5. Indices & Log

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    INDICES AND LOGARITHMS

    ADDITIONAL

    MATHEMATICS

    MODULE 8

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    1

    CHAPTER 5 : INDICES AND LOGARITHMS

    CONTENTS PAGE

    5.0 INDICES AND LOGARITHM

    5.1 Concept Map 2

    5.2 Indices and laws of Indices 3

    Exercise 5.2

    5.3 Simplify Algebraic Expressions 4 - 5

    Exercise 5.3

    5.4 Equation Involving Indices 5 - 7

    Exercise 5.4

    5.5 Past Year Questions 8

    5.6 Assessment 9 - 10

    Answers 11

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    CHAPTER 5 : INDICES AND LOGARITHMS

    5.1 CONCEPTUAL MAP

    Indices

    an index

    base

    Logarithms

    If N = ax, then loga N = x

    Fractional indices

    a) a1/n

    = ___________

    b) am/n = ___________

    = ___________

    Laws of indices

    a) a

    m

    x a

    n

    = _________

    b) am an = _________

    c) (am)n = _________

    Integer indices

    a) an = a x a x a x a x a

    n factors

    b) Negative index, a-n

    = _________

    c) Zero index, a0

    = __________

    Equations involving indices

    a) If ax = ay, then _________

    b) If mx

    = nx, then ________

    INDICES AND LOGARITHMS

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    5.2 INDICES AND LAWS OF INDICES

    Examples Hit the Buttons

    Find the values of the following.

    1. 63 = 216

    2. 4-2 =2

    4

    1

    =16

    1

    3. 32

    8 = ( 3 8 )2 = 22

    = 4

    EXERCISE 5.2

    a) Evaluate the following

    1. 0.44

    Solution

    2. 32

    8

    27

    Solution

    3.

    3

    8

    1

    Solution

    4.2

    1

    4

    1

    Solution

    6 ^ 3 =

    ( 3 shift ^ 8

    ) =x2

    1c

    ba 4 =x2

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    5.3 SIMPLIFY ALGEBRAIC EXPRESSIONS

    Examples Solution

    Simplify

    1. 2a2 x 3a3

    = (2 x 3) x (a2 x a3)= 6 x a2 + 3

    Sign : (+) x (+) = (+)

    Number : 2 x 3 = 6Unknown/ : a2 x a3 = a5

    base

    2. 33n 2

    3n 3

    = 33n 2 - ( n 3)

    = 33n 2 n + 3

    = 3 2n + 1

    am an = a m n

    Use the laws of indices to simplify thedivision

    EXERCISE 5.3

    Simplify the following

    1. (34)2n x 3n

    Solution

    2. 31 2n x 34 x 33n + 2

    Solution

    3. 121 48 nn

    Solution

    4. a2 x 2a3 (4a)2

    Solution

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    5

    5.3n5

    2n-32

    p

    pp

    n

    Solution

    6.22

    27

    b6a

    b18a

    Solution

    7. 3x 3x 1

    Solution

    8. 2n + 2 - 2n + 12( 2n 1)

    Solution

    5.4 EQUATIONS INVOLVING INDICES

    Examples Steps / Method

    Solve each of the following equations

    1. 33x = 8133x = 34

    3 x = 4

    x = 3

    4

    Express in the _________________ andcompare the indices

    _____________________ the indices

    2. 2x . 4x+1 = 642x . 22 (x+1) = 26

    x + 2x + 2 = 6

    3x = 4

    x =3

    4

    Use ______ as the same base throughout

    _______________ the indices using the

    laws of indices

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    3. 0168 12

    xx

    022 1432

    xx

    143 222

    xx

    443

    22

    2 xx

    3x2

    = 4x + 4

    3x2- 4x 4 = 0

    (3x + 2)(x 2) = 0

    x =3

    2, x = 2

    Use 2 as the same base throughout

    ______________________of a quadraticequation

    _________________________________

    EXERCISE 5.4

    1. Solve 8x3

    = 27

    Solution

    2. Solvex8 =

    4

    1

    Solution

    3. Solve 2x . 3

    x = 36

    Solution

    4. Solve 21

    4x = 10

    Solution

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    5. Solve 14 2793 xx

    Solution

    6. Solve 53x 25x + 1 =

    125

    1

    Solution

    7. Solve427

    x =xx

    93

    13

    Solution

    8. Solve3

    1

    5

    25125

    x

    x

    Solution

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    5.5 PAST YEAR QUESTIONS

    1. Solve the equation 122 34 xx (SPM 05)

    Solution

    2. Solve the equation 684 432 xx (SPM 04)

    Solution

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    5.6 ASSESSMENT

    Answer All the questions Time : 30 minutes

    1. Solve the equation 163x = 86x + 1

    Solution

    2. Solve the equation 32x =

    243

    1

    Solution

    3.Solve the equation 8x . 2x = 32

    Solution

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    4.Solve the equation 093 26

    2

    xx

    Solution

    5. Solve the equation28 x =

    xx

    24

    11

    Solution

    6.Solve the equation 52x 52x 1 = 100

    Solution

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    ANSWERS

    EXERCISE 1.1

    1. 0.0256

    2. 2.253. 512

    4 2

    EXERCISE 2.1

    1. 39n

    5. 12 n

    2. 3n+7

    6. 2a5

    3.np 4

    17.

