Ch 3 Load and Stress Analysis Shigley Ed 9

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    Chapter 3

    Load and Stress Analysis

    Lecture Slides

    The McGraw-Hill Companies © 2012

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    Chapter Outline

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    Free-Body Diagram Example 3-1

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    Free-Body Diagram Example 3-1

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    Fig. 3-1

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    Free-Body Diagram Example 3-1

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    Free-Body Diagram Example 3-1

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    Free-Body Diagram Example 3-1

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    Shear Force and Bending oments in Beams

    Cut beam at any location x1

    Internal shear force V  and bending moment M  must ensureequilibrium

    Shigley’s Mechanical Engineering Design

    Fig. 3−2

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    Sign Con!entions "or Bending and Shear

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    Fig. 3−3

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    Distri#uted Load on Beam

    Distributed load q( x called load intensity

    !nits of force "er unit length

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    Fig. 3−#

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    $elationships #et%een Load& Shear& and Bending

    $he change in shear force from A to B is equal to the area of theloading diagram bet%een x A and x B.

    $he change in moment from A to B is equal to the area of the

    shear-force diagram bet%een x A and x B.

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    Shear-oment Diagrams

    Shigley’s Mechanical Engineering DesignFig. 3−&

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    oment Diagrams ' (%o )lanes

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    Fig. 3−2#

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    Com#ining oments "rom (%o )lanes

    'dd moments from t%o "lanes as "er"endicularectors

     

    Shigley’s Mechanical Engineering DesignFig. 3−2#

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    Singularity Functions

    ' notation useful

    for integrating

    across

    discontinuities

    'ngle brac)ets

    indicate s"ecial

    function to

    determine %hether

    forces and moments

    are actie

    Shigley’s Mechanical Engineering Design$able 3−1

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    Example 3-*

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    Fig. 3-&

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    Example 3-*

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    Example 3-*

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    Example 3-3

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    Fig. 3-*

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    Example 3-3

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    Example 3-3

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    Fig. 3-*

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    Stress

     Normal stress is normal to a surface+ designated by σ 

    Tangential shear stress is tangent to a surface+ designated by τ  ,ormal stress acting out%ard on surface is tensile stress

     ,ormal stress acting in%ard on surface is compressive stress

    !.. Customary units of stress are "ounds "er square inch ("si

    I units of stress are ne%tons "er square meter (,m21 ,m2 / 1 "ascal (0a

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    Stress element

    e"resents stress at a point 

    Coordinate directions are arbitraryChoosing coordinates %hich result in ero shear stress %ill

     "roduce "rinci"al stresses

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    Cartesian Stress Components

    Defined by three mutually orthogonal surfaces at a "oint %ithin

    a body

    ach surface can hae normal and shear stress

    hear stress is often resoled into "er"endicular com"onents

    First subscri"t indicates direction of surface normal

    econd subscri"t indicates direction of shear stress

    Shigley’s Mechanical Engineering DesignFig. 3−4Fig. 3−5 (a

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    Cartesian Stress Components

    Defined by three mutually orthogonal surfaces at a "oint %ithin

    a body

    ach surface can hae normal and shear stress

    hear stress is often resoled into "er"endicular com"onents

    First subscri"t indicates direction of surface normal

    econd subscri"t indicates direction of shear stress

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    Cartesian Stress Components

    In most cases+ 6cross shears7 are equal

     Plane stress occurs %hen stresses on one surface are ero

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    Fig. 3−5

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    )lane-Stress (rans"ormation E+uations

    Cutting "lane stress element at an arbitrary angle and balancing

    stresses gies plane-stress transformation equations

    Shigley’s Mechanical Engineering DesignFig. 3−8

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    )rincipal Stresses "or )lane Stress

    Differentiating q. (3-5 %ith res"ect to φ  and setting equal toero ma9imies σ  and gies

    $he t%o alues of 2φ  p are the principal directions

    $he stresses in the "rinci"al directions are the principal stresses

    $he "rinci"al direction surfaces hae ero shear stresses.

    ubstituting q. (3-1: into q. (3-5 gies e9"ression for thenon-ero "rinci"al stresses.

