APTITUDE BITS - 20 Q n A

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    APTITUDE

    ENGLISH SECTION

    Antonyms

    Idioms And Phrases

    One Word Substitute

    Preposition

    Synonyms

    CURRENT AFFAIRS

    August 2012

    July 2012

    October 2012

    September 2012

    ADVERTISEMENT

    GENERAL AWARENESS

    Awards

    Books And Authors

    Famous Personalities

    Inventions And Discoveries

    REASONING SECTION

    Analogy Test

    Blood Relations

    Coding - Decoding

    Direction Sense Test

    Number Series

    Seating Arrangments

    Verification Of Statement

    CATEGORIES

    Aptitude questions

    Basic Networking

    C language

    C++ Mcq

    Computer Arithmetic

    Computer Graphics

    Computer Network

    Current Affairs

    Data Structure

    DBMS

    Discrete Structure

    English

    General Knowlegde

    Information Technology Operating System

    Probability

    Software Engineering

    COMPUTER GRAPHICS

    Page 1

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ntonyms
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    Page 5

    Multiple Choice Questions On Aptitude | UGC NET Exam 2012 SampleSunday, 29 April 2012

    1) A die is tossed once. What is the probability of getting an oddnumber?

    a. 1/3

    b. 1/2c. 1

    d. 3/4

    Show/Hide Answer

    Answer = BExplanation:We know that the sample space for a die tossed once is { 1, 2, 3,4, 5, 6} out of which {1, 3, 5} are odd numbers. So the p(getting anodd number)= (Favorable cases/Total cases) = 3/6 = 1/2

    2) A coin is tossed once. Find the probability of getting a head ?a. 1/2

    b. 3/2

    c. 3/4

    d. None of above

    Show/Hide Answer

    Answer = AExplanation:We know that sample space for a head tossed once is { head,tail} out of which head comes only once so the P(getting head) = 1/2

    3) A Bag contains 8 red, 7 white, 6 black balls. Find the probability of gettinga black ball ?

    a. 1

    b. 6/8

    c. 6/7d. 2/7

    Show/Hide Answer

    Answer =DExplanation:

    Here Total number of balls are: 21We have to find the probability of black ball and number of black balls are 6.So the P(black ball) = 6/21 = 2/7

    4) A bag contains 2 red, 8 black, and 7 white balls. Find the probability of notgetting a white ball ?

    a. 7/10

    b. 7/8c. 10/17

    d. None

    Show/Hide Answer

    Answer = CExplanation:

    Total balls=17

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    White balls = 7P(white ball) = 7/17P(Not white ball) = 1 - (7/17) = 10/17

    5) Given that E and F are two events such that P(E) = 0.6, P(F) = 0.3 and P(Eand F) = 0.2, Then what is the value of P(E/F) ?

    a. 2/3

    b. 1/3

    c. 1

    d. None

    Show/Hide Answer

    Answer = AExplanation:

    P(E/F) = P(E and F) / p(E)

    = 0.2 / 0.3= 2 / 3

    6) A four digit number is formed, using the digits 1,2,3,5 with no repetitions.The probability that the number is divisible by 5 ?

    a. 4/5

    b. 1/4

    c. 3/4

    d. Can't say

    Show/Hide Answer

    Answer = B

    Explanation:

    Let m be the favorable cases = Numbers of four digit which are divisible by 5= 6

    Let n be the total number of cases = 4C4 = 24Required Probability = 6/24 = 1/4

    7) A coin is tossed twice. What is the probability that the head occurs at leastonce ?

    a. 4/4

    b. 2/4

    c. 3/4

    d. 0

    Show/Hide Answer

    Answer = 3/4

    Explanation:

    As a coin is tossed twice so sample space = { HH , HT , TH , TT} Where H =

    head and T= tailSample space for favorable cases that the head occurs at least once = (HH,HT, TH}

    Reqd. Probability = 3/4

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    8) A Coin is tossed twice. Find the probability that the head occurs at mostonce ?

    a. 3/4

    b. 1/4

    c. 2/4

    d. None

    Show/Hide Answer

    Answer = AExplanation:

    Sample space = {HH, HT, TH, TT}Favorable cases = {HT, TH , TT}P(Head occurs at most once) = 3/4

    9) Let E and F are two events. P(E) = 0.2, What is P(F) ?

    a. can't be findableb. 1

    c. 2

    d. 0.8

    Show/Hide Answer

    Answer = DExplanation:

    As we know that the total probability of all the events = 1P(One event)=0.2P(second event)=1 - 0.2

    = 0.8

    10) A die is thrown thrice. Then the total number of cases will be?a. 3

    b. 6

    c. 8

    d. 216

    Show/Hide Answer

    Answer = DExplanation:Total number of cases will be = 6 * 6 * 6 = 216

    Multiple Choice Questions On Aptitude With ExplanationTuesday, 1 May 2012

    1)A man buys an article for Rs. 27.50 and sells it for Rs. 28.60. What will be

    his gain percent ?a. 10%

    b. 4%

    c. 3%

    d. 1%

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    Show/Hide Answer

    Answer = BExplanation:

