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Ha
m
t
o
ns
Pr
nci
p
I
e
3.1
Introduction
In
the previous chapters the equations of motion have been presented
as
differential equa-
tions.
In
this chapter we shall express the equations in the form of stationary values of
a
time
integral. The idea of zero variation of a quantity was seen in the method of virtual work and
extended to dynamics by means of DAlemberts p rinciple. It has long been considered that
nature works
so as
to minimize some quantity often called action. One of the first statements
was made by Maupertuis in 1744. The most commonly used form is that devised by Sir
William Rowan Ham ilton around 1834.
Ham iltons principle could be considered to be a basic statement of mechanics, especially
as it has wide applications in other areas of physics, but we shall develop the principle
directly from Newtonian laws. For the case with conservative forces the principle states that
the time integral of the Lagrangian is stationary with respect to variations in the path in
configuration space. That is, the correct displacement-time relationships give a m inimum
(or maximum ) value of the integral.
In the usual notation
61;.
dt
= 0
or
61 = 0
where
This integral is som etimes referred to
as
the action integral. There are several different inte-
grals which are also
known
as ac tion integrals.
The calculus of variations has an interesting history with many applications but we shall
develop only the techniques necessary for the problem in hand.
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Derivation
of
Hamilton Sprinciple
47
3.2
Derivation
of
Hamiltons principle
Consider a single particle acted upon by non-conservative forces
F,, F
Fk nd conservative
forcesf;, J , which are derivable from a position-dependent potential function. Referring to
Fig.
3.1
we see that, with p designating momentum, in the x direction
d
F ,
+ f ;
= PI)
with similar expressions for the y and z directions.
For a system having
N
particles DAlemberts principle gives
F, f; t p,)
6xl =
0,
1 5
i S
3N
?(
l
1
?(
l f;
;il
l
P I )
6 4
dt
=
0
?( Fl dt
-
1
t
-
[Pl6X11+ 1
PI)
6x1) dt ) = 0
1 E
16xl-
6V +E1 6 x , ) dt
= 0
We
may
now integrate this expression over the time interval t , to t2
Nowf; = -
av
and the third term can be integrated by parts.
So
interchanging the order of
summ ation and integration and then integrating the third term we obtain
x1
t 2 I2 d
3.3)
t 2 t2 av
tl
t, axl
tl tl
We now impose a restriction on the variation such that
it
is zero at the extreme points
t ,
and
tz;
therefore the third term in the above equation vanishes. Reversing the order of summa-
tion and integration again, equation 3.3) becomes
3.4)
I 1
Let us assume that the momentum is a function ofvelocity but not necessarily a
lin-
ear one. With reference to Fig.
3.2
if P is the resultant force acting on a particle then
by definition
Fig. 3.1
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4 8
Hamilton
s
principle
Fig. 3.2
dP i
pi =
dt
so the work done over an elemental displacement is
d p .
P, ; = - dr = xidpi
dt
The kinetic energy of the particle is equal to the work done,
so
T
=
$ x i d p i
Let the complementary kinetic energy, or co-kinetic energy, be defmed by
Tc = Jp,&
It follows that
6P
= pi6& so substitution into equation 3.4) leads to
1 6 T *
-
V) +?j 6 x j ) dt = 0
or
(T* V) dt = - (Z F ; S x , )d t = 6 1'2(-W)dt
ti
I t , I t ,
;
t,
1:
3.5)
where 6
W
is the virtual work done by non-conservative forces. This is Hamilton sprinciple.
If mom entum is
a
linear function of velocity then
T* =
T. It is seen
in
section
3.4
that the
quantity T* V) is in fact the Lagrangian.
If all the forces are derivable from potential functions then Ham ilton's p rinciple reduces
to
6 X d t = O 3.6)
All the comments made in the previous chapter regarding generalized cosrdinates apply
equally well here
so
that Z is independent of the co-ordinate system.
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Application
of
HamiltonS rinciple 49
3.3 Application
of
Hamilton s principle
In
order to establish a general method for seeking a stationary value of the action integral
we shall consider the simple madspring system with a single degree of freedom shown in
Fig. 3.3. Figure 3.4 shows a plot o fx versus t between two arbitrary times. The solid line is
the actual plot, or path, and the dashed line is a varied path. The difference between the two
paths is
6x.
This is made equal to Eq t), where
q
is an arbitrary k c t i o n
of
time except that
it is zero at the extremes. The factor E is such that when it equals zero the two paths coin-
cide. We can establish the conditions for a stationary value of
the
integralI by setting dlldc
= 0
andthenputtingE=O.
From Fig. 3.4we see that
6
x + dx) = 6x + d 6x)
Therefore
6 dr)
= d 6x) and dividing by dt gives
d x d
dt dt
6 -
=
6x)
m i 2 kx2
3
-7)
For the problem at hand the Lagrangian is
E =
2 2
Fig.
