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ACTM State Exam-Statistics For the 25 multiple-choice questions, make your answer choice and record it on the answer sheet provided. Once you have completed that section of the test, proceed to the tie-breaker items. These will be graded in numerical order, so itโ€™s in your best interest to respond to these in that order. Be sure that your name is on each sheet of the tie-breaker items. 1. Generally, Greek letters are used to represent ___________, and Roman letters are used to represent ______________. a. Statistics, parameters b. Parameters, statistics c. Measures of variation, measures of spread d. Measures of spread, measures of variation 2. If the mode is to the left of median and the mean is to the right of the median, then the distribution is _____________ skewed. a. Positively b. Negatively c. Not d. Highly 3. A set of 45 values has a mean of 23 and a set of 53 values has a mean of 47, what is the mean of the combined set of values? (Round to nearest tenths if needed.) a. 49.0 b. 50.4 c. 35.0 d. None of these 4. Suppose we use a least squares linear regression model on a set of data points (x,y). We find the coefficient of determination is 0.81 and the regression line is given by y = -51x + 32. What is the value of the correlation coefficient? a. 0.6561 b. 0.9 c. -0.6561 d. -0.9

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Page 1: ACTM State Exam-Statistics

ACTMStateExam-Statistics

Forthe25multiple-choicequestions,makeyouranswerchoiceandrecorditontheanswersheetprovided.Onceyouhavecompletedthatsectionofthetest,proceedtothetie-breakeritems.Thesewillbegradedinnumericalorder,soitโ€™sinyourbestinteresttorespondtotheseinthatorder.Besurethatyournameisoneachsheetofthetie-breakeritems.

1. Generally,Greeklettersareusedtorepresent___________,andRomanlettersareusedtorepresent______________.

a. Statistics,parametersb. Parameters,statisticsc. Measuresofvariation,measuresofspreadd. Measuresofspread,measuresofvariation

2. Ifthemodeistotheleftofmedianandthemeanistotherightofthemedian,thenthedistributionis_____________skewed.

a. Positivelyb. Negativelyc. Notd. Highly

3. Asetof45valueshasameanof23andasetof53valueshasameanof47,whatisthemeanofthecombinedsetofvalues?(Roundtonearesttenthsifneeded.)

a. 49.0b. 50.4c. 35.0d. Noneofthese

4. Supposeweusealeastsquareslinearregressionmodelonasetofdatapoints(x,y).Wefindthecoefficientofdeterminationis0.81andtheregressionlineisgivenbyy=-51x+32.Whatisthevalueofthecorrelationcoefficient?

a. 0.6561b. 0.9c. -0.6561d. -0.9

Page 2: ACTM State Exam-Statistics

5. Giventhesamescenarioasinquestion#4andtheQQplotofresidualsbelow,doyoubelieve

thelinearmodelisagoodone?

a. Yes,becausetheabsolutevalueofthecorrelationcoefficientisclosetooneandthe

residualsareclosetotheidentityline.b. No,becausetheabsolutevalueofthecorrelationcoefficientisnotclosetoone.c. No,becausetheQQplotshowsthattheresidualsarenotnormallydistributed.d. Yes,becausetheQQplotshowsthattheresidualsarenormallydistributedandthe

absolutevalueofthecorrelationcoefficientisclosetoone.

6. Thefollowinglistgivesnumberofhoursastudentstudiesperweek.Whatisthelargestvalueinthesamplethatisnotconsideredanoutlier?

0,1,2,2,5,5,5,6,6,7,7,7,8,8,8,8,8,8,9,10,10,10,12,20

a. 12b. 20c. 0d. Noneoftheabove

7. Youstepontoabusthatwilltakebetween15and25minutestoarriveoncampus.Assumethatthedistributionofthesetimesisuniform,yourstatisticsclassbeginsin20minutes,anditwilltaketwominutesforyoutowalkfromthebustotheclassroom.Whatistheprobabilitythatyouarrivelatetoclass?

a. 70%b. 30%c. 50%d. Noneoftheabove

Page 3: ACTM State Exam-Statistics

8. Adrawercontains10differentpairsofgloves.If6glovesaredrawnrandomlyfromthedrawer,whatistheprobabilitythattherewillbenomatchingpairinthesample?

a. !(!",!)!(!",!)

b. !!(!",!)!(!",!)

c. !!!(!",!)!(!",!)

d. Noneofthese

9. Afamilyhastwochildren.Giventhatatleastoneofthemisagirl,wasittheprobabilitythatthefamilyhastwogirls?

a. 1/2b. 1/3c. 1/4d. ยพ

10. Supposeweknowthatatleast88.89%ofthemembersofagymhaveanagebetween32years62years.WhatcanyouconcludeusingChebyshevโ€™stheoremaboutthemeanandstandarddeviationofthedistributionofagesforthemembers?

a. Youcannotdrawaconclusionfromtheinformationgiven.b. Thestandarddeviationis3years,butwecannotfindthemean.c. Themeanis47yearsandthestandarddeviationis5years.d. Themeanis47yearsandthestandarddeviationis1.67years.