    C.P = 27.50S.P = 28.60Gain = Rs(28.60 - 27.50) = 1.10Gain % = ( (1.10 / 27.50 ) * 100 )% = 4%

    2) If the radio is purchased for Rs 490 and sold for Rs. 465.50 then what is theLoss percent?

    a. 50%

    b. 20%

    c. 10%

    d. 5%

    Show/Hide Answer

    Answer = DExplanation:

    C.P = 490S.P = 465.50Loss = Rs(490 - 465.50)= Rs 24.50Loss % = ((24.50/490)*100)% = 5%

    3) By selling a book for Rs. 115.20, a man losses 10%. At what price should hesell it to gain 5% ?

    a. 150

    b. 143.50

    c. 134.40

    d. 134.42

    Show/Hide Answer

    Answer = CExplanation:

    Let the new S.P be Rs x(100 - loss%) : (1st SP) = (100 + gain%) : (2nd SP)

    or=> (100 - 10) / 115.20 = (100 + 5) / x

    => x = (105 * 115.20)/90 = 134.40

    4) A trader lost 20% by selling a watch for Rs. 1024 What percent shall he

    gain or loss by selling it for Rs. 1472 ?a. 23%

    b. 15%

    c. 32%

    d. 43%

    Show/Hide Answer

    Answer = B

    Explanation:Let the gain % be x=> 80 : 1024 = (100 + x) : 1472=> 80 / 1024 = (100 +x) / 1472

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    => 100+x = (80 * 1472) / 1024=> 100+x = 115=> x = 15

    Hence gain% = 15%

    5) Hari purchased 25kg of wheat at Rs 4 per Kg and 35 Kg of wheat at Rs 4.50

    per Kg. He sold the mixture at Rs 4.25 per Kg. Find his gain or loss ?a. 3.50

    b. 4.50

    c. 5.50

    d. 2.50

    Show/Hide Answer

    Answer = D

    Explanation:Total C.P = Rs (25*4 + 35*4.50)

    = Rs. 257.50Total S.P = Rs (60*4.25)

    = Rs 255Loss = Rs ( 257.50 - 255 ) = Rs. 2.50

    6) A man sells an article at a profit of 25%. If he had bought it at 20% less andsold it for Rs. 10.50 less, he would have gained 30%. Find the cost price of thearticle ?

    a. 50

    b. 60

    c. 70

    d. 80

    Show/Hide Answer

    Answer = AExplanation:

    Let the C.P be Rs x1st S.P = 125% of Rs x = (125 / 100 )x = 54 / x2nd C.P = 80% of x = (80/100)x=(4/5)x2nd S.P= 130% of (4/5)x= (130/100)*(4/5)x = (26 / 25)x

    Hence (5/4)x - (26/25)x = 10.50=> x = (10.50*100) / 21

    = 50

    7) A Grocer purchased 80Kg of rice at Rs 13.50 per Kg and mixed it with120Kg of rice at Rs. 16 per Kg. At what rate per Kg should he sell the mixtureto gain 16% ?

    a. 20.00

    b. 17.40

    c. 18.56

    d. 34.67

    Show/Hide Answer

    Answer = BExplanation:C.P of 200 Kg of mix = Rs(80 * 13.50 + 120 * 16) = Rs. 3000

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    S.P = 116% of Rs.3000 = Rs (116/100) * 3000 = Rs. 3480Rate of S.P of the mixture = Rs(3480/200) per Kg = Rs 17.40 per Kg8) A vender sells 10 toffees for a rupee, gaining thereby 20%. How many did

    he buy for a rupee ?a. 15

    b. 10

    c. 12

    d. 20

    Show/Hide Answer

    Answer =C

    Explanation:S.P of 10 toffees = Re 1, gain = 20%Re 5 / 6 is C.P of 10Re 1 is the C.P of ( 10 * (6/5)) = 12

    Hence he bought 12 toffees for a rupee

    9) A trader allows discount of 10% on the marked price and allows a discount

    of 15% on it. Find his gain percent ?a. 1%

    b. 2%

    c. 3%

    d. 5%

    Show/Hide Answer

    Answer = BExplanation:

    Let C.P = Rs. 100 Then marked price = 120so S.P = 85% of Rs 120 = Rs 102Hence gain% = 2%10) A shopkeeper allows a discount of 10% on the marked price. How much

    above cost price must he mark his goods to gain 8% ?a. 120

    b. 140

    c. 200

    d. 250

    Show/Hide Answer

    Answer = A

    Explanation:Let C.P = Rs. 100 Then S.P = Rs 108Let marked price be Rs x

    => 90% of x = 108

    => x = (108 ) * (100/90) = 120Hence Marked price = Rs. 120