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Aim: Differentiating Natural Log Function Course: Calculus
Do Now:
Aim: How do we differentiate the natural logarithmic function?
5
1
1Evaluate: dx
x
1
, 11
nn x
x dx C nn
Power Rule
Aim: Differentiating Natural Log Function Course: Calculus
Exponential Equation
y = bx
Inverse Exponential Function
y = logbxLogarithmic Equation
Inverse of Exponential Equation
x = by
Exponential example
y = 2x
y = log2xLogarithmic example
Inverse of Exponential example
x = 2y
logb x = y if and only if by = xThe expression logb x is read as the “log base b of x”. The function f(x) = logb x is the logarithmic function with base b.
Logarithm = Exponent
y = bx
“x is the logarithm of y”
y = logbx
“y is the logarithm of x
Aim: Differentiating Natural Log Function Course: Calculus
Natural Logarithmic Function
f(x) = logex = ln x, x > 01. ln 1 = 0
2. ln e = 1
3. ln ex = x
because e0 = 1
because e1 = e
because ex = ex
4
2
-2
-4
-5 5
u x = lnx
4
2
-2
-4
-5 5
v x = ex
The logarithmic function with base eis called the natural
log function.
4. e ln x x inverse property5. If ln x = ln y, then x = y
1lim 1
x
xe
x
Aim: Differentiating Natural Log Function Course: Calculus
Properties of Natural Log
1. The domain is (0, ) and the range is (-, ).
2. The function is continuous, increasing, and one-to-one.
3. The graph is concave down.
If a and b are positive numbers and n is rational, then the following are true
• ln(1) = 0
• ln(ab) = ln a + ln b
• ln(an) = n ln a
• ln (a/b) = ln a – ln b
4
2
-2
-4
-5 5
u x = lnx
Aim: Differentiating Natural Log Function Course: Calculus
Using Properties of Natural Logarithms
2. ln e2
3. ln e0
Rewrite each expression:
e
11. ln
ln ex = x because ex = ex
= -1
= 2
= 0
4. 2ln e = 2 ln e = 1 because e1 = e
e 1ln
ln ex = x
ln ex = x
Aim: Differentiating Natural Log Function Course: Calculus
Model Problems
Use natural logarithms to evaluate log4 30
log b M log c M
log c b
`
log4 30ln30
ln4
3.401198...
1.38629...2.4538....
Given ln 2 0.693, ln 3 1.099, and ln 7 1.946, use the properties of logs to approximate a) ln 6 b) ln 7/27
ln 6
ln 7/27
= ln (2 • 3) = ln 2 + ln 3 0.693 + 1.099 1.792= ln 7 – ln 27 = ln 7 – 3 ln 3 1.946 – 3(1.099) -1.351
Aim: Differentiating Natural Log Function Course: Calculus
Model Problems
Use properties of logarithms to rewrite
ln3x 5
7 = ln(3x – 5)1/2 – ln 7
= 1/2 ln(3x – 5) – ln 7
22
23
3ln
1
x
x x
2 2 23
1 32 2
1 32 2
2 2
ln( 3) ln 1
2ln( 3) ln ln 1
2ln( 3) ln ln 1
12ln( 3) ln ln 1
3
x x x
x x x
x x x
x x x
Aim: Differentiating Natural Log Function Course: Calculus
Power Rule – the exception
3 32 2
2 21 1
0
1
1 2 12
3 3
2 2
??? ???
x
x
x
x
x
x xD x x dx C
x xD x x dx C
D x x dx x C
dxD x C
xdx
D x x x Cx
Aim: Differentiating Natural Log Function Course: Calculus
Power Rule – the exception
1
, 11
nn x
x dx C nn
Power Rule
5
1
1Evaluate: dx
x5 1
1x dx
5 51 1 0
1 1
!!!!0 0
x x
don’t work!
Aim: Differentiating Natural Log Function Course: Calculus
Power Rule – the exception
1
, 11
nn x
x dx C nn
Power Rule
no antiderivative for f(x) = 1/x
1
1ln , 0
xx dt x
t
The domain of the natural logarithmic function is the set of all positive real
numbers.
Definition of the Natural Logarithmic Function
2nd Fundamental Theorem of Calculus
( )x
a
d dFf t dt f x
dx dx
accumulation function
Aim: Differentiating Natural Log Function Course: Calculus
Definition of the Natural Log Function
1
1ln , 0
xx dt x
t
4
3.5
3
2.5
2
1.5
1
0.5
1 2 3 4
f x = 1
x
4
3.5
3
2.5
2
1.5
1
0.5
1 2 3 4
f x = 1
x
ln x is positive when x > 1
1
1If 1, 0
xx dt
t
x x
1
1If 0 < 1, 0
xx dt
t
11
ln x is negative when x < 1
ln(1) = 01
1
10dt
t
4
2
-2
-4
-5 5
u x = lnx
The natural log function measures the area under the curve f(x) = 1/x between 1 and x.