11. Redjellybeansaremyfavorite.IfIrandomlyselectajellybeanfrombowl,theprobabilityofdrawingaredoneis0.21.SupposeIgrabahandfulof13jellybeans,whatistheprobabilityofgettingatleast5thatarered?

a. 0.0797b. 0.1173c. 0.8827d. 0.9625

12. TherandomvariableXisthenumberthatshowsupwhenaloaded4-sideddieisrolled.Its

probabilitydistributionisgiveninthetable.DeterminethemeanofthedistributionofX.

x 1 2 3 4P(X=x) 0.30 0.30 0.15 0.25

a. 2.35b. 2c. 0.5875d. 2.5

Page 4: ACTM State Exam-Statistics

13. Inadatasetwitharangeof52.2to114.5and500observations,thereare345observations

withvalueslessthan87.1.Findthepercentilefor87.1.a. 69b. 131.458c. 698d. 32

14. Whichscorehasahigherrelativeposition,ascoreof48onatestforwhichthemeanis40andstandarddeviationis4,orascoreof288.6onatestforwhichthemeanis260andstandarddeviationis26?

a. Ascoreof48b. Ascoreof288.6c. Bothscoreshavethesamerelativeposition

15. Thebrandmanagerforabrandoftoothpastemustplananewcampaigndesignedtoincreasebrandrecognition.Aprevioussurveysuggestedthatabout76%ofadultshaveheardofthebrand.Hewantstofirstdeterminethepresentpercentageofadultswhohaveheardofthebrand.Howmanyadultsmusthesurveyinordertobe80%confidentthathisestimateiswithinsixpercentagepointsofthetruepopulationpercentage?

a. Atleast84b. Atleast83c. Atleast115d. Atleast116

16. WhichofthefollowingisNOTtrueoftheconfidencelevelofaconfidenceinterval?

a. Theconfidencelevelgivesusthesuccessrateoftheprocedureusedtoconstructtheconfidenceinterval.

b. Theconfidencelevelisoftenexpressedasanarea1-ฮฑ,whereฮฑisthecomplementoftheconfidencelevel.

c. Theconfidencelevelisalsocalledthedegreeofconfidence.d. Thereisa1-ฮฑchance,whereฮฑisthecomplementoftheconfidencelevel,thatthetrue

valueoftheparameterwillfallintheconfidenceintervalproducedbythesample.

17. Usinga95%confidencelevel,findaconfidenceintervalforestimatingthetruemeanweight,ยต,ofallpackagesreceivedbytheparcelservicegiventhatasampleof31packageshadameanweightof13.2lb.andthestandarddeviationofallpackagesisฯƒ=2.4lbs.

a. 12.2lb<ยต<14.2lb.b. 12.4lb<ยต<14.0lb.c. 12.1lb<ยต<14.3lb.d. 12.5lb<ยต<13.9lb.

Page 5: ACTM State Exam-Statistics

18. Themeanreplacementtimeforarandomsampleof20washingmachinesis10.8yearsandthestandarddeviation2.8years.Constructa99%confidenceintervalforthestandarddeviation,ฯƒ,ofthereplacementtimesofallwashingmachinesofthistype.

a. 2.5years<ฯƒ<5.9yearsb. 2.0years<ฯƒ<4.7yearsc. 0.3years<ฯƒ<5.3yearsd. 1.2years<ฯƒ<4.4years

19. Afarmerhasdecidedtouseanewadditivetogrowhiscrops.Hedividedhisfarminto10plotsandkeptrecordsofthecornyield(inbushels)beforeandafterusingtheadditive.Theresultsareinthetablebelow.Usinga1%levelofsignificance,findthep-valuefortestingtheclaimthattheadditiveproducesahighermeanyield.

a. 0.1355b. 0.0004c. 0.0070d. 0.2709

20. Whichofthefollowingisnotanadvantageofpoolingsamplevariances?a. Confidenceintervalsarealittlenarrower.b. Thenumberofdegreesoffreedomisalittlehigher.c. Hypothesistestshavemorepower.d. Weoftenknowthatthepopulationvariancesareequal.

