Aldehyde Ketone and Acid

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    Class-XII AldehydesKetonesCarboxylic Acids

    Jayanta kumar sahuPGT : ChemistryKendriya Vidyalaya Sangathan Page - 1

    ALIPHATIC PORTION

    [1] Preparation of Aldehydes and Ketones

    (a) From alcoholsPrimary alcohols in presence of oxidizing agents such as anhydrous CrO3 or PCC , or by

    catalytic dehydrogenation with Cu at 573 K get oxidised to aldehydes whereas secondaryalcohols results in the formation of ketones.

    R CH2 OHAnhydrous CrO 3 / PCC

    OxidationR CHOR CHO

    Cu / 573 K

    Dehydrogenation1o AlcoholAldehyde Aldehyde

    2 Cu O2 2 CuO+

    R CH2 OH + CuO Cu OH2R CHO + +

    Details of dehydrogenation

    (b) From alkenesThe alkenes on treatment with ozone followed by reductive cleavage (by Zn dust and water)results in the formation of aldehydes whereas substituted alkenes form ketones.

    CH CH2R O3+

    O O

    C C

    OR

    H

    H

    H

    Zn / H2OH C

    O

    HR C

    O

    H +Alkene

    Ozonide

    Aldehydes

    CH CH2R

    R

    O3+

    O O

    C C

    OR

    R

    H

    HZn / H2O

    R C

    O

    R + H CO

    H

    Ketone Aldehyde

    (c) From alkynesEthyne reacts with water in the presence of mercuric sulphate and sulphuric acid to yieldaldehyde i.e. ethanal. Other alkynes give ketones.

    CH CH +HgSO 4H2SO4

    H OHCH2 CH

    O H

    TautomerisationCH3 C

    O

    HEthyne Ethanalenol ( Unstable )

    C CHR + H OH+ HgSO 4

    H2SO4R C

    O H

    CH2

    TautomerisationR C CH

    3

    O

    Ketone

    [2] Preparation of Aldehydes only

    (a) From acid chlorides [ Rosenmund reduction ]

    R C

    O

    ClH2

    Pd - BaSO 4R C

    O

    H

    Acid chloride Aldehyde

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    Class-XII AldehydesKetonesCarboxylic Acids

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    (b) From Nitriles [ Stephen Reduction ]The reaction of alkanenitrile with HCl in the presence of anhydrous stannous chlorideyields corresponding imine, which on hydrolysis give corresponding aldehyde.

    R C NSnCl 2

    HClR CH NH

    imine

    OH3+

    R CHO

    (c) From Acid derivatives

    AcidLiAlH4

    AldehydeLiAlH4 1o Alcohol

    In order to prevent formation of alcohol, we use a derivative of carboxylic acid ( Acidchloride, Ester and Nitrile ) that is more easily reduced and an derivative of aluminiumhydride ( DIBAL-H ) that is less reactive than lithium aluminium hydride.

    AlH

    Diisobutylaluminium hydride ( DIBAL-H ) is less reactive than LiAlH4, because

    it is much more sterically hindered and ,therefore, have difficulty intransferring hydride ions.

    R C NAl H (i-Bu) 2 i.e. DIBAL-H

    OH2

    R CHO

    R C

    O

    OR1

    Nitrile

    Ester

    Al H (i-Bu) 2 i.e. DIBAL-HOH2

    R CHO

    R C

    O

    ClAcid chloride

    Al H (i-Bu) 2 i.e. DIBAL-HOH2

    R CHO

    [3] Preparation of Ketones only

    (a) From Acid chlorides

    Treatment of acyl chlorides with dialkylcadmium, prepared by the reaction of cadmiumchloride with Grignard reagent, gives ketones.

    R Mg X CdCl 2 R2Cd 2 Mg(X)Cl2 + +

    R1 C

    O

    Cl2 + R2Cd R1 CO

    R2 + CdCl 2(b) From Nitriles

    Treatment of nitrile with Grignard reagent followed by hydrolysis yields a ketone.

