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Florian Ion PETRESCU & Relly Victoria PETRESCU CAMSHAFT PRECISION COLOR Germany 2013

Camshaft precision color petrescu

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Florian Ion PETRESCU & Relly Victoria PETRESCU CAMSHAFT PRECISION COLOR Germany 2013

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Page 1: Camshaft precision color petrescu

Florian Ion PETRESCU & Relly Victoria PETRESCU

CAMSHAFT PRECISION

COLOR

Germany 2013

Page 2: Camshaft precision color petrescu

2

Scientific reviewer:

Dr. Veturia CHIROIU

Honorific member of Technical Sciences Academy of Romania (ASTR) PhD supervisor in Mechanical Engineering

Copyright

Title book: Camshaft Precision Color

Authors book: Florian Ion Petrescu & Relly Victoria Petrescu

© 2001-2013, Florian Ion PETRESCU

[email protected]

ALL RIGHTS RESERVED. This book contains material protected under International and Federal Copyright Laws and Treaties. Any unauthorized reprint or use of this material is prohibited. No part of this book may be reproduced or transmitted in any form or by any means, electronic or mechanical, including photocopying, recording, or by any information storage and retrieval system without express written permission from the authors / publisher.

Manufactured and published by: Books on Demand GmbH, Norderstedt

ISBN 978-3-8482-2487-6

Page 3: Camshaft precision color petrescu

3

WELCOME

0A

A

B

A-

Fn, vn

Fm, vm

Fa, va

Fi, viFn, vn

Fu, v2

B

B0

A0

A

O

x

e

s0

rb

r0

rA

rB

s

n

C

rb

Page 4: Camshaft precision color petrescu

4

0

A

A

2

B

Fn, vn

Fm, vmFa, va

Fc, vc

Fn, vn

Fu, vu

B

B0

A0

x

rb

r0

rA

rB

A

B

OD

0

d

b

b

r0

G

B

O D

d

A

A0

B0

H

I

l

b

G0

l.’

.’r

M

m

x

1

2

A

Fn; vn

Fm; vm

Fa; va

You are welcome to read the full book! The authors.

Page 5: Camshaft precision color petrescu

5

CONTENT

Welcome............................................................................ 003

Content............................................................................... 005

Cap 01 CAM GEARS EFFICIENCY…………………….… 006

Cap 02 CONTRIBUTIONS AT THE

DYNAMIC OF CAMS ……………………………….……... 013

Cap 03 CAM GEARS DYNAMICS ILLUSTRATED IN THE CLASSIC DISTRIBUTION ……..…………….….. 020

Cap 04 CAM GEARS DYNAMICS

TO THE MODULE B (WITH TRANSLATED

FOLLOWER WITH ROLL)..……………………………….. 030

Cap 05 DYNAMICS OF THE

CLASSIC DISTRIBUTION………………..……………….. 040

Cap 06 PRECISION OF THE

CLASSIC DISTRIBUTION……….……………………….. 046

Cap 07 DYNAMIC SYNTHESIS OF THE ROTARY

CAM AND TRANSLATED TAPPET WITH ROLL..…….. 056

Bibliography........................................................................069

Annex…………………………………………………………..075

Page 6: Camshaft precision color petrescu

6

CHAPTER I

CAM GEARS EFFICIENCY

Abstract: The chapter presents an original method to determine the efficiency of a mechanism with cam and follower. The originality of this method consists in eliminating the friction modulus. In this chapter it analyses four types of cam mechanisms: 1.The mechanism with rotary cam and plate translated follower; 2.The mechanism with rotary cam and translated follower with roll; 3.The mechanism with rotary cam and rocking-follower with roll; 4.The mechanism with rotary cam and plate rocking-follower. For every kind of cam and follower mechanism one uses a different method to determine the most efficient design. We take into account the cam’s mechanism (distribution mechanism), which is the second mechanism in internal-combustion engines. The optimizing of this mechanism (the distribution mechanism), can improve the functionality of the engine and may increase the comfort of the vehicle too.

Keywords: cam, efficiency, translated follower, rocking-follower, follower with roll

1 Introduction

In this chapter the authors present an original method to calculate the efficiency of the cam’s mechanisms. Four kinds of cam and follower mechanisms are analyzed: 1. A mechanism with rotary cam and plate translated follower; 2. A mechanism with rotary cam and translated follower with roll; 3. A mechanism with rotary cam and rocking-follower with roll; 4. A mechanism with rotary cam and plate rocking follower. For every kind of cams and followers mechanism, a different method for the cam’s design with a better efficiency has been utilized.

2 Determining of momentary mechanical efficiency of the rotary cam and plate translated

follower

The consumed motor force, Fc, perpendicular at A to the vector rA, is divided into two components [1, 2]: a) Fm, which represents the useful force, or the motor force reduced to the

follower; b) F, which is the sliding force between the two profiles of cam and follower (Fig. 1). See the written relations (2.1-2.10):

sin cm FF (2.1)

sin12 vv (2.2)

212 sin vFvFP cmu (2.3)

1vFP cc (2.4)

22

1

21 cossin

sin

vF

vF

P

P

c

c

c

ui

(2.5)

22

0

2

2

22

')(

''sin

ssr

s

r

s

A (2.6)

cos cFF (2.7)

Page 7: Camshaft precision color petrescu

7

cos112 vv (2.8)

2

112 cos vFvFP c (2.9)

22

1

21 sincos

cos

vF

vF

P

P

c

c

ci

(2.10)

O

A

r0

s

s’

rA

1vr

2vr

12vr

B

C

D

w

Fr mF

rcFr F

E

© 2002 Florian PETRESCU

The Copyright-Law

Of March, 01, 1989

U.S. Copyright Office

Library of Congress

Washington, DC 20559-6000

202-707-3000

Fig. 1 Forces and speeds to the cam with plate translated follower

3 Determining of momentary dynamic efficiency of the rotary cam and translated follower

with roll

The pressure angle (Fig. 2), is determined by relations (3.5-3.6) [1, 2]. We can write the next forces, speeds and powers (3.13-3.18). Fm, vm, are perpendicular to the vector rA at A. Fm is divided into Fa (the sliding force) and Fn (the normal force). Fn is divided too, into Fi (the bending force) and Fu (the useful force). The momentary dynamic efficiency can be obtained from relation (3.18):

The written relations are the following.

20

22B s)(ser (3.1)

2BB rr (3.2)

B

Br

e sincos (3.3)

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8

B

Br

ss 0cossin (3.4)

0A

A

B

A-

Fn, vn

Fm, vm

Fa, va

Fi, viFn, vn

Fu, v2

B

B0

A0

A

O

x

e

s0

rb

r0

rA

rB

s

n

C

rb

Fig. 2 Forces and speeds to the cam with translated follower with roll

22

0

0

)'()(

cos

esss

ss

(3.5)

22

0 )'()(

'sin

esss

es

(3.6)

sinsincoscos)cos( (3.7)

)cos(2222 BbbBA rrrrr (3.8)

Page 9: Camshaft precision color petrescu

9

22

0

220

)'()(

)'()'()(cos

esssr

esressse

A

bA

(3.9)

22

0

2200

)'()(

])'()([)(sin

esssr

resssss

A

bA

(3.10)

cos'

)'()(

')()cos(

220

0

AA

Ar

s

esssr

sss (3.11)

2cos'

cos)cos( A

Ar

s (3.12)

)sin(

)sin(

Ama

Ama

FF

vv (3.13)

)cos(

)cos(

Amn

Amn

FF

vv (3.14)

sin

sin

ni

ni

FF

vv (3.15)

cos)cos(cos

cos)cos(cos2

Amnu

Amn

FFF

vvv (3.16)

mmc

Ammuu

vFP

vFvFP 222 cos)(cos

(3.17)

4

2

2222

22

cos'

]cos'

[]cos)[cos(

cos)(cos

AAA

mm

Amm

c

ui

r

s

r

s

vF

vF

P

P

(3.18)

4 Determining of momentary dynamic efficiency of the rotary cam and rocking follower with

roll

Fm, vm, are perpendicular to the vector rA at A. Fm is divided into Fa (the sliding force) and Fn (the normal force). Fn is divided too into Fc (the compressed force) and Fu (the useful force). The written relations are the following [1, 2] (4.1-4.31).

db

rrdb b

2

)(cos

20

22

0 (4.1)

02 (4.2)

2222 cos)'1(2)'1( bdbdRAD (4.3)

Page 10: Camshaft precision color petrescu

10

0

A

A

2

B

Fn, vn

Fm, vmFa, va

Fc, vc

Fn, vn

Fu, vu

B

B0

A0

x

rb

r0

rA

rB

A

B

OD

0

d

b

b

Fig. 3 Forces and speeds for the rotary cam and rocking follower with roll

RAD

bbd

'cossin 2

(4.4)

RAD

d 2sincos

(4.5)

2222 cos2 dbdbrB (4.6)

B

BB

rd

brd

2cos

222

(4.7)

B

Br

b 2sinsin

(4.8)

cossincossin)sin( 222 (4.9)

sinsincoscos)cos( 222 (4.10)

2

2

BB (4.11)

)sin(cos 2 BB (4.12)

)cos(sin 2 BB (4.13)

)cos(sincos)sin(cos 22 BBB (4.14)

Page 11: Camshaft precision color petrescu

11

)cos(cossin)sin(sin 22 BBB (4.15)

Brrrrr BbbBA cos2222 (4.16) BA

bBA

rr

rrr

2cos

222

(4.17)

Br

r

A

b sinsin (4.18) BA (4.19)

sinsincoscoscos BBA (4.20)

sincoscossinsin BBA (4.21)

2A (4.22) AA

A

cos)cos(sin)sin(

)cos(cos

22

2

(4.23)

cos'

cos

Ar

b (4.24)

2cos

'coscos

Ar

b (4.25)

sin

sin

ma

ma

vv

FF (4.26)

cos

cos

mn

mn

vv

FF (4.27)

sin

sin

nc

nc

vv

FF (4.28)

coscoscos

coscoscos

2 mn

mnu

vvv

FFF (4.29)

mmc

mmuu

vFP

vFvFP 222 coscos

(4.30)

4

2

2222

222

cos'

)cos'

(

)cos(coscoscos

AA

c

ui

r

b

r

b

P

P

(4.31)

5 Determining of momentary mechanical efficiency of the rotary cam and general plate

rocking follower

The written relations are following, (5.1-5.6) (see Fig. 4) [1, 2]:

'1

']sin)(cos)([ 0

20

2

brbrdAH (5.1)

sin)(cos)( 20

20 brdbrbOH (5.2)

222 OHAHr (5.3)

22

2

2

22sin;sin

OHAH

AH

r

AH

r

AH

(5.4)

sincos

;sincos

mmn

mmn

vvv

FFF

(5.5)

Page 12: Camshaft precision color petrescu

12

22

22

2

sinsin

OHAH

AH

vF

vF

vF

vF

P

P

mm

mm

mm

nn

c

ni

(5.6)

r0

G

B

O D

d

A

A0

B0

H

I

l

b

G0

l.’

.’r

M

m

x

1

2

A

Fn; vn

Fm; vm

Fa; va

Fig. 4 Forces and speeds for the rotary cam and general plate rocking follower

6 Conclusions

The follower with roll makes the input-force be divided into several components. This is the reason why, the dynamics and the precise-kinematics (the dynamic-kinematics) of mechanism with rotary cam and follower with roll, are more different and difficult. The presented dynamic efficiency of followers with roll is not the same like the classical mechanical efficiency. For plate followers the dynamic and the mechanical efficiency are the same. This is the great advantage of plate followers.

References

[1] PETRESCU F.I., PETRESCU R.V., Determining the dynamic efficiency of cams. SYROM 2005, Bucharest, Romania, Vol. I, pp. 129-134, 2005. [2] PETRESCU F.I., PETRESCU R.V., POPESCU N., The efficiency of cams. In the Second International Conference “Mechanics and Machine Elements”, Technical University of Sofia, November 4-6, Sofia, Bulgaria, Vol. II, pp. 237-243, 2005.

Page 13: Camshaft precision color petrescu

13

CHAPTER II

CONTRIBUTIONS AT THE

DYNAMIC OF CAMS

ABSTRACT: The chapter presents an original method in determining a general, dynamic and differential equation for the motion of machines and mechanisms, particularized for the mechanisms with rotation cams and followers. This equation can be directly integrated by an original method presented in this chapter. After integration the resulted mother equation may be solved immediately. It presents an original dynamic model with one degree of freedom, with variable internal amortization. It determines the resistant force reduced at the valve (4), the motor force reduced at the valve (5), and the coefficient of variable internal amortization (6). The reduced mass can be calculated with the form (8). The differential motion equation takes the exact form (31), and the approximate form (32). The equation (31) is preparing for its integration with the form (35, 36, 37). The (37) form can be directly integrated and it obtains the parental equation (38). The equation (38) can be arranged in forms (39, 40, 41). The mother equation (41) can be solved directly (42-45), or more elegant with finished differences (48 and 49-50).

Keywords: Motor-force, resistant-force, variable internal amortization, differential equation, valve rocker, valve push rod, valve lifter, valve spring.

1. INTRODUCTION

The chapter presents shortly an original method in determining a general dynamic differential equation, particularized for the mechanisms with rotation cams and followers [1, 2, 3].

This equation can be integrated directly by an original method presented in this chapter.

