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8/10/2019 47083207 Grade 11 Math Exam Notes
1/13
MCR3U Exam Review
Polynomials
A polynomial is an algebraic expression with real coefficients and non-negative integer exponents.
A polynomial with 1 term is called a monomial, x7 .
A polynomial with 2 terms is called a binomial, 93 2 x .A polynomial with 3 terms is called a trinomial, 973 2 + xx .
he degree of the polynomial is determined by the val!e of the highest exponent of the variable in the
polynomial.
e.g. 973 2 + xx , degree is 2.
"or polynomials with one variable, if the degree is #, then it is called a constant.$f the degree is 1, then it is called linear.
$f the degree is 2, then it is called %!adratic.
$f the degree is 3, then it is called c!bic.
&e can add and s!btract polynomials by collecting li'e terms.e.g. (implify.
( ) ( )
3)2)
*232*
*322*
*322*
23)
223))
23)2)
23)2)
++=
++=
++=
+
xxx
xxxxx
xxxxx
xxxxx
o m!ltiply polynomials, m!ltiply each term in the first polynomial by each term in the second.
e.g. +xpand and simplify.
( )( )
1272
12)32
32)
23)
223)
22
++=
+++=
++
xxxx
xxxxx
xxx
Factoring Polynomials
o expandmeans to write a prod!ct of polynomials as a s!m or a difference of terms.
o factormeans to write a s!m or a difference of terms as a prod!ct of polynomials.
"actoring is the inverse operation of expanding.
+xpanding
( ) ( ) 21*-7332 2 =+ xxxx"actoring
1
he negative in front of the brac'ets
applies to every term inside the brac'ets.
hat is, yo! m!ltiply each term by 1.
/rod!ct of
polynomials
(!m ordifference ofterms
8/10/2019 47083207 Grade 11 Math Exam Notes
2/13
8/10/2019 47083207 Grade 11 Math Exam Notes
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MCR3U Exam Review
Rational Expressions
"or polynomialsFand G, a rational expression is formed when #, GG
F.
e.g.91)21
732 ++
+xx
x
%implifying Rational Expressionse.g. (implify and state the restrictions.
3,3
3
33
33
33
33
9-
92
2
+
=
+++=
+++=
++
mm
m
mm
mm
mm
mm
mm
m
Mltiplying and "ividing Rational Expressions
e.g. (implify and state the restrictions.
7,1,71
2
77
21
11
7
77
21
11
7
)91)
23
1
70
2
2
2
2
+
+=
++++
+
+=
++++
+
+=
++++
+
xxx
xx
xx
xx
xx
xx
xx
xx
xx
xx
xx
xx
x
xxA
3,1,),
1
3
31
1)
1)
33
31
1)
1)
33
1)
31
1)
33
)*
3)
)*
90
2
2
2
2
+=
++
+++
=
++
+++
=
++
+++
=
+++
++
x
x
x
xx
xx
xx
xx
xx
xx
xx
xx
xx
xx
xx
xx
xx
xx
xx
xB
&dding and %btracting Rational Expressions
e.g. (implify and state the restrictions.
2,22
7*
22
1#*3
22
2*
22
3
2
*
22
3
2
*
)
30
2
+
=
+ +=
+
++
=
++
+=
++
xxx
x
xx
x
xx
x
xx
xxx
xxA
#,,#,
32
3
2
3
2
320
22
=
=
=
yyxyxxy
xy
yxxy
x
yxxy
y
yxyyxx
yxyxyxB
8/10/2019 47083207 Grade 11 Math Exam Notes
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MCR3U Exam Review
Radicals
e.g. n a , is called the radical sign, nis the index of the radical, and ais called the radicand.
3 is said to be a radical of order 2. 3 is a radical of order 3.
