A Glimpse into the Special Theory of RelativitySiim Ainsaar January 20131 Why relativity?..............................12 Postulates of special relativity.......23 Basic thought experiments............2

3.1 Time dilation................................23.2 Length contraction.......................33.3 Proper time..................................3

4 Lorentz transformations................34.1 Spacetime interval.......................34.2 Minkowski spacetime,

Poincar transformations.............44.3 Rapidity.......................................44.4 Hyperbolic trigonometry..............54.5 Length contraction, time dilation

and velocity addition....................5

4.6 Light-cones, simultaneity andcausality......................................6

4.7 Lorentz transformationsalgebraically.................................7

5 Dynamics.......................................75.1 Four-velocity and

four-acceleration..........................75.2 Mass, momentum and energy......85.3 Force............................................9

6 Optical effects................................97 Electromagnetism..........................98 Basic problems...............................99 Olympiad problems........................910 Further reading............................9

1 Why relativity?

Relativity is often seen as an intric-ate theory that is necessary onlywhen dealing with really highspeeds or ultra-precise measure-ments. However, there are somequite often-encountered topics thatare paradoxical if treated non-relativistically. These are also someof the main sources of Olympiadproblems on relativity.

Think for a moment about twocharged initially stationaryparticles. They feel only the elec-trostatic force from each another.But in another, moving referenceframe there is also the magneticforce, in general, in a different dir-ection! How could force depend onthe choice of inertial referenceframe? What principles forbid theparticles from colliding in one

frame and departing in another?Electromagnetism needs relativityfor an explanation.

Photons (thus, much of optics) arealways relativistic and otherparticles often are. Anything wherethe speed of light matters for ex-ample, the GPS measuring the timefor a radio signal to travel fromsatellites uses relativity.

Particle physics needs relativity inseveral aspects. Particles cannot becontrolled in a modern acceleratorwithout taking into account theirrelativistic dynamics. The only suc-cessful quantum theory predictingthe outcomes of particle collisions,quantum field theory, is relativistic.Muons in cosmic rays would decaylong before reaching the ground,but we still detect them thanks torelativistic time dilation.

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Relativistic theory of gravity gen-eral relativity allows to formulatethe physics independently ofwhether the reference frame is iner-tial or not, thus unifying time andspace even more tightly. It is neces-sary for astrophysics (precession ofplanets' orbits, gravitational lens-ing, black holes), and cosmology(history and future of large-scalestructures).

* * *

In the following, we shall derive themost important results of the spe-cial theory of relativity, startingfrom the fundamental postulates.Most steps of the derivation are giv-en as problems, which are alsogood examples of what one can askin relativity and exercise thereader's ability to use the theory.

The most important general tech-nique for problem-solving is rota-tion of Minkowski spacetime incomplex coordinates, this is de-scribed in section 4. Section 3 showsthe way from postulates to the use-ful techniques, its problems may beskipped if concentrating purely onOlympiad preparation. Section 4 ismostly on kinematics, the followingones develop dynamics, optics and(briefly) electromagnetism from it.Finally, some problems for prac-tising are given.

2 Postulates of special relativity

1. The laws of all physics arethe same in every inertial ref-erence frame.

A reference frame is inertial if andonly if objects onto which no forceacts move in a straight line withconstant velocity.

2. The speed of light in vacu-um (c) is the same in everyinertial reference frame.

In SI, after defining the second,* themetre is defined through fixing (ex-actly!) c = 299,792,458 m/s.

3 Basic thought experiments

3.1 Time dilation

Problem 1. Consider a lightclock that works as follows. Aphoton is emitted towards amirror at a known distance land reflected back. It is detec-ted (almost) at the emitteragain. The time from the emis-sion to the detection (a tick)is measured to be t. Now we

* One second is the duration of9,192,631,770 periods of theradiation corresponding to thetransition between the two hyperfine levels of the ground stateof the caesium-133 atom at rest at atemperature of 0 K.

2

look at the clock from a refer-ence frame where the wholeapparatus is moving with velo-city v perpendicularly to the lightbeam. Assume that the lengthsperpendicular to the motion donot change. How long is thetick for us? (Hint: the lightbeam follows a zig-zag path.)

The answer is given by the follow-ing fact.

