93
Changing Bases

Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Embed Size (px)

Citation preview

Page 1: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Changing Bases

Page 2: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Base 10: example number 2120

10³ 10² 10¹ 10⁰

2 1 2 0 ₁₀

10³∙2 + 10²∙1 + 10¹∙2 + 10 ∙0 = 2120⁰ ₁₀

Implied base 10

Base 8: 4110₈

8³ 8² 8¹ 8⁰

4 1 1 0 ₈

8³∙4 + 8²∙1 + 8¹∙1 + 8 ∙0 = 2120⁰ ₁₀

Base 8

Page 3: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²
Page 4: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Hexadecimal Numbers

Hexadecimal numbers are interesting. There are 16 of them!

They look the same as the decimal numbers up to 9, but then there are the letters ("A',"B","C","D","E","F") in place of the decimal numbers 10 to 15. So a single Hexadecimal digit can show 16 different values instead of the normal 10 like this:Decimal: 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15Hexadecimal: 0 1 2 3 4 5 6 7 8 9 A B C D E F

Page 5: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Problem Solving:

3, 2, 1, … lets go!

Page 6: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Express the base 4 number 321₄ as a base ten number.

Page 7: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Answer:

57

Page 8: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Add:

23₄ + 54₈ = _______₁₀ (Base 10 number)

Page 9: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Answer:

55

Page 10: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Subtract:

123.11₄ - 15.23₆ = ______₁₀

(Base 10 number)

Page 11: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Answer:

15 ⁴³⁄₄₈

Page 12: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Express the base 10 number 493 as a base two number.

Page 13: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Answer:

111101101₂

Page 14: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Add:

347.213₁₀ + 11.428₁₀ =

________₁₀(Base 10 number)

Page 15: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Answer:

358.641

Page 16: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Add:

234 + 324 =

________4(Base 4 number)

Page 17: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Answer:

1214

Page 18: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Add:

234 + 324 =

________10(Base 10 number)

Page 19: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Answer:

1214

Page 20: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Factorials

Page 21: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Factorial symbol ! is a shorthand notation for a special type of

multiplication.

Page 22: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

N! is written asN∙(N-1)∙(N-2)∙(N-3)∙ ….. ∙1

Note: 0! = 1

Example: 5! = 5∙4∙3∙2∙1 = 120

Page 23: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Problem Solving:

3, 2, 1, … lets go!

Page 24: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Solve:

6! = _____

Page 25: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Answer:

720

Page 26: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Solve:

5! 3!

Page 27: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Answer:

20

Page 28: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Solve:

5! 3!2!

Page 29: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Answer:

10

Page 30: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Squares

Page 31: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Positive Exponents

“Squared”: a² = a·a

example: 3² = 3·3 = 9

Page 32: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

0²=0 6²=36 12²=1441²=1 7²=49 13²=1692²=4 8²=64 15²=2253²=9 9²=81 16²=2564²=16 10²=100 20²=4005²=25 11²=121 25²=625

Page 33: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

What is the sum of the first 9 perfect squares?

Page 34: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Answer:

1+4+9+16+25+36+49+64+81=

285

Page 35: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Shortcut:Use this formula

n(n+1)(2n+1)6

Page 36: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Shortcut:Use this formula9(9+1)(2∙9+1)

6

Answer: 285

Page 37: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Square Roots

Page 38: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Evaluating Roots

1. Find square roots.2. Decide whether a given root is rational, irrational, or not a real number.

3. Find decimal approximations for irrational square roots.4. Use the Pythagorean formula.5. Use the distance formula.6. Find cube, fourth, and other roots.

9.19.19.19.1

Page 39: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

9.1.1: Find square roots.

•When squaring a number, multiply the number by itself. To find the square root of a number, find a number that when multiplied by itself, results in the given number. The number a is called a square root of the number a

2.

Page 40: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

The positive or principal square root of a number is written with

the symbol .

Find square roots. (cont’d)

0 0

a

Radical Sign Radicand

The symbol , is called a radical sign, always represents the

positive square root (except that ). The number inside the

radical sign is called the radicand, and the entire expression—radical

sign and radicand—is called a radical.

The symbol – is used for the negative square root of a number.

Page 41: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Find square roots. (cont’d)

The statement is incorrect. It says, in part, that a positive number equals a negative number.

9 3

Page 42: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

EXAMPLE 1

• Find all square roots of 64.

