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Algebraic Fractions with monomial Denominators
A monomial
is a number, a variable, or a product of a number and variables. The degree of a monomial is the sum of the exponents of the variables
Objective: Simplify fractions using the highest common factor.
Find the HCF of each set of numbers or monomials.1. 22, 55
5-Minute Check
Find the HCF of each set of numbers or monomials.1. 22, 55 11
Find the HCF of each set of numbers or monomials.1. 22, 55
2. 106, 318
5-Minute Check
Find the HCF of each set of numbers or monomials.1. 22, 55
2. 106, 318 106
5-Minute Check
Find the HCF of each set of numbers or monomials.1. 22, 55
2. 106, 318
3. 15, 18, 30
5-Minute Check
Find the HCF of each set of numbers or monomials.1. 22, 55
2. 106, 318
3. 15, 18, 30 3
5-Minute Check
Find the HCF of each set of numbers or monomials.1. 22, 55
2. 106, 318
3. 15, 18, 30
4. 12ab3, 16a4b2
5-Minute Check
Find the HCF of each set of numbers or monomials.1. 22, 55
2. 106, 318
3. 15, 18, 30
4. 12ab3, 16a4b2 4ab2
5-Minute Check
Find the HCF of each set of numbers or monomials.1. 22, 55
2. 106, 318
3. 15, 18, 30
4. 12ab3, 16a4b2
5. 15mnp, 45mp3, 90m3n4
5-Minute Check
Find the HCF of each set of numbers or monomials.1. 22, 55
2. 106, 318
3. 15, 18, 30
4. 12ab3, 16a4b2
5. 15mnp, 45mp3, 90m3n4 15m
5-Minute Check
Example
a. Write 63/105 in simplest form.63 = 7*3*3 The HCF of 63 and 105 is 3*7 or 21.
105 7*5*3
Example
a. Write 63/105 in simplest form.63 = 7*3*3 The HCF of 63 and 105 is 3*7 or 21.
105 7*5*3 Divide the numerator and the
denominator by 21.
Example
a. Write 63/105 in simplest form.63 = 7*3*3 The HCF of 63 and 105 is 3*7 or 21.
105 7*5*3 Divide the numerator and the
denominator by 21.
Since the HCF of 3 and 5 is 1, the fraction is in simplest form.
Exampleb. Simplify . Assume that x and y are not equal to zero.15x2y2
35xy2
The HCF of 15x2y2 and 35xy2 is 5*x*y*y.
Exampleb. Simplify . Assume that x and y are not equal to zero.15x2y2
35xy2
15x2y2
35xy2
Divide the numerator and denominator by 5xy2.
The HCF of 15x2y2 and 35xy2 is 5*x*y*y.
Exampleb. Simplify . Assume that x and y are not equal to zero.15x2y2
35xy2
15x2y2
35xy2
Since the HCF of 3x and 7 is 1, the fraction 3x/7 is in simplest form.
Divide the numerator and denominator by 5xy2.
The HCF of 15x2y2 and 35xy2 is 5*x*y*y.
Exampleb. Simplify . Assume that x and y are not equal to zero.15x2y2
35xy2
15x2y2
35xy2
I need two volunteers to rewrite the fraction below in simplest form.
2460
40100
Rewrite the fraction below in simplest form.
2460
40100
Each individual now needs to find other fractions that when reduced equals 2/5.
