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Atomic Structure II. Electron Configurations. Atomic Orbitals. Each electron is assigned to: Primary energy level (shell), n Orbital type in the shell (s,p,d,f) Specific orbital of the type - PowerPoint PPT Presentation
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Atomic Structure II
Electron Configurations
Barbara A. Gage PGCC CHM 1010
Atomic Orbitals
• Each electron is assigned to:Primary energy level (shell), nOrbital type in the shell (s,p,d,f)Specific orbital of the type
Because of repulsion considerations only 2 electrons can occupy any orbital (spinning in opposite directions)
Barbara A. Gage PGCC CHM 1010
Shell (n)
# s orbita
ls
# p orbita
ls
# d orbita
ls
# f orbita
ls
Total e-
1 1 2
2 1 3 8
3 1 3 5 18
4 1 3 5 7 32
5 1 3 5 7 50
Atomic Shells and Orbitals
Barbara A. Gage PGCC CHM 1010
This diagramshows the energylevels of the atomic orbitals.
Electrons fill orbitals from bottom to top ofthe diagram.
Barbara A. Gage PGCC CHM 1010
dark - filled, spin-paired
light - half-filled
no color-empty
TA pg. 241 A vertical orbital diagram for the Li ground state.
Silberberg, Principles of Chemistry
The electron configuration is written as: 1s22s1
shellorbital
# electrons in orbital
Barbara A. Gage PGCC CHM 1010
Table 8.2
Silberberg, Principles of Chemistry Barbara A. Gage PGCC CHM 1010
Silberberg, Principles of Chemistry Barbara A. Gage PGCC CHM 1010
You can use a chartlike this to determine the electron configuration.
(But there is an easierway.)
Barbara A. Gage PGCC CHM 1010
Figure 8.5
A periodic table of partial ground-state electron
configurations.
Silberberg, Principles of Chemistry Barbara A. Gage PGCC CHM 1010
Figure 8.6 The relation between orbital filling and the periodic table.
Silberberg, Principles of Chemistry Barbara A. Gage PGCC CHM 1010
SAMPLE PROBLEM 8.2
Determining Electron Configuration
PLAN:
SOLUTION:
PROBLEM: Using the periodic table on the inside cover of the text (not Figure 8.12 or Table 8.4), give the full and condensed electrons configurations, partial orbital diagrams showing valence electrons, and number of inner electrons for the following elements:
(a) potassium (K: Z = 19)
(b) molybdenum (Mo: Z = 42)
(c) lead (Pb: Z = 82)
Use the atomic number for the number of electrons and the periodic table for the order of filling for electron orbitals. Condensed configurations consist of the preceding noble gas and outer electrons.
(a) for K (Z = 19)
1s22s22p63s23p64s1
[Ar] 4s1
4s1
condensed configurationpartial orbital diagram
full configuration
There are 18 inner electrons.
3d 4pBarbara A. Gage PGCC CHM 1010
SAMPLE PROBLEM 8.2
continued
(b) for Mo (Z = 42)
1s22s22p63s23p64s23d104p65s14d5 [Kr] 5s14d5
(c) for Pb (Z = 82)
[Xe] 6s24f145d106p2
condensed configurationpartial orbital diagram
full configuration
5s1 4d5
condensed configurationpartial orbital diagram
full configuration 1s22s22p63s23p64s23d104p65s24d105p66s24f145d106p2
There are 36 inner electrons and 6 valence electrons.
6s2 6p2
There are 78 inner electrons and 4 valence electrons.
5p
Barbara A. Gage PGCC CHM 1010
Configuration for Ions
• What is the electron configuration for Na+?
Na = 1s22s22p63s1
Na+ = 1s22s22p63s1
• What is the electron configuration for Se2-?
Se = 1s22s22p63s23p64s23d104p4
Se2- = 1s22s22p63s23p64s23d104p6
Barbara A. Gage PGCC CHM 1010
Configuration for Ions
• Transitions metals have a twist…Fe = 1s22s22p63s23p64s23d6
Fe2+ = 1s22s22p63s23p64s23d6
Fe3+ = 1s22s22p63s23p64s23d5
Barbara A. Gage PGCC CHM 1010