOH until pink color produced
3- Add 2 ml formalin then shake (pink color disappear)
4- Titer by NaOH pink color will appear.
5- Prepare the blank ( 5ml H2O and 2 drops of ph.ph).
6- Titer with NaOH to produced pink color.
Equipment
Conical flask (250ml) Small beaker (50ml)
Pipette (10ml) Measuring cylinder (25-50 ml)
Dropper
Burette and stand
33 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
T= test
B= Blank
Calculation
Protein = T-B x factor
Cow milk factor = 1.67gm%
Baffle milk factor = 1.66gm %
34 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
Result Sheet
35 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
Determination of chloride content in cheese
Background
Sodium chloride is added to cheese to enhance its
taste, and also as a preservative so that some types of
cheese will keep well at room temperature. In the
industrial preparation of certain cheeses, such as
mozzarella, it is important to check that the quantity of salt added is of an optimum
concentration.
Objective
Determine the concentration of chloride ions in cheeses
Principle
Sodium chloride is precipitated in acidic solution with excess silver nitrate; the
excess unreacted silver nitrate is determined by back titration with a thiocyanate
solution.
Before the titration an excess volume of a silver nitrate solution is added to the
solution containing chloride ions, forming a precipitate of silver chloride. The term
„excess„ is used as the moles of silver nitrate added are known to exceed the moles of
sodium chloride present in the sample so that all chloride ions present will react.
Ag+(aq) + Cl–
(aq) → AgCl(s)
36 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
The indicator Fe+3
(ferric ion) is then added and the solution is titrated with the
potassium thiocyanate solution. The titrate remains pale yellow as the excess (unreacted)
silver ions react with the thiocyanate ions to form a silver thiocyanate precipitate.
Once all the silver ions have reacted, the slightest excess of thiocyanate reacts with
Fe+3
to form a dark red complex.
Ag+(aq) + SCN–(aq) → AgSCN(s)
Fe3+(aq) + SCN–(aq) → [FeSCN]2+
(aq)
Left flask: before the titration endpoint, addition of SCN-
ions leads to formation of silver thiocyanate precipitate,
making the solution cloudy. Here the solution also takes a
faint yellow color due to the color of the cheese extract.
Centre flask: at the endpoint all the free silver ions have
been precipitated by SCN-. The slightest excess of SCN-
forms a dark red colored complex with theFe3+ ions from
the ferric ammonium sulfate indicator, giving the solution a
slight orange/ red coloration
Right flask: If addition of SCN- is continued past the
endpoint, further ferric thiocyanate
complex is formed and a stronger dark red color results.
37 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
Method
1- Weigh accurately a sample of cheese (about 0.5g) into a conical flask.
2- Add 3.5 ml water and heat the flask to about 75oC in water bath for 10 minutes.
3- Add 8.5 ml of standard 0.05 M silver nitrate (in hood).
and add 1.7 ml conc. nitric acid (HNO3) (in hood)
4-Digest the cheese curd by boiling gently for 10 minutes.
5-Cool, filter in conical flask then add about 16.5 ml water.
6-Titrate with standard potassium thoicyanate using iron (III) alum (Ferric alum)
indicator (0.6 ml).
7-The end-point is an dark red tint, which should persist for fifteen
seconds. Record the volume of KSCN as volume.
8- The experiment can be repeated with different cheese for comparison. For each
calculate the percentage of chloride (expressed as NaCl).
Chemical & Material Hazards
Concentrated nitric acid [HNO3-] Corrosive
Silver nitrate [AgNO3], (0.05N) Corrosive
Potassium thiocyanate [KSCN]
Ferric alum [Fe+] indicator
Cheese
Distilled water
Equipment
Conical (Erlenmeyer)flask (50-100ml) Laboratory balances
Volumetric Cylinder Water Bath
Filter Paper Hot plate
Funnel
Pipette 10ml & 2ml
Burette and stand
38 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
Calculation
1L 1N of silver nitrate= M.Wt. of sodium chloride
1 ml (0.05N) of silver nitrate=
of NaCl
1 ml (0.05N) of silver nitrate = 0.0029 g of NaCl
(8.5 ml - Titer No.) = ??
Number of grams of sodium chloride = ( )
= Y gm
% NaCl =
( )
× 100= Z g%
References
Determination of Chloride Ion Concentration by Titration (Volhard’s Method).