2. PRESENTING A DYNAMIC MODEL, WITH ONE GRADE

OF FREEDOM, WITH VARIABLE INTERNAL AMORTIZATION

2.1. Determining the amortization coefficient of the mechanism

Starting with the kinematical schema of the classical valve gear mechanism (see the figure 1), one creates the translating dynamic model, with a single degree of freedom (with a single mass), with variable internal amortization (see the picture 2), having the motion equation (1).

The formula (1) is just a Newton equation, where the sum of forces on a single element is 0, [1, 2, 3]:

0)( FxcxkxyKxM (1)

Page 14: Camshaft precision color petrescu

14

Where:

M –the mass of the mechanism, reduced at the valve;

K –the elastically constant of the system;

k –the elastically constant of the valve spring;

c –the coefficient of the system’s amortization;

F0 –the elastically force which compressing the valve spring;

x –the effective displacement of the valve;

ys –the theoretical displacement of the tappet reduced at the valve, imposed by the cam’s profile.

5 w1

2

3

4

A

B

C

D

C0

O

FIG. 1. The kinematical schema of the classical valve gear mechanism

M M

k

kx F

F(t) c .

cx

xx(t)

K(y-x)K

y(t)

w

camã

Fig. 2. Dynamic model with a single liberty, with variable internal amortization

Page 15: Camshaft precision color petrescu

15

The Newton equation (1) can be written in form (2):

)()( 0 xkFxyKxcxM (2)

The differential equation, Lagrange, can be written in form (3).

rm FFxdt

dMxM

2

1 (3)

Comparing the two equations, (2 and 3), we identifie the coefficients and obtain the resistant force (4), the motor force (5) and the coefficient of internal amortization (6), [1, 3]. It can see that the internal amortization coefficient, c, is a variable:

)( 000 xxkxkxkxkFFr (4)

)()( xsKxyKFm (5)

dt

dMc

2

1 (6)

It places the variable coefficient, c, (see the relation 6), in the Newton equation (form 1 or 2) and obtains the equation (7), [1, 3]:

0)(2

1FyKxkKx

dt

dMxM (7)

The reduced mass can be written in form (8), (the reduced mass of the system, reduced at the valve), [1]:

244

211

22325 )()()()(

xJ

xJ

x

ymmmM

ww (8)

With the following notations:

m2 =the mass of the tappet (of the valve lifter);

m3 =the mass of the valve push rod;

m5 =the valve mass;

J1 =the inertia mechanical moment of the cam;

J4 =the inertia mechanical moment of the valve rocker;

2y =the tappet velocity, or the second movement-low, imposed by the cam’s profile;

x =the real (dynamic) valve velocity.

If one notes with i=i25, the ratio of transmission tappet-valve, given from the valve rocker, the theoretically velocity of the valve, y , (the tappet velocity reduced at the valve), takes the form

(9), where the ratio of transmission, i, is given from the formula (10).

i

yyy 2

5

(9)

DC

CCi

0

0 (10)

It can write the following relations (11-16), where y’ is the reduced velocity forced at the tappet by the cam’s profile. With the relations (10, 13, 14, 16) the reduced mass (8), can be written in the forms (17–19):

'1 xx w (11)

''21 xx w (12)

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16

'1'212 yiyy ww (13)

'

1

'1

11

xxx

w

ww

(14)

DC

y

DC

CC

CC

y

CC

iy

CC

y

CC

y

0

1

0

0

0

1

0

1

0

'21

0

24

'''.

wwwww

(15)

'

'1

'

'

010

14

x

y

DCxDC

y

x

w

ww

(16)

2

04

21

2325 )

'

'1()

'

1()

'

'()(

x

y

DCJ

xJ

x

yimmmM

(17)

21

2

20

432

25 )

'

1()

'

'(]

)()([

xJ

x

y

DC

JmmimM (18)

21

25 )

'

1()

'

'(*

xJ

x

ymmM (19)

It derivates dM/d and obtains the relations (20–22):

)'

''

'

''()

'

'(2)

'

'''''(

'

'2

'

)''''''(

'

'2])

'

'[(

2

2

2

2

x

x

y

y

x

y

x

yxy

x

y

x

yxxy

x

y

d

x

yd

(20)

32

2

'

''2

'

''

'

2])

'

1[(

x

x

x

x

xd

xd

(21)

312

'

''2)

'

''

'

''()

'

'(*2

x

xJ

x

x

y

y

x

ym

d

dM

(22)

The relation (6) can be written in form (23) and with relation (22), it’s taking the forms (24–25):

w

d

dMc

2 (23)

}'

'')

'

''

'

''()

'

'(]

)()({[

312

20

432

2

x

xJ

x

x

y

y

x

y

DC

Jmmic w (24)

]'

'')

'

''

'

''()

'

'(*[

312

x

xJ

x

x

y

y

x

ymc w (25)

With the notation (26):

20

432

2

)()(*

DC

Jmmim (26)

2.2. Determining the movement equations

With the relations (19, 12, 25, 11) the equation (2) takes the forms (27, 28, 29, 30 and 31):

02 )(''' FyKxkKxcxM ww (27)

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17

03122

2221

225

2

)('

''')

'

''

'

''()

'

'(

*''')'

1('')

'

'(*''

FyKxkKx

xJx

x

x

y

y

x

y

mxxx

Jxx

ymmx

w

wwww

(28)

0

2

2222

5

2

)('

'''*

'')'

'(*)

'

'(''*''

FyKxkKx

yym

xx

ym

x

yxmxm

w

www

(29)

02

52

'

'''*)('' FyK

x

yymxkKxm ww (30)

052 )()

'

'''*''( FyKxkK

x

yymxm w (31)

The exact equation (31) can be approximated at the form (32) with x’y’:

052 )()''*''( FyKxkKymxm w (32)

With the following notations: y=s, y’=s’, y’’=s’’, y’’’=s’’’, the equation (32) takes the approximate form (33) and the complete equation (31) takes the exact form (34).

052 )()''*''( FsKxkKsmxm w (33)

052 )()

'

'''*''( FsKxkK

x

ssmxm w (34)

3. SOLVING THE DIFFERENTIAL EQUATION BY DIRECT

INTEGRATION AND OBTAINING THE MOTHER EQUATION

It integrates the equation (31) directly. It prepares the equation (31) for the integration. First, we write (31) in form (35):

I

IIITII

Sx

yymxmxkyKxkK

2*2*

0)(w

w (35)

The equation (35), can be amplified by x’ and obtains the relation (36):

III

T

III

S

III

yymxxm

xxkxyKxxkK

2*2*

0)(

ww (36)

Now, it replaces the term K.y.x’ with IykK

KyK

, (taken in calculation the statically

assumption, Fm=Fr) and it obtains the form (37):

III

T

III

S

III

yymxxm

xxkyykK

KxxkK

2*2*

0

2

)(

ww

(37)

It integrates directly the equation (37) and obtains the mother equation (38):

Page 18: Camshaft precision color petrescu

18

Cy

mx

m

xxky

kK

KxkK

TS

2

'

2

'

22)(

22*

22*

0

222

ww

(38)

With the initial condition, at the =0, y=y’=0 and x=x’=0, it obtains for the constant of integration, C the value 0. In this case the equation (38), takes the form (39):

2

'

2

'

22)(

22*

22*

0

222 ym

xmxxk

y

kK

KxkK TS

ww (39)

The equation (39) can be put in the form (40), if one divides it with the 2

kK :

0)(

''2 2

2

22

2*2

2*02

y

kK

Ky

kK

mx

kK

mx

kK

xkx TS ww

(40)

The mother equation (40), take the form (41), if one notes: '' ykK

Kx

, (the static

assumption, Fm=Fr).

0')(

)(

)(2 22

**

2

2

2

2

202

y

kK

mmkK

K

ykK

Kx

kK

xkx

TS

w (41)

3.1. Solving the mother equation (41) directly

The equation (41) is a two degree equation in x; One determines directly, (42-43) and X1,2 (44):

22

*

2

2*

2

220 '

)(

)(

)(

)()(w

y

kK

mkK

Km

kK

sKxkTS

(42)

22

*

2

2*

2

220 )'(

)(

)(

)(

)()(w

sD

kK

mkK

Km

kK

sKxkTS

(43)

kK

xkX 0

2,1 (44)

Physically, just the positive solution is valid (see the relation 45):

kK

xkX

0 (45)

3.2. Solving the mother equation (41) with finished differences

We can solve the mother equation (41) using the finished differences. We notes:

XsX (46)

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19

With the notation (46) placed in the mother equation (41), it obtains the equation (47):

0')(

)(

)(

222)(

22

**

2

2

2

2

2

0022

ykK

mmkK

K

skK

K

XkK

xks

kK

xksXXs

TS

w

(47)

The equation (47) is a two degree equation in X, which can be solved directly with (49)

and X1,2, (50), or transformed in a single degree equation in X, with (X)20, solved by the

relation (48).

20

22**2

0

22

)()(2

)'(])([)(2)2(

)1(

kKkK

xks

DsmkKmkK

KskKxksKkk

XTS

w (48)

2

22**2

20

222

)(

)'(])([

kK

sDmkKmkK

KxksK TS

w

(49)

)( 0

kK

xksX

(50)

CONCLUSION

The direct integration of the differential equation (31) generates the mother equation (41), which can be solved directly, with the relation (48). “D” represents the dynamic transmission function (the dynamic transmission coefficient).

REFERENCES

[1] Antonescu, P., Oprean, M., Petrescu, Fl., Analiza dinamică a mecanismelor de distribuţie cu came, In: The Proceedings of 7

th National Symposium on RIMS, MERO’87, Bucureşti, vol. 3, pp.

126-133, 1987. [2] Antonescu, P., Petrescu, Fl., Contributii la analiza cinetoelastodinamică a mecanismelor de distribuţie, In: The Proceedings of 5

th International Symposium on TMM, SYROM’89, Bucureşti, pp.

33-40, 1989. [3] Petrescu, F., Petrescu, R., Elemente de dinamica mecanismelor cu came, In: The Proceedings of 7

th National Symposium, PRASIC’02, Braşov, vol. I, pp. 327-332, 2002.

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CHAPTER III CAM GEARS DYNAMICS ILLUSTRATED

IN THE CLASSIC DISTRIBUTION

Abstract: The chapter presents an original method to determine the general dynamics of mechanisms with rotation cams and followers, particularized to the plate translated follower. First, it presents the dynamics kinematics. Then it solves the Lagrange equation and using an original dynamic model with one degree of freedom, with variable internal amortization, it makes the dynamic analysis. Keywords: cam dynamics, classic distribution, cams, followers, dynamics

1 Introduction

The chapter proposes an original dynamic model illustrated for the rotating cam with plate translate follower. It presents the dynamics kinematics (the original kinematics); the variable velocity of the camshaft obtained by an approximate method is used with an original dynamic system having one degree of freedom and a variable internal amortization [1]; it tests two movement laws, one classic and the other original.

2 Dynamics of the classic distribution mechanism 2.1 Precision kinematics in the classic distribution mechanism

In the picture number one, it presents the kinematic schema of the classic distribution mechanism, in two consecutive positions; with an interrupted line is represented the particular position when the follower is situated in the lowest possible plane, (s=0), and the cam which has a

clockwise rotation, with constant angular velocity, w, is situated in the point A0, (the fillet point between the base profile and the rise profile), a particular point that marks the beginning of the rise movement of the follower, imposed by the cam-profile; with a continue line is represented the higher joint in a certain position of the rise phase.

O

Ai

r0=s0

s

s’

rA

A0

1vr

2vr

12vr

B

C

D

A0i

w

Fig. 1 The kinematics of the classic distribution mechanism

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The point A0, which marks the initial higher pair, represents in the same time the contact point between the cam and the follower in the first position. The cam is rotating with the angular

velocity, w (the camshaft angular velocity), describing the angle , which shows how the base circle has rotated clockwise (together with the camshaft); this rotation can be seen on the base circle between the two particular points, A0 and A0i.

In this time the vector rA=OA (which represents the distance between the centre of cam O,

and the contact point A), has rotated anticlockwise with the angle . If one measures the angle , which positions the general vector, rA, in function of the particular vector, rA0, it obtains the relation (0):

(0)

where rA is the module of the vector Arr

, and A represents the phase angle of the vector Arr

.

The angular velocity of the vector Arr

is A which is a function of the angular velocity of the

camshaft, w, and of the angle (by the movement laws s(), s’(), s’’()).

The follower isn’t acted directly by the angle and the angular velocity w; it’s acted by the

vector Arr

, which has the module rA, the position angle A and the angular velocity A . From here

we deduce a particular (dynamic) kinematics, the classical kinematics being just static and approximate kinematics.

Kinematic, it defines the next velocities (Fig. 1).

1vr

=the cam’s velocity; which is the velocity of the vector Arr

, in the point A; now the classical

relation (1) becomes an approximate relation, and the real relation takes the form (2).

w.1 Arv (1)

AArv .1 (2)

The velocity ACv 1

r is separating into the velocity 2v

r=BC (the follower’s velocity which

acts on its axe, vertically) and 12vr

=AB (the slide velocity between the two profiles, the sliding

velocity between the cam and the follower, which works along the direction of the commune tangent line of the two profiles in the contact point).

Because usually the cam profile is synthesis for the classical module C with the AD=s’ known, we can write the relations:

22

0

2 ')( ssrrA (3)

22

0 ')( ssrrA (4)

22

0

00

')(cos

ssr

sr

r

sr

A

(5)

22

0 ')(

''sin

ssr

s

r

s

r

AD

AA (6)

A

A

AA sr

srvv '.

