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7/28/2019 Analysis of Lug Joints
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Djarot Widagdo
FTMDITB
7/28/2019 Analysis of Lug Joints
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Eccentric
Load Centroid ofloads(loadequivalence)
Loaddistribution
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Eccentric
Load
Calculatetheloaddistributiononthe
asteners
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Lug
Joint
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LugJoint AxialLoad
Failuresoflug
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LugJoint AxialLoad
Shearbearing
tubrbrbru FAKP =
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LugJoint AxialLoad
NettensionFAKP =
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LugJoint AxialLoad
Yield ( )minu
ty
y PF
CP =tu
( ) tubruminu PorPofsmallerP =
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LugJoint TransverseLoad
FAKP =
tyxbrtrytry FAKP =
+
+
+
=
4321
av
A
1
A
1
A
1
A
3A
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LugJoint TransverseLoad
= tuxrtrutru
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Lugjoint
Oblique
minuuu PKP =
6.1/1
6.1
sin
1K
=
minutru
.
PPcos +
tubruminu PorPofsmallerP =
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Lugjoint
Pindesign
D1a
2tr=
++
=
42b
= 2PMu
tubruu PorPofsmallerP =
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Lugjoint
Pindesign
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Lugjoint
Allowables forANsteelbolts(Ftu =125ksi,
su = s
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Lugdesign
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Lugdesign
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Lugdesign
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Lugdesign
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Lugdesign
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Lugdesign