Aim: Differentiating Natural Log Function Course: Calculus
e
1
1ln
xx dt
t
1
1ln 1
ee dt
t
What is the value of x?
4
3.5
3
2.5
2
1.5
1
0.5
1 2 3 4
f x = 1
x
e1
1
1Area = 1
edt
t
ln 1e 1log 1e e e e
ln ne
ln
1
n e
n
n
1
e
x
4
2
-2
-4
-5 5
u x = lnx
(e, 1)
Aim: Differentiating Natural Log Function Course: Calculus
The Derivative of the Natural Log Function
Let be a differentiable function of .
1ln , 0
u x
dx x
dx x
Chain Rule
1 'ln , 0
d du uu u
dx u dx u
1
1 1ln 0
xd ddt x x
dx t x dx
2nd Fundamental Theorem of Calculus
( )x
a
d dFf t dt f x
dx dx
1
1ln , 0
xx dt x
t
Aim: Differentiating Natural Log Function Course: Calculus
Model Problems
1. ln 2d
xdx
2u x
' 2 1ln 2
2
d ux
dx u x x
u’ = 2
2. lnd
xdx
u x
1 21 2
1 1 1 1 1ln '
2 2
du x
dx u u x x
1 21'
2u x
Aim: Differentiating Natural Log Function Course: Calculus
Model Problems
2ln 1d
xdx
2
' 2
1
u x
u x
lnd
x xdx
ln lnd d
x x x xdx dx
1ln 1 1lnx x x
x
2 1u x u’ = 2x
3ln
dx
dx 2
3 ln lnd
x xdx
2 13 ln x
x
Aim: Differentiating Natural Log Function Course: Calculus
Rewrite Before Differentiating
Differentiate ( ) ln 1f x x
rewrite 1 2 ( ) ln 1f x x
1 ln 1
2x
1 1 1
'( )2 1 2 1
f xx x
1 1 ln 1 ln 1
2 2
d dx x
dx dx
1u x u’ = 1 1 'ln
d du uu
dx u dx u
Aim: Differentiating Natural Log Function Course: Calculus
Model Problem
22
3
1Differentiate ( ) ln
2 1
x xf x
x
1 'ln
d du uu
dx u dx u
rewrite 2 31ln 2ln 1 2 1
2x x x
'( )f x
u = x2 + 1 u = 2x3 – 1 u’ = 2x u’ = 6x2
2
2 3
1 4 3
1 2 1
x x
x x x
1
x 2
22
1
x
x
2
3
1 6
2 2 1
x
x
Aim: Differentiating Natural Log Function Course: Calculus
Logarithmic Differentiation
2
2
2Differentiate
1
xy
x
14
12
10
8
6
4
2
-2
5 10 15
g x = x-2 2
x2+1 0.5
y is always positive therefore ln y is defined
take ln of both sides
2
2
2ln ln
1
xy
x
Log properties 21ln 2ln 2 ln 1
2y x x
2
' 1 1 22
2 2 1
y x
y x x
Differentiate
Applying the laws of logs to simplify functions that include quotients, products and/or powers can simplify differentiation.
Aim: Differentiating Natural Log Function Course: Calculus
Using Log Derivative
2
2
2Differentiate
1
xy
x
2
' 1 1 22
2 2 1
y x
y x x 2
2
2 1
x
x x
Solve for y’,
Substitute for y
& Simplify
2
2'
2 1
xy y
x x
2 2
22
2 2 2
2 11
x x x
x xx
2
3 22
2 2 2
1
x x x
x
Aim: Differentiating Natural Log Function Course: Calculus
Derivative Involving Absolute ValueIf is a differentiable function of
such that 0, then
'ln
u x
u
d uu
dx u
Find the derivative of f(x) = ln|cosx|
'ln cos
sin
costan
d ux
dx ux
xx
u = cosx u’ = -sinx
Aim: Differentiating Natural Log Function Course: Calculus
Model Problem
2Find the relative extrema of ln 2 3y x x u = x2 + 2x + 3
u’ = 2x + 22
' 2 2'
2 3
u xy
u x x
2
2 20 1
2 3
xx
x x
1st Derivative Test
f(-1) = ln[-12 + 2(-1) + 3] = ln 2
Relative Extrema – (-1, ln2)
Evaluate critical point
Minimum
2
22
2 4 2''
2 3
at 1 positive result
concave up
x xy
x x
x
2nd Derivative Test
6
4
2
-5 5
g x = ln x2+2x+3
Aim: Differentiating Natural Log Function Course: Calculus
Do Now:
Aim: How do we differentiate the natural logarithmic function?
2
lnFind the derivative for ( )
tg t
t