     ,ote that there is a third "rinci"al stress+ equal to ero for "lanestress.

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    Extreme-!alue Shear Stresses "or )lane Stress

    0erforming similar "rocedure %ith shear stress in q. (3-8+ the

    ma9imum shear stresses are found to be on surfaces that are

    ;#&< from the "rinci"al directions.

    $he t%o e9treme-alue shear stresses are

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    aximum Shear Stress

    $here are al%ays three "rinci"al stresses. =ne is ero for "lane

    stress.

    $here are al%ays three e9treme-alue shear stresses.

    $he maximum shear stress is al%ays the greatest of these three.q. (3-1# %ill not gie the maximum shear stress in cases

    %here there are t%o non-ero "rinci"al stresses that are both

     "ositie or both negatie.

    If "rinci"al stresses are ordered so that σ 1 > σ 2 > σ 3+then τ ma9 / τ 1.3

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    ohr,s Circle Diagram

    ' gra"hical method for isualiing the stress state at a "oint

    e"resents relation bet%een 9-y stresses and "rinci"al stresses0arametric relationshi" bet%een σ  and τ  (%ith 2φ  as "arameter

    elationshi" is a circle %ith center at

    !  / (σ + τ  / ?(σ  x @ σ  y2+ : A

    and radius of

    Shigley’s Mechanical Engineering Design

    2

    2

    2

     x y

     xy "

    σ σ 

    τ 

    = +

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    ohr,s Circle Diagram

    Shigley’s Mechanical Engineering DesignFig. 3−1:

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    Example 3-

    Shigley’s Mechanical Engineering DesignFig. 3−11

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    Example 3-

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    Example 3-

    Shigley’s Mechanical Engineering DesignFig. 3−11

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    Example 3-

    Shigley’s Mechanical Engineering DesignFig. 3−11

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    Example 3-

    Shigley’s Mechanical Engineering DesignFig. 3−11(d

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    Example 3-

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    Example 3-

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    Example 3- Summary

     x-y 

    orientation

    0rinci"al stress

    orientation

    Ba9 shear

    orientation

    . i i S

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    .eneral (hree-Dimensional Stress

    'll stress elements are actually 3-D.

    0lane stress elements sim"ly hae one surface %ith ero stresses.

    For cases %here there is no stress-free surface+ the "rinci"al

    stresses are found from the roots of the cubic equation

    Shigley’s Mechanical Engineering DesignFig. 3−12

    . l (h Di i l S

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    .eneral (hree-Dimensional Stress

    'l%ays three e9treme shear alues

     Maximum #hear #tress is the largest

    0rinci"al stresses are usually ordered such that σ 1 > σ 2 > σ 3+

    in %hich case τ ma9 / τ 1.3

    Shigley’s Mechanical Engineering DesignFig. 3−12

    El ti St i

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    Elastic Strain

     $oo%e&s la'

     (  is oungs modulus+ or modulus of elasticity

    $ension in on direction "roduces negatie strain (contraction

    in a "er"endicular direction.For a9ial stress in x direction+

    $he constant of "ro"ortionality n is Poisson&s ratio

    ee $able '-& for alues for common materials.

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    El ti St i

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    Elastic Strain

    For a stress element undergoing σ  x+ σ  y+ and σ  ) + simultaneously+

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    El ti St i

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    Elastic Strain

    Eoo)es la% for shear

    #hear strain γ  is the change in a right angle of a stress element%hen subGected to "ure shear stress.

    * is the shear modulus of elasticity or modulus of rigidity

    For a linear+ isotro"ic+ homogeneous material+

    Shigley’s Mechanical Engineering Design

    / i" l Di t i# t d St

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    /ni"ormly Distri#uted Stresses

    !niformly distributed stress distribution is often assumed for

     "ure tension+ "ure com"ression+ or "ure shear.

