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TASK 1IP ADDRESS > 172.24.114.250NETWORK MASK > 255.255.0.0 (/16)
IP Address 172.25.114.250 10101100 00011001 01110010 11111010Net Mask 255.255.0.0 11111111 11111111 00000000 00000000Net Address 172.25.0.0 10101100 00011001 00000000 00000000
172/2=86 - 0 25/2=12.5 - 1 114/2=57 - 0 250/2=125 - 086/2=43 - 0 12/2=6 - 0 57/2=28.5 - 1 125/2=62.5 - 143/2=21.5 - 1 6/2=3 - 0 28/2=14 - 0 62/2=31 - 021/2=10.5 - 1 3/2=1.5 - 1 14/2=7 - 0 31/2=15.5 - 110/2=5 - 0 1/2=0.5 - 1 7/2=3.5 - 1 15/2=7.5 - 15/2=2.5 - 1 0/2=0 - 0 3/2=1.5 - 1 7/2=3.5 - 12/2=1 - 0 0/2=0 - 0 1/2=0.5 - 1 3/2=1.5 - 11/2=0.5 - 1 0/2=0 - 0 0/2=0 - 0 1/2=0.5 - 1=10101100 =00011001 =01110010 =11111010
NETWORK MASK=255.255.0.0
255/2=127.5 - 1 255/2=127.5 – 1 0/2=0 0/2=0127/2=63.5 - 1 127/2=63.5 - 1 0/2=0 0/2=063/2=31.5 - 1 63/2=31.5 - 1 0/2=0 0/2=031/2=15.5 - 1 31/2=15.5 - 1 0/2=0 0/2=015/2=7.5 - 1 15/2=7.5 - 1 0/2=0 0/2=07/2=3.5 - 1 7/2=3.5 - 1 0/2=0 0/2=03/2=1.5 - 1 3/2=1.5 - 1 0/2=0 0/2=01/2=0.5 - 1 1/2=0.5 -1 0/2=0 0/2=0=11111111 =11111111 =00000000 =00000000
2) Network Broadcast Address’How to get the broadcast address
IP Address 172.25.114.250Binary 10101100 00011001 01110010 11111010
Subnet Mask Binary
11111111 11111111 00000000 00000000
Firstly convert the number 1 to 0 and number 0 to 1 will get broadcast binary
Broadcast Binary
00000000 00000000 11111111 11111111
Then convert the number 0 into the network address binary into 1 become the network broadcast binary
Network Broadcast Address Binary
10101100 00010000 11111111 11111111
Network broadcast address 172 25 255 255Subnet Mask 255 255 0 0
3) Total number of host bits
Formula of the possible host:
2n - 2
Using of the possible host:
2n - 2216 - 265536 - 265534
4) Number of host
Number of bits in IP address 32Number of host bits 16
Solution of number of host 32-16=16
TASK 2PROBLEM 1
IP Address 172.30.1.33 10101100 00011110 00000001 00100001Net Mask 255.255.0.0 11111111 11111111 00000000 00000000Net Address 172.30.1.0 10101100 00011110 00000001 00000000
172/2=86 - 0 30/2=15 - 0 1/2=0.5 - 1 33/2=16.5 - 186/2=43 - 0 15/2=7.5 - 1 0/2=0 - 0 16/2=8 - 043/2=21.5 - 1 7/2=3.5 - 1 0/2=0 - 0 8/2=4 - 021/2=10.5 - 1 3/2=1.5 - 1 0/2=0 - 0 4/2=2 - 010/2=5 - 0 1/2=0.5 - 1 0/2=0 - 0 2/2=1 - 05/2=2.5 - 1 0/2=0 - 0 0/2=0 - 0 1/2=0.5 - 12/2=1 - 0 0/2=0 - 0 0/2=0 - 0 0/2=0 - 01/2=0.5 - 1 0/2=0 - 0 0/2=0 - 0 0/2=0 - 0=10101100 =00011110 =00000001 =00100001
NETWORK MASK=255.255.0.0
255/2=127.5 - 1 255/2=127.5 – 1 0/2=0 0/2=0127/2=63.5 - 1 127/2=63.5 - 1 0/2=0 0/2=063/2=31.5 - 1 63/2=31.5 - 1 0/2=0 0/2=031/2=15.5 - 1 31/2=15.5 - 1 0/2=0 0/2=015/2=7.5 - 1 15/2=7.5 - 1 0/2=0 0/2=07/2=3.5 - 1 7/2=3.5 - 1 0/2=0 0/2=03/2=1.5 - 1 3/2=1.5 - 1 0/2=0 0/2=01/2=0.5 - 1 1/2=0.5 -1 0/2=0 0/2=0=11111111 =11111111 =00000000 =00000000
2) Network Broadcast AddressHow to get the broadcast address
IP Address 172.24.114.250Binary 10101100 00011001 01110010 11111010
Subnet Mask Binary
11111111 11111111 00000000 00000000