=i'e radicals0 *3,*2,* >nli'e radicals0 3,*,* 3
+ntire radicals0 29,1-,
?ixed radicals0 7*,32,2)
A radical in simplest formmeets the following conditions0
"or a radical of order
n, the radicand has no
factor that is the nth
power of an integer.
he radicand contains
no fractions.
he radicand contains
no factors with
negative exponents.
he index of a radical
m!st be as small as
possible.
&ddition and %btraction of Radicals
o add or s!btract radicals, yo! add or s!btract the coefficients of each radical.
e.g. (implify.
( ) ( ) ( )
1#-311
1#-31*3)
1#2333*322
1#)339*3)2)#327*122
+=
+=
+=
+=+
Mltiplying Radicals
e.g. (implify.( )( ) ( )( ) ( )( ) ( )( ) ( )( )
( )
-1-
-2-312
3--2-32
333223233222332322
=
+=
+=
+=+
)
(ame order, li'eradicands
ifferent order ifferent radicands
22
22
2)
2
=
==
8/10/2019 47083207 Grade 11 Math Exam Notes
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MCR3U Exam Review
Con'gates
( ( dcbadcba + and are called con@!gates.
&hen con@!gates are m!ltiplied the res!lt is a rational expression no radicals.
e.g. "ind the prod!ct.
( )( ) ( ) ( )
13
1*
29*
23*23*23* 22
===
=+
"ividing Radicals
Prime Factori(ation
"actor a n!mber into its prime
factors !sing the tree diagram
method.
Exponent Rles
Rle "escription Example
/rod!ct nmnm aaa += 7*2 ))) =!otient nmnm aaa = 22) *** =/ower of a power ( ) nmnm aa = ( ) )2 33 =/ower of a %!otient
#, =
bb
a
b
an
nn
*
**
)
3
)
3=
Bero as an exponent 1# =a 17# =
8/10/2019 47083207 Grade 11 Math Exam Notes
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2
-2
MCR3U Exam Review
( ) ( )
1##
1
1#
1
1#
9133
2
2
222#
=
=
=
+=+
--
-
-2
232
-
23
232
3
3
)
2
2
22
ba
a
b
a
b
a
b
a
b
=
=
=
=
%olving Exponential E!ations
e.g. (olve forx.
22
2
2
2
99
19
739
739
=
=
+=
=
x
x
x
x
)
22
22
=+==
x
x
x
chec's)73
1
9
7392)
2
=====
==
xRS
RSLS x
Fnctions
A relationis a relationship between two sets. :elations can be described !sing0an e%!ation an arrow diagram a graph a table
73 2 = xy
in wordsDo!tp!t is three more than inp!tE
a set of ordered pairsF,),3,#,2,1G
f!nction notation
xxxf 3 2 =
he domainof a relation is the set of possible inp!t val!es xval!es.
he rangeis the set of possible o!tp!t val!es yval!es.
e.g. (tate the domain and range.
A0 F,),3,#,2,1G H0 60 *= xy omain G#, 1, )F
:ange G2, 3, F
Add to both sides.
(implify.
8/10/2019 47083207 Grade 11 Math Exam Notes
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MCR3U Exam Review
A fnctionis a special type of relation in which every element of the domain corresponds to exactlyone element of the range.
7= xy and 1*2 += xy are examples of f!nctions. xy = is not a f!nction beca!se for everyval!e ofxthere are two val!es ofy.
he vertical line testis !sed to determine if a graph of a relation is a f!nction. $f a vertical line can be
passed along the entire length of the graph and it never to!ches more than one point at a time, then therelation is a f!nction.
e.g. A0 H0
)nverse Fnctions
he inverse, 1f , of a relation, f , maps each o!tp!t of the original relation bac' onto the
corresponding inp!t val!e. he domain of the inverse is the range of the f!nction, and the range of theinverse is the domain of the f!nction. hat is, if fba , , then 1, fab . he graph of
1 xfy = is the reflection of the graph xfy= in the line xy= .
e.g. ;iven*
13
= x
xf .
