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7-9 Special Products of Binomials
Warm UpWarm Up
Lesson Presentation
California Standards
PreviewPreview
7-9 Special Products of Binomials
Warm UpSimplify.
1. 42
3. (–2)2 4. (x)2
5. –(5y2)
16 49
4 x2
2. 72
6. (m2)2 m4
7. 2(6xy) 2(8x2)8. 16x2
–5y2
12xy
7-9 Special Products of Binomials
California Standards
10.0 Students add, subtract, multiply, and divide monomials and polynomials. Student solve multistep problems, including word problems, by using these techniques.
7-9 Special Products of Binomials
Vocabularyperfect-square trinomialdifference of two squares
7-9 Special Products of Binomials
Imagine a square with sides of length (a + b):
The area of this square is (a + b)(a + b) or (a + b)2. The area of this square can also be found by adding the areas of the smaller squares and the rectangles inside. The sum of the areas inside is a2 + ab + ab + b2.
7-9 Special Products of Binomials
This means that (a + b)2 = a2+ 2ab + b2.You can use the FOIL method to verify this:
(a + b)2 = (a + b)(a + b) = a2 + ab + ab + b2
F L
I
O = a2 + 2ab + b2
A trinomial of the form a2 + 2ab + b2 is called a perfect-square trinomial. A perfect-square trinomial is a trinomial that is the result of squaring a binomial.
7-9 Special Products of Binomials
Multiply.
Additional Example 1: Finding Products in the Form (a + b)2
A. (x + 3)2
(a + b)2 = a2 + 2ab + b2
Use the rule for (a + b)2.
(x + 3)2 = x2 + 2(x)(3) + 32
= x2 + 6x + 9
Identify a and b: a = x and b = 3.
Simplify.
B. (4s + 3t)2
(a + b)2 = a2 + 2ab + b2
(4s + 3t)2 = (4s)2 + 2(4s)(3t) + (3t)2
Use the rule for (a + b)2.
= 16s2 + 24st + 9t2
Identify a and b: a = 4s and b = 3t.
Simplify.
7-9 Special Products of Binomials
Multiply.
Additional Example 1: Finding Products in the Form (a + b)2
C. (5 + m2)2
(a + b)2 = a2 + 2ab + b2
(5 + m2)2 = 52 + 2(5)(m2) + (m2)2
= 25 + 10m2 + m4
Use the rule for (a + b)2.
Identify a and b: a = 5 and b = m2.
Simplify.
7-9 Special Products of BinomialsCheck It Out! Example 1
Multiply.A. (x + 6)2
(a + b)2 = a2 + 2ab + b2 Identify a and b: a = x and b = 6.
Use the rule for (a + b)2.
(x + 6)2 = x2 + 2(x)(6) + 62
= x2 + 12x + 36 Simplify.
B. (5a + b)2
(a + b)2 = a2 + 2ab + b2
Use the rule for (a + b)2.
(5a + b)2 = (5a)2 + 2(5a)(b) + b2
Identify a and b: a = 5a and b = b.
= 25a2 + 10ab + b2 Simplify.
7-9 Special Products of Binomials
Check It Out! Example 1
Multiply.
c. (1 + c3)2 Use the rule for (a + b)2.
(a + b)2 = a2 + 2ab + b2 Identify a and b: a = 1 and b = c3.
(1 + c3)2 = 12 + 2(1)(c3) + (c3)2
= 1 + 2c3 + c6 Simplify.
7-9 Special Products of Binomials
You can use the FOIL method to find products in the form of (a – b)2.
(a – b)2 = (a – b)(a – b) = a2 – ab – ab + b2
F L
IO = a2 – 2ab + b2
A trinomial of the form a2 – ab + b2 is also a perfect-square trinomial because it is the result of squaring the binomial (a – b).
7-9 Special Products of Binomials
Multiply.
Additional Example 2: Finding Products in the Form (a – b)2
A. (x – 6)2
(a – b)2 = a2 – 2ab + b2
(x – 6)2 = x2 – 2x(6) + (6)2
= x2 – 12x + 36
Use the rule for (a – b)2.
Identify a and b: a = x and b = 6.
Simplify.
B. (4m – 10)2
(a – b)2 = a2 – 2ab + b2
(4m – 10)2 = (4m)2 – 2(4m)(10) + 102
= 16m2 – 80m + 100
Use the rule for (a – b)2.
