4
G C D B A E F #1 write A for always, S for sometimes, and N for never. _____ 1. If two points, A and B, are equidistant from the endpoints of a segment PQ, then a third point, C, between A and B is also equidistant from P and Q. _____ 2. If AB bisec tor CD , then CD bisec tor AB . _____ 3. If two angles are congruent, then they are right angles _____ 4 . If two lines intersect to form two congruent supplementary angles, then they are perpendicular. ______ 5. If a line is a perpendicular bisector to a segment, then any point on the perpendicular bisector is equidistant to the endpoints of the segment. #2 Fill in the blanks with the correct response or write no perpendicular bisector. a) Given: G is the midpoint of EF CE CF _______ is the perpendicular bisector of ______ b) Given: EA EC AD DC _______ is the perpendicular bisector of ______ #3 The altitude to the base of an isosceles triangle divides the triangle into 2 congruent triangles. GIVEN: DIAGRAM: PROVE: #4. Two circles intersect at two points. Prove the segment joining the centers of the circles bisects the segment joining the points of intersection. GIVEN: DIAGRAM: PROVE: 4.1-4.4 Review - Martian Darts

4.1-4.4 Review - Martian Dartscoachgriffin.weebly.com/.../4.1-4.4_martian_darts_review_-_key_2.pdf · 4.1-4.4 Review - Martian Darts . C T A (-3,4) (4,7) 4y2 10 #5 A is the midpoint

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Page 1: 4.1-4.4 Review - Martian Dartscoachgriffin.weebly.com/.../4.1-4.4_martian_darts_review_-_key_2.pdf · 4.1-4.4 Review - Martian Darts . C T A (-3,4) (4,7) 4y2 10 #5 A is the midpoint

G

C

D B

A

E F

#1 write A for always, S for sometimes, and N for

never.

_____ 1. If two points, A and B, are equidistant

from the endpoints of a segment PQ, then a third

point, C, between A and B is also equidistant from

P and Q.

_____ 2. If AB bisec tor CD , then

CD bisec tor AB .

_____ 3. If two angles are congruent, then they

are right angles

_____ 4 . If two lines intersect to form two

congruent supplementary angles, then they are

perpendicular.

______ 5. If a line is a perpendicular bisector to a

segment, then any point on the perpendicular

bisector is equidistant to the endpoints of the

segment.

#2 Fill in the blanks with the correct response or

write no perpendicular bisector.

a) Given: G is the midpoint of EF

CE CF

_______ is the perpendicular bisector of ______

b) Given: EA EC

AD DC

_______ is the perpendicular bisector of ______

#3 The altitude to the base of an isosceles triangle divides

the triangle into 2 congruent triangles.

GIVEN: DIAGRAM:

PROVE:

#4. Two circles intersect at two points. Prove the segment

joining the centers of the circles bisects the segment joining

the points of intersection.

GIVEN: DIAGRAM:

PROVE:

4.1-4.4 Review - Martian Darts

Page 2: 4.1-4.4 Review - Martian Dartscoachgriffin.weebly.com/.../4.1-4.4_martian_darts_review_-_key_2.pdf · 4.1-4.4 Review - Martian Darts . C T A (-3,4) (4,7) 4y2 10 #5 A is the midpoint

C

TA

(-3,4)(4,7)

4 102y

#5 A is the midpoint of CT . Find the coordinates

of T.

#7 Find x and y: (note the expressions are for the

angles, not the sides)

`

#8 If PT PK and MTS MKS

Is PM a perpendicular bisector of KT?

If so, state the theorem that tells you this.

If not, say what information you are missing.

F

L

A

K

E

(3x+4y)°

(8y)° (x)°

#6 Are the following lines perpendicular? Verify

algebraically.

3x + 5

P

T K M

S

Page 3: 4.1-4.4 Review - Martian Dartscoachgriffin.weebly.com/.../4.1-4.4_martian_darts_review_-_key_2.pdf · 4.1-4.4 Review - Martian Darts . C T A (-3,4) (4,7) 4y2 10 #5 A is the midpoint

#9

#10 Given: EHL CHA

HR bisects LHA

Prove: RH EC

Given: EA ED EA = 4x + 15 ED = 7x - 21

CA = 3x - 6 CD = x + 18

CBA = (10y + 5)

Determine if EB is the bisector of ADand explain how you know. Then findthe value of y.

BA

D

C

E

R

A

C H E

L

3

4 2

1

Page 4: 4.1-4.4 Review - Martian Dartscoachgriffin.weebly.com/.../4.1-4.4_martian_darts_review_-_key_2.pdf · 4.1-4.4 Review - Martian Darts . C T A (-3,4) (4,7) 4y2 10 #5 A is the midpoint

#11 Given: 3 4

5 6

Prove: BE EK

(do NOT use a detour!)

Y

X

K B

E