Solution:

Finding All Square Roots of a Number

Positive Square Root

Negative Square Root

64 8

64 8

Page 43: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

EXAMPLE 2:

•Find each square root.Solution:

Finding Square Roots

169

225

13

15

25

64

25

64 5

8

Page 44: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

EXAMPLE 3:

•Find the square of each radical expression.

Squaring Radical Expressions

Solution:

17 2

17 17

29 2

29 29

22 3x 222 3x 22 3x

Page 45: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

9.1.2: Deciding whether a given root is rational, irrational, or not a real number.

All numbers with square roots that are rational are called perfect squares.

Perfect Squares Rational Square Roots

25

144

4

9

25 5

144 12

4 2

9 3

A number that is not a perfect square has a square root that is irrational. Many square roots of integers are irrational.

Not every number has a real number square root. The square of a real number can never be negative. Therefore, is not a real number.

-36

Page 46: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

EXAMPLE 4:

•Tell whether each square root is rational, irrational, or not a real number.

Identifying Types of Square Roots

27 irrational

36 26 rational

27 not a real number

Solution:

Not all irrational numbers are square roots of integers. For example (approx. 3.14159) is a irrational number that is not an square root of an integer.

Page 47: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

9.1.3: Find decimal approximations for irrational

square roots.A calculator can be used to find a decimal approximation even if a number is irrational.

Estimating can also be used to find a decimal approximation for irrational square roots.

Page 48: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

EXAMPLE 5: Approximating Irrational Square Roots

Find a decimal approximation for each square root. Round answers to the nearest thousandth.

Solution:

190 13.784048 13.784

99 9.9498743 9.950

Page 49: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Many applications of square roots require the use of the Pythagorean formula.

If c is the length of the hypotenuse of a right triangle, and a and b are the lengths of the two legs, then

9.1.4: Use the Pythagorean formula.

2 2 2.a b c

Be careful not to make the common mistake thinking that

equals .

2 2a b

a b

Page 50: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

What is a right triangle?

It is a triangle which has an angle that is 90 degrees.

The two sides that make up the right angle are called legs.

The side opposite the right angle is the hypotenuse.

leg

leg

hypotenuse

right angle

Page 51: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

The Pythagorean Theorem

In a right triangle, if a and b are the measures of the legs and c is the

hypotenuse, thena2 + b2 = c2.

Note: The hypotenuse, c, is always the longest side.

Page 52: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

The Pythagorean Theorem

“For any right triangle, the sum of the areas of the two small squares is equal to the area of the larger.”

aa22 + b + b22 = c = c22

Page 53: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Proof

Page 54: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Find the length of the hypotenuse if1. a = 12 and b = 16.

122 + 162 = c2

144 + 256 = c2

400 = c2

Take the square root of both sides.

20 = c

2400 c

Page 55: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

52 + 72 = c2

25 + 49 = c2

74 = c2

Take the square root of both sides.

8.60 = c

Find the length of the hypotenuse if2. a = 5 and b = 7.

274 c

Page 56: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Find the length of the hypotenuse given a = 6 and b = 12

1. 1802. 3243. 13.424. 18

Page 57: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Find the length of the leg, to the nearest hundredth, if

3. a = 4 and c = 10.42 + b2 = 102

16 + b2 = 100Solve for b.

16 - 16 + b2 = 100 - 16b2 = 84

b = 9.17

2 84b

Page 58: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Find the length of the leg, to the nearest hundredth, if4. c = 10 and b = 7.

a2 + 72 = 102

a2 + 49 = 100Solve for a.

a2 = 100 - 49a2 = 51

a = 7.14

2 51a

Page 59: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Find the length of the missing side given a = 4 and c = 5

1. 12. 33. 6.44. 9

Page 60: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

5. The measures of three sides of a triangle are given below. Determine

whether each triangle is a right triangle. , 3, and 8

Which side is the biggest?The square root of 73 (= 8.5)! This must be

the hypotenuse (c).Plug your information into the Pythagorean

Theorem. It doesn’t matter which number is a or b.

73

Page 61: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

9 + 64 = 7373 = 73

Since this is true, the triangle is a right triangle!! If it was not true, it

would not be a right triangle.

Sides: , 3, and 832 + 82 = ( ) 2

7373

Page 62: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Determine whether the triangle is a right triangle given the sides 6, 9, and 45

1. Yes2. No3. Purple

Page 63: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

EXAMPLE 6

2 2 213 15a 2 169 225a 2 56a

Using the Pythagorean Formula

7, 24a b

Find the length of the unknown side in each right triangle.