Fact 1. If the time intervalbetween to events happeningat a stationary point is t, thenin a reference frame where thespeed of the point is v thetime interval is t , wherethe Lorentz factor

= 11v2c2 .Another useful quantity in relativ-istic calculations is =v /c . As>1 , we see everything in a mov-

ing vehicle take longer than in a sta-tionary one time is dilated(stretched) in a moving referenceframe.

3.2 Length contraction

Problem 2. Now consider thesame light clock as in Prob-lem 1., but moving in parallel tothe light beam, with velocity v.What is the distance to the mir-

ror in our reference frame, ifthe distance in the stationaryframe is l?

The answer is in the following fact.

Fact 2. If the length of a station-ary rod is l, then its length in areference frame moving inparallel to the rod with speedv is l / .

Lengths are contracted (compressed)in the direction of motion.

3.3 Proper time

Problem 3. A spaceship fliesfreely from (t1 ,x1 , y1 , z1)(event 1) to (t2 , x2 , y2 , z2)(event 2). What is the propertime time measured by apassenger on the spaceship between these events? [Answer:c2 2=c2(t2t1)2(x2x1)2

( y2 y1)2( z2z1)2]

4 Lorentz transformations

4.1 Spacetime interval

In ordinary, Galilean relativity,lengths and time intervals are abso-lute. As we have now seen, the pos-tulates of Einsteinian relativity im-ply that neither is so, once speedsbecome comparable to c. However,proper time time in a comovingframe must clearly be independ-ent of our reference frame. There-fore we can define a new invariant

3

quantity with the dimension oflength.

Fact 3. The spacetime intervals=c2( t)2( x)2( y)2( z )2

is independent of the choiceof reference frame.

If s is a real number, the interval iscalled time-like; if s is imaginary, theinterval is space-like. If s is zero, theinterval is light-like.

Fact 4. The interval between twoevents on the same light-ray(in vacuum) is zero thus,light-like.

4.2 Minkowski spacetime,Poincar transformations

We can say that spacetime pointsare represented by position four-vec-tors* x=(ct , x , y , z) and the in-terval calculates the length of thedisplacement four-vector x .However, this law of calculating thelength has important minus signs init, so these four-vectors form aMinkowski spacetime, not the usualEuclidean space, where lengthswould be calculated using the usualPythagoras' law.

We can reuse our familiar laws ofgeometry if we introduce complex

* Four-vectors are customarilylabelled by Greek indices writtenas superscripts; subscripts have ameaning in more advanced theory.

numbers. Namely, the invariantquantity

is=( i c t)2+( x)2+( y )2+( z)2is now expressed just like Py-thagorean theorem. So, the Euc-lidean distance between two eventsin the spacetime of (ict, x, y, z) is in-dependent of reference frame.

What transformations of Euclideanspace leave lengths invariant? Rota-tions and translations and combina-tions thereof!

Fact 5. Changes of inertial refer-ence frames correspond to ro-tations and shifts in the space-time coordinates ict, x, y and z.

In general, such transformations arecalled the Poincar transformations*

and, if we only rotate and do notshift the coordinates, the Lorentztransformations.

4.3 Rapidity

By what angle should we rotate theaxes? Clearly, as one axis has ima-ginary numbers on it, the anglemust also be complex.

Luckily this poses no problems indrawing the angle, as long as weconsider only one-dimensional mo-tion: it turns out to be a purely ima-ginary angle, so its cosine

* The Poincar transformations arealso known as the inhomogeneousLorentz transformations.

4

cos = ei+ei

2 (a projection of the

unit direction vector) is real (can bedrawn on the real x-axis) and its

sine sin = eiei

2 i is purely ima-

ginary (can be drawn on the ima-ginary ict-axis).

Problem 4. Take two coordinatesystems, O and O', with thespatial axes parallel and the(spatial) origin* of O' moving inthe x-direction with velocity v.Calculate the angle betweenthe x- and x'-axis. (Hint: makea diagram with ict on one axisand x on another. Add the ict'-and x'-axes. Calculate the x-and ict-coordinate of one arbit-rary point the spatial origin ofO' passes through. The ratio ofthese coordinates is tan .)

Such a Lorentz transformation in-volving only time and one spatialcoordinate is called the Lorentz boostin the x-direction. The answer to theproblem is the following useful fact.

Fact 6. A Lorentz boost in the x-direction from standstill to ve-locity v corresponds to rota-tion of x- and ict-axis by anangle of

=arctan vic=arctani .