    For tension and com"ression+

    For direct shear (no bending "resent+

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    0 l St " B i B di

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    0ormal Stresses "or Beams in Bending

    traight beam in "ositie bending

     x a9is is neutral axis x) "lane is neutral plane

     Neutral axis is coincident %ith the

    centroidal axis of the cross section

    Shigley’s Mechanical Engineering Design

    Fig. 3−13

    0 l St " B i B di

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    0ormal Stresses "or Beams in Bending

    Hending stress aries linearly %ith distance from neutral a9is+  y

     +  is the second-area moment  about the )  a9is

    Shigley’s Mechanical Engineering DesignFig. 3−1#

    0ormal Stresses "or Beams in Bending

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    0ormal Stresses "or Beams in Bending

    Ba9imum bending stress is %here y is greatest.

    c is the magnitude of the greatest y

     , +.c is the section modulus

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    Assumptions "or 0ormal Bending Stress

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    Assumptions "or 0ormal Bending Stress

    0ure bending (though effects of a9ial+ torsional+ and shear

    loads are often assumed to hae minimal effect on bending

    stress

    Baterial is isotro"ic and homogeneous

    Baterial obeys Eoo)es la%

    Heam is initially straight %ith constant cross sectionHeam has a9is of symmetry in the "lane of bending

    0ro"ortions are such that failure is by bending rather than

    crushing+ %rin)ling+ or side%ise buc)ling

    0lane cross sections remain "lane during bending

    Shigley’s Mechanical Engineering Design

    Example 3

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    Example 3-

    Shigley’s Mechanical Engineering DesignDimensions in mmFig. 3−1&

    Example 3

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    Example 3-

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    Example 3

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    Example 3-

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    Example 3

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    Example 3-

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    Example 3-

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    Example 3-

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    (%o-)lane Bending

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    (%o-)lane Bending

    Consider bending in both xy and x)  "lanes

    Cross sections %ith one or t%o "lanes of symmetry only

    For solid circular cross section+ the ma9imum bending stress is

    Shigley’s Mechanical Engineering Design

    Example 3-2

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    Example 3-2

    Shigley’s Mechanical Engineering DesignFig. 3−1*

    Example 3-2

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    Example 3-2

    Shigley’s Mechanical Engineering DesignFig. 3−1*

    Example 3-2

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    Example 3 2

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    Example 3-2

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    Example 3 2

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    Shear Stresses "or Beams in Bending

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    Shear Stresses "or Beams in Bending

    Shigley’s Mechanical Engineering Design

    Fig. 3−14

    (rans!erse Shear Stress

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    (rans!erse Shear Stress

    $ranserse shear stress is al%ays accom"anied %ith bending

    stress.

    Shigley’s Mechanical Engineering Design

    Fig. 3−15

    (rans!erse Shear Stress in a $ectangular Beam

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    (rans!erse Shear Stress in a $ectangular Beam

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    aximum alues o" (rans!erse Shear Stress

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    aximum alues o" (rans!erse Shear Stress

    Shigley’s Mechanical Engineering Design

    $able 3−2

    Signi"icance o" (rans!erse Shear Compared to Bending

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    S g c ce o s!e se S e Co p ed o e d g

    Shigley’s Mechanical Engineering Design

    9am"le Cantileer beam+ rectangular cross section

    Ba9imum shear stress+ including bending stress ( My.+  and

    transerse shear stress (V/ +0+

    Signi"icance o" (rans!erse Shear Compared to Bending

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    g p g

    Shigley’s Mechanical Engineering Design

    Critical stress element (largest τ ma9 %ill al%ays be either

    ◦ Due to bending+ on the outer surface ( y.c1+ %here the transerse

    shear is ero◦ =r due to transerse shear at the neutral a9is ( y.c:+ %here the

     bending is ero $ransition ha""ens at some critical alue of 1.h alid for any cross section that does not increase in %idth farther a%ay

    from the neutral a9is.