Give any decimal approximations to the nearest thousandth.

15, 13c b

118

?

2 2 27 24 c 249 576 c 2625 c

625c 25

56a 7.483

2 2 28 11b 264 121b 2 57b

57b 7.550

Solution:

Page 64: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

EXAMPLE 7 Using the Pythagorean Formula to Solve an Application

A rectangle has dimensions of 5 ft by 12 ft. Find the length

of its diagonal.

5 ft

12 ft

Solution:

2 2 25 12 c 225 144 c

2169 c

169c

13ftc

Page 65: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

9.1.5: Use the distance formula.

2 2,x yThe distance between the points and is

1 1,x y

2 2

2 1 2 1 .d x x y y

Page 66: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

EXAMPLE 8

• Find the distance between and .

Using the Distance Formula

6,3 2, 4

2 22 6 4 3d

Solution:

224 7d

65d

16 49d

Page 67: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

9.1.6: Find cube, fourth, and other roots. • Finding the square root of a number is the inverse of

squaring a number. In a similar way, there are inverses to finding the cube of a number or to finding the fourth or greater power of a number.

• The nth root of a is written .n a

n a

n a

Radical signIndex

Radicand

In , the number n is the index or order of the radical.

It can be helpful to complete and keep a list to refer to of third and fourth powers from 1-10.

Page 68: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

EXAMPLE 9

• Find each cube root.• Solution:

Finding Cube Roots

3 64

3 27

3 512

4

3

Page 69: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

EXAMPLE 10

• Find each root.

Finding Other Roots

4 81

4 81

4 81

5 243

5 243

3

3

Not a real number.

3

3

Solution:

Page 70: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Evaluating Roots

1. Multiply square root radicals.2. Simplify radicals by using the product rule.

3. Simplify radicals by using the quotient rule.

4. Simplify radicals involving variables.5. Simplify other roots.

9.29.29.29.2

Page 71: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

9.2.1: Multiply square root radicals.

•For nonnegative real numbers a and b, and

•That is, the product of two square roots is the square root of the product, and the square root of a product is the product

of the square roots.

a b a b .a b a b

It is important to note that the radicands not be negative numbers in the product rule. Also, in general, .x y x y

Page 72: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

EXAMPLE 1•Find each product. Assume that

6 11

13 x

Using the Product Rule to Multiply Radicals

Solution:

0.x

3 5

6 11

13 x

10 10

3 5

10 10

15

66

13x

100 10

Page 73: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

9.2.2: Simplify radicals using the product rule.

• A square root radical is simplified when no perfect square factor remains under the radical sign.

• This can be accomplished by using the product rule:

a b a b

Page 74: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

EXAMPLE 2•Simplify each radical.

500

17

Using the Product Rule to Simplify Radicals

Solution:

60 4 15

100 5

It cannot be simplified further.

2 15

10 5

Page 75: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

EXAMPLE 3•Find each product and simplify.

6 2

100 5

Multiplying and Simplifying Radicals

Solution:

10 50

6 2

10 50 500 10 5

12 2 3

Page 76: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

9.2.3: Simplify radicals by using the quotient rule.

• The quotient rule for radicals is similar to the product• rule.

Page 77: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

EXAMPLE 4•Simplify each radical.

48

3

5

36

Solution:

Using the Quotient Rule to Simply Radicals

4

494

49

2

7

48

3 16 4

5

36

5

6

Page 78: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

EXAMPLE 5

• Simplify. Solution:

Using the Quotient Rule to Divide Radicals

8 50

4 5

8 50

4 5

502

5 2 10

2 10

Page 79: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

EXAMPLE 6

• Simplify.

Using Both the Product and Quotient Rules

Solution:

3 7

8 2

3 7

8 2

21

16

21

16

21

4

Page 80: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

9.2.4: Simplify radicals involving variables.

•Radicals can also involve variables.

•The square root of a squared number is always nonnegative. The absolute value is used to express this.

•The product and quotient rules apply when variables appear under the radical sign, as long as the variables represent only nonnegative real numbers

2For any real number , .a a a

, .0x x x

Page 81: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

EXAMPLE 7

•Simplify each radical. Assume that all variables represent positive real numbers.