'..sin.12 (7)

Now, the follower’s velocity isn’t s ( w '2 ssv ), but it’s given by the relation (9). In the

case of the classical distribution mechanism the transmitting function D is given by the relations (8):

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22

w

w

A

A

D

D

.

(8)

w .'.'.2 Dssv A (9)

The determining of the sliding velocity between the profiles is made with the relation (10):

A

A

AA srr

srrvv ).(..cos. 0

0

112

(10)

The angles and A will be determined, and also their first and second derivatives.

The angle has been determined from the triangle ODAi (Fig.1) with the relations (11-13):

22

0 ')(

'sin

ssr

s

(11)

22

0

0

')(cos

ssr

sr

(12)

sr

stg

0

' (13)

It derives (11) in function of angle and obtains (14):

22

0

0

')(

'''.').('.'.'

cos'.ssr

r

ssssrsrs

A

A

(14)

The relation (14) will be written in the form (15):

22

0

22

0

2

0

222

0

')(].')[(

''.').('''.')'.('cos'.

ssrssr

sssrssssrs

(15)

From the relation (12) it extracts the value of cos, which will be introduced in the left term of the expression (15); then we can reduce s’’.s’2 from the right term of the expression (15) and it obtains the relation (16):

22

0

22

0

2

00

22

0

0

')(].')[(

]')'.(').[(

')('.

ssrssr

ssrssr

ssr

sr

(16)

After some simplifications the relation (17), which represents the expression of ’, is finally obtained:

22

0

2

0

')(

')'.(''

ssr

ssrs

(17)

Now when ’ has been explicitly deduced, the next derivatives can be determined. The expression (17) will be derived directly and it obtains for the beginning the relation (18):

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23

222

0

0

2

0

22

00

]')[(

]'''')][(')(''[2]')][('''2''')('''[''

ssr

ssssrssrsssrsssssrs

(18)

The terms from the first bracket of the numerator (s’.s’’) are reduced, and then it draws out s’ from the fourth bracket of the numerator and obtains the expression (19):

222

0

0

2

0

22

00

]')[(

]''].[')'.(''.[.2]')].[('''.)'.(''[''

ssr

ssrssrssssrsssrs

(19)

Now we can calculate A, with its first two derivatives, A and A

. We will write instead of

A, to simplify the notation. It determines the relation (20) which is the same of (0):

(20)

We derive the relation (20) and one obtains the expression (21):

wwww .)'1.('. D (21)

It derives twice (20), or derives (21) and obtains (22):

22 ''' ww D (22)

We can write now the transmission functions, D and D’ (for the classical module, C), in the forms (23-24):

1'D (23)

''ID (24)

To calculate the follower’s velocity (25) we need the expression of the transmission function, D.

DsDssswsv A w ''''2 (25)

Where:

w.Dw (26)

For the classical distribution mechanism (Module C), the variable w is the same as A (see

the relation 25).

But in the case of B and F modules (at the cam gears where the follower has a roll), the transmitted function D and w take complex forms.

We can determine now the acceleration of the follower (27).

2

2 )''''( w DsDsay (27)

Figure 2 represents the classical and dynamic kinematics; the velocities (a), and the accelerations (b).

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24

-4

-3

-2

-1

0

1

2

3

4

0 50 100 150 200

Vclasic[m/s]

Vprecis[m/s]

Fig. 2a The classical and dynamic kinematics; velocities of the follower

-4000

-3000

-2000

-1000

0

1000

2000

3000

4000

5000

0 50 100 150 200

a2clasic[m/s2]

a2precis[m/s2]

Fig. 2b The classical and dynamic kinematics; accelerations of the follower

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25

To determine the acceleration of the follower, s’ and s’’, D and D’, ’ and ’’ are necessary be known.

The dynamic kinematics diagrams of v2 (obtained with relation 25, see Fig. 2a), and a2 (obtained with relation 27, see Fig. 2b), have a more dynamic aspect than one kinematic (classic).

It has used the movement law SIN, a rotational speed of the crankshaft n=5500 rpm, a rise

angle u=750, a fall angle d=750 (identically with the ascendant angle), a ray of the basic circle of the cam, r0=17 mm and a maxim stroke of the follower, hT=6 mm.

Anyway, the dynamics is more complex, having in view the masses and the inertia moments, the resistant and motor forces, the elasticity constants and the amortization coefficient of the kinematic chain, the inertia forces of the system, the angular velocity of the camshaft and

the variation of the camshaft’s angular velocity, w, with the cam’s position, , and with the rotational speed of the crankshaft, n.

2.2 Solving approximately the Lagrange movement equation

In the kinematics and the static forces study of the mechanisms one considers the shaft’s

angular velocity constant, w =constant, and the angular acceleration null, 0 w . In

reality, this angular velocity w isn’t constant, it is variable with the camshaft position, .

In mechanisms with cam and follower the camshaft’s angular velocity is variable as well.We shall see further the Lagrange equation, written in the differentiate mode and its general solution.The differentiate Lagrange equation has the form (28):

*2** ..

2

1. MJJ I (28)

Where J* is the mechanical inertia moment (mass moment, or mechanic moment) of the mechanism, reduced at the crank, and M* represents the difference between the motor moment

reduced at the crank and the resistant moment reduced at the crank; the angle represents the rotation angle of the crank (crankshaft). J*I represents the derivative of the mechanic moment in

function of the rotation angle of the crank (29).

Ld

dJJ I

** .

2

1.

2

1 (29)

Using the notation (29), the equation (28) will be written in the form (30):

*2* .. MLJ (30)

We divide the terms by J* and (30) takes the form (31):

*

*2

*.

J

M

J

L (31)

The term with 2 will be moved to the right side of the equation and the form (32) will be

obtained:

2

**

*

. J

L

J

M (32)

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26

Replacing the left term of the expression (32) with (33) we obtain the relation (34):

w

w

...

d

d

d

d

dt

d

d

d

dt

d

(33)

*

2*2

**

* ...

J

LM

J

L

J

M

d

d ww

ww

(34)

Because, for an angle , w is different from the nominal constant value wn, it can write the

relation (35), where dw represents the momentary variation for the angle ; the variable dw and

the constant wn lead us to the needed variable, w:

www dn (35)

In the relation (35), w and dw are functions of the angle , and wn is a constant parameter, which can take different values in function of the rotational speed of the drive-shaft, n. At a

moment, n is a constant and wn is a constant as well (because wn is a function of n). The angular

velocity, w, becomes a function of n too (see the relation 36):

))(,()(),( ndnn nn wwww (36)

With (35) in (34), it obtains the equation (37):

wwwww ddJ

L

J

Mdd nn ].).([).( 2

**

*

(37)

The relation (37) takes the form (38):

]..2)(.[..)(. 22

**

*2 wwwwwww ddd

J

Ld

J

Mdd nnn (38)

The equation (38) will be written in the form (39):

0....2).(.

...)(.

*

2

*

2

**

*2

www

wwww

ddJ

Ldd

J

L

dJ

Ld

J

Mdd

n

nn

(39)

The relation (39) takes the form (40):

0)...(

.).2

1..(2)).(1.(

2

**

*

*

2

*

n

n

dJ

Ld

J

M

ddJ

Ldd

J

L

w

www

(40)

The relation (40) is an equation of the second degree in dw. The discriminate of the equation (40) can be written in the forms (41) and (42):

2

*

22

2*

2

*

*

2

2*

*2

*

222

2*

2

...).(.

).(.

..4

.).(

nn

nn

n

dJ

Ld

J

Ld

J

M

dJ

MLd

J

Ld

J

L

ww

ww

w

(41)

w

dJ

Md

J

MLn .).(.

4 *

*2

2*

*2

(42)

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27

We keep for dw just the positive solution, which can generate positives and negatives

normal values (43), and in this mode only normal values will be obtained for w; for 0 it

considers dw=0 (this case must be not seeing if the equation is correct).

1.

2..

*

*

ww

w

dJ

L

dJ

L

d

n

n

(43)

Observations: For mechanisms with rotate cam and follower, using the new relations, with M* (the reduced moment of the mechanism) obtained by the writing of the known reduced resistant moment and by the determination of the reduced motor moment by the integration of the resistant

moment it frequently obtains some bigger values for dw, or zones with negative, with complex

solutions for dw. This fact gives us the obligation to reconsider the method to determine the reduced moment.

If we take into consideration M*r and M*m, calculated independently (without integration), it

obtains for the mechanisms with cam and follower normal values for dw, and 0 .

In paper [1] it presents the relations to determine the resistant force (44) reduced to the valve, and the motor force (45) reduced to the ax of the valve:

).( 0

* xxkFr (44)

).(* xyKFm (45)

The reduced resistant moment (46), or the reduced motor moment (47), can be obtained by the resistant or motor force multiplied by the reduced velocity, x’.

')..( 0

* xxxkM r (46)

')..(* xxyKM m (47)

2.3 The dynamic relations used

The dynamics relations used (48-49), have been deduced in the paper [1]:

20

22**2

022

)()(2

)'(])([)(2)2(

)1(

kKkK

xks

DsmkKmkK

KskKxksKkk

XTS

w (48)

20

0

22

20

22**2

)()(2

)(2)2(

)()(2

)'(])([

kKkK

xks

skKxksKkk

kKkK

xks

DsmkKmkK

K

sXTS

w

(49)

2.4 The dynamic analysis

The dynamic analysis or the classical movement law sin, can be seen in the diagram from figure 3, and in figure 4 one can see the diagram of an original movement law (C4P) (module C).

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28

-2000

-1000

0

1000

2000

3000

4000

5000

6000

0 50 100 150 200

a[m/s2]

673.05s*k[mm] k=

n=5000[rot/min]

u=75 [grad]

k=20 [N/mm]

r0=14 [mm]

x0=40 [mm]

hs=6 [mm]

hT=6 [mm]

i=1;=8.9%

legea: sin-0

y=x-sin(2x)/(2)

Analiza dinamicã la cama rotativã cu tachet

translant plat - A10amax=4900

s max =5.78

amin= -1400

Fig. 3 The dynamic analysis of the law sin, Module C, u=750,

n=5000 rpm

-10000

0

10000

20000

30000

40000

50000

0 20 40 60 80 100a[m/s2]

7531.65s*k[mm] k=

n=10000[rot/min]

u=45 [grad]

k=200 [N/mm]

r0=17 [mm]

x0=50 [mm]

hs=6 [mm]

hT=6 [mm]

i=1;=15.7%

legea:C4P1-1

y=2x-x2

yc=1-x2

Analiza dinamicã la cama rotativã cu tachet

translant plat - A10

amax=39000

s max =4.10

amin= -8000

Fig. 4 The dynamic analysis of the new law, C4P, Module C, u=450,

n=10000 rpm

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29

-40000

-20000

0

20000

40000

60000

80000

100000

120000

0 50 100 150 200

a[m/s2]

19963,94s*k[mm] k=

n=40000[rot/min]

u=80 [grad]

k=400 [N/mm]

r0=13 [mm]

x0=150 [mm]

hs=10 [mm]

hT=10 [mm]

i=1;=12.7%

rb=2 [mm]

e=0 [mm]

legea: C4P1-5

y=2x-x2

Analiza dinamicã la cama rotativã cu tachet

translant cu rolã

amax=97000

smax=3.88

amin= -33000

Fig. 5 Law C4P1-5, Module B, u=800, n=40000 rpm

-60000

-40000

-20000

0

20000

40000

60000

80000

100000

0 50 100 150 200

a[m/s2]

15044,81s*k[mm] k=

n=40000[rot/min]

u=85 [grad]

k=800 [N/mm]

r0=10 [mm]

rb=3 [mm]

b=30 [mm]

d=30 [mm]

x0=200 [mm]

i=1;=16.5%

legea: C4P3-2

y=2x-x2

yc=1-x2

Analiza dinamicã la cama rotativã cu tachet

balansier cu rolã (Modul F) - A12amax=80600

s max=4.28

amin= -40600

hT=15.70 [mm]

Fig. 6 Law C4P3-2, Module F, u=850, n=40000 rpm

3 Conclusions

Using the classical movement laws, the dynamics of the distribution cam-gears depreciate rapidly at the increasing of the rotational speed of the shaft. To support a high rotational speed it is necessary the synthesis of the cam-profile by new movement laws, and for the new Modules.

A new and original movement law is presented in the pictures number 4, 5 and 6; it allows the increase of the rotational speed to the values: 10000-20000 rpm, in the classical module C presented (Fig. 4). With others modules (B, F) it can obtain 30000-40000 rpm (see Figs. 5, 6).

References

[1] Petrescu F.I., Petrescu R.V., Contributions at the dynamics of cams. In the Ninth IFToMM International Sympozium on Theory of Machines and Mechanisms, SYROM 2005, Bucharest, Romania, Vol. I, pp. 123-128, 2005.

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30

CHAPTER IV

CAM GEARS DYNAMICS TO THE MODULE B (WITH TRANSLATED FOLLOWER WITH ROLL)

Abstract: The chapter briefly presents an original method for determining the dynamics of mechanisms with rotation cam and translated follower with roll. First, one presents the dynamics kinematics. Then one performs the dynamic analysis of a few models, for some movement laws, imposed on the follower, by the designed cam profile. Keywords: cam dynamics, translated follower with roll, movement laws, dynamics kinematic

1 Introduction

The chapter proposes an original dynamic model of the cam gear with a translated follower with a roll. First, one presents the dynamics kinematics. Then one performs the dynamic analysis of a few models, for some movement laws, imposed on the follower, by the designed cam profile.

