Cau Hoi Chuong 2012

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    Nm hc: 2012 2013

    CU HI CHNG MN VT LIU HC I CNG

    I. Cu hi chng 1

    L thuyt:1) Th no l lin kt cng ho tr, lin kt ion, lin kt kim loi?

    2) K tn mt s trc tinh th ca vt rn. Nu c im chnh ca mng tinh thlp phng tm mt (A1), mng kim cng (A4)

    3) Polyme l g, Phn loi cu trc ca polyme

    4) C my loi sai lch ng trong tinh th. Nu c im ca sai lch xon, sailch bin

    5) Trnh by sai lch im trong mng tinh th.

    6) C my loi sai lch mt tinh th trong mng tinh th. Nu c im ca bin

    gii ht7) Th no l n tinh th, a tinh th. Nu c tnh v ng dng ca chng

    II. CU HI V BI TP

    Bi 1: Xc nh ch s phng sau ca cc vct A, B, C, D sau:

    Bi 2: Xc nh ch s Miller ca cc mt A, B sau:

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    Nm hc: 2012 2013

    Bi 3: Xc nh ch s Miller - Bravais ca mt sau:

    Bi 4: Tnh mt nguyn t theo phng [110] ca Cu (Fcc). . Bit tinh th Cu c

    cu trc lp phng tm mt. Cho chu k tun hon l a = 3,61.10-8 m

    Bi 5: Tinh mt nguyn t theo phng [112] ca: a) Fe (Bcc) c rFe = 1,241 A0 b) Ni(Fcc) c rNi = 1,245 A0.Bi 6: Tinh mt xp cht theo mt (111), (110), (101) ca: a) Fe (Bcc); b) Ni (Fcc).Bi 7: Tnh mt nguyn t theo mt (100), (111), ca Pb (Fcc)

    Tnh mt phng trn phng [1 0 0], [1 1 1] ca Pb (lp phng tm mt). Cho

    bn knh Pb theo ph lc l RPb = 1,750 .

    Bi 8. So snh d111 v d200 trong Pb (lp phng tm mt), aPb = 4,95 A0.

    Bi 8: Tnh mt xp th tch Mv ca NaCl, bit r(Na+) = 0,98 Ao, R(Cl-) = 1,81 Ao.

    Bi 9: Tnh lp li trn phng [211] ca Cu. Cho bit Cu c cu trc lp

    phng tm mt. Cho hng s mng ca Cu l a = 3,61.10-8m

    Bi 10: Ag (Fcc) c r = 1,444 A0. Tnh hng s mng v th tch c s.

    Bi 11: ng (Fcc) c bn knh nguyn t l 1,278 Ao. Tnh khi lng ring ca Cu vso snh vi s liu trong ph lc. (Theo ph lc dCu = 8,96 g/cm3)

    Bi 12: Au (Fcc) c a = 4,078 A0, Nguyn t lng 197. Tnh khi lng ring ca n.Bi 13: Zn (Hcp) c c = 4,94 A0, khong cch gia tm 2 nguyn t k nhau trn mt y c s l 2,665 A0. Tnh: a) S nguyn t / c s b) Th tch c s c) Tnh khilng ringBi 14: Nguyn t lng ca Na l 22,990 v Cl l 35,453. Nu khi lng ring l2,165 g / cm3. Tnh: a) Hng s mng a b) ng cho mt c) ng cho khi ca c s NaCl.Bi 15: St thay i t Bcc sang Fcc 9100 C. nhit ny, bn knh nguyn t cast trong hai cu trc l 1,258 A0 (Bcc) v 1,292 A0 (Fcc). Tnh % th tch thay i.Bi 16: Hp kim cha 80% khi lng Al v 20 % khi lng Mg. Tnh % nguyn t

    mi loi.Bi 17: Trong cu trc MgO, cc ion Mg2+ b thay th bi Fe2+ theo t l Mg2+ / Fe2+ =17 / 10. Tnh t s khi lng MgO / FeO.

    Bi 18. Khi lng ring thc t ca Al n tinh th l 2,679 g/cm3. Hng s mng a =

    4,0490 (Al : Lp phng tm mt). Nu s khc nhau gia khi lng ring thc t v

    tnh ton l do s c mt cc l trng trong tinh th.

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    Nm hc: 2012 2013

    a) Tnh s v tr b trng trn 1cm3.

    b) Tnh phn v tr b trng

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    Nm hc: 2012 2013

    II. Cu hi chng 2

    1) Trnh by cu trc vng nng lng trong cc vt rn.

    2) Da vo khi nim linh ng ca in t v cu trc vng nng lng hy nu

    c im ca in tr kim loi, in tr ca bn dn tinh khit

    3) Nu v gii thch tnh cht dn in ca bn dn tp cht loi p.

    4) Nu v gii thch tnh cht dn in ca bn dn tp cht loi n.

    5) Nu c ch dn nhit ca vt liu. T gii thch tnh cht dn nhit ca kim

    loi, gm v polyme

    III. Cu hi chng 3

    1) Th no l cht thun t, nghch t, st t, phn st t, feri t. Nu c im

    ca chng

    2) Hy nu ngun gc momen t ca vt liu. Nu c im ca vt liu t cng.

    3) Th no l vt liu t mm, nu tnh cht, c im ca vt liu t mm

    4) Gii thch ng cong t tr thng qua khi nim domen t.So snh s ging v

    khc nhau gia vt liu t cng v vt liu t mm

    5) Nu c im ca siu dn, ng dng ca siu dn

    IV. Cu hi chng4

    1) Laser l g, ng dng ca laser. Nu s b cu to my pht laser

    2) Nu tnh cht quang hc ca vt liu phi kim loi. Trnh by c ch phtquang ca vt liu

    3) Nu tnh cht quang hc ca kim loi, gii thch

    4) Tng tc nh sng vi vt rn

    5) Tng tc nguyn t v in t

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