* In the spatial origin, x = y = z = 0,but ict changes.

Problem 5. Calculate cos andsin .

Fact 7. cos= , sin= /i .The quantity =/i is a real di-mensionless number and is calledthe rapidity.

4.4 Hyperbolic trigonometry

Some imaginary units i and someminuses can be eliminated by usinghyperbolic trigonometry. Employ-

ing the formulae sinh = ee

2 ,

cosh = e+e

2 , tanh=sinhcosh

and cosh 2sinh2=1 you canprove the following.

Problem 6. Prove for the rapidity that tanh= , cosh =

and sinh = .Consequently, using the inversefunction of hyperbolic tangent,=i=i artanh .4.5 Length contraction, time

dilation and velocity addition

Problem 7. Prove again the lengthcontraction formula of Fact 2.Here use rotation of Minkowskispacetime.

Problem 8. Prove similarly thetime dilation formula of Fact 1.

Fact 8. If an object moves with re-spect to reference frame O'with velocity u and O' moves

5

with respect to frame O withvelocity v in the same direc-tion, then the velocity of theobject in O is

w= u+v1+uv

c2.

Problem 9. Prove the velocity ad-dition formula in the last fact.

(Hint: tan(+)= tan+ tan1tan tanand

tanh(+)= tanh+tanh1+ tanh tanh .)

Problem 10. Show that the velocityaddition formula implies thepostulate that the speed of lightis universal. (Hint: u=c .)

Problem 11. Prove that if u and v inthe velocity addition formulaare both between c and c ,then so is w. (Hint: show thatdwdu >0 hence w is monoton-

ous and use the result of thelast problem that u=c cor-responds to w=c .)

Fact 9. If there exists a referenceframe where an object movesslower than light, then it doesso in every reference frame.

4.6 Light-cones, simultaneity andcausality

The trajectory of a particle in thespace-time is called its world-line.

The world-line of a photon cuts avery special wedge from the dia-gram: the inside of the wedge canbe influenced event at the tip of thecone; the outside cannot. The regionwhere an event can have influencein is called the light-cone of theevent.

Fact 10. If the spacetime diagramis scaled so that i metres (onthe ict-axis) is at the same dis-tance from the origin as 1metre (on the x-axis), then theworld-line of a photon is at45 from either axis.

Fact 11. Simultaneity is relative.

Problem 12. In reference frame O,two events take place at thesame time t = 0, but with spa-tial separation x . What is thetime t ' between them in ref-erence frame O', which is mov-ing in the x-direction with velo-city v? [Answer:t '= v x/ c2 ]

Fact 12. The order of two eventswith time-like or light-likeseparation is absolute. Forspace-like separation, the or-der depends on the referenceframe.

This means that only time-like orlight-like separation allows oneevent to be the cause of another. De-manding that the causality should

6

hold and, thus, no information maybe sent to the past, we get the fol-lowing fact.

Fact 13. Information cannotpropagate faster than light invacuum.

This means, among many other im-plications, that everything must besomewhat deformable: if we pushone end of a long rod, then the pushwill propagate to the other endslower than c (probably muchslower).

4.7 Lorentz transformationsalgebraically

Fact 14. When going to a referenceframe moving in the x-direc-tion with velocity v, the timeand space coordinates of anevent transform under Lorentztransformations as follows.

t '=( tvxc2

)x '=(xvt )y '= yz '=z

Problem 13. Prove the last fact.

Problem 14. Show algebraicallythat if boosting in both x- andy-directions, the order of boostsmatters.

Intuitively, as boosts are rotations,their order should matter just likethe order of ordinary spatial rota-tions matters: try turning a book

over around two different axes, re-member the result and then repeat,switching the axes. The result oftwo successive boosts in differentdirections is actually not just a boostin a third direction, but adds somerotation that depends on the orderof the boosts.

5 Dynamics

5.1 Four-velocity andfour-acceleration

Generalising from the position four-vector x=(ct , x , y ,z ) intro-duced in section 4.2, we now in gen-erality define a four-vector as a col-lection of four numbersq=(qt ,qx ,q y ,qz) that trans-

forms under Lorentz transforma-tions. The spatial components(qx ,q y , qz)q rotate just like ausual vector. The time- and space-components are mixed by Lorentzboosts that act as rotations in thefour-space of ( iqt , q) . A boost inthe x-direction is given just as inFact 14.

qt '=(qtqx)qx'=(qx qt )

The Lorentz-invariant length of thefour-vector is

q=(qt)2(q x)2(q y )2(qz)2 .We already know that periods ofproper time d are Lorentz-

7

invariant. Thus, the following deriv-atives can be formed.