University of Canterbury- College of Science-Christchurch-New Zealand
http://www.outreach.canterbury.ac.nz/chemistry/documents/chloride_volhard.pdf
If the cheese contain more than 30%
Salt, required add more AgNO3
39 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
Result Sheet
Calculate the concentration of sodium chloride in the different types of
cheese as grams of salt per 100 g cheese (% salt).
40 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
Determination of Vitamin C in Foods by Iodometric
Assay
Background
Vitamin C, is a water soluble vitamin that is an essential
antioxidant necessary for normal growth and development. It more
properly called ascorbic acid. Deficiency of vitamin C can lead to a
disease called scurvy, which is characterized by abnormalities in the bones and teeth. It is
important to consume it every day, because the body excretes it regularly and can‟t be
stored for later use.
Many fruits and vegetables such as (green peppers, broccoli, citrus fruits,
strawberries, tomatoes and white potato ) contain on vitamin C, that destroy by cooking,
so raw citrus fruits and their juices are the main source of ascorbic acid for most people.
Also the fish and milk contain small amounts vitamin C.
Objective
Determine the amount of vitamin C in different types of juice.
Principle
Vitamin C can be assayed by a redox titration using iodine. As the iodine is added
during the titration, the ascorbic acid is oxidized to dehydroascorbic acid, while the
iodine is reduced to iodide ions.
Recommended daily allowance (RDAs) of vitamin C is = 70mg/day.
41 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
Due to this reaction, the iodine formed is immediately
reduced to iodide as long as there is any ascorbic acid present.
Once all the ascorbic acid has been oxidized, the excess iodine
is free to react with the starch indicator, forming the blue-
black starch-iodine complex. This is the endpoint of the
titration.
Chemical & Material Hazards
Iodine I2 (0.1 N), keep in a dark glass bottle(Amber) to protect form light
Standard ascorbic acid 0.1 gm/100 ml
Starch indicator (1%)
+ I2 Oxidation
Reduction
2 I- 2 e- 2 H+ + ++
Ascorbic Acid
(Vitamin C)
Dehydroascorbic Acid
(Oxidized form)
Iodine Iodide
Figure: Redox Reaction
42 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
Method 1- Measure 10ml of juice in the flask
2- Add 10 drops of starch, mix well and cover the flask by aluminum foil to prevent
oxidation by atmospheric oxygen.
3- Titer with 0.1 N iodine to obtain → blue color
4- Repaid the experiment and take the average number
Equipment
Conical (Erlenmeyer) flask (250ml) Small beaker (50ml)
Pipette (10ml)
Dropper
Burette and stand
43 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
Calculation
1L 1N of iodine (I2) = M.Wt. of vitamin C (ascorbic acid) (179.14g/mol)
1 ml (0.01N) of iodine (I2) =
of ascorbic acid
1 ml (0.01N) of I- = 0.0088 g of ascorbic acid
Titer no. of iodine (I-) = T
No. of grams of ascorbic acid =
= Y gm
% Ascorbic acid =
( )
× 100= Z g%
References
Determination of Vitamin C Concentration by Titration
University of Canterbury- College of Science-Christchurch-New Zealand
http://www2.moh.gov.my/images/gallery/rni/8_chat.pdf
Official Methods of Analysis. 1999. 16th Edition, 5th Reversion, AOAC International,
Gaithersburg, MD, method 967.21.
44 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
Result Sheet
Calculations
1. Calculate the average volume of iodine solution used from your concordant
titers?
2. Calculate the moles of iodine reacting.
45 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
Result Sheet
3. Share your results with your class of another types of juices
Type of juice G % of vitamin C
4. Which is the type of juice rich with vitamin C ? and which is type have
the least amount of it ?
46 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
Total acidity of fruit juices
Background
The acidity of natural fruit juices is the result mainly of their content of organic acids. For
example, most fruits contain the tricarboxylic acid (citric acid) whereas grapes are rich in
tartaric acid & peaches, apricots & plums in malic acids. Both tartaric & malic acids are
dicaroxylic acids.
Objective
To determine the total acidity in various fruit juice samples by titration with alkali
Principle
The acidity of fruit juice may be determined by simple direct titration with 0.1M sodium
hydroxide, using phenolphthalein as an indicator.
