BÀI LUYỆN TẬP CHƯƠNG 11

7/29/2019 BI LUYN TP CHNG 11

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Bi ging: Truyn s liu Chng 11: Giao thc kt ni d liu

T KHA V CC NIM

Address field

Asynchronous balanced mode(ABM)

Asynchronous response mode

Balanced configurarion

Binary synchronous communication(BSC)

Bit-oriented protocol

Bit stufing

Block check count

Blocked asynchronous transmission(BLAST)

Byte

Byte stuffing

Character-oriented protocol

Combined station

Control character

Disconnect

Final bit

Flag

Frame

Frame check sequence

High-level data link control (HDLC)

Information frame (I-frame)

Kermit

Link access procedure (LAP)

Link access procedure, for D chanel(LAPD)

Link access procedure for modem(LAPM)

Normal response mode (NRM)

Piggybacking

Poll bit (P bit)

Poll/final bit (P/F bit)

Primary station

S- frame

Secondary station

Supervisory frame (S-frame)

Symmetrical configuration

Synchronous data link control(SDLC)

Transparency

(U-frame)

Unbalanced configuration

Unnumbered frame (U-frame)

XMODEM

YMODEM

ZMODEM

Bin dch: Nguyn Vit Hng Trang6


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TM TT

Trong thng tin d liu thgiao thc c hiu l mt

nhm cc c tnh cthit lp cho mt hay nhiulp trong m hnh OSI

Giao thc kt ni d liuc chia thnh giao thcng b v khng ng b

Cc giao thc khng ngb nh XMODEM,YMODEM, ZMODEM,BLAST, v Kermir dng c

ch truyn file. Giao thc ng b c

chia thnh 2 nhm:

a. Giao thc theo hng k t

b. Giao thc theo hng bit

Trong giao thc theo hngk t, mt frame c dindch t chui cc k t

Trong giao thc theo hngbit, mi bit hay nhm ccbit u c th c ngha

Giao thc BSC: binarysynchronouscommunication l giao thctheo hng k t ni tingnht.

BSC hot ng theo ch song cng (full-duplex)dng stop and wait ARQ, vcu hnh im-im hayim ni nhiu im.

C hai dng frame BSC:

a. Frame iu khin

b. Frame d liu

Cc frame iu khin thchin cc chc nng sau:

a. To kt ni

b. iu khin lu lng v li

c. Phc v kt ni

Mt chui bit ging nh kt iu khin BSC nmtrong trng d liu thi

khng th c hiu l kt iu khin, nn phi ctnh transparency (trongsut)

Tnh transparency trongBSC c thc hin dng

phng php bit nhi (bitstuffing).

Bit nhi bao gm:

a. Demacaratoin of thetransparency region

b. Thm k t DLE (trongvng transparency) trcmi k t DLE

Tt c cc giao thc theohng bit u c quan hvi HDLC

HDLC hot ng trong ch half duplex hay full-

duplex trong cu hnh im-im hay im ni nhiuim.

Cc trm trong HDLC cchia thnh cc phm trsau:

a. Trm s cp-gi yu cu

b. Trm th cp-gi p ng

c. Trm hn hp-gi yu cu

v p ng Cc trm trong HDLC c

cu hnh theo:

a. Khng i xng-mt scp, mt hay nhiu th cp

b. i xng-hay trm vt l,mi trm u c th chuynt s cp sang th cp

Cc trm trong HDLC c

thng tin vi nhau theo mttrong ba ch :



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a. Normal response mode(NRM)- trm th cp cn

php khi truyn

b. Asynchronous balancedmode (ARM) - th cpkhng cn c php khitruyn

c. Asynchronous balancedmode (ABM) - trm hnhp vt k c th khi tothng tin

Giao thc HDLC nhngha 3 dng frame:

a. I-frame: information frame;

dng cho truyn d liu viu khin

b. S-frame: supervisoryframe; dng cho iu khin

c. U-frame: unnumberedframe; dng cho iu khinv qun l

HDLC x l datatransparency bng cchthm s 0 vo sau 5 bit 1lin tip v c gi l

phng php bit nhi.



