3
Bisection method(1-2 arası kök) iteration f(xk) f(xort) f(xb) error 1 1.000000 1.500000 2.000000 ### ### 1.389056 0.018311 2 1.500000 1.750000 2.000000 ### 0.504603 1.389056 0.504603 3 1.500000 1.625000 1.750000 ### 0.203419 0.504603 0.203419 4 1.500000 1.562500 1.625000 ### 0.083233 0.203419 0.083233 5 1.500000 1.531250 1.562500 ### 0.030203 0.083233 0.030203 6 1.500000 1.515625 1.531250 ### 0.005390 0.030203 0.005390 7 1.500000 1.507813 1.515625 ### ### 0.005390 0.006598 8 1.507813 1.511719 1.515625 ### ### 0.005390 0.000638 9 1.511719 1.513672 1.515625 ### 0.002367 0.005390 0.002367 10 1.511719 1.512695 1.513672 ### 0.000862 0.002367 0.000862 11 1.511719 1.512207 1.512695 ### 0.000111 0.000862 0.000111 12 1.511719 1.511963 1.512207 ### ### 0.000111 0.000264 13 1.511963 1.512085 1.512207 ### ### 0.000111 0.000076 14 1.512085 1.512146 1.512207 ### 0.000018 0.000111 0.000018 15 1.512085 1.512115 1.512146 ### ### 0.000018 0.000029 16 1.512115 1.512131 1.512146 ### ### 0.000018 0.000006 Bisection method(0-1 arası kök) iteration f(xk) f(xort) f(xb) error 1 0.000000 0.500000 1.000000 1.000000 0.148721 ### 0.148721 2 0.500000 0.750000 1.000000 0.148721 ### ### 0.133000 3 0.500000 0.625000 0.750000 0.148721 ### ### 0.006754 4 0.500000 0.562500 0.625000 0.148721 0.067555 ### 0.067555 5 0.562500 0.593750 0.625000 0.067555 0.029516 ### 0.029516 6 0.593750 0.609375 0.625000 0.029516 0.011156 ### 0.011156 7 0.609375 0.617188 0.625000 0.011156 0.002145 ### 0.002145 8 0.617188 0.621094 0.625000 0.002145 ### ### 0.002319 9 0.617188 0.619141 0.621094 0.002145 ### ### 0.000091 10 0.617188 0.618164 0.619141 0.002145 0.001026 ### 0.001026 11 0.618164 0.618652 0.619141 0.001026 0.000468 ### 0.000468 12 0.618652 0.618896 0.619141 0.000468 0.000188 ### 0.000188 13 0.618896 0.619019 0.619141 0.000188 0.000049 ### 0.000049 14 0.619019 0.619080 0.619141 0.000049 ### ### 0.000021 15 0.619019 0.619049 0.619080 0.000049 0.000014 ### 0.000014 16 0.619049 0.619064 0.619080 0.000014 ### ### 0.000003 f(x)=e x -3x xk xort xb f(x)=e x -3x xk xort xb

Bisection vs Modified Newton Method Arif

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Bisection vs newton numerical iteration method example in excell

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f(x)=ex-3xBisection method(1-2 aras kk)f(x)=ex-3xModified Newton method(1-2 aras kk)iterationxkxortxbf(xk)f(xort)f(xb)error