47 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
Chemical & Material Hazards
Sodium hydroxide NaOH (0.1 M) Corrosive/irritant
Phenolphthalein 1% Harmful/ irritant
Fresh fruit juice ( orange or lemon )
Method
1. Weight 10ml of sample in conical flask & add 25ml distilled water
2. Titrate using 0.1M NaOH and add phenolphthalein as an indicator
3. Calculate the total acidity of your fruit juice.
Equipment
Conical flask (250ml) Small beaker (50ml)
Pipette (10ml) Measuring cylinder (25-50 ml)
Dropper
Burette and stand
48 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
Calculation
Calculate the total acidity:
eq . OH (moles) = 0.1 ×vol.ofNaOH (ml) ×10-3
g. citric acid = ( ) -
g. tartaric acid = ( ) -
g. malic acid = ( ) -
% acidity =
References
http://www.hawkinswatts.com/documents/OECD%20fruit%20acid%20determination%2
0method.pdf
https://www.flinnsci.com/media/620683/91263.pdf
49 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
Result Sheet
Calculations
Calculate the total acidity from your concordant titers?
50 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
Determination of nicotinic acid in food
Background
Niacin is a water-souluble vitamin, also known as vitamin B3. Niacin is
the generic term for nicotinic acid and nicotinamide with pyridine as the basic
structure. Nicotinic acid and nicotinamide function mainly as precursors of the
co-enzymes NAD and NADP. Thus, nicotinamide has physiologically critical
roles in mitochondrial respiration and in the metabolism of carbohydrates, lipids, and
amino acids.
Nicotinic Acid
(pyridine 3-carboxylic acid)
Nicotinamide
(pyridine 3-carboxylic amide)
Figure: Structural formula of niacin forms
Clinical evidence of niacin deficiency includes fatigue, poor appetite, diarrhea,
irritability, headache, emotional instability and possible memory loss. These may lead to
changes in the skin, mucosa of the mouth, stomach and intestinal tract and the nervous
system. These changes are called “pellagra”, which means “raw skin” and are most
pronounced in the parts of the skin exposed to sunlight. Other signs and symptoms
include dizziness, vomiting, constipation or diarrhea, and inflammation of the tongue and
51 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
gastric mucosa. The neurological symptoms can include fatigue, sleeplessness,
depression, memory loss and visual impairment. If untreated, pellagra is ultimately fatal.
Important sources of preformed niacin include beef, liver, fish, peanuts and other
nuts, whole grains and whole-meal wheat flour. In general, food rich in protein, with the
exception of tryptophan-poor grains, can satisfy some of the requirement for niacin.
Human milk contains a higher concentration of niacin than cow‟s milk. Besides dietary
niacin as a source for the synthesis of NAD, it may also be synthesized in the liver from
tryptophan, an essential amino acid.
Objective
Determine the amount of nicotinic acid in dried yeast
Principle
Nicotinic acid is pyridine-3-carboxylic acid, and can be determined by direct titration
with carbonate-free 0.1 N sodium hydroxide using phenol red or phenolphthalein as
indicator.
Chemical & Material Hazards
Sodium hydroxide [ NaOH ] (0.1 N)
Yeast
Distilled water
Phenol red or phenolphthalein
52 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
Method
1- Weigh accurately about 2g of sample.
2- Grind thoroughly in a mortar with about 10 ml of distilled water
3- Centrifuge at 3000 rpm for 10 min.
4-Transfer supernatant into conical flask for titration
3- Add about 2-3drops of either phenol red or phenolphthalein.
4- Titrate with 0.1 N NaOH until the end point is reached.
Equipment
Conical (Erlenmeyer) flask (250ml) Laboratory balances Pipette (10ml) Centrifuge and its tubes
Dropper Burette and stand
Mortar
Phenolphthalein is a
complex organic dye that is
colorless in acidic solutions
and pink in solutions that are
slightly alkaline, or basic
53 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
Calculation
1L 1N of NaOH = M.Wt. of nicotinic acid (123.11 g/mol)
1 ml (0.01N) of NaOH =
of nicotinic acid
1 ml (0.01N) of NaOH = 0.0123 g of nicotinic acid
Titer no. of NaOH = T
No. of grams of nicotinic acid =
= Y gm
% Nicotinic acid =
( )
× 100= Z g%
References
Benelux. L., (2012) Scientific Opinion on the safety and efficacy of niacin
(nicotinic acid and nicotinamide) as a feed additive for all animal species based
on a dossier. European Food Safety Authority Journal 10(7):2788
http://www2.moh.gov.my/images/gallery/rni/8_chat.pdf
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Result Sheet
.
Calculations
Calculate the weight of nicotinic acid in yeast as G% and mg%
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Determination of Tannins in Tea
Background
The word tannin is very old and reflects a traditional technology.
