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CHAPTER 20: INDUCED VO LTAGES AN D INDUCTANCE HERRIMAN HIGH AP PHYSICS 2

CHAPTER 20: INDUCED VOLTAGES AND INDUCTANCE HERRIMAN HIGH AP PHYSICS 2

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ELECTROMAGNETIC INDUCTION A changing magnetic field can produce an induced emf (potential difference) A potential difference can cause current to flow HERRIMAN HIGH AP PHYSICS 2

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Page 1: CHAPTER 20: INDUCED VOLTAGES AND INDUCTANCE HERRIMAN HIGH AP PHYSICS 2

CHAPTER 20:

INDUCED VOLTAGES AND IN

DUCTANCE

HERRIMAN HIGH AP PHYSICS 2

Page 2: CHAPTER 20: INDUCED VOLTAGES AND INDUCTANCE HERRIMAN HIGH AP PHYSICS 2

ELECTROMAGNETISMWhen charge is moving (current) it produces a magnetic field.So if current produces a magnetic field can a magnetic field

produce current?

HERRIMAN HIGH AP PHYSICS B

Page 3: CHAPTER 20: INDUCED VOLTAGES AND INDUCTANCE HERRIMAN HIGH AP PHYSICS 2

ELECTROMAGNETIC INDUCTION

A changing magnetic field can produce an induced emf (potential difference)A potential difference can cause current to flow

HERRIMAN HIGH AP PHYSICS 2

Page 4: CHAPTER 20: INDUCED VOLTAGES AND INDUCTANCE HERRIMAN HIGH AP PHYSICS 2

SECTION 20.1 MAGNETIC FLUXIt is actually the change in something called the magnetic flux that induces an emfMagnetic flux is defined as the value of a perpendicular magnetic field multiplied by the area.***NOTE θ is the angle between B and the perpendicular (or “normal”) to the loop***________________________________________________B is perpendicular to the plane of the loop with an area of A, and θ is the angle between B and the normal.

cosBAAB HERRIMAN HIGH AP PHYSICS 2

Page 5: CHAPTER 20: INDUCED VOLTAGES AND INDUCTANCE HERRIMAN HIGH AP PHYSICS 2

SAMPLE PROBLEMA conducting circular loop of radius 0.250 m is place

d in the xy plane of a uniform magnetic field of 0.360 T that points in the positive z direction, the same direction as the normal to the plane.

a) Calculate the magnetic flux through the loop.b) Suppose the loop is rotated clockwise around the x

axis so that the normal direction now points at a 45° angle with respect to the z axis. Recalculate the magnetic flux of the loop.

c) What is the change in flux due to the rotation of the loop?

HERRIMAN HIGH AP PHYSICS 2

Page 6: CHAPTER 20: INDUCED VOLTAGES AND INDUCTANCE HERRIMAN HIGH AP PHYSICS 2

SOLUTION:a)A = πr2=π(0.250 m)2 = 0.196 m2

ΦB = AB cos θ = (0.196 m2)(0.360 T)(cos 0°) = 0.0706 Wb

b)ΦB = AB cos θ = (0.196 m2)(0.360 T)(cos 45°) = 0.0499 Wb

c)ΔΦB = 0.0499 Wb - 0.0706 Wb = -0.0207 Wb

HERRIMAN HIGH AP PHYSICS B

Page 7: CHAPTER 20: INDUCED VOLTAGES AND INDUCTANCE HERRIMAN HIGH AP PHYSICS 2

SECTION 20.2 FARADAY’S LAWThe instantaneous emf induced in a circuit equals the rate of change of the magnetic flux through the circuit ε=Emf (We also call this voltage!)N the number of turns∆Φ=Change in flux∆t=change in time t

N

HERRIMAN HIGH AP PHYSICS 2

Page 8: CHAPTER 20: INDUCED VOLTAGES AND INDUCTANCE HERRIMAN HIGH AP PHYSICS 2

WHEN IS EMF INDUCED?

If the magnitude of B changesIf the direction of B changesIf the area enclosed by the loop changes

HERRIMAN HIGH AP PHYSICS 2

Page 9: CHAPTER 20: INDUCED VOLTAGES AND INDUCTANCE HERRIMAN HIGH AP PHYSICS 2

MICHAEL FARADAY

Faraday is the scientist that was credited with the discovery of electromagnetic induction. He also invented the electric motor, electric generator, and transformer.

HERRIMAN HIGH AP PHYSICS 2

Page 10: CHAPTER 20: INDUCED VOLTAGES AND INDUCTANCE HERRIMAN HIGH AP PHYSICS 2

LENZ’S LAWThe polarity of the induced emf is such

that it produces a current whose magnetic field opposes the change in magnetic flux through the loop.