21. Astudywasdoneusingatreatmentgroupandaplacebogroup.Wewanttotesttheclaimthatthesamplesarefrompopulationswiththesamemean.Theresultsareshowninthetable.Assumethatthetwosamplesareindependentsimplerandomsamplesfromnormallydistributedpopulations.Usinga0.01significancelevel,statetheconclusionofthetest.

Treatment PlaceboSamplesize 26 38Samplemean 2.33 2.64Samplestandarddeviation 0.51 0.99

Plot Before After1 9 102 9 93 8 94 7 85 6 76 8 107 5 68 9 109 10 1010 11 12

Page 6: ACTM State Exam-Statistics

a. Rejectthenullhypothesis.Thereissufficientevidencetowarrantrejectionoftheclaimthatthetwosamplesarefrompopulationswiththesamemean.

b. Rejectthenullhypothesis.Thereisnotsufficientevidencetowarrantrejectionoftheclaimthatthetwosamplesarefrompopulationswiththesamemean.

c. Failtorejectthenullhypothesis.Thereisnotsufficientevidencetowarrantrejectionoftheclaimthatthetwosamplesarefrompopulationswiththesamemean.

d. Failtorejectthenullhypothesis.Thereissufficientevidencetowarrantrejectionoftheclaimthatthetwosamplesarefrompopulationswiththesamemean.

22. Theactivationtimesforanautomaticsprinklersystemareasubjectofstudybythesystemโ€™smanufacturer.Asampleofactivationtimesis27,41,22,27,23,35,30,33,24,27,28,22,and24seconds.Thedesignofthesystemcallsforitsactivationinatmost25seconds.Assuminganormalpopulation,doesthedatacontradictthevalidityofthisdesignspecification?

a. Yesb. Noc. Notenoughdatatodrawaconclusion

23. Callscomeintoatelephoneswitchboardatarateof4perminute.Findtheprobabilityof

getting6callsinanintervalof2minutesroundedtothreeplaces.UseaPoissondistribution.a. 0.122b. 0.104c. 0.313d. Noneofthese

24. SupposeweareinterestedinstudyingthefactorsthataffectGPAofseniorhighschoolstudents.

FiftyschoolsareselectedatrandomandwecollecttheGPAofonemaleandonefemalefromeachschool.Wealsoclassifyeachschoolaspublicorprivate.Whichofthefollowingproceduresismostappropriatetoconductfirst.

a. Anindependent2sampledttestonthemaleandfemaleGPA.b. ApairedttestonthemaleandfemaleGPA.c. ANOVAonthefoursetsofGPAs:malesatprivateschool,femalesatprivateschool,

malesatpublicschool,femalesatpublicschool.d. Two-WayANOVAusingtheschoolstatusasonefactorandgenderasthesecondfactor.

25. Theinterceptinlinearregressionrepresents:

a. Thestrengthoftherelationshipbetweenxandy.b. Theexpectedx-valuewhenyiszero.c. Theexpectedy-valuewhenxiszero.d. Theerrorinthemeasurements.

Page 7: ACTM State Exam-Statistics

TieBreakers

Name:___________________________________________

1. Yourteachertellstheclassthatthetestscoresonthemostrecentexamwerenormally

distributedwithmeanof82%andavarianceof4%.Youaredisappointedbecauseyourscorewas76%andusuallyyouhavethetopscoreintheclass!Soyourandomlyselect5ofyour25classmatesandfindouttheirtestscoreswere56%,78%,84%,67%,and81%.Assumingthefivescoresyoucollectedwereasimplerandomsample,answerthefollowingquestions.

a. Whatistheprobabilitythatarandomlyselectedstudentreceivesascoreof76%orlowerontheexam?

b. Assumingtheteacherwastruthful,whatistheprobabilitythattheaverageof5randomlyselectedstudentswouldbehigherthan83%.

c. Basedonthefivescoresyouknow,testtheclaimthattheaveragefortheclasswasactuallylessthan82%.Use0.05significancelevel.

d. Supposenowthattheteacherhadonlytoldyouthatthescoreswerenormallydistributedwithameanof82%,buthe/shedidnotcalculatethevariancefortheclass.Basedonthefivescoresyouknow,testtheclaimthattheaveragefortheclasswasactuallylessthan82%.Use0.05significancelevel.

e. DescribetheinterpretationsofatypeIandtypeIIerrorinthisscenario.