+val!ate 3f . +val!ate 123 +f
23
*
1#3
*
193
*
1333
=
=
=
=
f
f
f
f
)123
113
1*
*3
1
*
1-3
1*
1233123
=++=
+
=
+
=
+
=+
f
f
etermine 1 xf . +val!ate 21f
3
1*
3
1*
1*313*
*
13
*
13
1 +=
+=
+= =
=
=
xxf
xy
xyyx
yx
xy
3
112
3
11#
3
12*2
3
1*
1
1
1
=
+=
+=
+=
f
f
xxf
e.g. ('etch the graph of the inverse of the given f!nction xfy= .
7
2 2
his passes the
vertical linetest, so it is a
f!nction.
he line passes thro!gh more
than one point, so this relation
fails the vertical line test. $t isnot a f!nction.
:eplace all
xIs with 3.
+val!ate.
Mo! want to find the val!e of
the expression 123 +f .Mo! are not solving for 2f .
:ewrite xf as
*
13 =
xy $nterchangexand
y.
$f yo! have not already determined
1xf
do so.
>sing 1 xf , replace allxIs with
2.
4
2
-2
-4
2
-2
-
2
-2
-
raw the
lineyx.
:eflect thegraph in thelineyx.
xfy=
1xfy
=
8/10/2019 47083207 Grade 11 Math Exam Notes
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4
-
-4
4
-
-4
2
-2
-
4
-2
-4
4
2
-2
-
MCR3U Exam Review
he inverse of a f!nction is not necessarily going to be a f!nction. $f yo! wo!ld li'e the inverse to alsobe a f!nction, yo! may have to restrict the domain or range of the original f!nction. "or the example
above, the inverse will only be a f!nction if we restrict the domain to F,#LG R xxx orF,#LG R xxx .
Transformations of Fnctions
o graph qpxkafy += 4 from the graph xfy= consider0
a determines the vertical stretch. he graph xfy= is stretched vertically by a factor of a. $f aN #then the graph is reflected in thex-axis, as well.
k determines the horiKontal stretch. he graph xfy= is stretched horiKontally by a factor ofk
1.
$f kN # then the graph is also reflected in the y-axis.
p determines the horiKontal translation. $fpO # the graph shifts to the right byp!nits. $fpN # then
the graph shifts left byp!nits.
q determines the vertical translation. $f qO # the graph shifts !p by q!nits. $f qN # then the graph
shifts down by q!nits.
&hen applying transformations to a graph the stretches and reflections sho!ld be
applied before any translations.
e.g. he graph of xfy= istransformed into
)23 = xfy . escribethe transformations.
"irst, factor inside the
brac'ets to determine theval!es of kandp.
( )( )
2,2,3
223
====pka
xfy
here is a vertical stretch of
3.
A horiKontal stretch of2
1.
he graph will be shifted 2
!nits to the right.
e.g. ;iven the graph ofxfy= s'etch the graph of
( )( ) 122 += xfy
xfy=
(tretch vertically
by a factor of 2.
:eflect iny-axis.
(hift to the
right by 2.(hift !p by 1.
his is the graph of
(( 22 += x
8/10/2019 47083207 Grade 11 Math Exam Notes
9/13
4
2
-2
-4
-5 5
aO#
minim!m
maxim!m
aN#
)2
71
=
+=
x
x
9)
33)
7)1))
==
=
f
f
f
*.22*.2
1#*.21#2*.22*.2
=+=
f
f
*adratic Fnctions
he graph of the %!adratic f!nction, cbxaxxf ++= 2 , is a parabola.&hen a> # the parabola opens !p. &hen a< # the parabola opens down.
+ertex Form: f x a x h k = +2
he vertex is , kh . he maxim!m or minim!m val!e is k.
he axis of symmetry isy h.
Factored Form: f x a x p x q = %tandard Form: f x ax bx c = + +2
he Keroes are px= and qx= . hey-intercept is c.
Complete t#e s!areto change the standard form to vertex form.
e.g.
