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2/5/20151Chng 4BIN I LAPLACENi Dung1. nh ngha bin i Laplace2. Cc tnh cht ca bin i Laplace3. Cc nh l Heaviside 4. Bin i Laplace ca hm tun hon5. Bin i Laplace ngc6. ng dng php bin i Laplace2/5/20152nh Ngha Cho hm () tha mn cc iu kin Dirichlet vi 0. Bin i Laplace ca () l hm () sau: = () = 0
Trong , l mt bin phc Khi , bin i Laplace ngc ca hm () lhm (). K hiu: = 1()V D: , ,
: > ? p dng trc tip cng thc tm bin i Laplace:1 = 0
=
0= 1
= 0
=
0+ 0
=1
2eat= 0
= 0
() =
( )0=1 2/5/20153Tnh Cht Ca Bin i LAPLACE1. Tnh tuyn tnh2. Thay i t l thi gian3. Php dch min thi gian4. Php dch min S5. Vi phn min thi gian6. Tch phn min thi gian7. Vi phn min S8. Tch phn min S nh l Tch chp nh l Duhamel1) Tuyn tnh
1
1()
2
2()
1
1 +2
2
1
1() +2
2()2) Thay i t l thi gian 1
3) Dch min thi gian 0( 0)
0
0
0
( + 0)4) Dch min S
0
0Tnh Cht Ca Bin i LAPLACE ()2/5/201545) Vi phn min thi gian
(0)
=01
1
06) Tch phn min thi gian
0
Tnh Cht Ca Bin i LAPLACE ()7) Vi phn min S (1)
1
8) Tch phn min S
Tnh Cht Ca Bin i LAPLACE ()2/5/20155V d: , ?eat=1 ejat=1 = + +=
2 +2 +
2 +2Cng thc Euler & Tnh cht tuyn tnhejat = cos + sin ejat= cos +sincos =
2 + 2sin =
2 + 22/5/20156V d:
, ? p dng tnh cht tuyn tnh, ta c3 2
= 3 2
= 3 2 1 = 3 5 1 p dng tnh cht dch min S cos =
2 + 2 cos = +1 + 12 + 1V d:
, ? p dng tnh cht vi phn min S, ta co
=1
= 1=12osin =
2+2 t sin =
2 + 2=
2 + 2
2 +2 2=2
2 + 2 22/5/20157V d:
+? p dng tnh cht vi phn min S, ta c
= 1
1
= 1t 1
ln +1 1= 1
1
+1 1 + 1 1 = 1
12
2 1= 1
11 +1 1 1=
V d:
? p dng tnh cht tch phn min S, ta c
= 1
= 1
2 12 = 1 12(2 1)
= 112(2 1)= 4(
)2/5/20158Tnh Cht Ca Bin i LAPLACE ()nh l Tch chp = nh l Duhamel = 1 =
+0+ + 0+
Cng thc tch chp = 0
. . = 0
. . V d: .
+
? =. 2 + 2= .
2 +2.1 = . . p dng cng thc Duhamel = +0+ =1
2+2=sin =11 =
=cos()Ta c, g(0+) = g(0) = 0 =. cos
= .
0
cos . = 2. sin +. .
cos
2+22/5/20159Bin i LAPLACE Ca Hm Tun Hon Nu () l mt hm tun hon vi chu k T, tc l() =( +), trn on [0, ), v lin tc trntng on th = = 0
.
1 ; > 0V d: ?f(t) l hm lin tc, tun hon trong on [0, ) = 02.
1 2=11 2
0
2
=112
0
2=11212 +2
=12. 11+=1. 1+2/5/201510Bin i LAPLACE Ngcnh L Heaviside nh l 1: = 1
& > , :
t hoc l
tq(a): o hm ca q(s) ti aQ(a): a thc q(s) ti a v khng cha (s-a) H qu: = =1
t = =1
t; : ()V d:
++ +?Bc mu > bc t, v N0 ca mu: = 0, 1, 2Cch 1:
=32+6 +2 0 =2 1 =3 2 =6
0 =2 1 =1 2 =2Cch 2:
0 = +1 +2|=0 =2 =01 = +2|=1 =1 =12 = +1|=2 =2 =2 =0
0
0t +1
1
t +2
2
2t = 1 3 + 322/5/201511Bin i LAPLACE Ngcnh L Heaviside (tt) nh l 2: = 1
& > ,
: =
=011
1 !.