Identify a and b: a = 4m and b = 10.
Simplify.
7-9 Special Products of Binomials
Multiply.
Additional Example 2: Finding Products in the Form (a – b)2
C. (2x – 5y )2
(a – b)2 = a2 – 2ab + b2
(2x – 5y)2 = (2x)2 – 2(2x)(5y) + (5y)2
= 4x2 – 20xy +25y2
Use the rule for (a – b)2.
Identify a and b: a = 2x and b = 5y.
Simplify.
D. (7 – r3)2
(a – b)2 = a2 – 2ab + b2
(7 – r3)2 = 72 – 2(7)(r3) + (r3)2
= 49 – 14r3 + r6
Use the rule for (a – b)2.
Identify a and b: a = 7 and b = r3.
Simplify.
7-9 Special Products of BinomialsCheck It Out! Example 2
Multiply.
a. (x – 7)2
(a – b)2 = a2 – 2ab + b2
(x – 7)2 = x2 – 2(x)(7) + (7)2
= x2 – 14x + 49
Use the rule for (a – b)2.
Identify a and b: a = x and b = 7.
Simplify.
b. (3b – 2c)2
(a – b)2 = a2 – 2ab + b2
(3b – 2c)2 = (3b)2 – 2(3b)(2c) + (2c)2
= 9b2 – 12bc + 4c2
Use the rule for (a – b)2.
Identify a and b: a = 3b and b = 2c.
Simplify.
7-9 Special Products of BinomialsCheck It Out! Example 2
Multiply.
c. (a2 – 4)2
(a – b)2 = a2 – 2ab + b2
(a2 – 4)2 = a4 – 2(a2)(4) + (4)2
= a4 – 8a2 + 16
Use the rule for (a – b)2.
Identify a and b: a = a2 and b = 4.
Simplify.
7-9 Special Products of Binomials
You can use an area model to see that (a + b)(a – b) = a2 – b2.
Begin with a square with area a2. Remove a square with area b2. The area of the new figure is a2 – b2.
Then remove the smaller rectangle on the bottom. Turn it 90 and slide it up next to the top rectangle.
The new arrange- ment is a rectangle with length a + b and width a – b. Its area is (a + b)(a – b).
7-9 Special Products of Binomials
So (a + b)(a – b) = a2 – b2. A binomial of the form a2 – b2 is called a difference of two squares.
7-9 Special Products of Binomials
Multiply.
Additional Example 3: Finding Products in the Form (a + b)(a – b)
A. (x + 4)(x – 4)
(a + b)(a – b) = a2 – b2
(x + 4)(x – 4) = x2 – 42
= x2 – 16
Use the rule for (a + b)(a – b).
Identify a and b: a = x and b = 4.
Simplify.
B. (p2 + 8q)(p2 – 8q)
(a + b)(a – b) = a2 – b2
(p2 + 8q)(p2 – 8q) = p4 – (8q)2
= p4 – 64q2
Use the rule for (a + b)(a – b).
Identify a and b: a = p2 and b = 8q.
Simplify.
7-9 Special Products of Binomials
Multiply.
Additional Example 3: Finding Products in the Form (a + b)(a – b)
C. (10 + b)(10 – b)
(a + b)(a – b) = a2 – b2
(10 + b)(10 – b) = 102 – b2
= 100 – b2
Use the rule for (a + b)(a – b).
Identify a and b: a = 10 and b = b.
Simplify.
7-9 Special Products of BinomialsCheck It Out! Example 3
Multiply.a. (x + 8)(x – 8)
(a + b)(a – b) = a2 – b2
(x + 8)(x – 8) = x2 – 82
= x2 – 64
Use the rule for (a + b)(a – b).
Identify a and b: a = x and b = 8.
Simplify.
b. (3 + 2y2)(3 – 2y2)
(a + b)(a – b) = a2 – b2
(3 + 2y2)(3 – 2y2) = 32 – (2y2)2
= 9 – 4y4
Use the rule for (a + b)(a – b).
Identify a and b: a = 3 and b = 2y2.
Simplify.
7-9 Special Products of BinomialsCheck It Out! Example 3
Multiply.
c. (9 + r)(9 – r)
(a + b)(a – b) = a2 – b2
(9 + r)(9 – r) = 92 – r2
= 81 – r2
Use the rule for (a + b)(a – b).