Simplifying Radicals Involving Variables

Solution:6x

8100 p

4

7

y

3x 23 6Since x x

8100 p 410 p

4

7

y

2

7

y

Page 82: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

9.2.5: Simplify other roots.• To simplify cube roots, look for factors that are perfect

cubes. A perfect cube is a number with a rational cube root.

• For example, , and because 4 is a rational number, 64 is a perfect cube.

• For all real number for which the indicated roots exist,

3 64 4

n a . 0ndn

n n n

n

a aa b ab b

bb

Page 83: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

EXAMPLE 8

•Simplify each radical.

Simplifying Other Roots

Solution:3 108

4 160

416

625

33 27 4 33 4

4 16 10 4 416 10 42 10

4

4

16

625

2

5

Page 84: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Simplify other roots. (cont’d)

• Other roots of radicals involving variables can also be simplified. To simplify cube roots with variables, use the fact that for any real number a,

• This is true whether a is positive or negative.

3 3 .a a

Page 85: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

EXAMPLE 9

•Simplify each radical.

Simplifying Cube Roots Involving Variables

Solution:

3 9z

3 68x

3 554t

15

3a

64

3z

22x3 63 8 x

3 3 227 2t t 3 33 227 2t t 3 23 2t t

3 15

3 64

a

5

4

a

Page 86: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

Adding and Subtracting Radicals

1. Add and subtract radicals.2. Simplify radical sums and differences.3. Simplify more complicated radical expressions.

9.39.39.39.3

Page 87: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

9.3.1: Add and subtract radicals.•We add or subtract radicals by using the distributive

property. For example,8 3 36

8 6 3 .14 3

and 52 2 3,

32 3as well as and 2 3 .

Radicands are different

Indexes are different

Only like radicals—those which are multiples of the same root of the same number—can be combined this way. The preceding example shows like radicals. By contrast, examples of unlike radicals are

Note that cannot be simplified.35 + 5

Page 88: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

EXAMPLE 1

• Add or subtract, as indicated.

Solution:

Adding and Subtracting Like Radicals

8 5 2 5 3 11 12 11 7 10

8 2 5

10 5

3 12 11

9 11

It cannot be added by the distributive property.

Page 89: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

9.3.2: Simplify radical sums and differences.

• Sometimes, one or more radical expressions in a sum or difference must be simplified. Then, any like radicals that result can be added or subtracted.

Page 90: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

EXAMPLE 2

•Add or subtract, as indicated.

Solution:

Adding and Subtracting Radicals That Must Be Simplified

27 12 5 200 6 18332 54 4 2

3 3 2 3

5 3

5 100 2 6 9 2

5 100 2 6 9 2

50 2 18 2

32 2

3 332 27 2 4 2

3 32 3 2 4 2

3 36 2 4 2

310 2

Page 91: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

9.3.3: Simplify more complicated radical expressions.

• When simplifying more complicated radical expressions, recall the rules for order of operations.

A sum or difference of radicals can be simplified only if the radicals are like radicals. Thus, cannot be simplified further.

5 3 5 4 5, but 5 5 3

Page 92: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

EXAMPLE 3A•Simplify each radical expression. Assume that all variables represent nonnegative real numbers.

Simplifying Radical Expressions

7 21 2 27

7 21 2 27

147 2 27

49 3 2 27

49 3 2 27

7 3 2 27

7 3 2 3 3

7 3 6 3

13 3

6 3 8r r

6 2 2r r

6 3 2 2r r

18 2 2r r

9 2 2 2r r

3 2 2 2r r

5 2r

Solution:

Page 93: Changing Bases. Base 10: example number 2120 10³ 10² 10¹ 10 ⁰ 2 1 2 0 ₁₀ 10³∙2 + 10²∙1 + 10¹∙2 + 10 ⁰ ∙0 = 2120 ₁₀ Implied base 10 Base 8: 4110 ₈ 8³ 8²

EXAMPLE 3B

•Simplify each radical expression. Assume that all variables represent nonnegative real numbers.

Simplifying Radical Expressions (cont’d)

2y 72 18y

29 8 9 2y y

23 8 3 2y y

23 2 2 3 2y y

26 2 3 2y y

6 2 3 2y y

3 2y

3 2y

3 33 3 5 2 3x x x x

3 34 481 5 24x x

3 33 33 327 3 5 8 3x x x x

3 33 3 10 3x x x x

313 3x x

Solution: