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Philadelphia University Faculty of Engineering Dept. of Civil Eng. Q-1 : a- Student Name: Student Number: F'INAL EXAM : ( fLlJl / o=;[l^:Jl olj ) A,sand element is faited under the following pr. stresses ; or = 390.5 kPa , o3 = 120 kpa . Find i - the angle of internal friction (C). .... .... (4-Marks) (2-Marks) ii - shear strength ofsand... b - A core of (200) cm length is advanced in a rock layer produce a sampleconsisting of the following intact pieces ; Piece ; L z f-ength (cm); L2 9 Find the RQDof this layer. 5678 18 20 34 31 (3-Marks) (3x!3=9 Marks) 4 15 3 7 Q-2; The wall footing strowrfifig. is subjecting to (q=100 kpa), placed on a deep saturated clay layer. a- can the soil resists this pressure ? b-what will be the elastic settlement of wall. and c- the consolidation settlement when U= 100%. ,,vc=8.4 , ilr= 2,2 , A/6-_o.g E= y'o w kP^, 7t.= o. Q, fa= 3- Cc -- o. 19 t e.o= o,? Course Title: Foundation Engineering Course No: (0670531) Date 251112016 Time Allowed: 2 Hour

(4-Marks) (2-Marks) · Philadelphia University Faculty of Engineering Dept. of Civil Eng. Q-1 : a-Student Name: Student Number: F'INAL EXAM: ( fLlJl / o=;[l^:Jl olj ) A,sand element

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Page 1: (4-Marks) (2-Marks) · Philadelphia University Faculty of Engineering Dept. of Civil Eng. Q-1 : a-Student Name: Student Number: F'INAL EXAM: ( fLlJl / o=;[l^:Jl olj ) A,sand element

Philadelphia University

Faculty of EngineeringDept. of Civil Eng.

Q-1 :a-

Student Name:

Student Number:F'INAL EXAM

: ( fLlJl / o=;[l^:Jl olj )

A,sand element is faited under the following pr. stresses ;or = 390.5 kPa , o3 = 120 kpa . Find

i - the angle of internal friction (C). .... .... (4-Marks)(2-Marks)ii - shear strength ofsand...

b - A core of (200) cm length is advanced in a rock layer producea sample consisting of the following intact pieces ;

Piece ; L zf-ength (cm); L2 9Find the RQD of this layer.

567818 20 34 31

(3-Marks)

(3x!3=9 Marks)

4

15

3

7

Q-2;

The wall footing strowrfifig. is subjecting to (q=100 kpa),placed on a deep saturated clay layer.

a- can the soil resists this pressure ?b-what will be the elastic settlement of wall. andc- the consolidation settlement when U= 100%.

, ,vc=8.4 , i l r= 2,2 , A/6-_o.gE= y'o w kP^, 7t.= o. Q, fa= 3-

Cc - - o . 19 t e .o= o ,?

Course Title: Foundation EngineeringCourse No: (0670531)

Date 251112016Time Allowed: 2 Hour

Page 2: (4-Marks) (2-Marks) · Philadelphia University Faculty of Engineering Dept. of Civil Eng. Q-1 : a-Student Name: Student Number: F'INAL EXAM: ( fLlJl / o=;[l^:Jl olj ) A,sand element

Q-3 . . . . . . . Qx 3=6 Marks)sor,/; g=31

a - Check the safety of the slope shown in f ig. go*"[ q-_ S tb - prove that the safety factor ofa slope (i) built ofsand subjecting to seepage pressure parallel to slope is ;

SF- (Tr /y " " t ) ( tan q / tan i )

(8 Marks)

a- A reinforced concrete watl (.y = 25 Kn/ m3) retains sandas shown in Fig. Check the wall stability against g!ir!!4g

Z =5o kP"if it, is subjecting to active failure

(8 Marks)

Find the dimensions (L,B and t ) of a_combined footing for twocolumns each of (0.5 x 0.5) m section and carrys the Ctfollowing loading Pdt - 1.6 MN, Plr = 0.7 MN. and

Pd2 = 9.9 MN, Plr = 0.4 MNGiven : t = 25 MPa , the allowable B.C , (q"x = 200 kPa)

Q-s

Useful relations

I p \\ , \ t ' r--Un - O -!:.->=, 3

r lba

\ i l t= cN"

7 B !-L- 1*

r t ) /-:c ::- -{61

I * e o 4

, ' ,=, t / " no '55SMV

€vo * bI.