2 The dynamics of distribution mechanisms with translated follower with roll 2.1 Generalities

The angle 0 defines the basic position of the vector, 0Br , in the OCB0 triangle having a

right angle (1-4):

bB rrr 00 (1)

22

0 0ers B (2)

0

0cosBr

e (3)

0

0

0sinBr

s (4)

The pressure angle, , between the normal n (which passes through the contact point A) and a vertical line, can be calculated with relations (5-7).

22

0

0

)'()(cos

esss

ss

(5)

22

0 )'()(

'sin

esss

es

(6)

ss

estg

0

' (7)

The vector Ar can be determined with relations (8-9):

2

0

22 )cos()sin( bbA rssrer (8)

2

0

2 )cos()sin( bbA rssrer (9)

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31

0A

A

B

A-

Fn, vn

Fm, vm

Fa, va

Fi, viFn, vn

Fu, v2

B

B0

A0

A

O

x

e

s0

rb

r0

rA

rB

s

n

C

rb

Fig. 1 Mechanism with rotating cam and translating follower with roll

We can calculate A (10-11):

A

b

Ar

re

sincos

(10)

A

b

Ar

rss

cossin 0

(11)

2.2 The relations to design the profile

0 A (12)

00 sinsincoscoscos AA (13)

00 sincoscossinsin AA (14)

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32

A (15)

sinsincoscoscos A (16)

cossincossinsin A (17)

2.3 The exact kinematics of B Module

From the triangle OCB (fig. 1) the length rB (OB) and the complementary angles B (COB)

and (CBO) are determined.

2

0

22 )( sserB (18)

2

BB rr (19)

B

Br

e sincos (20)

B

Br

ss 0cossin (21)

From the general triangle OAB, where one knows OB, AB, and the angle between them, B

(ABO, which is the sum of and ), the length OA and the angle (AOB) can be determined:

sinsincoscos)cos( (22)

)cos(2222 BbbBA rrrrr (23)

BA

bBA

rr

rrr

2cos

222

(24)

cossincossin)sin( (25)

)sin(sin A

b

r

r (26)

With B and we can deduce now A and A :

BA (27)

BA (28)

From (20) one obtains B (32), (see 29-32) where Br (31) can be deduced from (18). Then, (33)

will be obtained from (24):

2

sinB

B

BBr

re

(29)

2

0 )( B

BB

Brss

rre

(30)

sssrrsssrr BBBB )()(22 00 (31)

22

0

0

)(

)(

BB

Br

se

rss

ssse

(32)

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33

BBAABA

BABA

rrrrrr

rrrr

22sin2

cos2cos2

(33)

From (33) one writes (38), but it is necessary to obtain first Ar (34) from expression

(23):

)()sin(2

)cos(222

Bb

BbBBAA

rr

rrrrrr (34)

To solve (34) we need the derivatives and . From (7) relations (35 and 36) will be

obtained. takes the form (37):

22

0

0

)'()(

)'(')('''

esss

essess

(35) w ' (36)

2

B

Br

se

(37)

Now we can determine (38), A (28) and A (39):

sin

coscos

BA

BBAABABA

rr

rrrrrrrr (38)

AA w (39)

We write cos A and sin A (40-41):

22

0

22

0

)'()(

)'()'()(cos

esssr

esressse

A

b

A

(40)

22

0

22

00

)'()(

])'()([)(sin

esssr

resssss

A

b

A

(41)

Further, we can obtain expression cos(A-) (42), and cos(A-).cos (43):

cos'

)'()(

')()cos(

22

0

0

AA

Ar

s

esssr

sss (42)

2cos'

cos)cos( A

Ar

s (43)

Finally the forces and the velocities are deduced as follows (48-50):

)sin(

)sin(

Ama

Ama

FF

vv

(44)

)cos(

)cos(

Amn

Amn

FF

vv

(45)

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34

sin

sin

ni

ni

FF

vv

(46)

cos)cos(cos

cos)cos(cos2

Amnu

Amn

FFF

vvv

(47)

2.4 Determining the efficiency of the Module B

22

2 cos)(cos Ammuu vFvFP (48)

mmc vFP (49)

4

2

222

222

22

cos'

]cos'

[

]cos)[cos(cos)(cos

cos)(cos

AA

AA

mm

Amm

c

ui

r

s

r

s

vF

vF

P

P

(50)

2.5 Determining the transmission function D, for the Module B

The follower’s velocity (47) can be written into the form (51):

w

222

2

2

cos'cos'cos'

cos'

cos)cos(cos

ssr

sr

r

svvvv

I

AA

A

AA

A

mAmn

(51)

With relations (51) and (52) we determine the transmission function (the dynamic modulus), D (53):

w Dsv '2 (52)

2cos I

AD (53)

Expression cos2 is known (54):

22

0

2

02

)'()(

)(cos

esss

ss

(54)

The expression of the ’A is more difficult (55):

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35

]}')[(2)'()(

])/{[(])'()[(

/]})'()()'(')(''[

)'()(])'(){[(

])'()(')[(

22

0

22

0

222

0

22

0

22

00

22

0

22

0

22

0

22

0

seessresss

ressesss

esssesssssr

esssesss

esssrseess

b

b

b

b

I

A

(55)

We will determine by its expressions (56-57):

22

0

22

0

22

0

22

0

)'()(

]')[()'()(])[(cos

esssrr

seessresssess

BA

b

(56)

22

0

0

)'()(

')(sin

esssrr

sssr

BA

b

(57)

2.6 The dynamics of the Module B

For the dynamics of the Module B the relations (58-60) are used:

][2

'

])(

[2

)(

2

0

2

2**

2

2

02

2

2

kK

kxs

ykK

mmkK

K

skK

kxs

kK

kKk

X

TS

w

(58)

][2

)'(

])(

[2

)(

2

0

2

2**

2

2

02

2

2

kK

kxs

sDkK

mmkK

K

skK

kxs

kK

kKk

X

TS

w

(59)

XsX (60)

2.7 The dynamic analysis of the module B

It presents now the dynamics of the module B for some known movement laws.

We begin with the classical law SIN (see the diagram in figure 2); A speed rotation n=5500 [rot/min], for a maxim theoretical displacement of the valve h=6 [mm] is used. The phase angle is

u=c=65 [degree]; the ray of the basic circle is r0=13 [mm].

For the ray of the roll the value rb=13 [mm] has been adopted.

Page 36: Camshaft precision color petrescu

36

-4000

-2000

0

2000

4000

6000

8000

0 50 100 150

a[m/s2]

880.53s*k[mm] k=

n=5500[rot/min]

u=65 [grad]

k=30 [N/mm]

r0=13 [mm]

x0=20 [mm]

hs=6 [mm]

hT=6 [mm]

i=1;=11.5%

rb=13 [mm]

e=6 [mm]

legea: sin-0

y=x-sin(2x)/(2)

Analiza dinamicã la cama rotativã cu tachet

translant cu rolãamax=6400

smax=5.81

amin= -3000

Fig. 2 The dynamic analysis of the module B. The law SIN, n=550 rpm, u=650,

r0=13 [mm], rb=13 [mm], hT=6 [mm], e=0 [mm],k=30 [N/mm], and x0=20 [mm].

-15

-10

-5

0

5

10

15

20

-20 -10 0 10 20

yC [mm]

PROFIL Camã rotativã cu tachet translant cu rolã

u= 65[grad]

c= 65[grad]

r0= 13[mm]

rb = 13[mm]

e= 6[mm]

hT= 6[mm]

Legea SIN

Suportã o turatie n=5500[rot/min]

w

Fig. 3 The profile SIN at the module B. n=5500 rpm

u=650, r0=13 [mm], rb=13 [mm], hT=6 [mm].

Page 37: Camshaft precision color petrescu

37

The dynamics are better than for the classical module C. For a phase angle of just 65 degrees the accelerations have the same values as for the classical module C for a relaxed phase (750-800).

In figure 3 we can see the cam’s profile. It uses the profile sin, a rotation speed n=5500

rpm, and u=650, r0=13 [mm], rb=13 [mm], hT=6 [mm].

The law COS can be seen in figures 4 and 5.

In the figure 4 is presented the dynamic analyze of the profile cos, and its profile design can be seen in the figure 5.

The principal parameters are:

Law COS, n=5500 rpm, u=650, r0=13 [mm], rb=6 [mm], hT=6 [mm], =10.5%.

-3000

-2000

-1000

0

1000

2000

3000

4000

5000

0 50 100 150

a[m/s2]

601.01s*k[mm] k=

n=5500[rot/min]

u=65 [grad]

k=30 [N/mm]

r0=13 [mm]

x0=30 [mm]

hs=6 [mm]

hT=6 [mm]

i=1;=10.5%

rb=6 [mm]

e=0 [mm]

legea: cos-0

y=.5-.5cos(x)

Analiza dinamicã la cama rotativã cu tachet

translant cu rolãamax=4300

smax=5.74

amin= -2000

Fig. 4 The dynamic analysis of the module B. Law COS, n=5500 rpm, u=650, r0=13 [mm], rb=6

[mm], hT=6 [mm], =10.5%.

-15

-10

-5

0

5

10

15

20

-20 -10 0 10 20

yC [mm]

PROFIL Camã rotativã cu tachet translant cu rolã

u= 65[grad]

c= 65[grad]

r0= 13[mm]

rb = 6[mm]

e= 0[mm]

hT= 6[mm]

Legea COS

Suportã o turatie n=5500[rot/min]

w

Fig. 5 The profile COS at the module B, n=5500 rpm, u=650, r0=13 [mm], rb=6 [mm], hT=6 [mm].

Page 38: Camshaft precision color petrescu

38

-2000

0

2000

4000

6000

8000

10000

12000

14000

0 50 100 150 200 a[m/s2]

1896.75s*k[mm] k=

n=5500[rot/min]

u=80 [grad]

k=50 [N/mm]

r0=13 [mm]

x0=50 [mm]

hs=6 [mm]

hT=6 [mm]

i=1;=8.6%

rb=6 [mm]

e=0 [mm]

legea: C4P1-0

y=2x-x2

Analiza dinamicã la cama rotativã cu tachet

translant cu rolãamax=13000

smax=5.37

amin= -600

Fig. 6 The dynamic analyze. Law C4P1-0, n=5500 rpm, u=800, r0=13 [mm], rb=6 [mm], hT=6 [mm].

In figure 6 the law C4P, created by the authors, is analyzed dynamic. The vibrations are diminished, the noises are limited, the effective displacement of the valve is increased, smax=5.37 [mm].

-20

-15

-10

-5

0

5

10

15

20

25

-20 -10 0 10 20

yC [mm]

PROFIL Camã rotativã cu tachet translant cu rolã

u= 80[grad]

c= 80[grad]

r0= 13[mm]

rb = 3[mm]

e= 0[mm]

hT= 6[mm]

Legea C4P1-0

Suportã o turatie n=5500[rot/min]

w

Fig. 7 The profile C4P of the module B.

The efficiency has a good value =8.6%. In figure 7 the profile of C4P law is presented. It starts at the law C4P with n=5500 [rpm], but for this law the rotation velocity can increase to high values of 30000-40000 [rpm] (see Fig. 8).

Page 39: Camshaft precision color petrescu

39

-40000

-20000

0

20000

40000

60000

80000

100000

120000

0 50 100 150 200

a[m/s2]

19371.43s*k[mm] k=

n=40000[rot/min]

u=80 [grad]

k=400 [N/mm]

r0=13 [mm]

x0=150 [mm]

hs=10 [mm]

hT=10 [mm]

i=1;=14.4%

rb=6 [mm]

e=0 [mm]

legea: C4P1-5

y=2x-x2

Analiza dinamicã la cama rotativã cu tachet

translant cu rolã

amax=94000

smax=3.88

amin= -33000

Fig. 8 The dynamic analysis of the module B. Law C4P1-5, n=40000 rpm.

3 Conclusions

We can speak about an advantage of the module B in comparison to the classical module C. With the module B, (when the follower is provided with a roll) it can obtain high rotation velocity with superior efficiency.

References

[1] Petrescu F.I., Petrescu R.V., Contributions at the dynamics of cams. In the Ninth IFToMM International Sympozium on Theory of Machines and Mechanisms, SYROM 2005, Bucharest, Romania, Vol. I, pp. 123-128, 2005.

Page 40: Camshaft precision color petrescu

40

CHAPTER V DYNAMICS OF THE CLASSIC DISTRIBUTION

Abstract: This chapter presents an original methods to determine the dynamic parameters at the camshaft (the distribution mechanisms). We determine initially the mass moment of inertia (mechanical) of the mechanism, reduced to the element of rotation, ie at cam (basically using kinetic energy conservation, the system 1). Average moment of inertia is calculated with equation (2). The expression (2) depends on the type of cam-tappet mechanism, and of the law of motion used both uphill and downhill. The angular velocity

is a function of the position cam () but also of its speed (3). To determine ω2 (relationship 3) have found J *,

and more specifically Jmax. Differentiating the formula (6), against time, is obtained the angular

acceleration expression (8). Differentiating twice successively, the expression (9) in the angle , we obtain a reduced tappet speed (equation 10), and reduced tappet acceleration (11). The real and dynamic, tappet acceleration can be determined directly using the relation (12). General (original) dynamic equations of

motion for the determination of ω and have the form (13).

