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Chapter 1: Number Patterns1.6: Geometric SequencesEssential Question: What is a geometric sequence?
1.6: Geometric Sequences• Back in section 1.4, we talked about arithmetic
sequences. An arithmetic sequence was a sequence that simply added a constant term, d.
• GEOMETRIC SEQUENCES (a.k.a. geometric progression) are sequences where A COMMON RATIO, r, IS MULTIPLIED TO SUCCESSIVE TERMS.
• Examples:▫{3, 9, 27, 81, …}▫
5 5 5 5, , , ,...2 4 8 16
r = 3
r = ½
1.6: Geometric Sequences
•Recursive Form:▫Recursive form for arithmetic sequence:
un = un-1 + d, for n ≥ 2
▫RECURSIVE FORM FOR GEOMETRIC SEQUENCE: un = run-1, for r≠0 and n ≥ 2
▫Remember, two things are necessary for a recursive function Starting point (u1) and the function (un)
1.6: Geometric Sequences
•Explicit Form▫If there is a constant number being
multiplied over and over, it’s the same as multiplying that common ratio as an exponent Ex: u2 = u1 ∙ r
u3 = u2 ∙ r = (u1 ∙ r) ∙ r = u1 ∙ r2 u4 = u3 ∙ r = (u1 ∙ r2) ∙ r = u1 ∙ r3
This gives us the EXPLICIT FORM:un = u1 ∙ rn-1
1.6: Geometric Sequences
•Example 4: Explicit▫Write the explicit form of a geometric
sequence where the first two terms are 2 and -2/5 and find the first five terms of the sequence. First, we need to FIND THE COMMON RATIO,
ACQUIRED BY DIVIDING SUCCESSIVE TERMS:
Explicit Form: un = 2 ∙ (-1/5)n-1
The sequence begins
25 1
2 5r
2 2 2 22, , , , ,...
5 25 125 625
1.6: Geometric Sequences•Example 5: Explicit Form
▫The 4th term and 9th terms of a geometric sequence are 20 and -640. Find the explicit form. The first thing we need to do is figure out the
common ratio. The 4th term: u4 = u1rn-1
20=u1r3
The 9th term: u9 = u1rn-1
-640=u1r8
Their ratio can be used to find r:
813
1
5
640
20
32
2
u r
u r
r
r
1.6: Geometric Sequences
•Example 5 (Continued)▫u4=20, u9=-640▫We now know r=-2
Find u1 by using u4: un = u1(-2)n-1
u4 =u1(-2)3
20 =u1(-8) -5/2=u1
We have everything we need for our sequence:un = -5/2 ∙ (-2)n-1
1.6: Geometric Sequences
•Partial Sums▫The kth partial sum of the geometric
sequence {un} with common ratio ≠ 1 is
▫We can also calculate the partial sums using the sum feature of the calculator: sum seq(function,x,1,k) where we plug our
function in
11
1
1
kk
nn
ru u
r
1.6: Geometric Sequences• Example 6: Partial Sums
▫Find the sum:
▫The first term is -3/2, and the common ratio is ½ ▫This is the 9th partial sum (9 terms) of the
geometric sequence:
▫Which you can plug into the formula from the last page, or use the calculator: sum seq((-3/2)*(-1/2)^(x-1),x,1,9) =
3 3 3 3 3 3 3 3 3
2 4 8 16 32 64 128 256 512
13 1
2 2
n
1.6: Geometric Sequences
•Exercises▫Page 63-64
1 – 17 23 – 33 39 – 41 odd problems