    3

    23x

    4. 3a

    8

    18. 92n

    EQUATION INVOLVING INDICES1. same base, compare

    2. 2, Add

    3. General form, solving by factorization

    EXERCISE 3.1

    1. x =2

    35. x = 6

    2. x =3

    26. x = -1

    3. x = 2 7. x = -2

    4. x = 6.25 8. x = 1

    PAST YEAR QUESTIONS

    1. x = -1

    2. x = 3

    ASSESSMENT

    1. x =2

    54. x = 6, -2

    2. x =2

    1 5. x = 2

    3. x =4

    56. x =

    2

    3

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    INDICES AND LOGARITHMS

    ADDITIONAL

    MATHEMATICS

    MODULE 9

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    __________________________________________

    CHAPTER 5 : INDICES AND LOGARITHMS

    CONTENTS PAGE

    5.0 INDICES AND LOGARITHM

    5.1 Conceptual Map 2

    5.2 Logarithm and laws of logarithm 3 4

    Exercise 5.2

    5.3 Finding Logarithm of numbers 4 6

    Exercise 5.3

    5.4 Changing the base of logarithm 7 - 9

    Exercise 5.4.1

    Exercise 5.4.2

    Exercise 5.4.3

    5.5 Equation Involving logarithm 10 11

    Exercise 5.5

    5.6 Past Year Questions 11 - 12

    5.7 Assessment 13

    Answers 14

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    CHAPTER 5 : INDICES AND LOGARITHMS

    5.1 CONCEPTUAL MAP

    Index

    an index

    base

    Logarithms

    If N = ax, then loga N = x

    Laws of Logarithms

    d) Loga xy = _________________

    e) Loga x/y = _________________

    f) Loga xm = _________________

    Change of base

    of logarithms

    a) Loga b = __________

    b) Loga b = __________

    Equations involving

    Logarithms

    If logaX = logaY, then

    __________________

    INDICES AND LOGARITHMS

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    5.2 LOGARITHM AND LAWS OF LOGARITHM

    Find the value of the following

    Examples Solution

    1. log4641

    Let . log464

    1= x

    Then 4x = 4-3

    x = -3

    2. log5= 5 Let . log5 5 = x

    Then 5x = 21

    5

    x =2

    1

    3. log2 x = - 5 Given log2 x = - 5Then x = 2

    -5

    =52

    1 =321

    EXERCISE 5.2

    Find the value of each of the following

    1. log2 128 2 log5 125

    3. . log864

    14. log10

    3

    5

    2

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    5. log100 10 6. log 644

    7. log9 x = - 1 8. logx 225

    1

    5.3 FINDING LOGARITHM OF NUMBERS

    Examples Solution

    Evaluate the following

    1. log3 18 log3 6

    = log36

    18

    = log3 3

    = 1

    2. log4 2 + log4 8= log4 (2 x 8)

    = log4 42

    = 2 log4 4

    = 2(1)= 2

    3. Given that loga 2 = 0.123 and loga 3 = 0.256, calculate the following

    a) loga 12 = loga (2 x 2 x 3)= loga 2

    2 + loga 3

    = 2loga 2 + loga 3

    = 2(0.123) + 0.256= 0.502

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    b) loga 6 = loga 21

    6

    =2

    1loga (2 x 3)

    =2

    1[ loga 2 + loga 3]

    =2

    1[0.123 + 0.256]

    = 0.1895

    4. Given that logx 2 = a and logx 3 = b, write logx 29

    4

    xin term of a and b.