Keywords: cam, cams, cam mechanisms, distribution mechanisms, camshaft, tappet.

We determine initially the mass moment of inertia (mechanical) of the mechanism, reduced to the element of rotation, ie at cam (basically using kinetic energy conservation, the system 1).

22

0

2

var

tan

*

22

0

22

0

*

222

0

*

22

0

22

0

2

2

''2

1

2

1

''2

1

2

1

2

1

''2

1

'2

1

'

2

1

smsMsRMsMJJ

JJJ

smsMsRMsMRMJ

smssRMJ

ssRMJ

ssRR

RMJ

Tccciabil

tcons

Tcccc

Tc

ccama

ccama

(1)

Average moment of inertia is calculated with equation (2).

22

1

2

max2

0

*

max

*

min* JRM

JJJ cm

(2)

The expression (2) depends on the type of cam-tappet mechanism, and of the law of

motion used both uphill and downhill. The angular velocity is a function of the position cam () but also of its speed (3).

Page 41: Camshaft precision color petrescu

41

*

2*2

J

J mm ww

(3)

O

A

r0

s

s’

rA

1vr

2vr

12vr

B

C

D

w

Fr mF

rcFr F

E

Fig. 1 Forces and speeds to the cam with plate translated follower

To determine ω2 (relationship 3) have found J *, and more specifically Jmax.

And at the classic distribution (rotative cam, and plat tappet in translational motion), the relationship which determine the Jmax, depend and of the law of movement.

We start the simulation with a classical law of motion, namely the cosine law. At the climb, the cosine law is expressed by relations (4).

uu

r

uu

r

uu

r

u

hs

has

hvs

hhs

sin2

'''

cos2

''

sin2

'

cos22

3

3

2

2 (4)

Where varies from 0 to u. It achieves Jmax for =u/2.

Page 42: Camshaft precision color petrescu

42

2

22

2

22

0

2

max48

1

28 u

T

u

c

hm

hhR

hMJ

(5)

The expression (3) now takes the form (6).

B

A

smsMsRMsMRMB

hm

hM

hRMh

MRMA

B

A

m

Tcccc

u

T

u

c

ccc

m

ww

ww

22

0

22

0

2

22

2

22

0

22

0

22

'2'2

4

1

8

1

2

1

8

(6)

Where ωm is the nominal cam velocity and it express at the distribution mechanisms, based on the speed shaft, with relationship (7).

60260

2

6022

nnn motorccm

w (7)

Differentiating the formula (6), against time, is obtained the angular acceleration expression (8).

B

ssmsMRMsM Tccc '''2''02 w (8)

For a classic cam and tappet mechanism (without valve) dynamic movement tappet is expressed by equation (9), who was presented and derived in Chapter 2 (equation 48), and now by canceling valve mass, will customize and reaching form below (9).

kK

xkskK

skKxksKkksmkKsx T

02

0

2222

)(2

)(2)2(')( w (9)

Where x is the dynamic movement of the pusher, while s is its normal, kinematics movement. K is the spring constant of the system, and k is the spring constant of the tappet spring. It note, with x0 the tappet spring preload, with mT the mass of the tappet, with ω the angular

rotation speed of the cam (or camshaft), where s’ is the first derivative in function of of the tappet

movement, s. Differentiating twice successively, the expression (9) in the angle , we obtain a reduced tappet speed (equation 10), and reduced tappet acceleration (11).

Page 43: Camshaft precision color petrescu

43

2

02

0

0

22

0

2222

2

''

'

'2'22'''2

)(2)2(')(

kK

kxskK

Msx

sNkK

kxs

skKkxsskKkssmkKM

skKxksKkksmkKN

T

T

w

w

(10)

3

02

00

0

22

22

0

0

22

0

2222

2

'2''

''''

''2'''22

''''''2

'

'2'22'''2

)(2)2(')(

kK

kxskK

sMkK

kxssN

kK

kxsO

sx

skKxksssKkk

sssmkKO

sNkK

kxs

skKkxsskKkssmkKM

skKxksKkksmkKN

T

T

T

w

w

w

(11)

The real and dynamic, tappet acceleration can be determined directly using the relation (12).

w ''' 2 xxx (12)

General (original) dynamic equations of motion for the determination of ω and have the form (13).

*

*'2

*

*2

*

*2

2

1

;

J

J

J

J

J

Jm

mm

m

w

wwww

(13)

With a program (written in excel) one obtains the diagrams of the movement laws (see the Figure 2), the dynamic tappet acceleration for a n=5500 [rpm] (Fig. 3), and the cam profile (Fig. 4).

Page 44: Camshaft precision color petrescu

44

Fig. 2 s, s’, s’’ diagrams at the cam with plate translated follower

Fig. 3 The dynamic tappet acceleration at the cam with plate translated follower

The profile synthesis was made with the system of relations (14) when the cam is moving in the orar sense, and (15) when the cam is rotating trigonometric.

Page 45: Camshaft precision color petrescu

45

sin'cos)(

sin)(cos'

0

0

ssry

srsx

c

c (14)

sin'cos)(

sin)(cos'

0

0

ssry

srsx

c

c (15)

Fig. 4 The cam profile, at the cam with plate translated follower

Page 46: Camshaft precision color petrescu

46

CHAPTER VI PRECISION OF THE CLASSIC DISTRIBUTION

Abstract: This chapter presents an original methods to determine the dynamic parameters at the camshaft (the distribution mechanisms), when the cam was made to work normally. We can make the geometrical synthesis of the cam profile with the help of the cinematics of the mechanism. One uses as well the reduced speed, s’. The reduced velocity, s’, folded to 90 degrees, completes the triangle OAB. We can determine the coordinates of the point A from the tappet (1), and from the cam (2). The forces and the velocities at a cam with plate translated tappet can be seen in the figure 2. The driving force Fm, perpendicular on the r in A, is decomposed in two forces: the utile force Fu, which acts the tappet and the lost force Fa, who is a slipping force. The velocities take the same positions (system 4). The efficiency of the mechanism is determining with the relationship (5). We can make the geometro-kinematics synthesis of the cam profile with the help of the cinematics of the mechanism (see the Figure 3). Now, we can make the geometro-kinematics synthesis of the classic cam profile (system 7). The moments of inertia is determined with the relationships from the

system 8. The angular velocity w, and the angular acceleration, are determined with the presented relationships (system 9). For a classic cam and tappet mechanism (without valve) dynamic movement tappet is expressed by equation (10), who was presented and derived in Chapter 2 (equation 48), and now by canceling valve mass, will customize and reaching form below (10). Where x is the dynamic movement of the pusher, while s is its normal, kinematics movement. K is the spring constant of the system, and k is the spring constant of the tappet spring. It note, with x0 the tappet spring preload, with mT the mass of the tappet, with ω the angular rotation speed of the cam (or camshaft), where s’ is the first derivative in function

of of the tappet movement, s. Differentiating twice successively, the expression (10) in the angle , we obtain a reduced tappet speed (equation 11), and reduced tappet acceleration (12). The real and dynamic, tappet acceleration can be determined directly using the relation (13). The presented dynamic system has the advantage to has a normal functionality. The synthesis was made using the natural geometro-kinematics parameters (of cam mechanism).

Keywords: cam, cams, cam mechanisms, distribution mechanisms, camshaft, tappet.

1. Geometrical synthesis of the cam profile

We can make the geometrical synthesis of the cam profile with the help of the cinematics of the mechanism. One uses as well the reduced speed, s’. The reduced velocity, s’, folded to 90 degrees, completes the triangle OAB (see the Figure 1).

OB=r0+s; BA=s’; OA=r=rA; r2=rA2=(r0+s)2+s’2

It establishes a system fixed Cartesian, xOy = xfOyf, and a mobil Cartesian system, xOy = xmOym fixed with the cam.

From the lower position 0, the tappet, pushed by cam, uplifts to a general position, when

the cam rotates with the angle. The contact point A, go from Ai0 to A0 (on the cam), and to A (on

the tappet). The position angle of the point A from the tappet is f, and from the cam is m. We can determine the coordinates of the point A from the tappet (1), and from the cam (2).

fA

f

AT

fA

f

AT

rsryy

rsxx

sin

cos'

0

(1)

Page 47: Camshaft precision color petrescu

47

sin'cossincos

cossincossinsinsin

sincos'sincos

sinsincoscoscoscos

0

0

ssrxy

rrrryy

srsyx

rrrrxx

TT

fffmA

m

Ac

TT

fffmA

m

Ac

(2)

PA0

iA0A

O

Arr

fx

0r

f

0r0r

s

's

fy

mx

w

cam

tappet 0P

0

m

A

A

A

fm

r

s

r

sr

ssrr

'sin

cos

')(

0

22

0

2

fA

f

AT

fA

f

AT

rsryy

rsxx

sin

cos'

0

fffmA

m

Ac

fffmA

m

Ac

rrrryy

rrrrxx

cossincossinsinsin

sinsincoscoscoscos

sin'cossincos

sincos'sincos

0

0

ssrxyyy

srsyxxx

TT

m

Ac

TT

m

Ac

B

Fig. 1 Geometry of the cam with plate translated follower

Page 48: Camshaft precision color petrescu

48

One uses the relationships (3).

A

A

A

fm

r

s

r

sr

ssrr

'sin

cos

')(

0

22

0

2

(3)

Now, we shall see the forces, the powers and the efficiency.

2. The efficiency of the cam

The forces and the velocities at a cam with plate translated tappet can be seen in the figure 2.

PA0

iA0A

O

Arr

fx

0r

f

0r0r

s

's

fy

mx

w

TTu vFF ,

0

m

mm vF ,

vFFa ,

Fig. 2 Forces and velocities of the cam with plate translated follower

Page 49: Camshaft precision color petrescu

49

The driving force Fm, perpendicular on the r in A, is decomposed in two forces: the utile force Fu, which acts the tappet and the lost force Fa, who is a slipping force. The velocities take the same positions (system 4).

cos;sin

cos;sin

mamu

mamu

vvvv

FFFF (4)

The efficiency of the mechanism is determining with the relationship (5).

22 cossinsinsin

mm

mm

mm

uu

c

ui

vF

vF

vF

vF

P

P (5)

3. Geometro-kinematics synthesis of the cam profile

We can make the geometro-kinematics synthesis of the cam profile with the help of the cinematics of the mechanism (see the Figure 3).

A

0

iA0A

O

r

fx

0r

f

0r0r

s

ar

fy

mx

w

svT

0

m

mv

aa rv

B

Fig. 3 Geometro-kinematics synthesis of the cam with plate translated follower

Page 50: Camshaft precision color petrescu

50

We denote the distance BA with ra. We can write the relationships (6).

sr

ssrtg

ssrr

ssr

ssrr

sr

ssrrr

ssrrssrrssrr

dssrdrrdr

ds

sr

r

dr

ds

dt

drdt

ds

r

s

sr

r

aaa

aa

a

a

aaa

a

0

2

0

2

0

2

0

2

0

2

0

2

0

0

2

0

2

0

2

0

2

0

22

0

2

0

0

0

2

24

2sin

24cos

24

222

1

2

1

tan

(6)

Now, we can make the geometro-kinematics synthesis of the classic cam profile (system 7).

sin2cossincos

sincoscossincossinsinsin

sincos2sincos

sincossinsincoscoscoscos

sin

2cos

2

000

0

2

00

0

2

0

ssrsrrsr

xyrrrry

srssrsrr

yxrrrrx

srry

ssrrrx

a

TTfffmc

a

TTfffmc

fT

afT

(7)

For a law cos, the profile takes the below form, bean-shaped (see the Figure 4).

Page 51: Camshaft precision color petrescu

51

Fig. 4 The profile of cam (bean-shaped) to the cam with plate translated follower

This profile can be closed with an additional curve, and one obtains the form in the Figure 5.

Page 52: Camshaft precision color petrescu

52

-0.025

-0.02

-0.015

-0.01

-0.005

0

0.005

0.01

0.015

-0.015 -0.01 -0.005 0 0.005 0.01 0.015 0.02 0.025

yc

Fig. 5 The closed profile of cam to the cam with plate translated follower

Page 53: Camshaft precision color petrescu

53

4. The dynamics of the cam

The moments of inertia is determined with the relationships from the system 8.

2

0

*

2

0

2

0

2

0

*

2

0

2

0

*

0

2

0

0

22

0

min

2

0

*

22

0

2

0

22

0

2

0

*

22

0

2

0

2

2

1

2

1

2

1

2

1

2

12

2

1

2

1

1cos0''

20'

0'

'''2'2'2'

'2

;0',00;2

1

2

1

'2

;2

1'24

2

1

';242

1

2

1

hrMJ

hrMhMhrMrMJ

hMhrMrMJ

IIsmsMrM

IhMhrMJhss

J

ssmssMsrMJ

smsMsrMMaxJJ

sswhenJwithJrMJ

smsMsrMJwith

JrMsmssrrMJ

smJssrrMrMJ

Cm

Ccccm

cccm

Tcc

ccM

Tcc

TccMMax

Mcm

Tcc

cTc

TTccc

(8)

The angular velocity w, and the angular acceleration, are determined with the presented relationships (system 9).

'''2'2'2'

'242

1

2

1

2

1

;

0

*'

22

0

2

0

*

2

0

*

*

*'2

*

*2

*

*2

ssmssMsrMJJ

smssrrMJ

hrMJ

J

J

J

J

J

J

Tcc

Tc

Cm

mm

mm

w

wwww

(9)

For a classic cam and tappet mechanism (without valve) dynamic movement tappet is expressed by equation (10), who was presented and derived in Chapter 2 (equation 48), and now by canceling valve mass, will customize and reaching form below (10).