Fact 15. Four-velocity v=d x

d and four-acceleration

a=d v

d of a particle arefour-vectors.

Problem 15. Show that the four-velocity of a particle movingwith speed v in the x-directionis ( c , v , 0,0) .

Problem 16. What Lorentz-invari-ant quantity is the length of thefour-velocity from the lastproblem? [Answer: c]

As the x-direction was arbitrary, wecan generalize the answer as fol-lows.

Fact 16. The length of any four-velocity is c.

Problem 17. Show that the four-acceleration of a particle mov-ing and accelerating in the x-direction with a three-accelera-tion of magnitude a=dv/ dt is( 4 a ,4 a ,0,0) with in-variant length a.

5.2 Mass, momentum and energy

Some texts about relativity distin-guish the rest mass or invariant massm from the relativistic mass m ,

but this would be misleading for

discussing motion in several dimen-sions. Therefore, in this studyingmaterial, we refer to m as just themass. This mass is an intrinsic prop-erty of any object and does not de-pend on the reference frame.

Fact 17. The four-momentum of aparticle with mass m is thefour-vector p=m v .

Fact 18. p=(E /c , p) where thetotal energy E=m c2 andthe relativistic momentump=m v .

Note that here v is the usual three-velocity and not the spatial part ofthe four-velocity that has an addi-tional in it.Fact 19. The length of the four-

momentum is mc, whateverthe velocity is. Therefore,E2=( p c)2+(mc2)2 .

For massless particles (such asphotons), E=pc .

Fact 20. In interactions, four-momentum is conserved.

This encompasses both the conser-vation of energy and the conserva-tion of momentum.

Fact 21. The total energy can beseparated into the rest energyE rest=mc2 and the kinetic

energy Ek=(1)m c2 .

8

Problem 18. Show that for low

speeds, Ekm v2

2 .

Note that if an object has any intern-al structure and, thus, internal en-ergy, then it must be taken into ac-count in its rest energy and, thus, its(rest) mass.

On the other hand, for any ul-trarelativistic object moving almostwith a speed of c, the rest energyand the rest mass can be neglected;thus, Epc .Since the speed of light, c, corres-ponds to = , we can deduce thefollowing.

Fact 22. It takes infinite energy toaccelerate a massive objectto c. Massless particles moveonly with a speed of c.

5.3 Force

Fact 23. F=d pd t =d (m v )

d t .

Fact 24. Four-force

F=m a=d p

d .

Problem 19. Show that if all themotion is in x-direction, thenF=( F , F ,0,0) .

In general, F=( vF /c , F)where vF=dE/dt is the power.

6 Optical effects

Problem 20. What is the apparentlength of a rod with rest lengthl moving with velocity v in par-allel to the rod, if you take intoaccount the finite travel timesof photons from its ends to oureyes?

Fact 25. Doppler shift of the fre-

quency of light: '=0 cvc+v .Problem 21. Prove the formula,

considering the world-lines oftwo wave-crests.

Problem 22. Reprove the for-mula using E=h .

At least two important relativisticoptical effects have been left out ofthis studying material, but are stillworthwhile to think about:

Measuring the Astronomic-al Unit through aberration

Compton scattering

7 Electromagnetism

The Lorentz force acting on a particlewith charge q moving in an electro-magnetic field is F=q E+q vB . Ifwe separate the fields into compon-ents parallel and perpendicular tov , it can be shown that the electric

and magnetic fields transform into

9

each other upon Lorentz transform-ations:

Fact 26. E '=E , B'=B ,E '=(E+ vB ) ,

B '=(BvE /c2) .