    ◦ Includes round and rectangular solids+ but not I beams and channels

    Example 3-4

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    p

    Shigley’s Mechanical Engineering DesignFig. 3−2:

    Example 3-4

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    p

    Shigley’s Mechanical Engineering DesignFig. 3−2:(b

    Example 3-4

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    p

    Shigley’s Mechanical Engineering Design

    Fig. 3−2:(c

    Example 3-4

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    p

    Shigley’s Mechanical Engineering Design

    Example 3-4

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    p

    Shigley’s Mechanical Engineering Design

    Example 3-4

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    p

    Shigley’s Mechanical Engineering Design

    Example 3-4

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    Shigley’s Mechanical Engineering Design

    (orsion

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    Torque vector  J a moment ector collinear %ith a9is of a

    mechanical element

    ' bar subGected to a torque ector is said to be in torsion

     Angle of t'ist + in radians+ for a solid round bar 

    Shigley’s Mechanical Engineering DesignFig. 3−21

    (orsional Shear Stress

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    For round bar in torsion+ torsional shear stress is "ro"ortional to

    the radius ρ 

    Ba9imum torsional shear stress is at the outer surface

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    Assumptions "or (orsion E+uations

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    quations (3-3& to (3-34 are only a""licable for the follo%ing

    conditions

    ◦ 0ure torque

    ◦ emote from any discontinuities or "oint of a""lication of

    torque

    ◦ Baterial obeys Eoo)es la%

    ◦ 'dGacent cross sections originally "lane and "arallel remain

     "lane and "arallel

    ◦ adial lines remain straight

    De"ends on a9isymmetry+ so does not hold true fornoncircular cross sections

    Consequently+ only a""licable for round cross sections

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    (orsional Shear in $ectangular Section

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    hear stress does not ary linearly %ith radial distance for

    rectangular cross section

    hear stress is ero at the corners

    Ba9imum shear stress is at the middle of the longest side

    For rectangular 0 9 c bar+ %here 0 is longest side

    Shigley’s Mechanical Engineering Design

    )o%er& Speed& and (or+ue

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    0o%er equals torque times s"eed

    ' conenient conersion %ith s"eed in r"m

    Shigley’s Mechanical Engineering Design

    %here $  / "o%er+ K  n / angular elocity+ reolutions "er minute

    )o%er& Speed& and (or+ue

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    In !.. Customary units+ %ith unit conersion built in

    Shigley’s Mechanical Engineering Design

    Example 3-5

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    Shigley’s Mechanical Engineering DesignFig. 3−22

    Example 3-5

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    Shigley’s Mechanical Engineering DesignFig. 3−23

    Example 3-5

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    Shigley’s Mechanical Engineering Design

    Example 3-5

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    Shigley’s Mechanical Engineering Design

    Example 3-5

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    Shigley’s Mechanical Engineering Design

    Example 3-5

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    Shigley’s Mechanical Engineering Design

    Example 3-5

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    Shigley’s Mechanical Engineering Design

    Example 3-6

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    Shigley’s Mechanical Engineering Design

    Fig. 3−2#

    Example 3-6

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    Shigley’s Mechanical Engineering Design

    Fig. 3−2#

    Example 3-6

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    Shigley’s Mechanical Engineering DesignFig. 3−2#

    Example 3-6

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    Shigley’s Mechanical Engineering Design

    Example 3-6

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    Shigley’s Mechanical Engineering DesignFi . 3−2#

    Example 3-6

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    Shigley’s Mechanical Engineering Design

    Closed (hin-7alled (u#es

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    Kall thic)ness t 22 tube

    radius r 

    0roduct of shear stress

    times %all thic)ness is

    constant

    hear stress is inersely

     "ro"ortional to %allthic)ness

    $otal torque T  is

     Am is the area enclosed by

    the section median line

    Shigley’s Mechanical Engineering Design

    Fig. 3−2&

    Closed (hin-7alled (u#es

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    oling for shear stress

    'ngular t%ist (radians "er unit length

     1m is the length of the section median line

    Shigley’s Mechanical Engineering Design

    Example 3-18

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    Shigley’s Mechanical Engineering DesignFig. 3−2*

    Example 3-18

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    Shigley’s Mechanical Engineering Design

    Example 3-11

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    Shigley’s Mechanical Engineering Design

    Open (hin-7alled Sections

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    Khen the median %all line is not closed+ the section is said to be

    an open section

    ome common o"en thin-%alled sections

    $orsional shear stress

    %here T  / $orque+ 1 / length of median line+ c / %all thic)ness+* / shear modulus+ and θ 1 / angle of t%ist "er unit length