This means the current tends to keep the original flux though the circuit

HERRIMAN HIGH AP PHYSICS 2

Page 11: CHAPTER 20: INDUCED VOLTAGES AND INDUCTANCE HERRIMAN HIGH AP PHYSICS 2

AN EXAMPLEAs the magnetic field goes into the loop of wire more magnetic field is going through the wire so the flux gets biggerThe current will flow in order to decrease the change in the flux so it will flowclockwise

HERRIMAN HIGH AP PHYSICS 2

Page 12: CHAPTER 20: INDUCED VOLTAGES AND INDUCTANCE HERRIMAN HIGH AP PHYSICS 2

AN EXAMPLEAs the magnetic field goes out of the loop of wire less magnetic field is going through the wire so the flux gets smallerThe current will flow in order to decrease the change in the flux so it will flowCounterclockwise

HERRIMAN HIGH AP PHYSICS 2

Page 13: CHAPTER 20: INDUCED VOLTAGES AND INDUCTANCE HERRIMAN HIGH AP PHYSICS 2

SAMPLE PROBLEMA coil with 25 turns of wire is wrapped in a frame with a

cross sectional area of 1.8 cm on a side. Each turn has the same area, equal to that of the frame, and the total resistance of the coil is 0.350 Ω. An applied uniform magnetic field is perpendicular to the plane of the coil.

a) If the field changes uniformly from 0.0 T to 0.5 T in 0.8 seconds, what is the induced EMF on the coil while the field is changing? Find the:

b) Magnitudec) And direction of the induced current in the coil while

the field is changing.

HERRIMAN HIGH AP PHYSICS 2

Page 14: CHAPTER 20: INDUCED VOLTAGES AND INDUCTANCE HERRIMAN HIGH AP PHYSICS 2

SOLUTIONa) A = L2 = (0.018 m)2 = 3.24 x 10—4 m2

ΦB i= 0 Wb ΦB f= AB cos θ = (3.24 x 10—4 m2)(0.50 T)(cos 0°) =

1.62 x 10 -4 Wb ε = -(25 turns)(1.62 x 10 -4 Wb/0.8 sec) = -5.06 x

10 -3 Vb) I = V/R = 5.06 x 10 -3 V/ 0.35 Ω = 0.0145 Amps c) Magnetic field is up, so put your palm in the opposite

direction, and your thumb will point in the direction of the current (clockwise).

HERRIMAN HIGH AP PHYSICS 2

Page 15: CHAPTER 20: INDUCED VOLTAGES AND INDUCTANCE HERRIMAN HIGH AP PHYSICS 2

SECTION 20.3 MOTIONAL EMFCONDUCTING BAR

As the bar moves through the magnetic field electrons move down because of the magnetic forceWhen there is a charge separation like that there is a potential difference and an Electric Field is createdThe charge will build until the downward magnetic force qvB is balanced by the upward electric force qE

x x x x x x x

x x x x x x x

x x x x x x x

x x x x x x x

x x x x x x x

v

+

HERRIMAN HIGH AP PHYSICS 2

Page 16: CHAPTER 20: INDUCED VOLTAGES AND INDUCTANCE HERRIMAN HIGH AP PHYSICS 2

CONDUCTING BAR IN CLOSED PATH

Because of the moving electrons again a voltage and electric field will be producedBecause it is a closed path current will flow

Diagram acquired at http://www.physics.upenn.edu/courses/gladney/phys151/lectures/lecture_mar_21_2003.shtml through www.google.com.

HERRIMAN HIGH AP PHYSICS 2

Page 17: CHAPTER 20: INDUCED VOLTAGES AND INDUCTANCE HERRIMAN HIGH AP PHYSICS 2

SAMPLE PROBLEMThe sliding bar has a length of 0.5 m and moves at 2.0 m/s in a magnetic field of 0.25 T. a)Find the induced voltage in the moving rod.b)If the resistance of the circuit is 0.5 Ω, find the current in the circuit and the power delivered to the resistor.c)Calculate the Magnetic force on the bar.

x x x x x x x

x x x x x x x

x x x x x x x

x x x x x x x

x x x x x x x

v

+

HERRIMAN HIGH AP PHYSICS 2

Page 18: CHAPTER 20: INDUCED VOLTAGES AND INDUCTANCE HERRIMAN HIGH AP PHYSICS 2

SOLUTIONa)ε= Blv = (0.25 T)((0.5 m)(2.0 m/s) =

0.25 Vb)I = ε/R = 0.25 V / 0.5 Ω = 0.5 A P = IV = (0.5 A)(0.25 V) = 0.125 Wc) Fin = IBl = (0.5 A)(0.25 T)(0.5 m) =

0.0625 N

HERRIMAN HIGH AP PHYSICS 2