8 Additional problems

The following problems have beentranslated from an Estonian book.*

Problem 23. A rod with rest lengthl0 is moving translationallywith speed v in such a way thatthe line connecting its end-points at an instant forms anangle with the direction ofmotion. Find its length. [An-

swer:l0

12sin 2 ](PK200)

Problem 24. A body is moving uni-formly in a circle, an orbit takest = 3 h. A clock inside the bodysees it to take =30min . Findthe radius R of the orbit. [An-swer: ct22/(2 ) ] (PK201)

* Paul Kard, Elektrodnaamika jaspetsiaalse relatiivsusteoorialesannete kogu (A collection ofproblems on electrodynamics and special relativity), Tartu State University 1961. Herewe cite it as PK, followed by theproblem number.

Problem 25. The characteristic life-time of a muon at rest is=2.2106 s. How long a paths can it travel since its creation,if its speed is v = 0.999c? [An-swer: v =14.7 km] (PK202)

Problem 26. A pion at rest decaysinto a muon and a neutrino.Find the total energy E and thekinetic energy T of the muon, ifthe rest masses of the pion andthe muon are, respectively, mand m ; the rest mass of theneutrino is zero. [Answers:

E=(m2+m2)c22m

,

T=(mm)2 c2

2 m] (PK234)

Problem 27. A muon at rest decaysinto an electron and two neutri-nos. The rest mass of the muonis , the mass of the electronis m, the mass of the neutrino iszero. Find the maximum pos-sible energy Emax of the elec-

tron. [Answer: mc 2 1+(/m)2

2(/m) ](PK235)

Problem 28. At least how big mustbe the energy E of a pion, if itscollision with a nucleon at restproduces a nucleon-antinucle-on pair and the pion is ab-sorbed? The rest masses of thenucleon and the pion are, re-

10

spectively, M and m. [Answer:(8 M 2m2)c2/(2M ) ] (PK244)

Problem 29. At least how bigshould be the energy E of a nuc-leon, if its collision with a nucle-on at rest produces a nuc-leon-antinucleon pair and theoriginal nucleons are bothintact? The rest mass of the nuc-leon is M. [Answer: 7 M c2 ] (PK245)

Problem 30. An atom withrest mass m, at rest, radiates aphoton with frequency . Whatis the rest mass m0 of the atomafter the process? [Answer:m12 h/(mc2) ] (PK248)

Problem 31. The differencebetween an excited energy leveland the ground level of an atomis E . What should the speed vof the excited atom be, if wewant a photon, that is radiatedin the direction of motion, have afrequency of E /h ? The restmass of the atom in its groundstate is m. [Answer:

c(+3 2 /4)(2+3 +5 2/ 4)1 ](Part of PK249)

9 Olympiad problems

See the following pages for the ori-ginal texts of the problems.

Cuba 1991 (RelativisticSquare)

Iceland 1998 (Faster thanLight?)

Taiwan 2003 (Neutrino De-cay)

China 1994 (RelativisticParticle)

Australia 1995 (Gravitation-al Red-shift)

Physics Cup 2012 (Electron-Positron annihilation)

10 Further reading

Ta-Pei Cheng, Relativity,gravitation, and cosmology:a basic introduction, Ox-ford University Press, 2005,2006

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T H E O R E T I C A L P R O B L E M S

Problem 1 The figure 1.1 shows a solid, homogeneous ball radius R. Before falling to the floor its center of mass isat rest, but the ball is spinning with angular velocity 0 about a horizontal axis through its center. Thelowest point of the ball is at a height h above the floor.

When released, the ball falls under gravity, and rebounds to a new height such that its lowest point is nowah above the floor. The deformation of the ball and the floor on impact may be considered negligible.Ignore the presence of the air. The impact time, although, is finite.

The mass of the ball is m, the acceleration due the gravity is g, the dynamic coefficient of friction betweenthe ball and the floor is k, and the moment of inertia of the ball about the given axis is:I =

52 2mR

You are required to consider two situations, in the first, the ball slips during the entire impact time, and in the second the slipping stops before the end of the impact time.

Situation I: slipping throughout the impact.Find:a) tan , where is the rebound angle indicated in the diagram;b)the horizontal distance traveled in flight between the first and second impacts;c) the minimum value of 0 for this situations.Situation II: slipping for part of the impacts.Find, again:a) tan ;b)the horizontal distance traveled in flight between the first and second impacts.Taking both of the above situations into account, sketch the variation of tan with 0.Problem 2 In a square loop with a side length L, a large number of balls of negligible radius and each with a charge q are moving at a speed u with a constant separation a between them, as seen from a frame of reference thatis fixed with respect to the loop. The balls are arranged on the loop like the beads on a necklace, L being much greater than a, as indicated in the figure 2.1. The no conducting wire formingthe loop has a homogeneous charge density per unit length in the in the frame of the loop. Its total chargeis equal and opposite to the total charge of the balls in that frame.