    Shigley’s Mechanical Engineering Design

    Fig. 3−24

    Open (hin-7alled Sections

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    hear stress is inersely "ro"ortional to c3

    'ngle of t%ist is inersely "ro"ortional to c3

    For small %all thic)ness+ stress and t%ist can become quite large

    9am"le

    ◦ Com"are thin round tube %ith and %ithout slit

    atio of %all thic)ness to outside diameter of :.1◦ tress %ith slit is 12.3 times greater 

    ◦ $%ist %ith slit is *1.& times greater 

    Shigley’s Mechanical Engineering Design

    Example 3-1*

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    Stress Concentration

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    Localied increase of stress near discontinuities

     4 t  is $heoretical (Meometric tress Concentration Factor 

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    (heoretical Stress Concentration Factor

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    Mra"hs aailable for

    standard configurations

    ee '""endi9 '-1& and'-1* for common

    e9am"les

    Bany more in Peterson&s

    #tress-!oncentration 5actors

     ,ote the trend for higher

     4 t at shar"er discontinuity

    radius+ and at greaterdisru"tion

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    Stress Concentration "or Static and Ductile Conditions

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    Kith static loads and ductile materials

    ◦ Eighest stressed fibers yield (cold %or)

    ◦ Load is shared %ith ne9t fibers

    ◦ Cold %or)ing is localied

    ◦ =erall "art does not see damage unless ultimate strength is

    e9ceeded

    ◦ tress concentration effect is commonly ignored for static

    loads on ductile materials

    Shigley’s Mechanical Engineering Design

    (echni+ues to $educe Stress Concentration

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    Increase radius

    educe disru"tion

    'llo% 6dead ones7 to sha"e flo%lines more gradually

    Shigley’s Mechanical Engineering Design

    Example 3-13

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    Shigley’s Mechanical Engineering Design

    Fig. 3−3:

    Example 3-13

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    Shigley’s Mechanical Engineering Design

    Fig. '−1& −1

    Example 3-13

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    Fig. '−1&−&

    Stresses in )ressuri9ed Cylinders

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    Cylinder %ith inside radius r i+ outside radius r o+ internal

     "ressure pi+ and e9ternal "ressure po

    $angential and radial stresses+

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    Fig. 3−31

    Stresses in )ressuri9ed Cylinders

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    "ecial case of ero outside "ressure+ po / :

    Shigley’s Mechanical Engineering DesignFig. 3−32

    Stresses in )ressuri9ed Cylinders

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    If ends are closed+ then longitudinal stresses also e9ist

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    (hin-7alled essels

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    Cylindrical "ressure essel %ith %all thic)ness 11: or less of

    the radius

    adial stress is quite small com"ared to tangential stress

    'erage tangential stress

    Ba9imum tangential stress

    Longitudinal stress (if ends are closed

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    Example 3-1

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    Stresses in $otating $ings

    i i h fl h l bl di )

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    otating rings+ such as fly%heels+ blo%ers+ dis)s+ etc.

    $angential and radial stresses are similar to thic)-%alled

     "ressure cylinders+ e9ce"t caused by inertial forces

    Conditions

    ◦ =utside radius is large com"ared %ith thic)ness (>1:1

    ◦ $hic)ness is constant

    ◦ tresses are constant oer the thic)ness

    tresses are

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    )ress and Shrin: Fits

    $ li d i l bl d i h di l i f δ

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    $%o cylindrical "arts are assembled %ith radial interference δ 

    0ressure at interface

    If both cylinders are of the same material

    Shigley’s Mechanical Engineering DesignFig. 3−33

    )ress and Shrin: Fits

    (3 #8 f li d li

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    q. (3-#8 for "ressure cylinders a""lies

    For the inner member+ po  p and pi / :

    For the outer member+ po / : and pi / p

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    (emperature E""ects

    , l t i d t i f t t h

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     ,ormal strain due to e9"ansion from tem"erature change

    %here α  is the coefficient of thermal expansion

    Thermal stresses occur %hen members are constrained to

     "reent strain during tem"erature change

    For a straight bar constrained at ends+ tem"erature increase %ill

    create a com"ressie stress

    Flat "late constrained at edges

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    Coe""icients o" (hermal Expansion