Firstly convert the number 1 to 0 and number 0 to 1 will get broadcast binary
Broadcast Binary
00000000 00000000 11111111 11111111
Then convert the number 0 into the network address binary into 1 become the network broadcast binary
Network Broadcast Address Binary
10101100 00011001 11111111 11111111
Network broadcast address 172 24 255 255Subnet Mask 255 255 0 0
3) Total number of host bits
Formula of the possible host:
2n - 2
Using of the possible host:
2n - 2216 - 265536 - 265534
4) Number of host
Number of bits in IP address 32Number of host bits 16
Solution of number of host 32-16=16
PROBLEM 2 IP Address 172.30.1.33 10101100 00011110 00000001 00100001Net Mask 255.255.255.0 11111111 11111111 11111111 00000000Net Address 172.30.1.0 10101100 00011110 00000001 00000000
172/2=86 - 0 30/2=15 - 0 1/2=0.5 - 1 33/2=16.5 - 186/2=43 - 0 15/2=7.5 - 1 0/2=0 - 0 16/2=8 - 043/2=21.5 - 1 7/2=3.5 - 1 0/2=0 - 0 8/2=4 - 021/2=10.5 - 1 3/2=1.5 - 1 0/2=0 - 0 4/2=2 - 010/2=5 - 0 1/2=0.5 - 1 0/2=0 - 0 2/2=1 - 05/2=2.5 - 1 0/2=0 - 0 0/2=0 - 0 1/2=0.5 - 12/2=1 - 0 0/2=0 - 0 0/2=0 - 0 0/2=0 - 01/2=0.5 - 1 0/2=0 - 0 0/2=0 - 0 0/2=0 - 0=10101100 =00011110 =00000001 =00100001
NETWORK MASK 255.255.255.0
255/2=127.5 - 1 255/2=127.5 – 1 255/2=127.5 – 1 0/2=0127/2=63.5 - 1 127/2=63.5 - 1 127/2=63.5 - 1 0/2=063/2=31.5 - 1 63/2=31.5 - 1 63/2=31.5 - 1 0/2=031/2=15.5 - 1 31/2=15.5 - 1 31/2=15.5 - 1 0/2=015/2=7.5 - 1 15/2=7.5 - 1 15/2=7.5 - 1 0/2=07/2=3.5 - 1 7/2=3.5 - 1 7/2=3.5 - 1 0/2=03/2=1.5 - 1 3/2=1.5 - 1 3/2=1.5 - 1 0/2=01/2=0.5 - 1 1/2=0.5 -1 1/2=0.5 -1 0/2=0=11111111 =11111111 =11111111 =00000000
2) Network Broadcast AddressHow to get the broadcast address
IP Address 172.30.1.33Binary 10101100 00011110 00000001 00100001
Subnet Mask Binary
11111111 11111111 11111111 00000000
Firstly convert the number 1 to 0 and number 0 to 1 will get broadcast binary
Broadcast Binary
00000000 00000000 00000000 11111111
Then convert the number 0 into the network address binary into 1 become the network broadcast binary
Network Broadcast Address Binary
10101100 00011110 00000001 11111111
Network broadcast address 172 30 1 255Subnet Mask 255 255 255 0
3) Total number of host bits
Formula of the possible host:
2n - 2
Using of the possible host:
2n - 228 - 2256 - 2254
4) Number of host
Number of bits in IP address 32Number of host bits 24
Solution of number of host 32-24=8
PROBLEM 3IP Address 192.168.10.234 11100000 10101000 00001010 11101010Net Mask 255.255.255.0 11111111 11111111 11111111 00000000Net Address
192.168.10.0 11100000 10101000 00001010 00000000
192/2=96 – 0 168/2=84 – 0 10/2=5 – 0 234/2=117 - 096/2=48 - 0 84/2=42 - 0 5/2=2.5 – 1 117/2=58.5 - 148/2=24 - 0 42/2=21 - 0 2/2=1 - 0 58/2=29 - 024/2=12 - 0 21/2=10.5 – 1 1/2=0.5 - 1 29/2=14.5 - 112/2=6 - 0 10/2=5 - 0 0/2=0 - 0 14/2=7 - 06/2=3 - 0 5/2=2.5 - 1 0/2=0 - 0 7/2=3.5 - 13/2=1.5 - 1 2/2=1 - 0 0/2=0 - 0 3/2=1.5 - 11/2=0.5 - 1 1/2=0.5 - 1 0/2=0 - 0 1/2=0.5 - 1=11000000 =10101000 =00001010 =11101010
NETWORK MASK 255.255.255.0