( )( )( )
2*32
79232
7323-2
733-2
7-2
7122
2
2
222
222
2
2
++=
++=
+++=
+++=
++=
+=
xxf
xxf
xxxf
xxxf
xxxf
xxxf
Maximm and Minimm +ales
Pertex form, maxim!mQminim!m val!e is k.
"actored form0
e.g. etermine the maxim!m or minim!m val!e of 71 = xxxf .he Keroes of xf are e%!idistant from the axis of symmetry. he Keroes are 1=x and 7=x
.
he axis of symmetry isx ). he axis of symmetry passes thro!gh the vertex.hex-coordinate of the vertex is ). o find they-coordinate of the vertex,
eval!ate )f .
he vertex is 9,) . Heca!se ais positive 1=a , the graph opens!p.
he minim!m val!e is 9.
(tandard form0
e.g. etermine the maxim!m or minim!m val!e of 1#1#2 2 += xxxf witho!t completing the s%!are.
xxxg 1#2 2 = is a vertical translation of 1#1#2 2 += xxxf withy-intercept of #.*2 += xxxg *,# =x are the Keroes.
*.22
*# =
=x *.2=x is thex-coordinate of
vertex.
hey-coordinate of vertex
is 22.*. $t is a maxim!mbeca!se the graph opens down.
,eroes
"actor the coefficient ofx2form the terms withx2andx.
ivide the coefficient ofxby 2. (%!are this n!mber. Add and s!btract it.
Hring the last term inside the brac'et o!tside the brac'ets.
"actor the perfect s%!are trinomial inside the brac'ets.
(implify.
"actor xxxg 1#2 2 = to determinKeroes, then find the axis of symmetry. Hot
xf and xg will have the samex-
coordinates for the vertex. o find they-
coordinate forf(x)simply eval!atef(x)!sin
the samex-coordinate.
8/10/2019 47083207 Grade 11 Math Exam Notes
10/13
6
2
f x( )= 2x
6
2
f x( )= 2x-2+3
o determine the n!mber of Keroes of a %!adratic f!nction consider the form of the f!nction.
Pertex form0 $f aand khave opposite signs there are 2 Keroes 2 roots.$f a and khave the same sign there are no Keroes # roots.
$f k # there is one Kero 1 root.
"actored form0 f x a x p x q = - 2 Keroes. he Keroes are px= and qx= .2 pxaxf = - 1 Kero. he Kero isxp.
(tandard form0 6hec' discriminant. acbD )2 =$f #D there are 2 Keroes.
o determine the Keroes of from the standard form !se the !adratic formla.
"or , #2 =++ cbxax !sea
acbbx
2
)2 = to solve forx.
Reciprocal fnctions
he reciprocal f!nction of a f!nction, f , is defined as f1 . o help yo! graph 1xfy= , yo! sho!ld
!se the following0
he vertical asymptotes of
1
xfy= will occ!r where # =xf
As xf increases,
1
xfdecreases. As xf decreases,
1
xfincreases.
"or # >xf , #
1 >xf
. "or # se theinformation above to help yo! s'etch thereciprocal.
Exponential Fnctions
2
-2
-
5
2
-2
-
5
xxy )2=
xxy
)
1
2
=
Pertical asymptotes
$n general, the exponential f!nction
is defined by the e%!ation, xay= or
xaxf = , Rxa > ,# .
ransformations apply to
exponential f!nctions the same waythey do to all other f!nctions.
8/10/2019 47083207 Grade 11 Math Exam Notes
11/13
b a
b sinA
C
AB
Exponential .rowt# and "ecay/op!lation growth and radioactive decay can be modelled !sing exponential f!nctions.