    R Mg XR1 C N +R1 C

    NMgBr

    R

    OH3+

    R1 C

    O

    R

    AROMATIC PORTION(a) From alcohols

    CH2

    OHK2Cr2O7 / H

    +

    CHO

    C CH3

    O

    K2Cr2O7 / H+

    CH CH3

    OH

    CH

    OH

    C

    O

    K2Cr2O7 / H+

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    (b) From acyl chloride ( Rosenmund reduction )

    CCl

    O

    H2

    Pd - BaSO 4

    CH

    O

    Benzoyl chloride Benzaldehyde

    (c) From nitriles ( stephen reaction )

    SnCl 2

    HCl

    C NCH NH

    BenzonitrileImine

    OH2 C H

    O

    (d) From Methyl benzene ( Etard reaction )

    CH3

    CrO 2Cl 2CS2

    +

    Toluene

    CH ( OCrOHCl 2 )2

    Chromyl chloride Chromium complex

    CH

    O

    OH3+

    Benzaldehyde

    CH3

    + CrO3 ( CH3CO ) 2O+Chromic oxide Acetic anhydride

    273 K - 283 KCH ( OCOCH 3 )2

    CH

    O

    OH3+

    Benzylidene diacetateToluene

    Not Etard reaction

    (e) From benzene ( Gatterman - Koch reaction )An aldehyde group is directly introduced by treating benzene with carbon monoxide and

    hydrogen chloride in the presence of aluminium chloride as a catalyst.

    + CO HClAlCl 3

    +CHO

    + HCl

    This is an electrophilic substitution reaction ( modified Friedel-crafts reaction ), wherethe most likely electrophile is acylium ion.

    CO + HCl + AlCl 3 C O

    H

    + + AlCl 4

    (f) From Toluene by side chain chlorination

    CH3

    Cl2

    / hCHCl 2

    373 K

    OH2CHO

    Benzalchloride

    (g) From Grignard reagent

    MgBr

    R C N+Ether

    CCH3

    NMgBr

    OH3+ C

    CH3

    O

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    Class-XII AldehydesKetonesCarboxylic Acids

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    Properties of Aldehydes and KetonesNucleophilic Addition Reaction

    C O

    R1

    R2

    + Nu C

    Nu

    R1O

    R2

    Slow H

    +

    FastC

    Nu

    R1OH

    R2

    [1] Addition of HCN in presence of a base

    C

    O

    R1 R2 + HCNBase

    C

    OH

    R1 R2

    CN Cyanohydrin

    Base is used to generate Cyanide ion : HCN + OH CN OH2+

    Strong Nucleophile

    [2] Addition of Sodium hydrogensulphite

    C

    O

    R1 R2 + NaHSO 3 C

    OSO2H

    R1 R2

    ONa

    H+ Transfer C

    OSO 2Na

    R1 R2

    OH

    Bisulphite addition product

    This bisulphite addition product is formed by all aldehydes and only by methyl ketones.The other ketones due to decrease in electrophilicity of carbonyl carbon and also becauseof steric factors due to alkyl groups, do not react with sodium bisulphite.

    This reaction is used to separate and purify aldehydes andketones, because aldehydes and ketones may be recovered from their suphite adducts bywarming them up with sodium carbonate solution.

    C

    OSO 2Na

    R1 R2

    OH

    Na2CO3C

    O

    R1 R2 + Na2SO3 NaHCO 3+

    [3] Addition of Grignard Reagent

    R Mg Br C

    O

    + +

    C

    O Mg Br

    R

    +

    OH2R C OH

    Alcohol

    + Mg Br OH

    Carbonyl compound

    Formaldehyde results in the formation of 1o alcohol

    Aldehyde ( Other than Formaldehyde ) results in the formation of 2o alcohol

    Ketones result in the formation of 3o alcohol

    [4] Addition of AlcoholsAddition of alcohols ( Weak nucleophile ) to aldehydes in acidic medium first formshemiacetals which on addition of second molecule of alcohol results in the formation ofacetals.

