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#6.43 B x =0 M D = J y *9.6-12*4.8-12*7.2=0 J y =15 kN

Ahmed.abubakr.201300656.SPC209 Assignment#3

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#6.43

Bx=0MD= Jy*9.6-12*4.8-12*7.2=0Jy=15 kNBy=24-15=9 kNFCD=-By=-9 kNMD=-FA*1.8-2.4*By=0FA=-12 kNFDF=-FA =12 kN

##6.47

Ay=Ax=Ny=0Fy=FDF*3/5+FEF+FEG*3/5=0 (1)Fy= 4/5FDF+4/5FEG+16=0 (2)ME=16*16-FDF*3/5*4=0FDF=40Substitute in (2) FEG=-60 kN In (1) FEF=-12 kN

###6.53

Ay=40 kNMA=-Bx*5-10(3+6+9+12)=0 Bx=-60 kNCD/5=9/12 CD=3.75 MC=-10(3+6+9)+FDF*12/13*-3.75=0FDF=-52 kNFCA=-FDF*12/13=45 kN-FCD-40-FDF*5/13=0FCD=20 kN

####6.63

MD=-5*3-FFI*4=0 FFI=-3.75 kNDDG=3.375 kN

#####6.49

KX=36 KnMK=20*4.5+20*9+36*2.4-BY*13.5=0BY=36.4 kNKY=40-26.4=13.6 KnMC=-FAD*1.2+36+1.2-26.4*2.25=0FAD=-13.5 KnFX=-36*-13.5+FCD15*17 +FCE*15/17=0 (1)MA=FCD*8/17*4.5=0FCD=0SUBSTITUTE IN (1)FCE=56.1