3.4
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50 Hamilton
S
rinciple
Thus
the
integral to be minim ized is
The varied integral with x replaced by =
x
+ ~q is
+ ET^) x + ~ q i t
2
Therefore
Integrating the first term in the integral by
parts
gives
By the definition of
q
the first term vanishes on account of
q
being zero at t and at t2,
so
P
12
Now q is an arbitrary fimction of time and can be chosen to be zero except for time = t
when it is non-zero. This means that the term in parentheses must be zero fo r any value of
t , that
is
m , f + k x =
0 3 -9
A quicker method, now that the exact meaning of variation is
known,
is as follows
k
2
S I t , ;X2 T ~ 2 )
r
= 0
Making use of equation 3.7), equation
3.10)
becomes
Again, integrating by parts,
h x
-
t mi 6x dt kx 6x dt = 0
4
(3.10)
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Lagrange
3
equations d er iv ed jk m Hamilton S principle
5
or
-
t : m2
+ la
6x dt = 0
and because
6r
s arbitrary
it
follows that
+ l a =
0
3.1 1
3.4 Lagrange s equations derived from Hamilton s principle
For a system having n degrees of freedom the Lagrangian can be expressed in terms of the
generalized co-ordinates, the generalized velocities and time, that is
P =
P qi
,qi
t .Thus
with
t
tl
I = / X d t
(3.12)
we have
Note that there is no partial differentiation with respect to time since the variation applies
only to the co-ordinates and their derivatives. Because the variations are arbitrary we can
consider the case for all q to be zero except for
q .
Thus
Integrating the second term by parts gives
Because
6qj =
0 at t , and at
t2
Owing to the arbitrary nature of 6qj we have
3.13)
These are Lagrange's equations for conservative systems. It should be noted that = T*
- V
because, with reference to Fig.
3.2,
it is the variation
of
co-kinetic energy which is
related to the momentum. But, as already stated, when the momentum is a linear function
of velocity the co-kinetic energy T* = T , he k inetic energy. The use of co-kinetic energy
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52 Hamilton
S rinciple
becomes important when particle speeds approach that of light and the non-linearity
becomes apparent.
3.5 Illustrative example
One of the areas in which Hamilton s principle is useful is that of continuous media where
the number of degrees of freedom is infinite.
In
particular it is helpful in complex problems
for which approximate solutions are sought, because approximations in energy terms are
often easier to see than they are in compatibility requirements.
As
an
example we shall
look
at wave motion in long strings under tension. The free-body
diagram approach requires assumptions to be made in order that a simple equation of motion
is generated; whilst the same is true for this treatment the implications of the assumptions
are
clearer.
Figure 3.5 shows a string of finite length. We assume that the stretching of the string is neg-
ligible and that no energy is stored owing to bending. We further assume that the tension T in
the string remains constant.
This
can be arranged by having a pre-tensioned constant-force
spring at one end and assuming that aulax is small. In practice the elasticity of the string and
its
supports is such that for small deviations the tension remains sensibly constant.
We need an expression for the potential energy of the string in a deformed state.
If
the
string is deflected from the straight line then point B will move to the left. Thus the neg-
ative of the work done by the tensile force at B will be the change in potential energy of
the system.
The length of the deformed string is
If we assume that the slope dddx is small then
1
= O
For small deflectionss Q
L so the upper limit can be taken
as
L. Thus
r
Fig. 3.5
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Illustrative example 53
The po tential energy is
-T -s)
=
TS
giving
(3.14)
I f
u is also a function of time then duldx will be replaced by
duldx.
If
p
is
the density and
a
is the cross-sectional area
of
the string then the kinetic energy is
The Lagrangian is
E = J-
r
= 0
According to Hamiltons principle we need to find the conditions so that
t2
r = L
6 1 ,
r = Of [ g ) 2 - L 2 ) 2 ]ax
d x d t = O
Carrying out the variation
t 2 = L
s . L o [
( & ) 6 ( ) - T ( $ ) 6 ( $ ) p d 2 = O
(3.15)
(3.16)
(3.17)
(3.18)
To keep the process as clear as possible we will consider the two terms separately. For the
first
term the order
of
integration is reversed and then the time integral will be integrated by
Parts
because 6u = 0 at t, and t2. The second term in equation (3.18) is
Integrating by parts gives
(3.19)
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54 Hamilton
S
principle
3.20)
The first term is zero provided that the em U re passive, that is no energy is being fed into
the string after motion has been initiated. This means that either
6u = 0
or du/dx
= 0
at
each end. The specification of the problem indicated that 6u
=
0
but any condition that
makes energy transfer zero at the extremes excludes the first term.
Combining equations
3.19)
and 3.20) and substituting into equation 3.18) yields
and because 6u is arbitrary the integrand must s u m o zero so that finally
-
a u
p a , , ,
- T s
3.21)
This is the well-known wave equation for strings. It is readily obtained from free-body dia-
gram
methods but this approach is much easier to modify if other effects, such as that of
bending stiffness of the wire, are to be considered. Extra energy terms can be added to the
above treatment without the need to rework the w hole problem. This fact will be exploited
in Chapter
6
which d iscusses wave motion in more detail.