Identify a and b: a = 9 and b = r.
Simplify.
7-9 Special Products of Binomials
Write a polynomial that represents the area of the yard around the pool shown below.
Additional Example 4: Problem-Solving Application
7-9 Special Products of Binomials
List important information:• The yard is a square with a side length of x + 5.• The pool has side lengths of x + 2 and x – 2.
11 Understand the Problem
The answer will be an expression that shows the area of the yard less the area of the pool.
Additional Example 4 Continued
7-9 Special Products of Binomials
22 Make a Plan
The area of the yard is (x + 5)2 less the area of the pool. The area of the pool is (x + 2)(x – 2). You can subtract the area of the pool from the yard to find the area of the yard surrounding the pool.
Additional Example 4 Continued
7-9 Special Products of Binomials
Solve33
Step 1 Find the total area.
(x + 5)2 = x2 + 2(x)(5) + 52Use the rule for
(a + b)2: a = x and b = 5.
Step 2 Find the area of the pool.
(x + 2)(x – 2) Use the rule for (a + b)(a – b): a = x and b = 2.
x2 + 10x + 25=
x2 – 4 =
Additional Example 4 Continued
7-9 Special Products of Binomials
Step 3 Find the area of the yard.
Area of yard = total area – area of pool
a = x2 + 10x + 25 (x2 – 4) –
= x2 + 10x + 25 – x2 + 4
= (x2 – x2) + 10x + ( 25 + 4)
= 10x + 29
Identify like terms.
Group like terms together
The area of the yard is 10x + 29.
Additional Example 4 Continued
Solve33
7-9 Special Products of Binomials
Look Back44
Suppose that x = 20. Then the total area in the back yard would be 252 or 625. The area of the pool would be 22 18 or 396. The area of the yard around the pool would be 625 – 396 = 229.
According to the solution, the area of the pool is 10x + 29. If x = 20, then 10x +29 = 10(20) + 29 = 229.
Additional Example 4 Continued
7-9 Special Products of BinomialsCheck It Out! Example 4
Write an expression that represents the area of the swimming pool.
7-9 Special Products of BinomialsCheck It Out! Example 4 Continued
11 Understand the Problem
The answer will be an expression that shows the area of the two rectangles combined.
List important information:• The upper rectangle has side lengths of 5 + x
and 5 – x .• The lower rectangle is a square with side
length of x.
7-9 Special Products of Binomials
22 Make a Plan
The area of the upper rectangle is (5 + x)(5 – x). The area of the lower square is x2. Added together they give the total area of the pool.
Check It Out! Example 4 Continued
7-9 Special Products of Binomials
Solve33
Step 1 Find the area of the upper rectangle.
Step 2 Find the area lower square.
(5 + x)(5 – x) = 25 – 5x + 5x – x2 Use the rule for (a + b)
(a – b): a = 5 and b = x.–x2 + 25=
x2 =
= x x
Check It Out! Example 4 Continued
7-9 Special Products of Binomials
Step 3 Find the area of the pool.
Area of pool = rectangle area + square area
a x2 +
= –x2 + 25 + x2
= (x2 – x2) + 25
= 25
–x2 + 25=
Identify like terms.
Group like terms together
The area of the pool is 25.
Solve33
Check It Out! Example 4 Continued
7-9 Special Products of Binomials
Look Back44
Suppose that x = 2. Then the area of the upper rectangle would be 21. The area of the lower square would be 4. The area of the pool would be 21 + 4 = 25.
According to the solution, the area of the pool is 25.
Check It Out! Example 4 Continued
7-9 Special Products of Binomials
7-9 Special Products of BinomialsLesson Quiz: Part I
Multiply.
1. (x + 7)2
2. (x – 2)2
3. (5x + 2y)2
4. (2x – 9y)2
5. (4x + 5y)(4x – 5y)
6. (m2 + 2n)(m2 – 2n)
x2 – 4x + 4
x2 + 14x + 49
25x2 + 20xy + 4y2
4x2 – 36xy + 81y2
16x2 – 25y2
m4 – 4n2
7-9 Special Products of BinomialsLesson Quiz: Part II
7. Write a polynomial that represents the shaded area of the figure below.
14x – 85
x + 6
x – 6x – 7
x – 7