    Addition of alcohols to ketones to form hemiketals and ketals does not occur readilybecause of the steric hindrance.

    R C

    O

    H R1 OH+H

    +R C

    OH

    OR1

    H

    R1 OHR C

    OR1

    OR1

    HHemiacetal AcetalAldehyde

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    R C

    O

    R R1 OH+H

    +

    R C

    OH

    OR1

    R

    R1 OHR C

    OR1

    OR1

    RKetone

    HemiketalKetal

    Alcohol

    C O

    R

    R

    CH2

    CH2

    O

    OC

    R

    R

    + HCl gasdil. HCl

    CH2

    CH2

    OH

    OH

    Ethyleneglycol ketal

    Acetals and ketals are hydrolysed with aqueous mineral acids to yield correspondingaldehydes and ketones.

    Nucleophilic Addition - Elimination Reaction

    Addition of ammonia and its derivatives

    C O

    R

    R

    + NH2 ZH

    +

    C N

    R

    R

    Z + OH2

    C

    O

    R R

    H+

    C

    OH

    R R+

    NH2 Z

    x x

    C

    R

    R

    OH

    N+

    H

    H

    Z H+

    C

    R

    R

    OH

    N

    H

    ZOH2

    C

    R

    R

    N Z

    C O

    R

    R

    H2 NH+Ammonia Imine

    C

    R

    R

    N H

    C O

    R

    R

    + H2 NR CR

    R

    N R

    Amine Substituted i mine

    ( Schiff's base )

    C O

    R

    R

    + H2 NOH

    Hydroxyl amine

    C

    R

    R

    N OH

    Oxime

    C O

    R

    R

    + H2 N NH2 CR

    R

    N NH2Hydrazone

    NHNH

    H

    Phenylhydrazine

    C O

    R

    R

    + NHNC

    R

    RPhenylhydrazone

    C O

    R

    R+ NHN

    H

    HNO2

    O2N

    NHNC

    R

    R

    NO2

    O2N

    2, 4 - dinitrophenylhydrazine2, 4 - dinitrophenylhydrazone

    ( Yellow, Orange or Red solid )

    C O

    R

    R

    + C NH2NH

    O

    NH

    HSemicarbazide

    C NH2NH

    O

    NC

    R

    R Semicarbazone

    Hydrazine

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    Reduction Reaction[1] Catalytic Reduction

    R C

    O

    HH2 / Pt ( Primary alcohol )

    AldehydeR CH2 OH

    R C

    O

    R H2 / Pt R HC OH

    RKetone( Secondary alcohol )

    O

    OH

    H2 / Pt

    ( Secondary alcohol )

    LiAlH4 / NaBH 4

    LiAlH4 / NaBH 4

    [2] Wolff - Kishner Reduction

    C O

    R

    R

    + H2 N NH2 CR

    R

    N NH2Hydrazone

    Hydrazine

    KOH / ethylene glycol

    HeatR CH2 R + N2

    Alkane

    [3] Clemmensen Reduction

    R C R

    O

    Zn - Hg

    Conc. HCl +R CH2 RAlkane

    OH2

    Carbonyl compounds

    Oxidation Reaction

    R C CH3

    O

    R C H

    O

    Ketone

    Aldehyde

    Strong oxidising agent

    Strong oxidising agent

    RCOOH HCOOH+

    RCOOH

    Mild oxidising agent

    Mild oxidising agentRCOOH

    No product

    The oxidation of ketone required cleavage of carbon - carbon bond, which can not break by

    mild oxidising agents such as Tollen's reagent and Fehling's solution.

