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8/14/2019 BICMOS INVERTERS.pptx
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By
Syed Inthiyaz
BiCMOS INVERTERS
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The simplified BiCMOS Inverter
Two bipolar transistors (T3
and T4), one nMOS and
one pMOS transistor (both
enhancement-type
devices)
Vin = 0 :
T1 is off. Therefore T3 is non-
conducting
T2 ON - supplies current tobase of T4
T4 base voltage set to Vdd.
T4 conducts & acts as current
source to charge load CL towards
Vdd.
Vout rises to Vdd - Vbe (of T4)
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The simplified BiCMOS
Inverter(Contd..)
Vin = Vdd :
T2 is off.Therefore T4 is non-
conducting.
T1 is on and supplies current to the
base of T3
T3 conducts & acts as a current
sink to discharge load CL towards 0V. Vout falls to 0V+ VCEsat (of T3)
T3 & T4 present low impedances when turned on
into saturation & load CL will be charged or
discharged rapidly
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Advantages
Output logic levels will be good & will beclose to rail voltages since VCEsat is
quite small & VBE 0.7V. Therefore,
inverter has high noise margins
Inverter has high input impedance, i.e.,
MOS gate input
Inverter has low output impedance
Inverter has high drive capability butoccupies a relatively small area
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Disadvantages
However, this is not a good arrangement toimplement since no discharge path exists
for current from the base of either bipolar
transistor when it is being turned off, i.e.,
when Vin=Vdd
T2 is off and no conducting path to the base
of T4 exists when Vin=0
T1 is off and no conducting path to the baseof T3 exists
This will slow down the action of the circuit
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Alternative BiCMOS Inverter with no
static current flow
The DC path through
T3and T1 is eliminated
The output swing isnow reduced, since the
output cannot fall below
the base to emitter VBE
of T3
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BiCMOS Inverter using Resistors
In this circuit resistors
provide the improved
swing of output voltage
when each bipolartransistor is off,
It also provide
discharge paths for basecurrent during turn-off.
The provision of on chip resistors of
suitable value is not always convenient and
may be space-consuming, so that other
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BiCMOS Inverter using MOS
transistors for base current discharge
Vin = 0 : T,1T3,T6 are off
T2,T4,T5 are ON
T4 base voltage set to Vdd.
T4 conducts & acts as curren
source to charge load CL
towards Vdd.
Vout rises to Vdd
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transistors for base current discharge
(Contd..)
Vin = Vdd :
T2,T4,T5 are Off
T,1T3,T6 are oN
The load CL dischargethrough T1 and T6 towards 0v.
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