Page 8: ACTM State Exam-Statistics

Name:______________________________________

2. Inaboltfactory,machinesA,BandCmanufacture20%,30%and50%(respectively)ofthetotaloutput.Oftheiroutput,3%,2%and1%aredefective.

a. Suppose500boltsaremadeeveryhour,howmanydefectiveboltsdoyouexpecttofindoverthecourseofa40hourworkweek?

b. Ifaboltisselectedatrandom,whatistheprobabilitythatitisdefective?

c. Aboltisselectedatrandomandfoundtobedefective,whatistheprobabilitythatitcamefrommachineA?

3. AnExperimentwasconductedtocomparetheeffectivenessofthreetrainingprograms,A,B,

andC,intrainingassemblersofapieceofelectronicequipment.Fifteenemployeeswererandomlyassigned,fiveeachtothethreeprograms.Aftercompletionofthecourses,eachpersonwasrequiredtoassemblefourpiecesoftheequipment,andtheaveragelengthoftimerequiredtocompletetheassemblywasrecorded.Severaloftheemployeesresignedduringthecourseoftheprogram;theremainderwereevaluated,producingthedatashownintheaccompanyingtable.Usethefollowingoutputtoanswerthequestions.TrainingProgram AverageAssemblyTime(min)A 59 64 57 62 B 52 58 54 C 58 65 71 63 64

Source DF SS MS F P Program 2 170.5 85.2 5.7 .025 Error 9 134.5 14.9 Total 11 304.9

Level N Mean StDev A 4 60.500 3.109 B 3 54.667 3.055 C 5 64.200 4.658

a. Dothedataprovidesufficientevidencetoindicateadifferenceinmeanassemblytimesforpeopletrainedbythethreeprograms?Useasignificancelevelof0.05.

b. Findsimultaneous99%confidenceintervalsforthemeanassemblytimesbetweenpersonstrainedbyprogramsA,B,andC.Whatcanyouconcludebasedontheseconfidenceintervals?

Page 9: ACTM State Exam-Statistics

Solutions

1.b

2.a

3.d

4.d

5.c

6.a

7.b

8.c

9.b

10.c

11.b

12.a

13.a

14.a

15.a

16.d

17.b

18.b

19.b

20.d

21.c

22.a

23.a

24.d

25.c

Page 10: ACTM State Exam-Statistics

SolutionstoTieBreakers

1. Yourteachertellstheclassthatthetestscoresonthemostrecentexamwerenormallydistributedwithmeanof82%andavarianceof4%.Youaredisappointedbecauseyourscorewas76%andusuallyyouhavethetopscoreintheclass!Soyourandomlyselect5ofyour25classmatesandfindouttheirtestscoreswere56%,78%,84%,67%,and81%.Assumingthe6scoresyoucollectedwereasimplerandomsample,answerthefollowingquestions.

a. Whatistheprobabilitythatarandomlyselectedstudentreceivesascoreof76%orlowerontheexam?

P(X<76)=0.0013bycalculator.Iftheyuseempiricalrulewithz-scoreof-3,theprobabilityisapproximately0.0015.

b. Assumingtheteacherwastruthful,whatistheprobabilitythattheaverageof5

randomlyselectedstudentswouldbehigherthan83%.

Thesamplingdistributionofthemeanhasameanof82andvarianceof4/5.

P(๐‘ฟ>83)=0.1318

c. Basedonthe6scoresyouknow,testtheclaimthattheaveragefortheclasswasactuallylessthan82%.Use0.05significancelevel.

Ho:ยต=82vs.H1:ยต<82Zstat=-9,839andp-valueisvery,veryclosetozero.Rejectthenullhypothesis.Wehaveevidencethattheclassaveragewasprobablylessthan82%.Weshouldconcludethatmaybetheteachermiscalculatedtheaverageorthevarianceoftheclass.

d. Supposenowthattheteacherhadonlytoldyouthatthescoreswerenormally

distributedwithameanof82%,buthe/shedidnotcalculatethevariancefortheclass.Basedonthe6scoresyouknow,testtheclaimthattheaveragefortheclasswasactuallylessthan82%.Use0.05significancelevel.

Ho:ยต=82vs.H1:ยต<82Tstat=-1.702andp-valueis0.082.Failtorejectthenullhypothesis.Wedonothaveevidencethattheclassaveragewaslessthan82%.

e. DescribetheinterpretationsofatypeIandtypeIIerrorinthisscenario.

AtypeIerrorwouldmeanthatwerejectthenullhypothesiswheninfactthenullhypothesisistrue.HereatypeIerrorwouldmeanthatwewouldconcludetheteacherwaswrong(orlied)aboutthemeanoftheclassbasedonthesamplecollected,butinfacttheaveragereallywas82%.