255/2=127.5 - 1 255/2=127.5 – 1 255/2=127.5 – 1 0/2=0127/2=63.5 - 1 127/2=63.5 - 1 127/2=63.5 - 1 0/2=063/2=31.5 - 1 63/2=31.5 - 1 63/2=31.5 - 1 0/2=031/2=15.5 - 1 31/2=15.5 - 1 31/2=15.5 - 1 0/2=015/2=7.5 - 1 15/2=7.5 - 1 15/2=7.5 - 1 0/2=07/2=3.5 - 1 7/2=3.5 - 1 7/2=3.5 - 1 0/2=03/2=1.5 - 1 3/2=1.5 - 1 3/2=1.5 - 1 0/2=01/2=0.5 - 1 1/2=0.5 -1 1/2=0.5 -1 0/2=0=11111111 =11111111 =11111111 =00000000
2) Network Broadcast AddressHow to get the broadcast address
IP Address 192.168.10.234Binary 11100000 10101000 00001010 11101010
Subnet Mask Binary
11111111 11111111 11111111 00000000
Firstly convert the number 1 to 0 and number 0 to 1 will get broadcast binary
Broadcast Binary
00000000 00000000 00000000 11111111
Then convert the number 0 into the network address binary into 1 become the network broadcast binary
Network Broadcast Address Binary
11100000 10101000 00001010 11111111
Network broadcast address 192 168 10 255Subnet Mask 255 255 255 0
3) Total number of host bits
Formula of the possible host:
2n - 2
Using of the possible host:
2n - 228 - 2256 - 2254
4) Number of host
Number of bits in IP address 32Number of host bits 24
Solution of number of host 32-24=8
PROBLEM 4 IP Address 172.17.99.71 10101100 00010001 01100011 01000111Net Mask 255.255.0.0Net Address 172.17.0.0 10101100 00010001 00000000 00000000
172/2=86 – 0 17/2=8.5 - 1 99/2=49.5 - 1 71/2=35.5 - 186/2=43 - 0 8/2=4 - 0 49/2=24.5 - 1 35/2=17.5 - 143/2=21.5 - 1 4/2=2 - 0 24/2=12 - 0 17/2=8.5 - 121/2=10.5 - 1 2/2=1 - 0 12/2=6 - 0 8/2=4 - 010/2=5 - 0 1/2=0.5 - 1 6/2=3 - 0 4/2=2 - 05/2=2.5 - 1 0/2=0 - 0 3/2=1.5 - 1 2/2=1 - 02/2=1 - 0 0/2=0 - 0 1/2=0.5 - 1 1/2=0.5 - 11/2=0.5 - 1 0/2=0 - 0 0/2=0 - 0 0/2=0 - 0=10101100 =00010001 =01100011 =01000111
NETWORK MASK=255.255.0.0
255/2=127.5 - 1 255/2=127.5 – 1 0/2=0 0/2=0127/2=63.5 - 1 127/2=63.5 - 1 0/2=0 0/2=063/2=31.5 - 1 63/2=31.5 - 1 0/2=0 0/2=031/2=15.5 - 1 31/2=15.5 - 1 0/2=0 0/2=015/2=7.5 - 1 15/2=7.5 - 1 0/2=0 0/2=07/2=3.5 - 1 7/2=3.5 - 1 0/2=0 0/2=03/2=1.5 - 1 3/2=1.5 - 1 0/2=0 0/2=01/2=0.5 - 1 1/2=0.5 -1 0/2=0 0/2=0=11111111 =11111111 =00000000 =00000000
2) Network Broadcast AddressHow to get the broadcast address
IP Address 172.17.99.71Binary 10101100 00010001 01100011 01000111
Subnet Mask Binary
11111111 11111111 00000000 00000000
Firstly convert the number 1 to 0 and number 0 to 1 will get broadcast binary
Broadcast Binary
00000000 00000000 11111111 11111111
Then convert the number 0 into the network address binary into 1 become the network broadcast binary
Network Broadcast Address Binary
10101100 00010001 11111111 11111111
Network broadcast address 172 17 255 255Subnet Mask 255 255 0 0
3) Total number of host bits
Formula of the possible host:
2n - 2
Using of the possible host:
2n - 2216 - 265536 - 265534
4) Number of host
Number of bits in IP address 32Number of host bits 16
Solution of number of host 32-16=16
PROBLEM 5IP Address 192.168.3.219 11000000 10101000 00000011 11011011Net Mask 255.255.0.0 11111111 11111111 00000000 00000000Net Address 192.168.0.0 11000000 10101000 00000000 00000000