    O

    Cyclohexanone

    Tollen's reagent

    Fehling's solutionNo product

    K2Cr2O7 / H+

    OR KMnO 4 / H+

    OR CrO 3 / H+

    ( CH2 )4

    COOH

    COOH

    Hexanedioic acid ( Adipic acid )Tollen's Test

    Aldehyde + Tollen's reagent Silver mirror

    Ketone No silver mirror+ Tollen's reagent

    To aqueous silver nitrate,a drop of dilute sodium hydroxide is added, forming a brownprecipitate of silver oxide.

    Concentrated ammonia is then added until the precipitate just dissolves

    So Tollen's reagent is ammonical silver nitrate i.e.

    2 AgNO 3 2 NaOH+ Ag2O 2 NaNO 3 OH2+ +

    Ag2O + 2 NH 3 NaNO 3+ + OH2 [ Ag ( NH 3 )2 ] NO 3 2 NaOH

    +[ Ag ( NH 3 )2 ] NO 3

    RCHO 3 OH RCOO 2 H2O 2 e+ + +

    [ Ag ( NH 3 )2 ]+

    + e

    Ag 2 NH 3+ X 2

    RCHO + 3 OH + 2 [ Ag ( NH3 )2 ]+

    RCOO + 2 H2O + 4 NH 3 + 2 Ag

    Silver mirror

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    Fehling's TestFehling solution is a mixture of alkaline copper(II) sulphate solution and sodium poatssiumtartarate (Rochelle salt ) Aldehyde + Fehling's reagent

    Ketone + Fehling's reagent No Reddish Brow n precipitateReddish Brow n precipitate

    Aromatic aldehyde + Fehling's reagent No Reddish Brow n precipitate

    RCHO 3 OH RCOO 2 H2O 2 e+ + +

    2 Cu 2 OH Cu2O OH2++ 2 e

    +

    2+

    RCHO + 2 Cu2+

    + 5 OH

    RCOO

    + 3 H2O + Cu2O Reddish Brown precipitate

    Hydroxyketones give positive Tollen's and Fehling test, because inhydroxyketones,thesecondary alcoholic group gets oxidised to ketonic group.

    CH3 CH2 CH

    OH

    C CH3

    O3-Hydoxypentan- 2-one( hydroxyketone )

    CH3 CH2 C

    O

    C CH3

    OPentane- 2, 3 - dione

    +Fehling's reagentTollen's reagent

    2 H2O + 4 NH 3 + 2 AgSilver mirror

    3 H2O

    +Cu

    2O

    Reddish Brow n precipitate

    Idoform TestThe reaction is used to detect the and groups in an organiccompound. The organic compounds containing the above groups when treated withhalogen in presence of an alkali results in the formation of Chloroform,bromoform oridoform. Idoform is a yellow solid.

    CH3 C

    O

    CH3 CH

    OH

    R C CH3

    O

    + NaOIsodium hypoiodite

    i.e. I 2 & NaOHR C

    O

    ONa + CHI 3 Idoform( Yellow ppt. )

    CH3CH

    OH

    R + I2 2 HI

    CH3C

    O

    R+I2 NaOH

    R C

    O

    ONa + CHI 3 Idoform( Yellow ppt. )

    This oxidation does not affect a carbon- carbon double bond, if present in the molecule.

    CH3 CH C

    CH3

    C CH3

    O

    + NaOIsodium hypoiodite

    CH3 CH C

    CH3

    C

    O

    ONa + CHI 3 Idoform( Yellow ppt. )

    The iodoform reaction is given by:

    (1) Ethanol [ The only 1o alcohol ]

    (2) All secondary alcohols with group. (3) Acetaldehyde [ the only aldehyde ]CH3 CH

    OH

    CH3 C

    O

    CH3 C

    O

    group is necessary for idoform reaction, because the group is an

    electron withdrawing group, which makes the H of methyl group acidic in nature.

    C

    O

    The conjugate base, after removal of H, become resonance stabilised.