AtypeIIerrorwouldmeanthatwefailtorejectthenullhypothesiswhenthenullhypothesisisinfactfalse.HereatypeIIerrorwouldmeanthatwewouldconcludetherewasnotenoughevidenceforsayingtheteacherwasincorrect,butactuallytheaverageoftheclasswaslessthan82%.

Page 11: ACTM State Exam-Statistics

2. Inaboltfactory,machinesA,BandCmanufacture20%,30%and50%(respectively)ofthetotaloutput.Oftheiroutput,3%,2%and1%aredefective.

a. Suppose500boltsaremadeeveryhour,howmanydefectiveboltsdoyouexpecttofindoverthecourseofa40hourworkweek?

Amakes100boltswithapprox.3defectiveperhour.Bmakes150boltswithapprox..3defectiveperhour.Cmakes250boltswithapprox.2.5defectiveperhour.Totalweexpect8.5defectiveboltsperhouror340per40hours.(TheycouldalsousepartB)

b. Ifaboltisselectedatrandom,whatistheprobabilitythatitisdefective?

P(defective)=P(defective|A)P(A)+P(defective|B)P(B)+P(defective|C)P(C)=0.03*0.20+0.02*0.30+0.01*0.5=0.017

c. Aboltisselectedatrandomandfoundtobedefective,whatistheprobabilitythatitcamefrommachineA?

P(A|defective)=P(defective|A)P(A)/P(defective)=(0.03*0.20)/0.017=0.3529

3. a. For the hypotheses ๐‘ฏ๐ŸŽ: ๐๐‘จ = ๐๐‘ฉ = ๐๐‘ช; ๐‘ฏ๐Ÿ:At least one mean is different.

The cr it ical value is ๐‘ญ๐‘ช๐‘ฝ = ๐Ÿ’.๐Ÿ๐Ÿ”, Reject ๐‘ฏ๐ŸŽ s ince the test stat ist ic fa l ls ins ide the r ight ta i led reject ion region with p value of 0.025. There is evidence to indicate a difference in the mean assembly t imes for people trained by the three programs.

b . (Using F isherโ€™s Least S ignif icant Difference) The t-value for a l l confidence

intervals is 3.250 and the est imate for s is square root of MSE= ๐Ÿ๐Ÿ’.๐Ÿ— โ‰ˆ ๐Ÿ‘.๐Ÿ–๐Ÿ”๐ŸŽ๐ŸŽ๐Ÿ“

The 99% Confidence intervals for the mean assembly t ime for programs A, B, and C are

๐Ÿ“๐Ÿ’.๐Ÿ๐Ÿ๐Ÿ• < ๐๐‘จ < ๐Ÿ”๐Ÿ”.๐Ÿ•๐Ÿ•๐Ÿ‘ ๐Ÿ’๐Ÿ•.๐Ÿ’๐Ÿ๐Ÿ’ < ๐๐‘ฉ < ๐Ÿ”๐Ÿ.๐Ÿ—๐Ÿ๐ŸŽ ๐Ÿ“๐Ÿ–.๐Ÿ“๐Ÿ—๐ŸŽ < ๐๐‘ช < ๐Ÿ”๐Ÿ—.๐Ÿ–๐Ÿ๐ŸŽ

With 99% confidence there doesnโ€™t seem to be a s ignif icant difference among the three methods. This is because there is an intersect ion in a l l confidence intervals .

This is not contradictory to our result because the test in (a) had s ignif icance level 0.05 (or confidence 95%). You can verify this by construct ing the 95% simultaneous CIs (B and C do not intersect.)

Page 12: ACTM State Exam-Statistics

I t is more l ikely that they wi l l compute confidence intervals for each set separately, g iv ing even wider intervals that st i l l overlap.

๐Ÿ“๐Ÿ.๐Ÿ’๐Ÿ < ๐๐‘จ < ๐Ÿ”๐Ÿ—.๐Ÿ“๐Ÿ– ๐Ÿ‘๐Ÿ•.๐Ÿ๐Ÿ”๐Ÿ < ๐๐‘ฉ < ๐Ÿ•๐Ÿ.๐Ÿ๐Ÿ•๐Ÿ ๐Ÿ“๐Ÿ’.๐Ÿ”๐ŸŽ๐Ÿ– < ๐๐‘ช < ๐Ÿ•๐Ÿ‘.๐Ÿ•๐Ÿ—๐Ÿ