Page 54: Camshaft precision color petrescu

54

kK

xkskK

skKxksKkksmkKsx T

02

0

2222

)(2

)(2)2(')( w (10)

Where x is the dynamic movement of the pusher, while s is its normal, kinematics movement. K is the spring constant of the system, and k is the spring constant of the tappet spring. It note, with x0 the tappet spring preload, with mT the mass of the tappet, with ω the angular

rotation speed of the cam (or camshaft), where s’ is the first derivative in function of of the tappet

movement, s. Differentiating twice successively, the expression (10) in the angle , we obtain a reduced tappet speed (equation 11), and reduced tappet acceleration (12).

2

02

0

0

22

0

2222

2

''

'

'2'22'''2

)(2)2(')(

kK

kxskK

Msx

sNkK

kxs

skKkxsskKkssmkKM

skKxksKkksmkKN

T

T

w

w

(11)

3

02

00

0

22

22

0

0

22

0

2222

2

'2''

''''

''2'''22

''''''2

'

'2'22'''2

)(2)2(')(

kK

kxskK

sMkK

kxssN

kK

kxsO

sx

skKxksssKkk

sssmkKO

sNkK

kxs

skKkxsskKkssmkKM

skKxksKkksmkKN

T

T

T

w

w

w

(12)

The real and dynamic, tappet acceleration can be determined directly using the relation (13).

w ''' 2 xxx (13)

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55

For a law cos (14) we obtain the dynamic diagram from the Figure 6.

uu

r

uu

r

uu

r

u

hs

has

hvs

hhs

sin2

'''

cos2

''

sin2

'

cos22

3

3

2

2 (14)

Fig. 6 The dynamic diagram of the tappet acceleration from a cos profile of cam used to the cam with plate

translated follower; r0=13 [mm], Mc=200 [g], mT=100 [g], u=c=/2, h=6 [mm], nm=10000 [rpm], x0=90 [mm], k=40 [kN/m], K=5000 [kN/m].

5. Conclusions

The presented dynamic system has the advantage to has a normal functionality. The synthesis was made using the natural geometro-kinematics parameters (of cam mechanism).

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56

CHAPTER VII DYNAMIC SYNTHESIS OF THE ROTARY CAM AND TRANSLATED

TAPPET WITH ROLL

Abstract: This chapter presents an original methods to determine the dynamic parameters at the camshaft (the distribution mechanisms). We determine initially the mass moment of inertia (mechanical) of the mechanism, reduced to the element of rotation, ie at cam (basically using kinetic energy conservation, the system 1). The rotary cam with translated follower with roll (Figure 1), is synthesized dynamic. We considered the law of motion of the tappet classic version already used the cosine law (both ascending and

descending). The angular velocity is a function of the cam position () but also its rotation speed (2). Where ωm is the nominal angular velocity of cam and express at the distribution mechanisms based on the motor shaft speed (3). We start the simulation with a classical law of motion, namely the cosine law. To climb cosine law system is expressed by relations (4). With the relation (5) is expressed the first derivative of the reduced mechanical moment of inertia. It is necessary to determine the angular acceleration (6). Relations (2) and (6) a general nature and is basically two original equations of motion crucial for mechanical mechanisms. For a rotary cam and translated tappet with roll mechanism (without valve), dynamic movement tappet is expressed by equation (7), who was presented and derived in Chapter 2 (equation 48), and now by canceling valve mass, will customize and reaching form below (7). Where x is the dynamic movement of the pusher, while s is its normal, kinematics movement. K is the spring constant of the system, and k is the spring constant of the tappet spring. It note, with x0 the tappet spring preload, with mT the mass of the tappet, with ω the angular rotation speed of the cam (or camshaft), where s’ is the first derivative in

function of of the tappet movement, s. Differentiating twice successively, the expression (7) in the angle , we obtain a reduced tappet speed (equation 8), and reduced tappet acceleration (9). Further the acceleration of the tappet can be determined directly real (dynamic) using the relation (10). For a good work one proposes to make a new geometro-kinematics synthesis of the cam profile, using some new relationships (16).

Keywords: cam, cams, cam mechanisms, distribution mechanisms, camshaft, tappet.

The rotary cam with translated follower with roll (Figure 1), is synthesized dynamic by the next relationships.

0A

A

B

A-

B

B0

A0

A

O

X’

e

s0

rb

r0

rA

rB

s

n

C

rb

x

y

s’

Fig. 1 The rotary cam with translated follower with roll

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57

First, one determines the mass moment of inertia (mechanical) of the mechanism, reduced to the element of rotation, ie cam (basically using kinetic energy conservation, system 1).

2

22

0

2

0

2

2

00

2

0

2*

2

0

22

2

0

2

0

2

0

2

0

2

00

22

0

*

22

0

22

0

2

02

0

222

22

0

00

22

0

2

0

222

0

2

0

222

0

222

0

2222222

2

''

'

2

122

2

1

8

22

22

2

1

16

1

4

1

2

1

'

'2

'

2

'2

'

'2

cossin2

cos2cos

sin2sin

2

1

smesss

sseserM

sMssMrrrrMJ

hm

ehh

s

hse

he

rM

hMhsMrrrrMJ

esss

eser

esss

ssrssrer

esss

ssssr

esss

eserssrer

sserssrer

ssrrss

rereyxrR

RMJ

Tbc

ccbbc

Tbc

ccbbcm

b

bbA

b

bbA

bbA

bb

bbAAA

ccama

(1)

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58

We considered the law of motion of the tappet classic version already used the cosine law (both ascending and descending).

The angular velocity is a function of the cam position () but also its rotation speed (2). Where ωm is the nominal angular velocity of cam and express at the distribution mechanisms based on the motor shaft speed (3).

2

*

*2

mm

J

Jww (2)

60260

2

6022

nnn motorccm

w (3)

We start the simulation with a classical law of motion, namely the cosine law. To climb cosine law system is expressed by relations (4).

uu

r

uu

r

uu

r

u

hs

has

hvs

hhs

sin2

'''

cos2

''

sin2

'

cos22

3

3

2

2 (4)

Where takes values from 0 to u.

Jmax occurs for =u/2.

With the relation (5) is expressed the first derivative of the reduced mechanical moment of inertia. It is necessary to determine the angular acceleration (6).

2/322

0

0

2

0

2

2/322

0

22

00

0

*'

'

'''''

'

''2''

'''2''

esss

sesssssseserM

esss

essssssserM

ssmssMssMJ

bc

bc

Tcc

(5)

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59

Differentiating the formula (2), against time, is obtained the angular acceleration expression (6).

*

*'2

2 J

J

w (6)

Relations (2) and (6) a general nature and is basically two original equations of motion crucial for mechanical mechanisms.

For a rotary cam and translated tappet with roll mechanism (without valve), dynamic movement tappet is expressed by equation (7), who was presented and derived in Chapter 2 (equation 48), and now by canceling valve mass, will customize and reaching form below (7).

kK

xkskK

skKxksKkksmkKsx T

02

0

2222

)(2

)(2)2(')( w

(7)

Where x is the dynamic movement of the pusher, while s is its normal, kinematics movement. K is the spring constant of the system, and k is the spring constant of the tappet spring.

It note, with x0 the tappet spring preload, with mT the mass of the tappet, with ω the angular

rotation speed of the cam (or camshaft), where s’ is the first derivative in function of of the tappet

movement, s. Differentiating twice successively, the expression (7) in the angle , we obtain a reduced tappet speed (equation 8), and reduced tappet acceleration (9).

2

02

0

0

22

0

2222

2

''

'

'2'22'''2

)(2)2(')(

kK

kxskK

Msx

sNkK

kxs

skKkxsskKkssmkKM

skKxksKkksmkKN

T

T

w

w

(8)

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60

3

02

00

0

22

22

0

0

22

0

2222

2

'2''

''''

''2'''22

''''''2

'

'2'22'''2

)(2)2(')(

kK

kxskK

sMkK

kxssN

kK

kxsO

sx

skKxksssKkk

sssmkKO

sNkK

kxs

skKkxsskKkssmkKM

skKxksKkksmkKN

T

T

T

w

w

w

(9)

Further the acceleration of the tappet can be determined directly real (dynamic) using the relation (10).

w ''' 2 xxx (10)

Dynamic synthesis

Give the following parameters:

r0=0.013 [m]; rb=0.005 [m]; h=0.008 [m]; e=0.01 [m]; x0=0.03 [m]; u=/2; c=/2; K=5000000 [N/m]; k=20000 [N/m]; mT=0.1 [kg]; Mc=0.2 [kg]; nmotor=5500 [rot/min].

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61

To sum up dynamically based on a computer program, you can vary the input data until the corresponding acceleration is obtained (see Figure 2). It then summarizes the corresponding cam profile (Figure 3) using the relations (11).

Fig. 2 Dynamic diagram to the rotary cam with translated follower with roll

coscossinsin

sincoscossin

cossin

sincos

cos

sin

0

0

0

bbC

bbC

TTC

TTC

bT

bT

rssrey

rssrex

yxy

yxx

rssy

rex

(11)

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62

Fig. 3 The cam profile to the rotary cam with translated follower with roll

rb=0.003 [m]; e=0.003 [m]; h=0.006 [m]; r0=0.013 [m]; 0=/2 [rad];

The geometry of the rotary cam and the translated follower with roll

Now, we shall see the geometry of a rotary cam with translated follower with roll (Figure 4). The cam rotation sense is positive (trigonometric).

We can make the geometrical synthesis of the cam profile with the help of the cinematics of the mechanism. One uses as well the reduced speed, s’.

OA=r=rA; r2=rA2

It establishes a system fixed Cartesian, xOy = xfOyf, and a mobil Cartesian system, xOy = xmOym fixed with the cam.

From the lower position 0, the tappet, pushed by cam, uplifts to a general position, when

the cam rotates with the angle. The contact point A, go from Ai0 to A0 (on the cam), and to A (on

the tappet). The position angle of the point A from the tappet is f, and from the cam is m. We can determine the coordinates of the point A from the tappet (12), and from the cam (13).

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63

f

m

A

0

iA

0AO

fx

fy

mx

0B

B

e

s

0s

w

r

0r

0r

br

br

Br

0

Fig. 4 The geometry of the rotary cam with translated follower with roll

Page 64: Camshaft precision color petrescu

64

ffAb

f

AT

ffAb

f

AT

rrrssyy

rrrexx

sinsincos

coscossin

0

(12)

sinsincoscossincos

cossincossinsinsin

sincoscossinsincos

sinsincoscoscoscos

0

0

bbTT

fffmA

m

Ac

bbTT

fffmA

m

Ac

rerssxy

rrrryy

rssreyx

rrrrxx

(13)

One uses and the next relationships (where the pressure angle was obtained with the classic Antonescu P. method):

ss

estg

esss

es

esss

ss

errs b

0

22

0

22

0

0

22

00

'

'

'sin

'cos

(14)

Determining the forces, the velocities and the efficiency (15)

The driving force Fm, perpendicular on r in A, is divided in two components: Fn, the normal force, and Fa, a force of slipping. Fn is divided, as well, in two components: FT is the transmitted (the utile) force, and FR is a radial force which bend the tappet (see 15, and the Figure 5).

cossin2

cossin

;;2

cos;22

;

coscoscoscoscoscoscoscos

coscoscos

coscoscos

cos

cos

0

2

0

22

2

0

222

2

0

2222

222

sserssrerr

rssreyxr

sserrr

rrrAAA

vF

vF

vF

vF

P

P

vvv

FFF

vv

FF

bbA

bbAfAf

B

b

Bb

mm

mm

mm

TT

c

ui

mnT

mnT

mn

mn

(15)

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65

f

m

A

0

iA

0AO

fx

fy

mx

0B

B

e

s

0s

w

r

0r

0r

br

br

Br

0

TF

RF

nF

nF

mF

aF

Fig. 5 Forces and velocities of the rotary cam with translated follower with roll

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66

Geometro-kinematics synthesis

For a good work one proposes to make a new geometro-kinematics synthesis of the cam profile, using some new relationships (16).

ffAb

f

AT

ffAb

f

AT

rrrssyy

rrrexx

sinsincos

coscossin

0

(12)

sinsincoscossincos

cossincossinsinsin

sincoscossinsincos

sinsincoscoscoscos

0

0

bbTT

fffmA

m

Ac

bbTT

fffmA

m

Ac

rerssxy

rrrryy

rssreyx

rrrrxx

(13)

One uses and the next relationships (where the pressure angle was obtained with the new Petrescu F. method):

][2

'2'4'4arccossinsin

][2

'2'4'4arccos

cosarccos

][2

'2'4'4cos

22

0

22

00

2

0

22

0

22

00

2

0

22

0

22

00

2

0

22

00

ess

sesesssssss

ess

sesesssssss

ess

sesesssssss

errs b

(16)

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67

The new profile can be seen in the Figure 6.