Consider the situation in which the loop moves with velocity v parallel to its side AB (fig. 2.1) through ahomogeneous electric field of strength E which is perpendicular to the loop velocity and makes an angle with the plane of the loop.

Taking into account relativistic effects, calculate the following magnitudes in the frame of reference of anobserver who sees the loop moving with velocity v:a)The spacing between the balls on each of the side of the loop, aAB , aBC , aCD , y aDA.b)The value of the net charge of the loop plus balls on each of the side of the loop: QAB , QBC , QCD y, QDAc)The modulus M of the electrically produced torque tending to rotate the system of the loop and the

balls.d)The energy W due to the interaction of the system, consisting of the loop and the balls with the electric

field.All the answers should be given in terms of quantities specified in the problem.

Note. The electric charge of an isolated object is independent of the frame of reference in which themeasurements takes place. Any electromagnetic radiation effects should be ignored.

Some formulae of special relativity

Consider a reference frame S moving with velocity V with reference to another reference frame S. Theaxes of the frames are parallel, and their origins coincide a t = 0. V is directed along the positive direction of the x axis.

Relativistic sum of velocities

If a particle is moving with velocity u in the x direction , as measured in S, the velocity of the particlemeasured in S is given by:

2cVu

1

Vuu

+

+=

Relativistic Contraction

If an object at rest in frame S has length L0 in the x-direction, an observer in frame S (moving at velocityV in the x-direction} will measure its length to be:

L = 2

2

0 1 cv

L

Theoretical Question 3

Part ANeutrino Mass and Neutron Decay

A free neutron of mass mn decays at rest in the laboratory frame of reference intothree non-interacting particles: a proton, an electron, and an anti-neutrino. The restmass of the proton is mp, while the rest mass of the anti-neutrino mv is assumed to benonzero and much smaller than the rest mass of the electron me. Denote the speed oflight in vacuum by c. The measured values of mass are as follows:

mn939.56563 MeV/c2, mp 938.27231 MeV/c2, me0.5109907 MeV/c2

In the following, all energies and velocities are referred to the laboratory frame. Let Ebe the total energy of the electron coming out of the decay.(a) Find the maximum possible value Emax of E and the speed vm of the anti-neutrino

when E = Emax. Both answers must be expressed in terms of the rest masses of theparticles and the speed of light. Given that mv < 7.3 eV/c2, compute Emax and theratio vm /c to 3 significant digits. [4.0 points]

Theoretical Problem 1RELATIVISTIC PARTICLE

In the theory of special relativity the relation between energy E and momentum Por a free particle with rest mass m0 is

2420

22 mccmcpE

When such a particle is subject to a conservative force, the total energy of the

particle, which is the sum of 42022 cmcp and the potential energy, is conserved. If

the energy of the particle is very high, the rest energy of the particle can be ignored(such a particle is called an ultra relativistic particle).

1) consider the one dimensional motion of a very high energy particle (in whichrest energy can be neglected) subject to an attractive central force of constantmagnitude f. Suppose the particle is located at the centre of force with initialmomentum p0 at time t=0. Describe the motion of the particle by separatelyplotting, for at least one period of the motion: x against time t, and momentump against space coordinate x. Specify the coordinates of the turning points interms of given parameters p0 and f. Indicate, with arrows, the direction of theprogress of the mothon in the (p, x) diagram. There may be short intervals oftime during which the particle is not ultrarelativistic. However, these should beneglected.Use Answer Sheet 1.

2) A meson is a particle made up of two quarks. The rest mass M of the meson isequal to the total energy of the two-quark system divided by c2.

Consider a one--dimensional model for a meson at rest, in which the twoquarks are assumed to move along the x-axis and attract each other with a forceof constant magnitude f It is assumed they can pass through each other freely.For analysis of the high energy motion of the quarks the rest mass of the quarkscan be neglected. At time t=0 the two quarks are both at x=0. Show separatelythe motion of the two quarks graphically by a (x, t) diagram and a (p, x)diagram, specify the coordinates of the turning points in terms of M and f,indicate the direction of the process in your (p, x) diagram, and determine themaximum distance between the two quarks.Use Answer Sheet 2.