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BI LUYN TP * CU HI N TP

1. Trong BSC, tnh minh ca d liu lg?

2. Khi no mu DLE DLE xut hintrong BSC?

3. Cho bit khc bit gia cc trngthng tin trong I-frame v U-frametrong HDLC.

4. nh ngha giao thc trong truyn dliu.

5. Cc giao thc trong kt ni d liuc chia ra thnh nhng lp no? Cs ca phng php chia?

6. Cc giao thc khng ng b banu c dng ch yu nh th no?

7. Ti sao cc giao thc khng ng bngy cng t c dng?

8. Cc giao thc ng b c phnloi ra sao? Trn c s no?

9. Cc giao thc theo hng k tchuyn thng tin iu khin nh thno?

10. M t cu hnh ng dy, ch truyn dn, phng php iu khinlu lng v kim tra li trong BSC.

11. M t cc dng frame ca BSC.

12. Ti sao mt bn tin BSC di th nnchia thnh nhiu block?

13. Trong BSC (truyn nhiu frame), chobit cch my thu phn bit gia phnkt thc mt frame v kt thc mt bntin.

14. Cc frame iu khin trong BSCc dng lm g?

15. M t ba dng trm trong HDLC?

16. Cho bit cc lnh v p ng trongcc cu hnh HDLC?

17. S khc bit gia ba dng frametrong cc frame HDLC?

18. Trong HDLC, bit nhi l g? Cngdng?

19. Lit k v m t vn tt cc bit trongtrong trng iu khin HDLC?

20. Piggybacking l g?

21. Cho bit bn loi S-frame?

22. Cho bit nm phm tr ca U-frame?

23. Cho bit khc bit gia cc loiLAPB, LAPD v LAPM?

* CU HI TRC NGHIM

24. BSC c ngha l:a. Binary synchronous control

b. Binary synchronouscommunication

c. Bit-oriented synchronouscomunication

d. Byte-oriented communication

25. Mt p ng m cho poll trong BSCl:

a. NAK

b. EOTc. WACK

d. b v c

26. Mt p ng m cho select trongBSC l

a. NAK

b. EOT

c. WACK

d. b v c



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27. Trong BSC, khi nhn c mtframe khng li v nh s chn thmy thu s tr li bng:

a. ACK

b. ACK0c. ACK1

d. a hay b

28. Ch truyn dn s liu dng tronggiao thc BSC l:

a. simplex

b. half-duplex

c. full-duplex

d. half -simplex29. Cc frame trong BSC c chia

thnh frame d liu v frame cn li l:

a. truyn dn

b. iu khin

c. thng tin

d. gim st

30. Trong giao thc BSC, th sau ETB,

ETX hay ITB, th dng trng no sauy?

a. DLE

b. EOT

c. BCC

d. SYN

31. Trong giao thc BSC, th kt thctruyn dn hay p ng m cho poll thdng:

a. DLE

b. ETX

c. EOT

d. ETB

32. Trng no sau y l trng c di thay i trong BSC?

a. d liu

b. BCCc. Tiu (header)

d. tt c cc cu trn

33. HDLC l vit tt ca:

a. high-duplex line communication

b. high-level data link control

c. half-duplex digital link combination

d. host double level circuit

34. Trong giao thc HDLC, trng ach ca frame cha a ch ca:

a. s cp

b. th cp

c. my th ba

d. a v b

35. HDLC l giao thc:

a. theo hng k t

b. theo hng bit

c. theo hng byte

d. theo hng m

36. BSC l giao thc:

a. theo hng k tb. theo hng bit

c. theo hng byte

d. theo hng m

37. Trong HDLC, phn bt u v ktthc frame c nh ngha bi trngsau:

a. c

b. a chc. iu khin

d. FSC

38. Trong mi trng iu khin caHDLC u tn ti:

a. bit (P/F)