"Tanning" (waterproofing and preserving) was the word used to describe
the process of transforming animal hides into leather by using plant extracts
from different plant parts of different plant species. Many food products
contain tannins in their consumable forms e.g.:
• Tea, Cocoa and Walnuts
• Unripe fruits (apples, cherries, strawberries, bananas)
• Plant parts containing tannins include bark, wood, fruit, fruit pods, leaves, roots,
and plant galls.
One of the most satisfactory definitions of tannins was given by Horvath (1981): "Any
phenolic compound of sufficiently high molecular weight containing sufficient hydroxyls
and other suitable groups (i.e. carboxyl‟s) to form effectively strong complexes with
protein and other macromolecules under the particular environmental conditions being
studied". Tannins can complex with: Proteins, starch, cellulose and minerals.
Tannins are phenolic compounds that precipitate proteins. There is some confusion
about the terminology used to identify or classify a substance as tannin, in fact.
Astringency is the contracting or drying taste, which results from coagulation of the
56 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
proteins of saliva and the mucous epithelium of the mouth, causing a reduced lubricant
action.
Objective
Determine the tannic acid concentration in different types of tea.
Principle
Tannins are water-soluble so they are extracted from tea by boiling with water.
Ferric chloride reagent gives a green-blue color with tannins under acidic conditions.
The color is measured spectrophotometrically at 540 nm and compared with the color
obtained with a standard tannins solution.
Chemical & Material Hazards Tannic acid solution, 0.2 g/100 ml irritation
ferric chloride reagent irritation
Tea (red- green) Distilled water
Equipment
Beaker (100-200 ml) Laboratory balances
Volumetric flask (100ml) Vortex mixer
Pipette 1ml & 5ml Hot palate
Volumetric Cylinder Spectrophotometer or colorimetric
Filter Paper Cuvette
Funnel Test Tube
Conical (Erlenmeyer)flask (100ml)
Method
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B. Preparation of tannic acid(unknown solution)
1- Weigh accurately 0.5g of tea.
2- Add 75ml of water and boil for 30min.
3- Filter in a 100ml-measuring flask and complete to volume with water, Shake well to
mix (use it as unknown).
C. Determination of tannic acid
1- Take 0.5ml of unknown solution; add 0.5ml of ferric chloride reagent and 4ml of
water and mix.
5- The standard is prepared by adding in a tube 0.5ml of standard, 0.5ml of
reagent and 4ml of water and mix.
6- Read the absorbance of unknown and standard against blank at 540 nm
Calculation
The concentration of the tannic acid in tea by the equation as follow.
=
Reference
Salunkhe, D. K., & Chavan, J. K. (1989). Dietary tannins: consequences and remedies.
CRC Press.
58 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
Result Sheet
* Fill the table with your results
* Determine the concentration of the tannic acid in tea samples and which is type
have the least amount of it ?
Sample Concentration
(Conc.)
Absorbance
(Abs( Red tea
Green tea
Standerd
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Estimation of water content in cow’s milk
Background
The quantities of the main milk constituents can vary considerably
depending on the individual animal, its breed, stage of lactation, age and health
status. The average composition of cow‟s milk is shown in table (1).
Table (1): composition of cow’s milk
Main constituent Range %
Water 85.5 –89.5
Fat 2.5 –6.0
Proteins 2.9 –5.0
Lactose 3.6 –5.5
Minerals 0.6 –0.9
Objective
Estimation of water content in milk
Principle
Water is the main constituent of milk. The water can be easily
extracted from the sample, and therefore determined, by using acetone. This
is because: acetone is miscible with water and both have lower boiling
points which mean they will be evaporated before any other major components such as
lipids, proteins, carbohydrates and minerals.
60 Organized by: Dalal Al-Saedi & Salha Al-Shamrani
Method
1. Pipette 5ml of milk into beaker and weight it = (X1)
2. Add 1ml acetone and heat to evaporate the milk to dryness on a hot plate
3. After complete evaporation of water, weigh the crucible again (X2)
Calculation
Weight of water= weight of crucible with milk (X1) –weight of crucible with dry milk
(X2)
Water % = ( )
Reference http://www.ilri.org/InfoServ/Webpub/Fulldocs/ILCA_Manual4/Milkchemistry.htm http://en.wikipedia.org/wiki/Acetone
http://www-unix.oit.umass.edu/~mcclemen/581moisture.html
Chemical & Material Hazards 0.1 M NaOH Corrosive/irritant
Acetone Flammable/Toxic
Milk
Equipment
Small beaker (50ml) Hot plates
Pipette (1ml & 5ml)
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Result Sheet
Calculations