3) The reference frame used in part 2 will be referred to as frame S, the Lab frame,referred to as S, moves in the negative x-direction with a constant velocityv=0.6c. the coordinates in the two reference frames are so chosen that the point

2

x=0 in S coincides with the point 0x in S at time 0tt . Plot themotion of the two quarks graphically in a ( x , t ) diagram. Specify thecoordinates of the turning points in terms of M, f and c, and determine themaximum distance between the two quarks observed in Lab frame S .Use Answer Sheet 3.The coordinates of particle observed in reference frames S and S are relatedby the Lorentz transformation

)(

)(

cxtt

ctxx

where cv / , 21/1 and v is the velocity of frame S moving relative

to the frame S .4) For a meson with rest energy Mc2=140 MeV and velocity 0.60c relative to the

Lab frame S , determine its energy E in the Lab Frame S .

ANSWER SHEET 1 ANSWER SHEET 21) 2)

3

Ot

x

Ox

p

t

x1, x

2

Ox

1

p1

Ox

2

p2

Quark1 Quark2

The maximum distance between the two quarks is d=

Theoretical Question 1

Gravitational Red Shift and the Measurement of Stellar Mass

(a) (3 marks)A photon of frequency f possesses an eective inertial mass m determined by its energy. Assumethat it has a gravitational mass equal to this inertial mass. Accordingly, a photon emitted at thesurface of a star will lose energy when it escapes from the stars gravitational eld. Show that thefrequency shift f of the photon when it escapes from the surface of the star to innity is given by

f

f

GM

Rc2

for f f where:

G = gravitational constant

R = radius of the star

c = velocity of light

M = mass of the star.

Thus, the red-shift of a known spectral line measured a long way from the star can be used tomeasure the ratio M/R. Knowledge of R will allow the mass of the star to be determined.

(b) (12 marks)An unmanned spacecraft is launched in an experiment to measure both the mass M and radiusR of a star in our galaxy. Photons are emitted from He+ ions on the surface of the star. Thesephotons can be monitored through resonant absorption by He+ ions contained in a test chamberin the spacecraft. Resonant absorption accors only if the He+ ions are given a velocity towards thestar to allow exactly for the red shifts.

As the spacecraft approaches the star radially, the velocity relative to the star (v = c) of the He+

ions in the test chamber at absorption resonance is measured as a function of the distance d fromthe (nearest) surface of the star. The experimental data are displayed in the accompanying table.

Fully utilize the data to determine graphically the mass M and radius R of the star. There is noneed to estimate the uncertainties in your answer.

Data for Resonance Condition

Velocity parameter = v/c (105) 3.352 3.279 3.195 3.077 2.955Distance from surface of star d (108m) 38.90 19.98 13.32 8.99 6.67

(c) (5 marks)In order to determine R and M in such an experiment, it is usual to consider the frequencycorrection due to the recoil of the emitting atom. [Thermal motion causes emission lines to bebroadened without displacing emission maxima, and we may therefore assume that all thermaleects have been taken into account.]

(i) (4 marks)Assume that the atom decays at rest, producing a photon and a recoiling atom. Obtain therelativistic expression for the energy hf of a photon emitted in terms of E (the dierence inrest energy between the two atomic levels) and the initial rest mass m0 of the atom.

(ii) (1 mark)

Hence make a numerical estimate of the relativistic frequency shift

f

f

recoil

for the case of

He+ ions.

Your answer should turn out to be much smaller than the gravitational red shift obtained inpart (b).

Data:

Velocity of light c = 3.0 108ms1

Rest energy of He m0c2 = 4 938(MeV)

Bohr energy En = 13.6Z2

n2(eV)

Gravitational constant G = 6.7 1011Nm2kg2

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Problem No 9Electron, initially at rest, is accelerated with a voltage , where is the electron's rest mass, the elementary charge, the speed of light, and a dimensionless number. The electron hits amotionless positron and annihilates creating two photons. The direction of one emitted photon defines thedirection of the other one. Find the smallest possible value of the angle between the directions of thetwo emitted photons (express it in terms of and provide a numrical value for ).

Problem No 9 | IPhO Estonia 2012 http://www.ipho2012.ee/physicscup/problem-no-9/

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