!Trong (s) l thng s ca p(s) v tt c cc h s ca q(s) ngoitr
V d:
+
+? i vi h s +2 = 2, L Heaviside 1
1 = 2 2
2 =213
2 =22 i vi h s +13 = 1, L Heaviside 2 =
+ 2; =2 + 22; =4 + 23;1 = 1; 1 = 2; 1 = 4;
2 =
131 !+
132 !
1!+ 10!
3131 !
=42+21
22
=2+212
2
=1 +2 =22+2+2 12
2
2/5/201512Bin i LAPLACE Ngcnh L Heaviside (tt) nh l 3: = 1
& > , () + 2 + 2 =
cos +
sinVi
l phn o &
l phn thc ca biu thc (a+ib) l thngs ca p(s) v tt c cc h s ca q(s) ngoi tr + 2 + 2V d:
+
++? i vi h s +22 = 2, L Heaviside 2 1 =
22 1 0!
00!+22 1 1!
11!
2=350 15 2 =
2 + 2 +10
=2 + 10
2 + 2 + 1022 = 15
2 =3502/5/201513V d:
+
++? 2 +2 +10 = +12 +32 = 1, = 3, L Heaviside 3 2 =
cos +
sin =
+ 22 =1+3 =13 950
= 1350;
= 950 2 = 3950cos3 + 1350sin3 =1 +2 =35015 2 +
3 950cos3 +1350sin 3WD Gii PTVPTT H S HngGii pt sau: 3 10 =2; 0 =1;0 =2 p dng tnh cht vi phn min t, ta c() = () = 0 = 1() = 2 0 0 =2 2 3 10 = 2 } 3 10{ = 2 2 2 3 1 10 =2
2/5/201514WD Gii PTVPTT H S Hng Rt gn
2 3 10 =
2 +2
=
2 +2 5 + 2 p dng nh l Heaviside 1, ta c Bc mu > bc t, v N0 ca mu: = 0, 5, 2
0 = 5 + 2|=0 = 105 = + 2|=5 = 352 = 5|=2 = 14
0 = 2 + 2|=0 = 25 = 2 + 2|=5 = 222 = 2 + 2|=2 = 8 = 15+2235
5 +47
2WD Phn Gii Mch inPhng php 1Phng php 22/5/201515V d: Tm () ? Bit t < 0, K 1; v t 0, K 2Phng Php 11. Lp phng trnh vi phn2. PTVP PT Ton T3. Gii pt ton t4. Chuyn n0pt ton t sang n0 thi gian2/5/201516Phng Php 1 Xt < 0, mch t 0= 0
0= 5PP1: 1/ Lp PTVP Xt 0, 2 p dng nh lut Kirchoff 2 + +1
=011
+ +1
=02 Ta c, 0= 0+= 0 &
0=
0+= 51 +5 =0 =52/5/201517PP1: 2/ PTVP PT Ton T () = () = 0 = () = 2 0 0 = 2 +52 +2 +5 +1
=0 =5 +2+1
=5
2 + +1=5 +122+322PP1:3/ Gii PT Ton T4/ Chuyn N0 p dng nh l Heaviside 3, ta c = 5 + = 12+32= 5 =
cos +
sin = 12
325 sin32
= 103
12
sin32
2/5/201518Phng Php 21. Laplace ha mch in2. p dng nh lut Ohm PT Mch in3. Gii pt mch in ( c Laplace ha)4. Suy ra nghimPP2: Laplace Ha Mch in i vi R i vi L i vi C2/5/201519Phng Php 2 Xt < 0, mch t 0= 0
0= 5PP2: 1/ Laplace Ha Mch in Xt 0, 2 p dng nh lut Kirchoff 2 + 0 +
+0
=0 =0 0
+ +1
=5
2 + +1