    Logx 29

    4

    x= logx 4 logx 29x

    = logx 22

    - [ logx 9 + logx x2

    ]= 2 logx2 - logx 3

    2 - 2 logx x= 2a - 2logx 3 - 2(1)

    = 2a - 2b - 2

    EXERCISE 5.3

    Simplify each of the following logarithms expression

    1. log4 2 + log4 32 2. log2 48 + log23 log29

    3. 2 log5 10 + 3 log5 2 log5 32 4. 4logx 2 3logx 4 + logx 6

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    5. Express logac

    b2in terms ofloga b

    and loga c

    Solution

    6. Given that log2 6 = 2.59 andlog2 5 = 2.32 find the value of

    log10 30

    Solution

    7. Given log3 2 = 0.631 and log3 5 = 1.465, find the values ofa) log3 20

    b) log35

    4

    c) log3 7.5

    Solution

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    5.4 CHANGING THE BASE OF LOGARITHM

    Examples

    Find the value of the logarithm

    1. log3

    5 =3log

    5log

    10

    10

    =4771.0

    699.0

    = 1.465

    EXERCISE 5.4.1

    Find the value of the logarithm by changing the base of the logarithm

    1. Log4 3 2. Log3 10

    3. Log2 0.1 4. Log5 0.048

    5.Log4

    5

    1 6.Log2

    4

    3

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    Examples

    Find the value of the logarithm

    1. log4 5 =4log

    5log

    2

    2

    = 2log2

    322.2

    2

    =2

    322.2

    = 1.161

    EXERCISE 5.4.2

    Given that log2 5 = 2.322 and log2 3 = 1.585, find the value of the logarithm

    1. Log3 5 2. Log8 15

    3. Log9 125 4. Log8 25

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    Examples

    Find the value of the logarithm

    1. log10 p2 =

    16log

    log

    4

    2

    4 p

    =4log2

    log2

    4

    4 p

    =2

    2m

    = m

    EXERCISE 5.4.3

    Given that log4 p = m. Express the following in terms of m

    1. Logp 4 2. Log8 p

    3. Log4p 64 4.Logp

    256

    1

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    5.5 EQUATION INVOLVING LOGARITHMS

    1. Solve the equation :

    Log 10( x 5 ) = log10 ( x 1 ) + 2

    Solution

    Log 10( x 5 ) = log10 ( x 1 ) + 2

    Log 10( x 5 ) log10 ( x 1 ) = 2

    Log 101

    5

    x

    x= 2

    1

    5

    x

    x= 10

    2

    x 5 = 100( x 1)x 5 = 100x 100

    99x = 95

    x =99

    95

    2. Solve the equation:

    3x

    = 52x + 1

    Solutionxlog103 = (2x + 1)log105

    xlog103 = 2x log105 + log105xlog103 2x log105 = log105

    x(log103 2 log105) = log105

    x =5log23log

    5log

    1010

    10

    x = 0.7591

    EXERCISE 5.5

    Solve each of the equation

    1. 5x

    = 27 2. 5x

    = 0.8

    3. 3x +

    = 18 4. 5x

    = 4x +

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    5. 2x3

    x= 5

    x +6. 3

    x. 4

    x += 6

    5.6 SPM QUESTIONS

    SPM 2005( Paper 1)

    1. Solve the equation 1)12(log4log 33 xx [ 3 marks]

    SPM 2005( Paper 1)

    2. Given that pm log and rm 3log , express

    4

    27log

    mm in term of p and r

    [ 4 marks]

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    SPM 2004(Paper 1)

    3. Given that 5log 2 = m and 5log = p, express 5log 4.9 in term of m and p

    [ 4 marks]

    SPM 2003(Paper1)

    4. Given that 2log T - 4log V = 3 , express T in term of V. Express T in term of V

    [ 4 marks]

    SPM 2003(Paper1)5. Solve the equation xx 74 12 [ 4 marks]

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    5.7 ASSESSMENT

    Answer All the questions Time : 30 minutes

    1. Solve the equation 4log3log2)48(log 555 x

    2. Given x = mk3log and nk2log . Find the value of 24log k in term ofm and n

    3. Given that ,4loglog 93 VT express T in terms of V

    4. Solve the equation xx 95 12

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    ANSWERS

    EXERCISE 5.2

    1. 7 4 -1.1938 7.9

    1

    2.2

    35.

    2

    18. 5

    3. -2 6. 6

    EXERCISE 5.3

    1. 3 5. 2 logab loga c

    2. 4 6. 4.913. 2 7. a) 2.727 c) 1.834

    4. logx2

    3b) - 0.203

    EXERCISE 5.4.11. 0.7924 3. -3.3222. 2.096 4. -1.887

    EXERCISE 5.4.2

    1. 1.465 3. 2.19752. 1.302 4. -1.548

    EXERCISE 5.4.3

    1.m

    13.

    m1

    3

    2. m32 4.

    m4

    EXERCISE 5.5

    1. 2.048 4. 20.642. -0.1386 5. 8.827

    3. 1.630 6. 0.1632

    SPM QUESTIONS

    1. x =2

    34. T = 8 v

    2. 3r 2p + 1 5. 1.677

    3. 2p - m -1

    ASSESSMENT

    1. 5 3. T =v

    81

    2.nm

    31 4. -1.575