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Chapter 19 - Reactions of Acids and Bases. Water is amphoteric - can act as either an acid or base. H 2 O H + + OH - (acting as acid) H 2 O + H + H 3 O + (acting as base) Water forms an equilibrium with itself H 2 O + H 2 O H 3 O + + OH - - PowerPoint PPT Presentation
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Chapter 19 - Chapter 19 - Reactions of Acids Reactions of Acids and Basesand Bases
Water is amphoteric - Water is amphoteric - can act as either an acid can act as either an acid or baseor base HH22O HO H++ + OH + OH-- (acting as acid) (acting as acid)
HH22O + HO + H++ H H33OO++ (acting as base) (acting as base) Water forms an equilibrium with itselfWater forms an equilibrium with itself HH22O + HO + H22O HO H33OO++ + OH + OH--
[H[H33OO++] [OH] [OH--] ]
Keq =Keq = --------------------------------
[H[H22O]O]22
KKeqeq [H [H22O]O]22 = [H = [H33OO++] [OH] [OH--]]
HH22O is a constant (the amount O is a constant (the amount does not change much on percent does not change much on percent basis)basis)
KKww = K = Keqeq [H [H22O]O]22 = [H = [H33OO++] [OH] [OH--] ]
KKww = [H = [H33OO++] [OH] [OH--] = 1.0 x 10] = 1.0 x 10-14-14
KKw w is the ion product constant for is the ion product constant for waterwater
KKww = x = x22 = 1.0 x 10 = 1.0 x 10-14-14
x = 1.0 x 10x = 1.0 x 10-7-7
If [HIf [H33OO++] > 1.0 x 10] > 1.0 x 10-7-7 the solution the solution is acidicis acidic
If [HIf [H33OO++] < 1.0 x 10] < 1.0 x 10-7-7 the solution the solution is basicis basic
See sample problem #1See sample problem #1 Assignment – practice problems 1 Assignment – practice problems 1
& 2 on page 628& 2 on page 628
pH scale – a more pH scale – a more compact way to express compact way to express [H[H33OO++] ] pH = -log [HpH = -log [H33OO++] ] If pH < 7 the solution is acidic If pH < 7 the solution is acidic If pH > 7 the solution is basicIf pH > 7 the solution is basic Example problem: What is the pH if Example problem: What is the pH if
[H[H33OO++] = 7.3 x 10] = 7.3 x 10-5-5 M? M?
pH = -log (7.3 x 10pH = -log (7.3 x 10-5-5 ) = 4.14 ) = 4.14
Do practice problems 3 & 4 on page Do practice problems 3 & 4 on page 630630
More on pHMore on pH
Measuring pH – use acid-base Measuring pH – use acid-base indicators (will change color with pH)indicators (will change color with pH)
Strong acids dissociate completely.Strong acids dissociate completely.
What is the pH of a .1 M solution of What is the pH of a .1 M solution of HCl?HCl?
What is the pH of a 1 M solution of HCl?What is the pH of a 1 M solution of HCl?
What is the pH of a 6 M solution of HCl?What is the pH of a 6 M solution of HCl?
One is not the lowest pH we can have.One is not the lowest pH we can have.
Buffers – resist change in Buffers – resist change in pH by absorbing or pH by absorbing or releasing Hreleasing H++ ions. ions. The most common buffers are The most common buffers are
mixtures of weak acids and their mixtures of weak acids and their conjugate bases.conjugate bases.
Example buffers: HCExample buffers: HC22HH33OO22 + NaC + NaC22HH33OO22
Acetic acid and its conjugate base the Acetic acid and its conjugate base the CC22HH33OO22
-- ion ion
NHNH44Cl and NHCl and NH33 (acid and conj. Base) (acid and conj. Base)
How a buffer worksHow a buffer works
show diagramshow diagram
The buffering capacity is limited The buffering capacity is limited by the amount of HCby the amount of HC22HH33OO22 and and NaCNaC22HH33O2. If we run out of either O2. If we run out of either the buffering capacity is exceeded.the buffering capacity is exceeded.
Equal amount of acetic acid and Equal amount of acetic acid and acetate ion stablize the pH near acetate ion stablize the pH near 4.74.7
We can derive this from the Ka of We can derive this from the Ka of acetic acid, which is 1.8 x 10acetic acid, which is 1.8 x 10-5-5
[H[H33OO++] [C] [C22HH33OO22--] ]
Ka =Ka = ---------------- = 1.8 x 10---------------- = 1.8 x 10-5-5
[HC[HC22HH33OO22] ]
If [CIf [C22HH33OO22--] and [HC] and [HC22HH33OO22] are equal ] are equal
they cancel out of the equationthey cancel out of the equation
Ka = [HKa = [H33OO++] = 1.8 x 10] = 1.8 x 10-5-5 M M
pH = -log 1.8 x 10pH = -log 1.8 x 10-5-5 = 4.74 = 4.74
Experimental Experimental Determination of acid Determination of acid concentration concentration The concentration of a The concentration of a very very
strongstrong acid can be determined by acid can be determined by pH. pH.
The concentration of a weak acid The concentration of a weak acid is more accurately determined by is more accurately determined by an acid/base titration. an acid/base titration.
An acid-base titration is a An acid-base titration is a carefully controlled neutralization carefully controlled neutralization reaction. (see page 637)reaction. (see page 637)
Acid – Base Titration Acid – Base Titration
Equivalence point – when we Equivalence point – when we have added just enough base to have added just enough base to neutralize all of the acid.neutralize all of the acid.
End point – when we are at the End point – when we are at the color change point of a titrationcolor change point of a titration
Phenolphthalein indicator – Phenolphthalein indicator – changes color over a pH range of changes color over a pH range of 8 – 10 (clear to red)8 – 10 (clear to red)
Do example problem on page 638 Do example problem on page 638 together in classtogether in class
Assignment – problems 5 & 6 on Assignment – problems 5 & 6 on page 638page 638
Questions page 646-647 (1-19, Questions page 646-647 (1-19, 32, 33)32, 33)
Problem bank 37, 39, 41, 43, 45, Problem bank 37, 39, 41, 43, 45, 47, 49, 51, 53, 54, 56, 58, 60 47, 49, 51, 53, 54, 56, 58, 60 (answers on page 945)(answers on page 945)