b. N(R)

c. N(S)

d. Cc bit m



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39. Poll v select l chc nng ca frametrong HDLC:

a. I-frame

b. S-frame

c. U-framed. a v b

40. Trong HDLC, ngha ca bitpoll/final ph thuc vo:

a. Cu hnh h thng

b. Ty thuc frame ang l iu khinhay p ng

c. ch ca h thng

d. tt c u sai

41. Trng ngn nht trong giao thcHDLC thng l trng:

a. thng tin

b. gim st

c. qun ld. tt c u sai

42. Khi gi cng lc d liu v xc nhntrong cng mt frame, phng php c gi l:

a. piggybacking

b. backpacking

c. piggypacking

d. a good ideaBi tp

43. Cho bit d liu thc trong frame hnh sau:

44. Cho bit d liu hin c trong frame hnh sau:

45. Minh ha phng thc m frame p ng gim st trong HDLC c th kch khi frameBSC no:

a. ACK 0

b. ACK 1

c. NAK

d. WACK

46. Dng phng php bit nhi cho chui d liu sau 000111111011111001111001111101

47. Dng phng php bit nhi cho chui c liu sau

00011111111111111111111111111111001111101

48. Frame HDLC trong hnh 11.35 c gi t trm s cp gi n th cp. Tr li cc cuhi sau:



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a. a ch th cp

b. dng frame

c. s ca chui pht (nu tn ti)

d. s ca xc nhn (nu tn ti)

e. frame c cha d liu khng? nu c, cho bit gi tr ca d liu

f. frame c mang d liu qun l khng? nu c cho bit gi tr

g. Mc ch ca frame l g?

49. Lm li bi tp 48, khi frame c gi t th cp n s cp

50. Frame HDLC trong hnh 11.36 c gi t s cp n th cp. Tr li cc cu hi sau:

a. a ch ca th cp

b. dng frame

c. s ca chui c gi (nu c)

d. s ca xc nhn (nu c)

e. frame c mang d liu user khng? nu c, cho bit gi tr

f. frame c mang d liu qun l khng? nu c, cho bit gi tr

g. mc ch ca frame

51. Lm li bi tp 50 khi frame c gi t th cp n s cp

52. Frame trong hnh 11.37 c gi t s cp n th cp. Tr li cc cu hi sau

a. a ch th cp

b. dng ca frame


d. s ca xc nhn (nu c)e. frame c mang d liu user khng? nu c, cho bit gi tr



a. a ch th cp

b. dng ca frame




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g. s ca xc nhn (nu c)

d. frame c mang d liu user khng? nu c, cho bit gi tr

e. frame c mang d liu qun l khng? nu c, cho bit gi tr


a. a ch th cp

b. dng ca frame


d. s ca xc nhn (nu c)

e. frame c mang d liu user khng? nu c, cho bit gi tr


55. Dng BSC, minh ho chui frame trong trng hp sau c cu hnh im im gia haimy tnh:

a. My tnh A xin php my tnh B gi d liu

b. My tnh B p ng dng

c. My tnh A gi ba frame, mi frame gm 4 block 100 byte

d. My tnh B xc nhn d liu nhn

56. Dng BSC, minh ho chui frame trong trng hp sau l (my A l s cp v my B lth cp)

a. My tnh A kim tra xem my tnh B c d liu gi khng

b. My tnh B gi frame 50 byte

c. My tnh A xc nhn d liu nhn



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57. Dng hnh 11.29, m t phng thc trao i frame nu my A khng c d liu cntruyn

58. Dng hnh 11.29, m t phng thc trao i frame nu frame 1 b tht lc59. Dng hnh 11.30, m t phng thc trao i cc frame nu trm B cha sn sng nhn

d liu

60. Dng hnh 11.30, m t phng thc trao i cc frame nu xc nhn b tht lc.


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BÀI LUYỆN TẬP CHƯƠNG 11