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5.2 Solving Quadratic Equations
Warm-up (IN)
CSAP Constructed Response
Learning Objective: To solve quadratic equations by taking square roots and to use the Pythagorean Theorem to solve problems involving right triangles.
Notes
Learning Objective: To solve quadratic equations by taking square roots and to use the Pythagorean Theorem to solve problems involving right triangles.
Properties of Square roots** Product property - ab ba
32
216 4 2
** Quotient property - b
a
b
a
9
4
9
4
3
2
Learning Objective: To solve quadratic equations by taking square roots and to use the Pythagorean Theorem to solve problems involving right triangles.
EX 1 – Solve 103237 a. 2 x27x 1262x 18 x 29 23 or 24.4
289546 b. 2 x
SADMEP!
25x 64
289
5x 17
8
x 8
175
or
x 8
17 5
8
23
8
57
Try t his p. 282 (middle and bottom)
Learning Objective: To solve quadratic equations by taking square roots and to use the Pythagorean Theorem to solve problems involving right triangles.
EX 2 – A helicopter 85 ft above a designated area drops a boxes of food to a disaster area. The height of the box above the ground can be modeled by , where t is the time in seconds after it has been released. After how many seconds will it hit the ground?
8516 2 tth
85160 2 t21685 t
2t4
17
2.3sect
Pythagorean Theorem!
Learning Objective: To solve quadratic equations by taking square roots and to use the Pythagorean Theorem to solve problems involving right triangles.
In a right , the sum of the squares of the lengths of the legs is equal to the square of the hypotenuse.
a
b
c22 2a cb
EX 3 – Find the unknown length
a. A B
5.3
8.4
b
C
28.4 23.5 2b56.70 09.28 2b
65.98 2b93.9 2b
b. J K
2.8
1.9
k
L
29.1 2k 28.261.3 2k 84.7
2k 23.4k 06.2
Learning Objective: To solve quadratic equations by taking square roots and to use the Pythagorean Theorem to solve problems involving right triangles.
Learning Objective: To solve quadratic equations by taking square roots and to use the Pythagorean Theorem to solve problems involving right triangles.
EX 4 – What must be the length of QS so that it contacts the ground halfway between the base of the tower and the point where PS contacts the ground?
S
P
75 ft106 ft
Q R
275 2PR 21065626 2PR 11236
2PR 5611PR 91.74 PRQR
2
1
45.37QR245.37 275 2SQ5625 2SQ
ft83.83 SQ
HW – p. 287
#21-43 odd,
51-54
Out – Describe the procedure you would use to solve
Summary – So, I was thinking…
POW!!
1235 2 x