Fig. 6 The new cam profile to the rotary cam with translated follower with roll

rb=0.003 [m]; e=0.003 [m]; h=0.006 [m]; r0=0.013 [m]; 0=/2 [rad];

Page 68: Camshaft precision color petrescu

68

Demonstration (explication)

][2

'2'4'4cos

][2

'4'2'2cos

0'cos'2cos

cos'2cos'coscos

cos'cos1cos

coscossin'cossin

cos

'

cossincossincossinsin

sincos

'sin

cos

'

sinsin

sincos

'

sin2

cos2

coscos

22;;

2

coscos'coscos

22

0

22

00

2

0

22

0

22

0

222

0

2

02

222

0

422

0

242242

0

22

0

22

0

2

00

0

ess

sesesssssss

ess

essssessesss

ssessess

seesssss

esss

esssr

ess

r

s

r

e

r

ssBBB

Br

sB

r

r

r

s

Br

rA

Ar

s

AAA

AA

rsrs

BB

BB

BA

B

A

A

B

A

AA

w

(17)

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69

Bibliography

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211.-S2. SILAS GH., s.a., Culegere de probleme de vibratii mecanice. Editura tehnicã, Bucuresti, 1967.

212.-S3. SARSTEN A.,VALLEND H., Computer aided design of valve cams. Internal Combustion Engines conference, Bucharest, Paper II-19, 1967.

213.-S4. SAVA I., Stadiul actual în dinamica mecanismelor cu came. I-II., Rev. S.C.M.A., Nr. 5., 1969.

214.-S5. SAVA I., Contributii la dinamica si sinteza optimalã a mecanismelor cu came. Tezã de doctorat, I.P.B., 1970.

215.-S6. SAVA I., Cu privire la functionarea in regim dinamic a supapei mecanismului distributiei motoarelor cu ardere interna. In revista C.M. Nr.12.,Bucuresti, 1971.

216.-S7. SAVIUC S., Optimizarea duratei de deschidere simultanã a supapelor la motoarele cu aprindere prin scânteie. Tezã de doctorat, I.P.B., 1979.

217.-S8. SIRETEANU T., GRUNDISCH O., PARAIAN S., Vibratiile aleatoare ale automobilelor. E.T., Bucuresti, 1981.

218.-S9. STOICESCU A., Dinamica autovehiculelor. Vol. I-II., I.P.B., Bucuresti, 1980-82.

219.-S10. STOICESCU A., Dinamica autovehiculelor pe roti. E.D.P., Bucuresti, 1981.

220.-S11. SONO H., UMIYAMA H., Honda RDCo., Ltd. Japan, A study of Combustion Stability of Non-Throttling S.I. Engine with Early Intake Valve Closing Mechanism. (945009), In XXV FISITA CONGRES, October 1994, Beijing, pp. 78-87.

Page 75: Camshaft precision color petrescu

75

221.-T1. TEMPEA I., POPA GH., Mecanisme plane articulate. I.P.B., Bucuresti, 1978.

222.-T2. TEMPEA I., MARTINEAC A., Organe de masini, teoria mecanismelor si prelucrãrii prin aschiere. Partea I , mecanisme, I.P.B., Bucuresti, 1983.

223.-T3. TEMPEA I., BALESCU C., ADIR G., Mecanism de presare destinat mecanizãrii operatiei de formare în rame (pãrtile I si II). In al VII-lea Simpozion national de roboti industriali si mecanisme spatiale. Vol. 3., Bucuresti, 1987.

224.-T4. TEMPEA I., GRADU M., Sinteza camei de translatie cu tachet cu rolã, cu ajutorul functiilor spline. In lucrãrile simpozionului de R.I., Timisoara, 1992.

225.-T5. TUTUNARU D., Mecanisme plane rectiliniare si inversoare. Editura tehnicã, Bucuresti, 1969.

226.-T6. TORAZZA G., A variable lift and event control device piston engine valve operation. In FISITA XIV Congres,Paper II / 10, London, 1972.

227.-T7. TESAR D., MATTHEW G.K., The design of modelled cam sistems. In Cams and cam mechanisms, 1974.

228.-T8. TERME D., Besondere Merkmalebeider Nutzung des Pressungwinkels fur kurvengetriebeanalyse und-Synthese. In SYROM’85,Vol. III-2, pp. 489-504, Bucuresti, iulie 1985.

229.-T9. TEMPEA I., DUGĂEŞESCU I., NEACŞA M., Mecanisme. Noţiuni teoretice şi teme de proiect rezolvate, Ed. Printech, ISBN (10) 973-718-560-9, 2006.

230.-T10. D. Taraza, N.A. Henein, W. Bryzik, "The Frequency Analysis of the Crankshaft's Speed Variation: A reliable Tool for Diesel Engine Diagnosis," ASME Journal for Gas Turbines and Power 123(2), 428-432, 2001 231.-T11. D. Taraza, "Accuracy Limits of IMEP Determination from Crankshaft Speed Measurements," SAE Transactions, Journal of Engines 111, 689-697, 2002.

232.-T12. D. Taraza, "Statistical Correlation Between the Crankshaft's Speed Variation and Engine Performance, Part I: Theoretical Model," ASME Journal of Engineering for Gas Turbines and Power 125(3), 791-796, 2003.

233.-T13. D. Taraza, "Statistical Correlation Between the Crankshaft's Speed Variation and Engine Performance, Part II: Detection of Deficient Cylinders and MIP Calculation," ASME journal of Engineering for Gas Turbines and Power 125(3), 797-803, 2003.

234.-U1. ULF A., WILLIAM S., A Simple Procedure for Modifying High-Speed Cam Profiles for Vibration Reduction, Journal of Mechanical Design - November 2004 - Volume 126, Issue 6, pp. 1105-1108.

235.-V1. VOINEA R., VOICULESCU D., CEAUSU V., Mecanica. E.D.P., Bucuresti, 1975.

236.-V2. VOINEA R., ATANASIU M., Metode analitice noi în teoria mecanismelor. Editura tehnicã, Bucuresti, 1964.

237.-V3. Van de Straete, H.J., De Schutter, J., Hybrid cam mechanisms, Mechatronics, IEEE/ASME Transactions on Volume 1, Issue 4, Dec. 1996 Page(s):284 - 289

238.-W1. WIEDERRICH J.L., ROTH B., Design of low vibration cam profiles. In Cams and cam mechanisms, Edited by J. REES JONES, MEP, London and Birmingham, Alabama, 1974.

239.-W2. WIEDERRICH J.L., ROTH B., Dynamic Synthesis of Cams Using Finite Trigonometric Series, Trans. ASME, 1974.

240.-Y1. YOUNG V.C., Considerations în valve gear design. Trans. SAE, 1, 1947, pp. 359-365.

241.-Z1. ZHANG J.L., LI Z., Research on the dynamics of a RSCR spatial mechanisms considering bearing clearances. In al VI-lea SYROM, Vol. II, Bucuresti, iunie 1993.

Annex

Profile of rotary cam and translated lift with roller; Law of motion ex:

-10

-5

0

5

10

15

-20 -10 0 10

u= 85[grad]

c= 85[grad]

r0= 3[mm]

rb = 15[mm]

e= 0[mm]

hT= 12[mm]

Law

y=(ex -e

-x)/a

w

Down profile

Up profile

Profile of rotary cam and translated lift with roll; Law of motion ex;

Good efficiency =25%; Name:Name: ““Elax001Elax001”” nncamcam=n/2=n/2

d0=6 [mm]

d0=6 [mm], h3 [mm], rb=15 [mm]; d0=12 [mm], h6 [mm], rb=30 [mm];

d0=24 [mm], h12 [mm], rb=60 [mm].

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76

-25000

-20000

-15000

-10000

-5000

0

5000

10000

0 50 100 150 200

a[m/s2]

312,85s*k[mm] k=

n=5500[rot/min]

ju=85 [grad]

k=50 [N/mm]

r0=3 [mm]

x0=80 [mm]

hs=12 [mm]

hT=12 [mm]

i=1;h=51.1%

rb=15 [mm]

e=0 [mm]

y=(ex-e

-x)/a

a=2.35040238

amax=4130smax=10.55

amin= -21300

Dynamic analysis to the rotary cam and translated follower with roll;

Law of motion ex; Name:Name: ““Elax001Elax001””

PProposed crankshaft rotation speed n=5500 [r/m]; roposed crankshaft rotation speed n=5500 [r/m]; nncamcam=n/2=n/2

-initial spring deflection x0=80 [mm]

-elastic constant of spring k=50-80 [N/mm]

-roll radius of the follower rb=15 [mm] at a r0=3 [mm].

Profile of rotary cam and translated lift with roller; Law of motion ex:

-10

-5

0

5

10

15

-20 -10 0 10

u= 85[grad]

c= 85[grad]

r0= 3[mm]

rb = 15[mm]

e= 0[mm]

hT= 12[mm]

Law

y=(ex -e

-x)/a

w

Down profile

Up profile

Profile of rotary cam and translated lift with roll; Law of motion ex;

Best efficiency =51%; Name:Name: ““2Elax0012Elax001”” ![![nncamcam=n/4=n/4]!]!

d0=6 [mm]

d0=6 [mm], h3 [mm], rb=15 [mm];

d0=12 [mm], h6 [mm], rb=30 [mm];

d0=24 [mm], h12 [mm], rb=60 [mm].

y=(ex-e-x)/a

a=2.35040238

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77

-10

-5

0

5

10

-20 -10 0 10

u= 55[grad]

c= 55[grad]

r0= 4[mm]

rb = 5[mm]

e= 0[mm]

hT= 12[mm]

Law LOG-0

a=1

profil dublat

w

Profile of rotary cam and translated lift with roll; Law of motion Log Nat;

Good efficiency =25-33%; Name:Name: ““2LogNat0012LogNat001”” ![![nncamcam=n/4=n/4]!]!

Up profile

Down profile

d0=8 [mm], h3,5 [mm], rb=5 [mm];

d0=16 [mm], h7 [mm], rb=10 [mm];

d0=24 [mm], h10,5 [mm], rb=15 [mm].

y=(ln(x+a)-ln(a))/

(ln(a+1)-ln(a))

-10000

-8000

-6000

-4000

-2000

0

2000

4000

6000

0 50 100 150

a[m/s2]

288,48s*k[mm] k=

n=5500[rot/min]

ju=55 [grad]

k=30 [N/mm]

r0=4 [mm]

x0=80 [mm]

hs=12 [mm]

hT=12 [mm]

i=1;h=32.3%

rb=5 [mm]

e=0 [mm]

legea:Log-0

a=1

amax=4040smax=11.21

amin= -8400

y=(ln(x+a)-ln(a))/(ln(a+1)-ln(a))

Dynamic analysis to the rotary cam and translated lift with roll; Law of motion Log Nat;

Good efficiency =25-33%; Name:Name: ““2LogNat0012LogNat001”” ![![nncamcam=n/4=n/4]!]!

-initial spring deflection x0=80 [mm]

-elastic constant of spring k=30-60 [N/mm]

-roll radius of the follower rb=5 [mm] at a r0=4 [mm].

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78

-10

-5

0

5

10

15

20

-20 -15 -10 -5 0 5 10

w

Profile of rotary cam and translated lift with roll; Law of motion Power;

Better efficiency =40-47%; Name:Name: ““2Power0012Power001”” ![![nncamcam=n/4=n/4]!]!

d0=8 [mm], h5 [mm], rb=20 [mm];

d0=16 [mm], h10 [mm], rb=40 [mm];

d0=24 [mm], h15 [mm], rb=60 [mm].

Up profile

Down profile

-10

-5

0

5

10

15

20

-20 -15 -10 -5 0 5 10

yC [mm]

ju= 85[grad]

jc= 85[grad]

r0= 4[mm]

rb = 20[mm]

e= 0[mm]

hT= 12[mm]

The Law

Power

y=2x-1

w

-25000

-20000

-15000

-10000

-5000

0

5000

10000

0 50 100 150 200

a[m/s2]

330,54s*k[mm] k=

n=5500[rot/min]

ju=85 [grad]

k=100 [N/mm]

r0=4 [mm]

x0=80 [mm]

hs=12 [mm]

hT=12 [mm]

i=1;h=47.2%

rb=20 [mm]

e=0 [mm]

law:Power-0

y=2x-1

amax=4000smax=9.55

amin= -22000

Dynamic analysis to the rotary cam and translated lift with roll; Law of motion Power;

Better efficiency =40-47%; Name:Name: ““2Power0012Power001”” ![![nncamcam=n/4=n/4]!]!

-initial spring deflection x0=80 [mm]

-elastic constant of spring k=100 [N/mm]

-roll radius of the follower rb=20 [mm] at a r0=4 [mm].

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79

-15

-10

-5

0

5

10

15

-15 -10 -5 0 5 10 15

u= 75[grad]

c= 75[grad]

r0= 6[mm]

rb = 14[mm]

e= 0[mm]

hT= 8[mm]

Law ATAN

w

Up profile

Down profile

y=arctg(x/a)

a=0.642

Profile of rotary cam and translated lift with roll; Law of motion Atan;

Good efficiency =30-40%; Name:Name: ““2Atan0012Atan001”” ![![nncamcam=n/4=n/4]!]!

d0=12 [mm], h3 [mm], rb=14 [mm];

d0=24 [mm], h6 [mm], rb=28 [mm];

d0=36 [mm], h9 [mm], rb=42 [mm].

