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8/4/2019 CH 3 Energy and Power in Hyd Systems (Image Compression)
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CH 3
ENERGY AND POWER INHYDRAULIC SYSTEMS
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OBJECTIVES1. Differentiate between hydraulic energy and hydraulic power.2. Define the term efficiency
3. Desribe the operation of and air-to-hydraulic pressure booster.
4. Explain the conservation of energy law
5. Calculate fluid flow rates and velocities using the continuity equation
6. Evaluate the power delivered by a hydraulic cylinder7. Determine the speed of a hydraulic cylinder
8. Describe the differences between potential energy, pressure energy
and Kinetic Energy
9. Describe the operation of a hydraulic jack
10. Apply Bernoullis equation to determine energy transfer within a
hydraulic system.11. Understand the meaning of the terms elevation head, pressure head
velocity head.
12. Differentiate between the terms pump head, motor head and head loss.
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NEWTONS SECOND LAW
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This is when you REALLY want to say f**k Newton and his second law.
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Zero accelerationConstant positive acceleration
with zero initial velocity
Increasing accelerationDecreasing acceleration
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A car travels 35 miles in 45 minutes. What is its average velocity in miles per hour?
PRACTICE
v = S/ T = 35 MILES/43 MINUTES = .814 MILES /MIN
.814 (MILES/MIN)(60MIN/HOUR) = 48.8 MPH
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An angry driver, after being cut off at the last intersection, pulls up next to
the offender at a stoplight. He gets out of his car with a 5 lb tire iron andproceeds to bash on the roof of the guys car with an acceleration of 50
ft/sec2. What force is imparted to the car with each blow?
PRACTICE
W=mg m = W/g = 5 lb/32.2 ft/sec*2 = .155 slugs
F=ma = .155 slugs x 50 ft/sec*2 = 7.76 lbs
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DEFINITION OF : 1 HORSEPOWER
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The engine on your new hot rod is finally broken in.
You take it to a shop to be dyno tested. The dyno
report states that your motor generates 247,000 ft-
lb/sec. If 4 girls = 1 Hp, how many Gp is that?
PRACTICE
Hp = 247,000/550 = 449 Hp
Gp = 4girls/Hp (449 Hp) = 1,796 Gp
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T = FR T = 70 lb x 5 ft = 350 ft -lb
The dimwit who installed the lug nuts on you girlfriends
car after the last tire rotation used an air impact jackedup to apply 300 ft-lb of Torque on the lug nuts. She has
a flat and calls you screaming that she cant get her tire
off using the 2 ft long tire iron in her trunk. Youre
girlfriends pretty scrawny and can only generate 70 lbs
force. You remember that you left a 5 foot long cheater
bar in her trunk. Can she get her tire off using that?
PRACTICE
which means, you dont
have to quit what you were
doin and go get her.
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P = F
A
PASCALS LAW
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In a garage, a car lift is used, compressed air exerts a force
on a small piston with diameter of 5 in. This pressure is
transmitted to a second piston of diameter 15 in. What force
must the compressed air exert in order to lift the a car
weighing 4,000 lb? What Air pressure will produce this force?
PRACTICE
F1 = (A1/A2) x F2 = (2.52)
(7.52)x 4,000 lb = 444 lbs
P1 = F1/A1 = 444 lb/(2.52) = 22.6 psi
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PRACTICE
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HAND OPERATED JACK
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AIR-to-HYDRAULIC BOOSTER
oil
air
air
oil
AA
pP
=
OILOILAIRAIRAPAP =
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AIR TO HYDRAULIC BOOSTER SYSTEM
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POTENTIAL ENERGY DUE TO ELEVATION
POTENTIAL ENERGY UNLEASHED
http://www.youtube.com/watch?v=FdCJzO3w7_M&NR=1http://www.youtube.com/watch?v=FdCJzO3w7_M&NR=18/4/2019 CH 3 Energy and Power in Hyd Systems (Image Compression)
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POTENTIAL ENERGY DUE TO PRESSURE
Pressure used badly
http://www.youtube.com/watch?v=LAiNW1jlmlUhttp://www.youtube.com/watch?v=LAiNW1jlmlU8/4/2019 CH 3 Energy and Power in Hyd Systems (Image Compression)
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KINETIC ENERGY
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Wile E Coyote teaches physics
http://www.youtube.com/watch?v=Jnj8mc04r9Ehttp://www.youtube.com/watch?v=Jnj8mc04r9E8/4/2019 CH 3 Energy and Power in Hyd Systems (Image Compression)
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CONTINUITY
Moving volume
http://www.youtube.com/watch?v=k8IRxT1sM6shttp://www.youtube.com/watch?v=k8IRxT1sM6s8/4/2019 CH 3 Energy and Power in Hyd Systems (Image Compression)
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PRACTICE
EXERCISE
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Load
pump
0 psig
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water zooka
http://www.youtube.com/watch?v=kIgdj0okT3s&feature=relatedhttp://www.youtube.com/watch?v=kIgdj0okT3s&feature=related8/4/2019 CH 3 Energy and Power in Hyd Systems (Image Compression)
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WHY DO AIRPLANES FLY?
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BERNOULLI'S PRINCIPLE
TANKER IMPLOSION
UNEDITED TANKER IMPLOSION
http://home.earthlink.net/~mmc1919/venturi.htmlhttp://www.youtube.com/watch?v=Zz95_VvTxZM&feature=relatedhttp://www.youtube.com/watch?v=hsdC9GX1By0&feature=relatedhttp://www.youtube.com/watch?v=hsdC9GX1By0&feature=relatedhttp://www.youtube.com/watch?v=Zz95_VvTxZM&feature=relatedhttp://home.earthlink.net/~mmc1919/venturi.html8/4/2019 CH 3 Energy and Power in Hyd Systems (Image Compression)
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P = H
substituting for P
we can derive this
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write down the basic Bernoulli equation
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TORRICELLIS THEOREM
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v2=
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ENERGY, POWER AND FLOW RATE IN THE SI SYSTEM
In the English system:
Energy (work) = F x S = lb x ft = lb-ft
Power = Work/t = (lb-ft)/s
from there, we created a derived unit called Horsepower
1HP = 33,000 (ft -lbs )/min1HP = 550 (ft-lbs)/s
In the SI Metric system:
Energy (work) = F x S = 1N x 1m = 1Joule
Power = Work/t = 1J/s = 1 Watt
In the SI system ALL forms of power are expressed in Watts!
1 Hp = 746 Watts
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PUMP HEAD
English
SI
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FLOW RATE
1 (m3/s) = 15,800 gpm, which is very large
Metric Flow Rates are usually specified in:
Liters per second (Lps)
Liters per minute (Lpm)
1 liter = .001 m3