    C CH

    O

    H B C CH

    O

    C CH

    O

    (4) All methyl ketones [ aliphatic and aromatic ] with group.

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    Class-XII AldehydesKetonesCarboxylic Acids

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    Aldol condensationAldehydes and ketones having at least one H undergo a reaction in presence of dilutealkali as catalyst to form hydroxy aldehydes or hydroxy ketones

    [ ALDOL = ALD ehyde + alcoh OL ]

    2 CH 3CHOdil NaOH

    CH3 CH CH2 CHO

    OH

    OH2

    CH3 CH CH CHO

    3 -Hydroxybutanal [ Aldol ] But-2-enal

    CH3 C

    O

    H

    H CH2 C H

    O

    +dil NaOH

    CH3 CH CH CHO

    OH H

    OH2

    CH3 CH CH CHO

    CH3 C

    O

    CH3

    H CH2 C CH3

    O

    +dil NaOH

    CH3 C CH C

    OHH

    O

    CH3

    CH3

    OH2

    Ethanal

    CH3 C CH3

    OBa(OH) 2

    2 CH3 CH CH2 C

    OH

    CH3

    O

    CH3

    OH2CH3 C CH C

    CH3

    O

    CH3

    Propanone

    4-Hydroxy- 4-methylpentan- 2-one

    4-Methylpent- 3-en- 2-one[ Ketol ]

    CH3 C CH C

    CH3

    O

    CH3

    When aldol condensation is carried out between two different aldehydes or ketones, it is

    called cross aldol condensation.

    CH3CHO

    CH3CH2CHO

    1. NaOH

    2. +

    CH3 CH CH CHO + CH2 CH C CHOCH3

    CH3

    Selfcondensationproduct

    H3C CH C CHO

    CH3

    + CH2 CH CH CHOCH3MixedcondensationproductPent- 2-enal2-Methylbut- 2-enal

    But- 2-enal 2-Methylpent - 2-enal

    C

    O

    H

    CCH2

    O

    H

    Benzaldehyde

    No hydrogen

    +

    Acetophenone

    Having hydrogen

    CH

    OH

    CH

    H

    C

    O

    CH CH C

    O

    dil NaOH

    OH2

    1,3-diphenylprop-2-en-1-oneCannizzaro Reaction

    Aldehydes having nohydrogen,when treated with conc. alkali, undergo self oxidationand reduction [ disproportionation / dismutation / auto oxidation-reduction ] reaction.

    H C H

    O

    2 Conc. NaOH CH3OH HCOONa+Methanal Methanol Sodium methanoate

    C

    O

    HConc. NaOH

    2

    Benzaldehyde

    CH2 OH C

    O

    ONa+

    Benzyl alcohol Sodium benzoate

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    Class-XII AldehydesKetonesCarboxylic Acids

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    Electrophilic substitution reaction.Carbonyl groups act as deactivating and meta - directing group.

    C

    OR

    R = H : aldehydeR = alkyl : Ketone

    Cl 2 / AlCl 3

    HNO 3 / H2SO4

    H2SO4 / SO 3

    C

    O

    R

    Cl

    C

    O

    R

    NO2

    C

    O

    R

    SO3H

    40%solutionofform

    aldehydeisknownasform

    alin.

    ALIPHATIC PORTION

    Preparation of Carboxylic Acids[a] From alcohol and aldehyde

    R C H

    O

    RCH 2OH RCOOH1. alkaline KMnO 4

    2. H3O+

    1o alcohol

    CH3 (CH2)8CH2OH

    1-Decanol

    CH3 (CH2)8COOH

    Decanoic acid

    1. alkaline KMnO 4

    2. H3O+

    Aldehyde

    RCOOHStrong oxidising agent

    Mild oxidising agentOR[b] From Grignard reagents

    C O

    O

    R MgBr +- +

    RC

    O MgBr

    O

    Dry etherH3O

    +

    RCOOH

    Dry ice

    - +

    [c] FromAcid derivatives

    Acid chloride

    Acid anhydride

    Ester

    Amide

    R C

    O

    ClOH2

    ClH+RCOOH

    R C

    O

    OC R1

    O

    OH2RCOOH + R1COOH

    R C

    O

    OR' RCOOH R' OH+H3O

    +NaOH

    RCOONa R' OH+H3O

    +

    RCOOH( Saponification)

