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7/27/2019 Assignment FKAX 0111.docx
http://slidepdf.com/reader/full/assignment-fkax-0111docx 1/2
Use the periodic table to predict the characteristic valence-electron configuration of the halogens.
In each of the halogens' outer 'shells', they have a full s-orbital, and a nearly full p subshell, with
one of the p orbitals missing one electron from a stable configuration. This is what makes the
halogens (especially fluorine and chlorine) so reactive.
At room temperature all the halogens exist as diatomic molecules. The melting points, boiling
points, atomic radii and ionic radii all increase on descending the Group. The shapes of the
covalent molecules and ions are readily explained by VSEPR (valence shell electron pair
repulsion) theory and these compounds are often used to illustrate the theory. Fluorine is never
surrounded by more than 8 electrons, whereas the other halogens may be surrounded by up to
14 electrons.
The most characteristic chemical feature of the halogens is their ability to oxidise. Fluorine has
the strongest oxidising ability, so other elements which combine with fluorine have their highest
possible oxidation number. Fluorine is such a strong oxidising agent that it must be prepared by
electrolysis. Chlorine is the next strongest oxidising agent, but it can be prepared by chemical
oxidation. Most elements react directly with chlorine, bromine and iodine, with decreasing
reactivity going down the Group, but often the reaction must be activated by heat or UV light.
The oxidation of thiosulfate ions, S2O 32-
, by the halogens is quantitative. This means that
oxidising agents can be estimated accurately; the oxidising agent is reacted with excess I-ions,
and the liberated I2 titrated with standard thiosulfate solution. The end point is detected with
starch as indicator, which forms a dark blue complex with iodine. Chlorine, bromine and iodine
disproportionate in the presence of water and alkalis.
The melting and boiling points increase down the group because of the van der Waals forces.
The size of the molecules increases down the group. This increase in size means an increase in
the strength of the van der Waals forces.
The size of the nucleus increases down a group because there is a higher number of protons and
neutrons. Also, more energy levels are added on after passing each period. This results in
a bigger orbital, and therefore a bigger radius.
If the outer valence electrons are not near the nucleus, it will not take as much energy to
remove them. Therefore, the energy required to pull off the outermost electron will not be as
high for the elements at the bottom of the group since there are more energy levels. Also, the
high ionization energy makes the element appear non-metallic. Iodine and astatine display
metallic properties so ionization energy should decrease down the group.
7/27/2019 Assignment FKAX 0111.docx
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The number of valence electrons increases due to the increase in energy levels as the elements
progress down the group. The electrons are not as near to the nucleus anymore. Therefore, the
nucleus and the electrons are not as attracted to each other as much. An increase in shielding is
observed. Electronegativity will therefore decrease down the group.
Since the atomic size increases down the group, electron affinity will decrease. An electron will
not be as attracted to the nucleus, resulting in a low electron affinity. However, fluorine has a
lower electron affinity than chlorine. This can be explained by the small size of fluorine,
compared to chlorine.
Down a group, the atomic radius gets bigger, and there is an increase in the amount of energy
levels. This results in less attraction of the valence electrons. It also decreases because
electronegativity decreases down a group, which means that there will be less interactions with
the electrons in terms of "pulling". Also, since there is a decrease in oxidizing ability down a
group, the reactivity of the elements will decrease as well.