-10000

-8000

-6000

-4000

-2000

0

2000

4000

6000

8000

10000

12000

0 50 100 150 200

a[m/s2]

1000,69s*k[mm] k=

n=5500[rot/min]

ju=75 [grad]

k=30 [N/mm]

r0=6 [mm]

x0=80 [mm]

hs=8 [mm]

hT=8 [mm]

i=1;h=28.4%

rb=14 [mm]

e=0 [mm]

law: ATAN-1

y=arctg(x/a)

a=0.642

amax=9229

smax=7.37

amin= -7753

Dynamic analysis to the rotary cam and translated lift with roll; Law of motion Atan;

Good efficiency =30-40%; Name:Name: ““2Atan0012Atan001”” ![![nncamcam=n/4=n/4]!]!

-initial spring deflection x0=80 [mm]

-elastic constant of spring k=30 [N/mm]

-roll radius of the follower rb=14 [mm] at a r0=6 [mm].

Page 80: Camshaft precision color petrescu

80

-20

-15

-10

-5

0

5

10

15

20

-30 -20 -10 0 10 20

u= 65[grad]

c= 65[grad]

r0= 13[mm]

rb = 12[mm]

e= 0[mm]

hT= 8[mm]

Law 2C4P1-001

y=2x-x2

w

Profile of rotary cam and translated lift with roll; Law of motion C4P1-001;

Good efficiency =20-35%; Name:Name: ““2C4P12C4P1--001001”” ![![nncamcam=n/4=n/4]!]!

d0=26 [mm], h6 [mm], rb=12 [mm];

d0=52 [mm], h12 [mm], rb=24 [mm];

Up profile

Down profile

-2000

0

2000

4000

6000

8000

10000

12000

0 50 100 150 a[m/s2]

1054,98s*k[mm] k=

n=5500[rot/min]

u=65 [grad]

k=50 [N/mm]

r0=13 [mm]

x0=20 [mm]

hs=8 [mm]

hT=8 [mm]

i=1;=16.7%

rb=12 [mm]

e=0 [mm]

law: 2C4P1-001

y=2x-x2

amax=10100

smax=7.66

amin= -260

Dynamic analysis to the rotary cam and translated lift with roll; Law of motion C4P1-001;

Good efficiency =20-35%; Name:Name: ““2C4P12C4P1--001001”” ![![nncamcam=n/4=n/4]!]!

-initial spring deflection x0=20 [mm]

-elastic constant of spring k=50 [N/mm]

-roll radius of the follower rb=12 [mm] at a r0=13 [mm].

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81

-20

-15

-10

-5

0

5

10

15

20

-30 -20 -10 0 10 20

u= 45[grad]

c= 45[grad]

r0= 13[mm]

rb = 12[mm]

e= 0[mm]

hT= 8[mm]

Law 4C4P1-001

y=2x-x2

w

Profile of rotary cam and translated lift with roll; Law of motion 4C4P1-001;

Best efficiency =40-70%; Name:Name: ““4C4P14C4P1--001001”” ![![nncamcam=n/8=n/8]!]!

d0=26 [mm], h3 [mm], rb=12 [mm];

d0=52 [mm], h6 [mm], rb=24 [mm];

d0=78 [mm], h9 [mm], rb=36 [mm].

Up profile

Down profile

-1000

0

1000

2000

3000

4000

5000

6000

7000

0 20 40 60 80 100 a[m/s2]

638,88s*k[mm] k=

n=5500[rot/min]

u=45 [grad]

k=35 [N/mm]

r0=13 [mm]

x0=20 [mm]

hs=8 [mm]

hT=8 [mm]

i=1;=23.5%

rb=12 [mm]

e=0 [mm]

law: 4C4P1-001

y=2x-x2

amax=6200

smax=7.76

amin= -140

Dynamic analysis to the rotary cam and translated lift with roll; Law of motion C4P1-001;

Best efficiency =40-70%; Name:Name: ““4C4P14C4P1--001001”” ![![nncamcam=n/8=n/8]!]!

-initial spring deflection x0=20 [mm]

-elastic constant of spring k=35 [N/mm]

-roll radius of the follower rb=12 [mm] at a r0=13 [mm].

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82

-15

-10

-5

0

5

10

15

20

-20 -10 0 10 20

ju= 45[grad]

jc= 45[grad]

r0= 13[mm]

rb = 3[mm]

e= 0[mm]

hT= 6[mm]

Law SIN

w

y=x-sin(2x)/(2)

Profile of rotary cam and translated lift with roll; Law of motion SIN-001;

Good efficiency =15-30%; Name:Name: ““2SIN2SIN--001001”” ![![nncamcam=n/4=n/4]!]!

d0=26 [mm], h6 [mm], rb=3 [mm];

d0=52 [mm], h12 [mm], rb=6 [mm].

Up profile

Down profile

-3000

-2000

-1000

0

1000

2000

3000

0 20 40 60 80 100

a[m/s2]

363,66s*k[mm] k=

n=5500[rot/min]

ju=45 [grad]

k=15 [N/mm]

r0=13 [mm]

x0=30 [mm]

hs=6 [mm]

hT=6 [mm]

i=1;h=15.3%

rb=3 [mm]

e=0 [mm]

law: sin

y=x-sin(2px)/(2p)

amax=2667

smax=5.87

amin= -1890

Dynamic analysis to the rotary cam and translated lift with roll; Law of motion SIN-001;

Good efficiency =15-30%; Name:Name: ““2SIN2SIN--001001”” ![![nncamcam=n/4=n/4]!]!

-initial spring deflection x0=30 [mm]

-elastic constant of spring k=15 [N/mm]

-roll radius of the follower rb=3 [mm] at a r0=13 [mm].

Page 83: Camshaft precision color petrescu

83

-25

-20

-15

-10

-5

0

5

10

15

20

25

-30 -20 -10 0 10 20 30

ju=22,5[grad]

jc=22,5[grad]

r0= 20[mm]

rb = 1[mm]

e= 0[mm]

hT= 6[mm]

Law SIN

y=x-sin(2x)/(2 )

Profile of rotary cam and translated lift with roll; Law of motion SIN-001;

Better efficiency =15-60%; Name:Name: ““4SIN4SIN--001001”” ![![nncamcam=n/8=n/8]!]!

d0=40 [mm], h6 [mm], rb=1 [mm];

d0=60 [mm], h9 [mm], rb=1,5 [mm].

Up profile

Down profile

w

-3000

-2000

-1000

0

1000

2000

3000

4000

0 10 20 30 40 50

a[m/s2]

442,41s*k[mm] k=

n=5500[rot/min]

ju=22,5 [grad]

k=5 [N/mm]

r0=20 [mm]

x0=100 [mm]

hs=6 [mm]

hT=6 [mm]

i=1;h=15.7%

rb=1 [mm]

e=0 [mm]

law: sin

y=x-sin(2px)/(2p)

amax=3250

smax=5.87

amin= -2030

Dynamic analysis to the rotary cam and translated lift with roll; Law of motion SIN-001;

Better efficiency =15-60%; Name:Name: ““4SIN4SIN--001001”” ![![nncamcam=n/8=n/8]!]!

-initial spring deflection x0=100 [mm]

-elastic constant of spring k=5 [N/mm]

-roll radius of the follower rb=1 [mm] at a r0=20 [mm].

Page 84: Camshaft precision color petrescu

84

d0=40 [mm], h6 [mm], rb=4 [mm];

d0=60 [mm], h9 [mm], rb=6 [mm].

-25

-20

-15

-10

-5

0

5

10

15

20

25

-30 -20 -10 0 10 20 30

ju=22,5[grad]

jc=22,5[grad]

r0= 20[mm]

rb = 4[mm]

e= 0[mm]

hT= 6[mm]

Law SIN

y=x-sin(2x)/(2 )

Profile of rotary cam and translated lift with roll; Law of motion SIN-002;

Better efficiency =17-70%; Name:Name: ““4SIN4SIN--002002”” ![![nncamcam=n/8=n/8]!]!

Down profile

Up profile

w

Dynamic analysis to the rotary cam and translated lift with roll; Law of motion SIN-002;

Better efficiency =17-70%; Name:Name: ““4SIN4SIN--002002”” ![![nncamcam=n/8=n/8]!]!

-3000

-2000

-1000

0

1000

2000

3000

4000

5000

0 10 20 30 40 50

a[m/s2]

546,62s*k[mm] k=

n=5500[rot/min]

ju=22,5 [grad]

k=5 [N/mm]

r0=20 [mm]

x0=100 [mm]

hs=6 [mm]

hT=6 [mm]

i=1;h=17.95%

rb=4 [mm]

e=0 [mm]

law: sin

y=x-sin(2px)/(2p)

amax=4000

smax=5.87

amin= -2000

-initial spring deflection x0=100 [mm]

-elastic constant of spring k=5 [N/mm]

-roll radius of the follower rb=4 [mm] at a r0=20 [mm].

Page 85: Camshaft precision color petrescu

85

-25

-20

-15

-10

-5

0

5

10

15

20

25

-30 -20 -10 0 10 20 30

ju=11,25[grad]

jc=11,25[grad]

r0= 20[mm]

rb = 1[mm]

e= 0[mm]

hT= 6[mm]

Law SIN

y=x-sin(2x)/(2 )

Profile of rotary cam and translated lift with roll; Law of motion SIN-001;

Better efficiency =14-80%; Name:Name: ““8SIN8SIN--001001”” ![![nncamcam=n/16=n/16]!]!

d0=40 [mm], h6 [mm], rb=1 [mm];

d0=60 [mm], h9 [mm], rb=1.5 [mm];

d0=80 [mm], h12 [mm], rb=2 [mm].

w

Up profile

Down profile

-4000

-2000

0

2000

4000

6000

8000

10000

12000

14000

16000

0 5 10 15 20 25a[m/s2]

1977,24s*k[mm] k=

n=5500[rot/min]

ju=11,25 [grad]

k=30 [N/mm]

r0=20 [mm]

x0=85 [mm]

hs=6 [mm]

hT=6 [mm]

i=1;h=14.0%

rb=1 [mm]

e=0 [mm]

law: sin

y=x-sin(2px)/(2p)

amax=13300

smax=5.39

amin= -1700

Dynamic analysis to the rotary cam and translated lift with roll; Law of motion SIN-001;

Better efficiency =14-80%; Name:Name: ““8SIN8SIN--001001”” ![![nncamcam=n/16=n/16]!]!

-initial spring deflection x0=85 [mm]

-elastic constant of spring k=30 [N/mm]

-roll radius of the follower rb=1 [mm] at a r0=20 [mm].

Page 86: Camshaft precision color petrescu

86

-40

-30

-20

-10

0

10

20

30

40

-60 -40 -20 0 20 40

ju= 15[grad]

jc= 15[grad]

r0= 30[mm]

rb = 3[mm]

e= 0[mm]

hT=8[mm]

Law COS

y=.5-.5cos(x)

w

Profile of rotary cam and translated lift with roll; Law of motion COS-001;

Better efficiency =21-60%; Name:Name: ““6COS6COS--001001”” ![![nncamcam=n/12=n/12]!]!

d0=60 [mm], h8 [mm], rb=3 [mm];

d0=90 [mm], h12 [mm], rb=4.5 [mm].

Down profile

Up profile

w

Dynamic analysis to the rotary cam and translated lift with roll; Law of motion COS-001;

Better efficiency =21-60%; Name:Name: ““6COS6COS--001001”” ![![nncamcam=n/12=n/12]!]!

-initial spring deflection x0=100 [mm]

-elastic constant of spring k=37 [N/mm]

-roll radius of the follower rb=3 [mm] at a r0=30 [mm].

-2000

-1000

0

1000

2000

3000

4000

5000

6000

0 10 20 30 40a[m/s2]

626,79s*k[mm] k=

n=5500[rot/min]

ju=15 [grad]

k=37 [N/mm]

r0=30 [mm]

x0=100 [mm]

hs=8 [mm]

hT=8 [mm]

i=1;h=21.0%

rb=3 [mm]

e=0 [mm]

law: cos

y=.5-.5cos(px)

amax=5600

smax=7.11

amin= -1400

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87

Profile of rotary cam and translated lift with roll; Law of motion COS-001;

Best efficiency =19-80%; Name:Name: ““12COS12COS--001001”” ![![nncamcam=n/24=n/24]!]!

-60

-40

-20

0

20

40

60

-80 -60 -40 -20 0 20 40 60

ju= 7,5[grad]

jc= 7,5[grad]

r0= 50[mm]

rb = 2[mm]

e= 0[mm]

hT=8[mm]

Law COS

y=.5-.5cos(x)

w

d0=50 [mm], h4 [mm], rb=1 [mm].

d0=100 [mm], h8 [mm], rb=2 [mm];

d0=150 [mm], h12 [mm], rb=3 [mm].

Down profile

Up profile

w

It would be desirable rounding the peaks!

Dynamic analysis to the rotary cam and translated lift with roll; Law of motion COS-001;

Best efficiency =19-80%; Name:Name: ““12COS12COS--001001”” ![![nncamcam=n/24=n/24]!]!

-initial spring deflection x0=100 [mm]

-elastic constant of spring k=50 [N/mm]

-roll radius of the follower rb=2 [mm] at a r0=50 [mm].

-2000

-1000

0

1000

2000

3000

4000

5000

0 5 10 15 20

a[m/s2]

474,38s*k[mm] k=

n=5500[rot/min]

ju=7,5 [grad]

k=50 [N/mm]

r0=50 [mm]

x0=100 [mm]

hs=8 [mm]

hT=8 [mm]

i=1;h=19.19%

rb=2 [mm]

e=0 [mm]

law: cos

y=.5-.5cos(px)

amax=4060

smax=6.85

amin= -1400

!All these matters are copyrighted!

Page 88: Camshaft precision color petrescu

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