192/2=96 - 0 168/2=84 - 0 3/2=1.5 - 1 219/2=109.5 - 196/2=48 - 0 84/2=42 - 0 1/2=0.5 - 1 109/2=54.5 - 148/2=24 - 0 42/2=21 - 0 0/2=0 - 0 54/2=27 - 024/2=12 - 0 21/2=10.5 - 1 0/2=0 - 0 27/2=13.5 - 112/2=6 - 0 10/2=5 - 0 0/2=0 - 0 13/2=6.5 - 16/2=3 - 0 5/2=2.5 - 1 0/2=0 - 0 6/2=3 - 03/2=1.5 - 1 2/2=1 - 0 0/2=0 - 0 3/2=1.5 - 11/2=0.5 - 1 1/2=0.5 - 1 0/2=0 - 0 1/2=0.5 - 1=11000000 =10101000 =00000011 =11011011
NETWORK MASK=255.255.0.0
255/2=127.5 - 1 255/2=127.5 – 1 0/2=0 0/2=0127/2=63.5 - 1 127/2=63.5 - 1 0/2=0 0/2=063/2=31.5 - 1 63/2=31.5 - 1 0/2=0 0/2=031/2=15.5 - 1 31/2=15.5 - 1 0/2=0 0/2=015/2=7.5 - 1 15/2=7.5 - 1 0/2=0 0/2=07/2=3.5 - 1 7/2=3.5 - 1 0/2=0 0/2=03/2=1.5 - 1 3/2=1.5 - 1 0/2=0 0/2=01/2=0.5 - 1 1/2=0.5 -1 0/2=0 0/2=0=11111111 =11111111 =00000000 =00000000
2) Network Broadcast AddressHow to get the broadcast address
IP Address 192.168.3.219Binary 11101100 00101000 00000011 11011011
Subnet Mask Binary
11111111 11111111 00000000 00000000
Firstly convert the number 1 to 0 and number 0 to 1 will get broadcast binary
Broadcast Binary
00000000 00000000 11111111 11111111
Then convert the number 0 into the network address binary into 1 become the network broadcast binary
Network Broadcast Address Binary
11111111 11111111 00000000 00000000
Network broadcast address 192 168 255 255Subnet Mask 255 255 0 0
3) Total number of host bits
Formula of the possible host:
2n - 2
Using of the possible host:
2n - 2216 - 265536 - 265534
4) Number of host
Number of bits in IP address 32Number of host bits 16
Solution of number of host 32-16=16
PROBLEM 6IP Address 192.168.3.219 11000000 10101000 00000011 11011011Net Mask 255.255.255.224 11111111 11111111 11111111 11100000Net Address
192.168.3.192 11101100 00101000 00000011 11000000
192/2=96 - 0 168/2=84 - 0 3/2=15 - 1 219/2=109.5 - 196/2=48 - 0 84/2=42 - 0 1/2=0.5 - 1 109/2=54.5 - 148/2=24 - 0 42/2=21 - 0 0/2=0 - 0 54/2=27 - 024/2=12 - 0 21/2=10.5 - 1 0/2=0 - 0 27/2=13.5 - 112/2=6 - 0 10/2=5 - 0 0/2=0 - 0 13/2=6.5 - 16/2=3 - 0 5/2=2.5 - 1 0/2=0 - 0 6/2=3 - 03/2=1.5 - 1 2/2=1 - 0 0/2=0 - 0 3/2=1.5 - 11/2=0.5 - 1 1/2=0.5 - 1 0/2=0 - 0 1/2=0.5 - 1=11000000 =10101000 =0000011 =11011011
2) Network Broadcast AddressHow to get the broadcast address
IP Address 192.168.3.219Binary 11101100 00101000 00000011 11011011
Subnet Mask Binary
11111111 11111111 11111111 11100000
Firstly convert the number 1 to 0 and number 0 to 1 will get broadcast binary
Broadcast Binary
00000000 00000000 00000000 00011111
Then convert the number 0 into the network address binary into 1 become the network broadcast binary
Network Broadcast Address Binary
11101100 00101000 00000011 11011111
Network broadcast address 192 168 3 223Subnet Mask 255 255 255 224
3) Total number of host bits
Formula of the possible host:
2n - 2
Using of the possible host:
2n - 2 25 - 232 - 230
4) Number of host
Number of bits in IP address 32Number of host bits 27
Solution of number of host 32-27=5
