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Linear Algebra I & Mathematics Tutorial 1b Tutorial 4, 27th October, 14:45 - 15:29 You are free to record this Tutorial for your own purposes. menti.com 13 73 60 0 Next week: Second quiz! (just 2 questions) Topic: Functions, Image, Injective, Surjective, Bijective (Week 3) (NOT 4) Also today

Alsotoday - Henrik Bachmann...Linear Algebra I & Mathematics Tutorial 1b Tutorial 4, 27th October, 14:45 - 15:29 • You are free to record this Tutorial for your own purposes. •

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  • Linear Algebra I & Mathematics Tutorial 1b Tutorial 4, 27th October, 14:45 - 15:29

    You are free to record this Tutorial for your own purposes. •menti.com 13 73 60 0 •

    Next week: Second quiz! (just 2 questions) Topic: Functions, Image, Injective, Surjective, Bijective (Week 3) (NOT 4)

    Alsotoday

  • Linear Algebra I & Mathematics Tutorial 1bNagoya University, G30 Program

    Fall 2020

    Instructor: Henrik Bachmann

    Homework 3: Functions & Linear maps

    Deadline: 8th November, 2020

    Exercise 1. (3+4+3=10 Points) We define the following four functions:

    f1 : R �! R2

    x 7�!✓cos(x)sin(x)

    ◆,

    f2 : R2 �! R3

    ✓x1x2

    ◆7�!

    0

    @x1 � 2x23x1 + x2x1 � x2

    1

    A ,

    f3 : R �! Rx 7�! 4x� 1 ,

    f4 : R2 �! R2✓x1x2

    ◆7�!

    ✓x1 + 2x2x1x2

    ◆.

    i) Calculate the image of each function, i.e. describe im(fj) for j = 1, 2, 3, 4 as explicit as possible.

    ii) Decide for each function if it is injective and/or surjective and/or bijective.

    iii) Decide which of the above functions are linear maps.

    Justify your answers in ii) and iii).

    Exercise 2. (6 Points) Show that there exist a unique linear map G : R2 ! R3 with the property

    G

    ✓�12

    ◆=

    0

    @1

    2

    3

    1

    A , G✓

    1

    �1

    ◆=

    0

    @4

    5

    6

    1

    A .

    What is the value of G(x) for an arbitrary x =

    ✓x1x2

    ◆2 R2? Determine the matrix of G.

    Exercise 3. (4 Points) Let F : Rn ! Rm be a linear map. Show that the following two statements areequivalent:

    i) F is injective.

    ii) The only solution to F (x) = 0 is x =

    0

    B@

    0

    .

    .

    .

    0

    1

    CA.

    To show that both statements are equivalent you need to show that i) implies ii) and ii) implies i).

    Version: October 24, 2020

    - 1 -

    Today

    NextTutorial3rd Nov

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