Page 3: (4-Marks) (2-Marks) · Philadelphia University Faculty of Engineering Dept. of Civil Eng. Q-1 : a-Student Name: Student Number: F'INAL EXAM: ( fLlJl / o=;[l^:Jl olj ) A,sand element

f t t i

kP^

kP^

+

.b=J3o--- 6'6s

itb

A":+oiI? +oS 6b (e)^/r

t - '

+

? 9e = tao;, (a) #CA =a.ons{*Ez

l - 6 ,4

4ow-'=nf"i;{f

7se= Is J:*Lo

6ng, f,e.tf,

) .e HY 6,lf en i/ 'f',n

av0 = 9,7 c4) = 3r,6 , b7S. - o,l9C8\ /. 3q,6o,-&

t +69 d 3?,6

= loo 4= =5a l:fa-6

T o,Zg' . ' * = ZEO * '

(r-s)

F|"J Et*,-*,2€/r/2.arC

a'rtnsi lrrSr

s*^l ,P;l..lr"JnA/, f ^./ s

9ol:

$in Q-- [?a-

Q.- 6'-t t = 27g_,d = Ef.J'z-z

%. 6it-€. = r/?.-a =25r,3z -L'ta <o - /3,i' 3' -

E; =o'53 + *=

s-Q(.. '? lr totcn3z=tt4f l3

PoD =

4-- s?o.g o'1

o-s = 42o

3z/cP"

kee

o :' kPa.7 =loo

c 3?o,4

2e

/Sr= f,v"o = 3s(6,4)+o+ o,t (1z.r-zg)(4x",e)-/.,1 = 294a t7,82 = 3)l'/2 1.9*

i ?,t = 3tl'8?- =las.g4 ltoo4norkErt*l,;r*'il' 3

o/*1 to

m 6trg pnrr, is n^."14 J,,,-,^,rlJoi*/$ o? C-s)- 8'n).e H9 6,*' ,

q S^ - q- t/ ,4- &rltg|

t s-=#4 I?vata?

i l .= 6.4: /V2 =zz" A/t.a,gc= low $ 2/ ' t=o, l

Irt = 3'Q- : o , l? s e =o,g

e =3,5t'?^, F= g"

Page 4: (4-Marks) (2-Marks) · Philadelphia University Faculty of Engineering Dept. of Civil Eng. Q-1 : a-Student Name: Student Number: F'INAL EXAM: ( fLlJl / o=;[l^:Jl olj ) A,sand element

As,

isF

b-

W= Vs"f4il c-;@-=Wcni=tsJ("(Ct;)

: =

: :" , -_ VIJA cn,- s;at)

J= q f+a Q& = vs*/C"(c?a - v,t (ol co.))

----=--:=-

g'6 - t-64s >t,to,364

ar fq . .

=(Yo-{6Q4Co'-

-'54- b,'t'v,"/6dsa-t, Y",l **rt

tz zo''5.F= 1".^-c0

- =fa'n, i 'sa4:

il-r-f = 18,8

=toda*,t L

/ +3 lo

lteVu d-ej;

Aa:

fu = &, lc,-q, = (tb z}t)k-tb=ty.1-7,g= glsb^' / ;

ko= t -1n jz _ o ,4 - l

- lfr;nlz - T;;-=o '3073

) 6i = Z.fEg? +/f, jzai 2-o + a^ = lE,sz &

+ of Z = 2,n +'q= zz,7t+ta-,gz= s8..?a

fo+

6{ a,

;VsJ=19.y''7= Bz""'7Tvrl €' [zq.r)

-9(,u,t)

(3'8.32>

(2-3)

Page 5: (4-Marks) (2-Marks) · Philadelphia University Faculty of Engineering Dept. of Civil Eng. Q-1 : a-Student Name: Student Number: F'INAL EXAM: ( fLlJl / o=;[l^:Jl olj ) A,sand element

'. , f r

Psz

Rt=

g/o b,' l,l't "q^J ^tl't/4!J

: __ - -O-+v -

t' P --,\'t''tf'177,J;l Fatc*

l - l+o,q =t'3M'

2,s+t,s = 3, 1MM=36"o' :

f?e;t/, Fare =zl/ l' h = 1,il /*-+rt/ - a W = o' 7 (sX?,s. ) + sol6.7 1.r, 2, a ( 8)( t s. I ) + z e (z) r 4 .( ) ( z.i),

= l4of 3s+ 4os,4 + t40+tooi l = 82o'4 N

R-,:i &f = f(aza<S1a,6zt)-- s1t.s; E / '

s/' J; 7

&'^ = -€ E = /, 3 7 G) + t Q2, ? f) (e) + ?.8 4 = 86,3 + t oLZT +.s 9/' q

' : tF = g* t = 638'47 Kv

"uiffi=o"c-s€ 1 t'5 /v' Q

2.3 r.,J

r- t_(;ax5i)

nf = Ei." = t8*E t \4c t =o * X=

I

# = 3, 174+o, t :3 ,694b

t q ? *> lB =- !- o, '- 2,.43 + 20-

7.4' f , '

Pn = t ,z6t .6)+t ,6(r . t ) = l ,?2+t" t2

Vn = P* = 3,a4 tzly'a =o.7s E Iq b,rn'l i ] d- = 2's J +rot

;; J" 7 L

s-' o q =''?l *'r" +' dlo'il- o' 6o8 --o

) af -- o's6€ -/'>tc"'n a'6 a L --J+ oll= o'7*

t S'b (7,4 *z,t td,t)

- . : - -+ ' - ; - - ' ,

krv'

lv4'

-- /'8of*+ ,! - x = s- t' 8a s' -'3'194'

+ L=zLs.{24)--7's6g/oE*, ; 7-4.n^

My' ,=- 3, o4

3.6

( s-s)