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    Cur!ed Beams in Bending

    I thi ) d b

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    In thic) cured beams

    ◦  ,eutral a9is and centroidal a9is are not coincident

    ◦ Hending stress does not ary linearly %ith distance from the

    neutral a9is

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    Fig. 3−3#

    Cur!ed Beams in Bending

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    r o / radius of outer fiber 

    r i  radius of inner fiber 

    r n  radius of neutral a9is

    r c / radius of centroidal a9is

    h / de"th of sectionco/ distance from neutral a9is to outer fiber 

    ci  distance from neutral a9is to inner fiber 

    e / distance from centroidal a9is to neutral a9is

    M bending momentN "ositie M decreases

    Fig. 3−3#

    Cur!ed Beams in Bending

    Location of ne tral a is

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    Location of neutral a9is

    tress distribution

    tress at inner and outer surfaces

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    Shigley’s Mechanical Engineering Design

    Fig. 3−3&

    Example 3-1

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    Shigley’s Mechanical Engineering Design

    Fig. 3−3&(0

    Example 3-1

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    Shigley’s Mechanical Engineering DesignFig. 3−3&

    Formulas "or Sections o" Cur!ed Beams ;(a#le 3-

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    Shigley’s Mechanical Engineering Design

    Alternati!e Calculations "or e

    '""ro9imation for e alid for large curature %here e is small

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    '""ro9imation for e6 alid for large curature %here e is small

    %ith r n  r c

    ubstituting q. (3-** into q. (3-*#+ %ith r n J y / r + gies

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    Example 3-12

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    Contact Stresses

    $%o bodies %ith cured surfaces "ressed together

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    $%o bodies %ith cured surfaces "ressed together 

    0oint or line contact changes to area contact

    tresses deelo"ed are three-dimensional

    Called contact stresses or $ert)ian stresses

    Common e9am"les

    ◦ Kheel rolling on rail

    ◦ Bating gear teeth

    ◦ olling bearings

    Shigley’s Mechanical Engineering Design

    Spherical Contact Stress

    $%o solid s"heres of diameters d1 and d2 are "ressed together

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    $%o solid s"heres of diameters d 1 and d 2 are "ressed together

    %ith force 5 

    Circular area of contact of radius a

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    Spherical Contact Stress

    0ressure distribution is hemis"herical

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    0ressure distribution is hemis"herical

    Ba9imum "ressure at the center of

    contact area

    Shigley’s Mechanical Engineering Design

    Fig. 3−3*

    Spherical Contact Stress

    Ba9imum stresses on the ) a9is

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    Ba9imum stresses on the )  a9is

    0rinci"al stresses

    From Bohrs circle+ ma9imum shear stress is

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    Spherical Contact Stress

    0lot of three "rinci"al

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    0lot of three "rinci"al

    stress and ma9imum

    shear stress as a functionof distance belo% the

    contact surface

     ,ote that τ ma9 "ea)s

     belo% the contact surfaceFatigue failure belo% the

    surface leads to "itting

    and s"alling

    For "oisson ratio of :.3:+τ ma9 / :.3 pma9 

    at de"th of

     )  / :.#5a

    Shigley’s Mechanical Engineering Design

    Fig. 3−34

    Cylindrical Contact Stress

    $%o right circular cylinders %ith length l and

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    $%o right circular cylinders %ith length l  and

    diameters d 1 and d 2

    'rea of contact is a narro% rectangle of %idth20 and length l 

    0ressure distribution is elli"tical

    Ealf-%idth 0

    Ba9imum "ressure

    Shigley’s Mechanical Engineering Design

    Fig. 3−35

    Cylindrical Contact Stress

    Ba9imum stresses on ) a9is

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    Ba9imum stresses on )  a9is

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    Cylindrical Contact Stress

    0lot of stress

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    0lot of stress

    com"onents and

    ma9imum shearstress as a function

    of distance belo%

    the contact surface

    For "oisson ratioof :.3:+

    τ ma9 / :.3 pma9 

    at de"th of

     )  / :.45*0