Antenna Ch4 1

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    4 1 Introduction

    This chapter will focus on array antennas . Arrays are antennascomprised of multiple physically identical individual elements , which are

    spatially arranged and excited with respect to each other in order tocreate a specific directional radiation pattern .

    To analyze radiation from an array, consider the antenna system depictedin Figure 4.1. The antenna consists of elements, numbered 0 through

    1 . All elements are physically identical , but positioned at differentspatial locations and excited by signals that may differ from each other inmagnitude and phase .

    Let the position of each element be characterized by a position vector, = 0, , 1, and let the current at the terminals of the individual

    elements be denoted by , = 0, , 1. 2

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    The electric field ( ) radiated by the array can be found from the far-field vector potential ( ) , which is given by:

    where ( ) denotes the total current on all array elements.

    (4.1)

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    Denoting the current on the individual elements by ( ), = 0, , 1, we have:

    and, hence:

    (4.2)

    (4.3)

    Figure 4 2 Arrayreference element and

    local coordinate definition 4

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    To simplify the integral, we decompose as = + , where is alocal position vector in a coordinate frame attached to element (Fig 4.2).

    (4.4)

    where ( ) denotes the current on a hypothetical reference element ,positioned at the origin, and excited by a terminal current = 1 .Substituting Eq.(4.4) into (4.3), and rearranging terms, yields:

    (4.5)

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    Eq.(4.5) indicates that the vector potential associated with radiation by

    an array equals the product of two factors : The vector potential associated with the reference element:

    A scalar quantity , further termed the array factor , given by:

    Using Equations (4.6) and (4.7), we may express the vector potentialassociated with an array also as:

    (4.6)

    (4.7)

    (4.8)6

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    The electric field radiated by the array may be obtained as:

    The magnetic field can be expressed similarly:

    where

    (4.9)

    (4.10)

    (4.11)

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    4 2 The Array Factor for Linear Equally Spaced Arrays

    Linear arrays consist of individual elements arranged along a straightline . In this and the following sections, we will assume that the arrayconsists of elements which are positioned along the -axis (Fig. 4.3).

    If the -coordinates of the array elements are denoted by , = 0, , 1, the expression for the array factor takes the form:

    (4.12)

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    In many practical applications, the array elements are equally spaced. Ifthe inter-element spacing is denoted by d , the positions of the elements ofa Linear Equally Spaced Array (LESA) are given by:

    The array factor of a LESA becomes:

    where = . From Eq.(4.14), we conclude that the array factor ofan element LESA can be expressed as a polynomial of degree 1 inthe complex variable . The portion of the unit circle = 1 with phaseangles in between and 0 = is termed " the visible region ".

    (4.13)

    (4.14)

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    (4.15)

    Often, we will write Eq.(4.14) in a more suggestive form as:

    where denotes the zero of the polynomial (4.14).

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    (4.16)

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    Solution

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    The magnitude of this array factor in the plane is plotted in Figure4.4. The pattern is axisymmetric, i.e. the pattern is identical to thepattern shown here.

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    (4.17)

    (4.18)

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    (4.19)

    we obtain:

    It is easily shown that the normalized array factor for which

    ( , ) = 1 is given by:

    (4.20)

    (4.21)15

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    In a Linear CoPhasal Equally Spaced Array (LCPESA) , we chooseelement excitations with the same magnitude, but with a uniform phaseprogression from element to element , as:

    The array factor becomes:

    where = = ( cos + ). It is now easily verified that the arrayfactor and normalized array factor of the LCPESA are still given by (4.20)

    and (4.21), provided that we generalize the definition for

    to:

    From now on, we will regard the LUEESA as a special case of theLCPESA with = 0 .

    (4.22)

    (4.23)

    = cos + (4.24)

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    o Examples

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    o Examples

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