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Module PMR
CHAPTER 4 : ALGEBRAIC FORMULAE
1. A variable is a quantity where its value is not fixed.
2. A constant is a quantity where its value is fixed.
3. An algebraic formula is an equation that relates several variables with
constants.
4. The subject of an algebraic formula is a variable expressed as a term in terms
of other variables.
5. An algebraic formula can be rearranged to let another variable to be the
subject of the formula. The process involves:
(a) change the operations: addition, subtraction, multiplication and division;
(b) change roots and square roots
(c) combined operations and determination of roots and power.
A. VARIABLES AND CONSTANTS.
State whether each of the following quantities is a variable or a constant.
Example:
The number of sides of a pentagon.
Constant.
Exercise:
1) The age of your parents.
2) The number of colours of the
rainbow.
3) The daily sales of PTA Stationaries.
Algebraic Formulae 42
Module PMR
State the possible values for each of the following variables.
Example:
The mass (m) of a watermelon, in
kg.
2.5 kg
Exercise:
4) The volume of food (V) consume by
your friends, everyday, in g.
5) The number of students who
scored A’s in Mathematics in
the PMR.
6) The water charges (q) per month of a
school, in RM.
B. FORMULAE
Write formulae based on statements and situations.
An iron pipe measures 95 cm long while a PVC pipe is 7.5 m long. Write a formula for the total length L, in m, of b iron pipes and p PVC pipes.
Errors
L = 95b + 7.5p
Correct Steps
L = 0.95b + 7.5p
Algebraic Formulae 43
Unit in m
Incorrect because unit is in cm
Units are in m
Correct because unit is in m
Module PMR
Example:
The entrance fees to a museum are RM4 for an adult and RM3 for a child. If, on a certain day, p adults and q children visited the museum, write a formula for the total collection of that day.Solution:
Let A = Total collection (in RM)
A = (Number of adults × 4) +
(Number of children × 3)
A = 4p + 3q
Exercise:
1) Saiful has RMp. After spending RM(q + 2) per day for a week, the remainder is RM18. Find a formula for p.
2) Syafik is b years old. His mother is twice his sister’s age. If Syafik is 5 years younger than his sister, write a formula for the sum (S) of their ages.
3) The price of a bicycle is RM500. Write down a formula for the new price, N, if the price is increased by r%.
Algebraic Formulae 44
Module PMR
Example:
Write a formula relating m and n based on the table below.
M 1 2 3 4 5
N 3 5 7 9 11
Solution:
From the table:m = 1 => n = 2(1) + 1 = 3m = 2 => n = 2(2) + 1 = 3m = 3 => n = 2(3) + 1 = 3׃ ׃ ׃ ׃ ׃ ׃ Hence; n = 2m + 1
4)
Write a formula relating m and n based on the table below.
m 1 2 3 4 5
n 3 6 9 12 15
Solution:
5)Write a formula relating m and n based on the table below.
m -1 0 1 2 3
n -3 -2 -1 0 1
Solution:
6)Write a formula relating m and n based on the table below.
M 0 1 2 3 4
n -5 -3 -1 1 3
Solution:
Algebraic Formulae 45
Values of m are substituted here
Module PMR
C. Change the subject
1) Given that 3m – = 1, express m in terms of n.
Common Errors
Error
3m – = 1
3m – 2n = 3
3m = 3 + 2n
m =
Correct Steps
3m – = 1
9m – 2n = 3
9m = 3 + 2n
m =
2) Given , express u in terms of v
Common ErrorErrors
u + v = 5
u = 5 – v
Correct Steps
5v + 5u = uv
uv – 5u = 5v
u(v – 5) = 5v
u =
3) Given that a2 – b2 = 9c2, express a in terms of b and c.
Algebraic Formulae 46
Incorrect because 3m is not multiplied by 3
Incorrect because the concept of LCM is not applied
Module PMR
Common ErrorError
a2 – b2 = 9c2
a2 = 9c2+ b2
a = 3c + b
Correct Steps
a2 – b2 = 9c2
a2 = 9c2+ b2
a =
4) Given that 2 = 3m, express h in terms of k and m.
Error
2 = 3m
2(h + k) = (3m)2
(h + k) =
h =
Correct Steps
2 = 3m
[2 ]2 = [3m]2
4(h + k) = 9m2
(h + k) =
h =
Exercise:
1) Express a in terms of w, if
w =
2) Given a = , express b in terms of a
and c
Algebraic Formulae 47
Incorrect because√(9c2+ b2) ≠ √9c2 + √ b2
Incorrect because2 should be squared
Module PMR
3) Given p = , express w in
terms of p and v
4) Given 2k – = m, express m in terms
of k and n.
5) Given 3(x – z) = 4xy, express x
in terms of y and z.6) Given , express u in terms of f
and v.
7) Given 5pq = qr – 2p, express p
in terms of q and r.8) Given 2π = T, express g in terms of
T and
9) Given v = , express x in
terms of v.
10) Given 5 = t, express n in terms
of m and t.
Algebraic Formulae 48
Module PMR
D Finding the value of a variable.
Example:
Given that W = 3a – , find
(a) W when a = 2 and b = 4,(b) b when a = 3 and W = 5.Solution:
W = 3a –
(a) Substitute a = 2 and b = 4 into
the formula
W = 3(2) –
= 6 – 2
= 4
(b) 5 = 3(3) –
= 9 – 5
b = 4 × 2
= 8
Exercise:
1) Given p = 3q + 5r, find the values of
(a) p when q = 4 and r = 3(b) q when p = 7 and r = 1
Solution:
2) Given k = 2m – 3n2, find the
values of
(a) k when m = 3 and n = -2(b) m when k = -5 and n = 3
Solution:
3) Given y = 2r – 3s + 6t, find the values
of
(a) y when r = 3, s = -2 and t =
(b) t when y = 4, s = 3 and r = -1Solution:
PMR past year questions
2003
1). Given that 3h = 5k + 4, express k
2004
Algebraic Formulae 49
Module PMR
in terms of h.
[2 marks]
2). Given that , express p in
terms of k.
[2 marks]
2005
3). Given , express y in terms
of p.
[2 marks]
2006
4). Given , express n in terms of
F and k.
[2 marks]
2007
5). Given that r2 + 7 = p, express r in
terms of p.
2008
6). Given qr + s = p, express r in terms of
p , q and s.
Algebraic Formulae 50
Module PMR
[2 marks] [2 marks]
CHAPTER 4 : ALGEBRAIC FORMULAEANSWERS
A. Variable and Constant1) Variable 2) Constant
3) Variable 4)
5) 20 students 6) RM300
B. Formulae1) p = 7(q + 2) + 18 2) S = 4b + 15
3) N = 500 + 5r 4) n = 3m
5) n = m – 2 6) n = 2m – 5
C. Change The Subject1) 2)
Algebraic Formulae 51
Module PMR
3) 4)
5) 6)
7) 8)
9) 10)
D Finding the value of a variable
1)a) P= 27b) q = 2/3
2)a) k=-6b) m=11
3) Y=15
T =
PMR past year questions
20031). 5k = 3h - 4
k =
1
1
20042). 2p - 6 = 5k 2p = 5k + 6
p =
11
1
20053). 4y - 3 = 2y + 2p 2y = 2p + 3
y =
11
1
Algebraic Formulae 52
Module PMR
20064). 5F = 3n - nk n(3 - k) = 5F
n =
11
1
20075). = p - 7
r =
11
20086). qr = p - s
r =
1
1
Algebraic Formulae 53