    R C

    O

    NH2

    H3O+

    RCOOH + NH3R C N

    Nitrile

    H3O+

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    AROMATIC PORTION

    CH2 R

    Alkyl benzene

    KMnO 4 - KOH

    COOKH3O

    + COOH

    [ The entire side chain is oxidised to the carboxylic acid irrespective of length of side chain ]

    CONH 2

    Benzamide

    H3O+

    COOH

    NH3+

    C

    O

    OC

    CH3

    O

    H3O+

    OH2

    Benzoic ethanoic anhydride

    COOH

    + CH3COOH

    Benzoic acid

    Benzoic acid

    Benzoic acidEthanoic acid

    C

    O

    OC2H5

    Ethyl benzoate

    COOH

    + C2H5OH

    Properties of Carboxylic Acid[1] Acidity

    Carboxylic acids dissociate in water to give resonance stabilised carboxylate anion.

    R C

    O

    OH + OH2 R CO

    O

    R C

    O

    O

    + H3O+

    2 RCOOH + 2 Na 2 RCOONa H2+

    RCOOH NaOH+ RCOONa OH2+RCOOH + NaHCO 3 RCOONa + OH2 + CO2 [ Test for carboxylic group ]

    [ Brisk effervescence ]

    CH2 CH COOH CH3 CH2 COOHAcidity of >

    SP2

    SP3

    C

    O

    OH CH2

    C OH

    O

    >

    SP2

    SP3

    carbon is more electronegative than carbon,SP2 SP3

    [2] Esterification

    CH3 C OH

    O

    H O CH3+Acid Alcohol

    CH3 C O

    O

    CH3H

    +

    + OH2Ester

    CH3 C OH

    O

    + OHH

    +

    OC

    O

    CH3 + OH2Phenyl ethanoateEthanoic acid Phenol

    The water should remove from the mixture, because ester may undergohydrolysis.

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    H2SO4 /

    or P2O5 /

    [3] Formation of Acid anhydride

    CH3 C

    O

    OHC CH3

    O

    OH

    CH3 C

    O

    O

    C CH3

    O

    +

    Ethanoic acid Ethanoic anhydride

    + OH2

    [4] Formation of Acid chloride

    CH3 C

    O

    OH PCl 5

    PCl 3

    SOCl 2

    +ClHPOCl 3CH3 C

    O

    Cl + +

    CH3 C

    O

    OH3 + CH3 C

    O

    Cl3 + H3PO 3

    CH3 C

    O

    OH + CH3 C

    O

    Cl + SO2 + ClH

    [5] Formation of Acid amide

    CH3 C

    O

    OH + NH3 CH3 C

    O

    O NH4+

    CH3 C

    O

    NH2

    Ammonium ethanoate Ethanamide

    COOH

    + NH3COO NH 4

    OH2

    OH2

    CONH 2

    Amm.benzoate Benzamide

    COOH

    COOH

    + NH3 COO NH4

    COO NH4

    - +

    - + 2 H2O

    CONH2

    CONH2

    Strong heating

    C

    C

    NH

    O

    OPhthalic acid Ammonium phthalate Phthalamide

    Phthalimide

    NH3

    [6] Formation of Alcohol [ Reduction ]

    R C

    O

    OH

    LiAlH4 / Ether

    H3O+

    R CH2 OH[ The reaction involve hydride transferand causes reuction of carbonyl group ]

    R C

    O

    OHH3O

    +

    B2H6R CH2 OH

    [ Diborane is better for this process, becauseit does not easily reduce ester,nitro and halogroups]

