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Analysis of Rainfall Data. 50.7. 59.4. Sample mean = Sample variance = S 2 = Approximately, 68% within 50.7 +/- 1 x 7.71 or 43.0 to 58.4 Approximately, 95% within 50.7 +/- 2 x 7.71 or 35.3 to 66.1. S = 7.71. Construction of Histogram. Rearrange data in increasing order - PowerPoint PPT Presentation
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Analysis of Rainfall DataAnalysis of Rainfall DataYearYear Rainfall Rainfall
IntensityIntensity
19181918 43.3043.30 19281928 54.4954.49 19381938 58.7158.71
19191919 53.0253.02 19291929 47.3847.38 19391939 42.9642.96
19201920 63.5263.52 19301930 40.7840.78 19401940 55.7755.77
19211921 45.9345.93 19311931 45.0545.05 19411941 41.3141.31
19221922 48.2648.26 19321932 50.3750.37 19421942 58.8358.83
19231923 50.5150.51 19331933 54.9154.91 19431943 48.2148.21
19241924 49.5749.57 19341934 51.2851.28 19441944 44.6744.67
19251925 43.9343.93 19351935 39.9139.91 19451945 67.7267.72
19261926 46.7746.77 19361936 53.2953.29 19461946 43.1143.11
19271927 59.1259.12 19371937 67.5967.59
Sample mean =Sample mean =
Sample variance = SSample variance = S2 2 ==
Approximately, Approximately, 68%68% within within 50.750.7 +/- +/- 11 xx 7.717.71 or or 43.0 to 58.443.0 to 58.4
Approximately, Approximately, 95%95% within within 50.750.7 +/- +/- 22 x 7.71 x 7.71 or or 35.3 to 66.135.3 to 66.1
n
xx i 50.7
1
)( 2
n
xxi 59.4
S = 7.71
Construction of HistogramConstruction of Histogram
1.1. Rearrange data in increasing orderRearrange data in increasing order
2.2. Note the range and divide into Note the range and divide into suitablesuitable
intervals (say at 4 inches in this example)intervals (say at 4 inches in this example)
3.3. Count number of occurrence in each Count number of occurrence in each
intervalinterval
4.4. Plot HistogramPlot Histogram
HISTOGRAM
FREQUENCY DIAGRAM
Total Area = 116
Total Area = 1.0
3/116 = 0.026
or 2.6%
Frequency DiagramFrequency Diagram
1.1. Determine total area of histogram, say ADetermine total area of histogram, say A
2.2. Modify the vertical scale of histogram by Modify the vertical scale of histogram by
dividing the value by A, dividing the value by A,
For the rainfall example, A= 116, For the rainfall example, A= 116,
ordinate of first strip = 3/116 = 0.026 or ordinate of first strip = 3/116 = 0.026 or
2.6%2.6%
Model
Area = 0.152
FREQUENCY DIAGRAM
Statistics of Sustained Live Statistics of Sustained Live LoadLoad
Floor Load Intensity (lb/ftFloor Load Intensity (lb/ft22) – ) –
National Bureau of Standard Report National Bureau of Standard Report
19521952
Data on First Floor, Bay Size Data on First Floor, Bay Size 400ft400ft22
7.87.8 72.672.6 42.542.5 55.955.9 26.026.0 66.466.4
73.473.4 106.5106.5 30.230.2 37.037.0 24.124.1 23.423.4
49.849.8 106.9106.9 48.448.4 55.055.0 54.854.8 65.765.7
62.562.5 68.768.7 118.2118.2 55.655.6
Xj, j= 1,2,3…….N N = 22
P(L.L.>56.88 lb/ft2) = ?
= 9/22
HistogramHistogram
1.1. Select interval, ∆X (e.g. ∆X=25 lb/ftSelect interval, ∆X (e.g. ∆X=25 lb/ft22))
2.2. Count no. observations within each iCount no. observations within each interval according to nterval according to
a < Xa < Xjj ≤ b ≤ b say nsay nii
HistogramHistogram3.3. Plot the resultsPlot the results
ScattergramScattergram