;rowth0 dt
NtN 2 #= #N - initial amo!nt ecay0
h
t
NtN
=2
1 # #
N - initial amo!nt
t time elapsed t time elapsedd do!bling period h half-life
tN - amo!nt at time t tN - amo!nt at time
t
Compond )nterest
6alc!lating the f!t!re amo!nt0niPA 1 += A f!t!re amo!nt P present initial
amo!nt
6alc!lating the present amo!nt0 niAP += 1 i interest rate per conversion periodn n!mber of conversion periods
Trigonometry
;iven a right angle triangle we can !se the following ratios
Primary Trigonometric Ratios
r
y=sin
r
x=cos
x
y=tan
Reciprocal Trigonometric Ratios
sin
1csc ==
y
r
cos
1sec ==
x
r
tan
1cot ==
y
x
Trigonometry of /bli!e Triangles
%ine 0aw
c
B
b
A
a
sinsinsin==
6an be !sed when yo! 'now A(A, AA(, ((A
Cosine 0aw
Abccba cos2222
+=6an be !sed when yo! 'now (((, (A(
&hen yo! 'now ((A it is considered the ambig!o!s case.Angle 6onditions R of riangles
9# 2
r
y
x
A
b c
6 a H
8/10/2019 47083207 Grade 11 Math Exam Notes
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1
0.5
-0.5
-1
50 100 150 200 250 300 350
1
0.5
-0.5
-1
50 100 150 200 250 300 350
5
-5
50 100 150 200 25 30 350
ba
C
AB
9#>A ba #ba> 1
Trigonometric )dentities
/ythagorean $dentity0 1cossin 22 =+ !otient $dentity0
cos
sintan =
e.g. /rove the identity. 222 cos1cos2sin =+
RS
LS
==
+=
++=
+=
2
2
222
22
cos
1cos1
1coscossin
1cos2sin
Periodic Fnctions
A periodic f!nction has a repeating pattern.
he cycleis the smallest complete repeating
pattern.
he axis of t#e crve is a horiKontal line that ismidway between the maxim!m and minim!m
val!es of the graph. he e%!ation is
2
min val!emax val!e +=y .
he periodis the length of the cycle.
he amplitdeis the magnit!de of the vertical
distance from the axis of the c!rve to the
maxim!m or minim!m val!e. he e%!ation is
2
min val!emax val!e=a
Trigonometric Fnctions
he graphs of sin=y , cos=y , and tan=y are shown below.sin=y tan=y
cos=y
Transformations of Trigonometric Fnctions
ransformations apply to trig f!nctions as they do to any other f!nction.
he graphs of dbkay ++= sin and dbkay ++= cos are transformations of the graphssin=y and cos=y respectively.
he val!e of adetermines the vertical stretch, called the amplitde.$t also tells whether the c!rve is reflected in the -axis.
sin=y/eriod 3#S
Amplit!de 1Beroes #S,
1#S, 3#ST
cos=y/eriod 3#SAmplit!de 1
Beroes 9#S, 27#ST
tan=y/eriod 1#S
Beroes #S, 1#S, 3#STPertical asymptotes 9#S, 27#ST
&or' with each side separately.=oo' for the %!otient or /ythagorean identities.
Mo! may need to factor, simplify or split terms !p.
&hen yo! are done, write a concl!ding statement.
(ince =(:( then 222 cos1cos2sin =+ is tr!e for all val!es of .
8/10/2019 47083207 Grade 11 Math Exam Notes
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2
1.5
1
0.5
-0.5
-1
50 100 150 200 250 300 350 400
g x( )= cos 2x( )+1
f x( )= cos x( )
1
0.5
-0.5
-1
50 100 150 200 250 300 350 400
g x( )= 0.5sin x+45( )
f x( )= sin x( )
he val!e of kdetermines the horiKontal stretch. he graph is stretched by a factor ofk
1. &e can !se
this val!e to determine the periodof the transformation of sin=y or cos=y .
he period of ky sin= or ky cos= isk
3-#, k O #. he period of ky tan= is
k
1#, k O #.
he val!e of bdetermines the horiKontal translation, 'nown as the p#ase s#ift.he val!e of ddetermines the vertical translation. dy= is the e%!ation of the axis of t#e crve.
e.g. e.g.
12cos += y ( ))*sin2
1 += y