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Dr. Munzer Ebaid Dr. Munzer Ebaid 11
Flow in conduits
SUMMARY
Chapter (10)
Dr. MUNZER EBAID
MECH. ENG. DEPT.
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Shear Stress and Velocity Distribution across a Pipe Section
1. Shear Stress distribution is linear.
2. Velocity distribution is parabolic.
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The Average Velocity
Laminar Flow in a Pipe
The Head Loss
The Discharge
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Velocity Distribution in a Smooth Pipe for Turbulent Flow
Applicable everywhere except near the wall
Turbulent Flow in a Pipe
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factorfrictioncalledisfwherefcf 4=
(m) varies from 1/6-1/10
Depending on Re
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Equation (10.22) is called Darcy-Weisbach Equation
64eRfFlowarLaFor =:min
8021 .)(log: −= fRf
FlowTurbulentFor e
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( ) .',,)( usedisdiagramsMoodyinplotD
KRHenceknownare
DK
andVWhen SeS ⎟
⎠⎞
⎜⎝⎛
⎟⎠⎞
⎜⎝⎛
( ) .',,)()( usedisdiagramsMoodyinplotD
KfRHenceknownare
DK
honlyandknownnotisVWhen SeS
f ⎟⎠
⎞⎜⎝
⎛⎟⎠
⎞⎜⎝
⎛
Moody’s Diagram
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Swamee & Jain Formula
%)(')(
)(
3
1021010104 2583
bydiagramsMoodyfromcediffererenfD
KandRFor Se
−− ×
Dr. Munzer Ebaid Dr. Munzer Ebaid 1010
SituationSituation Given ValuesGiven Values Computed Computed
Values in orderValues in orderValues Values
read from read from Moody's Moody's diagramdiagram
Final Value Final Value requiredrequired
Case (a)Case (a)
Case (b)Case (b)
Case (c)Case (c) Assume a value for , Assume a value for , then calculatethen calculate
Iterative Iterative procedure is procedure is used to computeused to compute
mLDKS &,,,
fS hLDK ,,,
LmhK fS ,,, &
DK
RV Se ,,
2123 2⎟⎠⎞
⎜⎝⎛
LghD
DK fS
ν,
f fh
QmV && ,,
DeS RVDK ,,⎟⎠⎞⎜⎝⎛)(D
eRf ,
eRf ,
The problems in the previous slide are summarized in the Table below:
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Example (10.7)Case (C)To solve for the pipe size, i.e (D), an iterative procedure is followed as follows
Assume an initial value for (f)
f D Vk/D Re New (f)Compare (f) with New (f)
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Explicit Equations for Discharge (Q) and Diameter (D)
Swamee & Jain Formula
Streeter & Wile
mLDKS &,,, To calculateGiven fh
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Loss Coefficients For Various Transition and Fittings
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Transition Losses and Grade Lines Energy Grade Line
Hydraulic Grade Line
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Pipe SystemsSimple Pump in a
Pipe Systems
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Pipe in Parallel
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Pipe Networks
S = Sources
L = Loads
The requirements of the pipe
networks design are:
1. Layout of the pipes.
1. Pipe sizes.
2. Future loads.
For the design of the pipe networks,two conditions must be satisfied:
1. Continuity must be satisfied.2. Head loss between any two junctions must
be the same.
DCACBCAB
DCACBCAB
hhhhConditionQQQQCondition
+=++=+
:)(:)(
21
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Uniform Free – Surface Flows
500eRFlowTurbulentFor :
2000/4=500
3000/4=750
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Rock – Bedded Channels
Example (10.16)
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The Chezy Equation and Manning Equation
Manning Eqn.(SI units)
n= The Manning’s Number
Chezy Equation
Manning Eqn.(Imperial units)
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Best Hydraulic Section
The best hydraulic section is the channel proportion that yields a minimum wetted perimeter for a given cross section, hence a large discharge.
factortionthecalledisPAAARtermThe h sec
3232 ⎟
⎠⎞
⎜⎝⎛=
PQandAQthatseenbecanIt 1αα(
For a given channel (hence resistance) and a slope
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Best Hydraulic Section
1. Trapezoidal channel=1/2 a hexagon
2. Circular channel=1/2 a Circle
3. Triangular channel=1/2 a square
Uniform Flow in Culverts and Sewers
Conditions for Design of Sewers:
1. Maximum flow condition.
2. Minimum velocity = 2 ft/s (0.60 m/s).
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Uniform Flow in Culverts
A Culvert is a conduit placed under a fill such as highway embracement. It is used to convey stream flow from uphill side of the fill to the downhill side.
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END OF SUMMARY