    Sodium borohydride does not reduce the carboxyl group.[7] Formation of Alkane [ Decarboxylation ]

    R C

    O

    ONa + NaO H

    CaORH + Na2CO3

    AlkaneSodium salt of carboxylic acid

    [ NaOH & CaO in the ratioof 3:1 is known as sodalime ]

    Kolbe electrolysis

    RCOONaElectrolysis

    R R + CO2 + NaOH H2+At anode At cathode

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    [8] Hell - Volhard - Zelinsky Reaction ( HVZ reaction )

    R CH2 COOH

    Having - hydrogen

    (i) X2 / Red phosphorous

    (ii) H 2O

    R HC COOH

    X

    X : Cl , Br

    If two hydrogens are present, both of them may be substituted by halogen.

    [9] Ring substitution reactionCarboxylic group act as deactivating and meta directing group.

    C

    OHO

    Cl 2 / AlCl 3

    HNO 3 / H2SO4

    H2SO4 / SO3

    HOOC

    Cl

    HOOC

    NO2

    HOOC

    SO3H

    ExplanationsDue to polarity of carbonyl group to ward oxygen,the intermolecular association of carbonylcompounds occurs which makes the boiling point of carbonyl compounds higher than the

    corresponding alkane of comparable mass.However carbonyl compounds can not form hydrogen bonding with

    each other and their boiling points are lower compared to alcohol (of comparable mass)

    The lower members of aldehydes and ketones are soluble in water in all proportions,because they associate with water molecules through hydrogen bonding.

    The reaction of Grignard reagent with nitriles is considered to be the best method for thepreparation of carbonyl compounds, because, in the first stage of addition an imine isformed as an intermediate product. The imine is then isolated and hydrolysed to give acarbonyl compound as the final product.

    Reaction of Grignard reagent with acid chloride and esters produce carbonylcompounds,but the reaction does not stop at this stage and proceeds further with another

    molecule of Grignard reagent to give corresponding alcohol as the final product.Grignard reagent and dialkyl cadmium both are organometallic compounds, but reaction ofacid halides with[a] Grignard reagent is not satisfactory method for the preparation of ketones.[b] Dialkylcadmium is a satisfactory method for the preparation of ketones.Because, in case of dialkylcadmium, due to less reactivity of cadmium, reaction with acidchloride occurs only upto the formation of ketone. The reaction of Grignard reagent doesnot stop after formation of ketone, since magnesium is more reactive metal,and proceedsfurther to form tertiary alcohol.

    Aryl ketones do not undergo addition of alcohol to form hemiacetals and ketals because ofsteric factor.

    CR

    O

    + R' OH

    R = alkyl / aryl

    H

    +

    No reaction

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    Aryl ketones do not give addition product with sodium bisulfite due to steric factor.

    C R

    O

    + NaHSO 3 No reaction

    R = alkyl / aryl

    The order of reactivity of aldehydes and ketonestoward nucleophilic addition reaction: C

    O

    H HC

    O

    R HC

    O

    R R

    Sterically the presence of two relatively large substituents in ketones hinder the approachof nucleophile to carbonyl carbon than in aldehydes.

    Electronically two alkyl groups in ketone reduce the electrophilicity of the carbonylmore effectively than in aldehyde.

    NH2 NH C

    O

    NH2x xx x

    [Semicarbazide]

    Involved in the formationof semicarbazone

    The right side -NH2 group is in conjugation with electron

    withdrawing carbonyl group and acquires positive charge and notin a position to act as the nucleophile, so does not involvein the formation of semicarbazone.

    O

    Cyclohexanone

    OH

    CN

    O

    CH3 CH3

    CH3

    HCNHCN No product

    cyanohydrin

    2, 4, 6-trimethylcyclohexanoneIn 2,4,6-trimethylcyclohexane, the three methyl groups will increase the electron densityon the carbonyl carbon atom and the nucleophile attack does not seem to be feasible.Moreover,the two methyl substituents at the ortho position will also hinder the attack of

    nucleophile CN ion on the carbonyl group.

