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5-4 Elimination Using Multiplication
aka Linear Combination
Algebra 1 Glencoe McGraw-Hill Linda Stamper
12y4x413y8x3
Often the equations are not ready for one variable to cancel. You will need to create the opposites.
Multiply one or both equations by a number to obtain coefficients that are opposites for one of the variables.
12y4x413y8x3
Choose one of the variables to create an opposite.
Multiply by a number needed to make one variable opposites.
212y4x42 24y8x8
Add your equation because you now have opposites.
x11 111x
13y8x3
13y81 3
2y16y813y83
Write solution as an ordered pair.(–1,2)
Substitute the solved value into either of the originaloriginal equations to find the value for the other variable.
13y8x 3
Yeah a handout. I do not have to
copy these notes in my notebook!
1328x 3
12y4x4
13y8x3
413y8x34 52y32x12 36 y12x12
y44 882y
13y8x 3
1x
3x3
1616
1316x3
(-1,2)
312y4x43
While you can choose either of the variables to make opposites, choosing wisely may save you some work. Here is the work if the x variable is used to create the opposite.
8y3x78y x3
Example 1
Solve the linear system using elimination.
Example 2
19y5x26y4x3
8y3x78y x3
Example 1 Solve the linear system.
38y x33 24y3x9
8 y3x7
x16 322x
8yx 3
8y2 3
2y8y6
(2,2)
6y42 3
19y5x26y4x3
Example 2 Solve the linear system. 56y4x35 30y20x15
76 y20x8
x23 46 2x
6y4x 3
3y12y46y46
(–2,3)
419y5x24
634x 3
12y8x6 19y5x2
6y4x3
Example 2 Solve the linear system. 26y4x32
75 y15x6
y23 693y
6y4x 3
2x
6x3
612x3
(–2,3)
319y5x23
Solving A Linear System By Elimination
1) Arrange the equations with like terms in columns.
2) Multiply, if necessary, one or both equations by the number needed to make one of the variables an opposite.
3) Add the equations when one of the variables have opposites. Then solve.
4) Substitute the value solved into either of the original equations and solve for the other variable.
5) Check the ordered pair solution in each of the original equations.
6y3x
When solving a system by elimination, rearrange the terms so that the corresponding variables are vertically stacked.
6y3x12y6x3
12y6x3
)3(6y3x3 18y9x3
12y6x3
30y15 2y Substitute the solved value
into either of the original equations.
6y 3x
6)2(3x
0x0x66x
Write answer as an ordered
pair. (0,2)
Example 3
Solve the linear system using elimination.
Example 4
x512y28y2x3
1y2x5y3x413
Example 5
18y2x615x5y3
Example 6 Write a linear system and then solve.
Five times the first number minus three times the second number is six. Two times the first number minus five times the second number is ten. Find the numbers.Assign
labels.Translate each sentence.Solve the system.Write a sentence to give the answer.
x512y28y2x3
Example 3 Solve the linear system. 8y2x3
12y2x5
18y2x31 8y2x3
12y2x5
2x4x2
8y2x 3
8y2)2( 3
y1y22
8y26
(2,1)
Rewrite in standard form.
1y2x5y3x413
Example 4 Solve the linear system.
Rewrite in standard form.
13y3x4 1y2x5
26y6x8 3y6x15
1x23x23
y3x 413
y31413
y3y39
y3413
(–1,3)
18y2x615x5y3
18y26x 15y3x5
54y68x1
30y6x10
24x8 3x
0,3
Example 5 Solve the linear system. 15x5y3
0y30
y
0y3
1515y3
1535y3
50y25x10 12y6x10 6y3x5
Example 6 Five times the first number minus 3 times the second number is six. Two times the first number minus five times the second number is 10. Find the numbers.
y19 382y
Let x = first numberLet y = second numberTranslate each sentence.Solve the system.
62 3x5
10y5x2
Write a sentence to give the answer.
The numbers are -2 and 0.
6y3x5
66x5 0x5 0x
Practice Problems
8y5x44y3x2 )1
9y3x3
2y2x6 )2
2y8x2
3y4x5 )3
1) (2,0) 2) (1,–2) 3)
31
,31
4) Six times the first number plus two times the second number is two. Four times the first number plus three times the second number is eight. Find the numbers. The numbers are -1 and
4.
5-A6 Page 276-278 #7–17,30,34-36,44-48.