    Upon heating , formic acid loses a molecule of water and gets dehydrated to give carbonmonoxide. Therefore it does not form anhydride upon heating.

    HCOOH H2OCOHeat

    +Phenoxide ion has more number of resonating structures than carboxylate ion, butcarboxylic acid is a stronger acid than phenol. Because, in carboxylate ion the negative

    charge is dispersed on two electronegative oxygen atoms while incase of phenoxide ion,there is only one oxygen atom to disperse the negative charge.

    Benzaldehyde and other aromatic aldehydes form silver mirror with Tollen's reagent butfail to react with fehling's solution and Benedict's solution. Due to resonance, the electrondensity on the carbonyl carbon atom inbcreases, as a result the CH bond becomesstronger. It can be oxidised to C OH with strong oxidising agents like Tollen's reagent

    ( EoAg2+|Ag = +0.8 V ) but not with weaker Fehling's or Bendedict's reagent

    ( Eo Cu2+ |Cu = +0.34 V )

    In Fehling solution , copper sulphate forms a soluble complex of Cu2+ ions with tartarate

    ion of the Rochelle's salt. The complex provides the Cu2+ ions and also checks the

    precipitation of copper hydroxide in the reaction.

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    Predict the ProductsOH

    PCC , CH 2Cl 2O

    Cyclohex- 2-en- 1-ol? Cyclohex- 2-en- 1-one

    + H5C2C

    O

    Cl ?Anhy. AlCl 3

    CS2

    ( C6H5CH2)2Cd 2 CH3COCl+ ?CH3 C CH

    Hg2+

    H2SO4 ?CH3 NO2

    1. CrO 2Cl 2

    2. H3O+ ?

    CC2H5

    O

    CCH3

    O

    CH2

    CH3

    C

    CH3

    O

    OHC NO2

    OHONH 2

    H+

    ?+

    O

    NH NO2

    O2N

    NH2+ ?

    R CH CH CHO NH2 C

    O

    NH NH2+ H+

    ?C

    CH3

    O

    CH3CH2NH2+ H+

    N OH

    NH NO2

    O2N

    N

    R CH CH CH N NH C

    O

    NH2

    C

    CH3

    N CH2CH3

    ?

    CH2 CH3KMnO 4

    KOH , Heat ?

    COOH

    COOH

    SOCl 2

    Heat ?

    CHONH2 C

    O

    NH NH2 ?O

    CHO

    [ Ag(NH 3)2]+

    ?

    COOK

    COCl

    COCl

    N NH C

    O

    NH2CH

    O

    COO

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    CHO

    COOH

    NaCN / HCl

    ?

    C6H5CHO CH3CH2CHOdil. NaOH+ ?

    CH3COCH 2COOC 2H5(i) NaBH 4

    (ii) H+

    OHCrO3

    ?

    ?

    COOH

    CH

    OH

    CN

    H5C6 CH C

    CH3

    CHO

    CH3 CH

    OH

    CH2 COOEt

    O

    (i) O3

    (ii) Zn - H 2O

    O

    ?

    CHO

    + C6H5MgBrH3O

    + CHC6H5

    OH

    ?

    [ Ag(NH 3)2]+

    OH-

    CHO

    + + ?COO

    -

    CHO

    + NH2 C

    O

    NH NH2 ?CH NHCONH 2

    C O

    H

    H OC 2H5+

    H OC 2H5 ? CH

    OC2H5

    O C2H5

    O

    +dil. NaOH

    OH

    O

    ?

    O

    O

    O

    Raney Ni / H 2

    NaBH 4 / CH 3OH

    OH

    ?

    ?OH

    CH C6H5(i) O3

    (ii) Zn / H 2O?

    O

    C6H5CHO+